Let's say i have two tables
Customer
---
Id Name
1 Foo
2 Bar
and
CustomerPurchase
---
CustomerId, Amount, AmountVAT, Accountable(bit)
1 10 11 1
1 20 22 0
2 5 6 0
2 2 3 0
I need a single record for every joined and grouped Customer and CustomerPurchase group.
Every record would contain
columns from table Customer
some aggregation functions like SUM
a 'calculated' column. For example difference of other columns
result of subquery to CustomerPurchase table
An example of result i would like to get
CustomerPurchases
---
Name Total TotalVAT VAT TotalAccountable
Foo 30 33 3 10
Bar 7 9 2 0
I was able to get a single row only by grouping by all the common columns, which i dont think is the right way to do. Plus i have no idea how to do the 'VAT' column and 'TotalAccountable' column, which filters out only certain rows of CustomerPurchase, and then runs some kind of aggregate function on the result. Following example doesn't work ofc but i wanted to show what i would like to achieve
select C.Name,
SUM(CP.Amount) as 'Total',
SUM(CP.AmountVAT) as 'TotalVAT',
diff? as 'VAT',
subquery? as 'TotalAccountable'
from Customer C
inner join CustomerPurchase CR
on C.Id = CR.CustomerId
group by C.Id
I would suggest you just need the follow slight changes to your query. I would also consider for clarity, if you can, to use the terms net and gross which is typical for prices excluding and including VAT.
select c.[Name],
Sum(cp.Amount) as Total,
Sum(cp.AmountVAT) as TotalVAT,
Sum(cp.AmountVAT) - Sum(CP.Amount) as VAT,
Sum(case when cp.Accountable = 1 then cp.Amount end) as TotalAccountable
from Customer c
join CustomerPurchase cp on cp.CustomerId = c.Id
group by c.[Name];
Related
I currently have a select statement that is causing me issues, i have two tables:
Customer table
ID Month4Value Month5Value
1 24 5
Orders table
ID Year Month Value Quantity
1 2018 8 10 2
1 2018 4 2 1
1 2018 6 10 4
1 2018 4 7 3
I currently have the below view:
Create View Values as
Select ID, Year, Month, ROUND(SUM(Value*Quantity),2) as NewQuantity
FROM Orders
GROUP BY ID, Year, Month
The below select statement is what i am trying to run
Select Customer.ID, Customer.Month5Value, NewQuantity
from Customer inner join Values on Customer.ID = Values.ID
where ROUND(Customer.Month5Value, 2) <> ROUND(NewQuantity,2)
AND Values.Year = 2018
AND Values.Month = 5
What i am trying to achieve is to find any mismatches between the Orders table and the Customer table. In the above example, what i am expecting is to highlight that the value in Customer.Month5Value does not match the total of the (Quantity*Value) from the Orders table.
As there are 0 orders for Month 5 in the Orders Table, the Month5Value should be 0. However, it returns no entrys.
Any thoughts about what i have missed?
EDIT -
I have updated my query to this:
Select Customer.ID, Customer.Month5Value, NewQuantity
from Customer left join Values on Customer.ID = Values.ID
where ROUND(Customer.Month5Value, 2) <> ISNULL((Select NewQuantity from Customer left join Values on Customer.ID = Values.ID where Values.Month = 5 and Values.Year = 2018),0)
This has given me a list of IDs which have an incorrect amount in Month5Value on the Customer table, but displays lines for each month entry
ID Month5Value NewQuantity
1 5 24
1 5 40
1 5 20
How can i adjust this so that I get one line per ID with the correct value for NewQuantity (either 0 or NULL in this case)?
I think the INNER JOIN is removing any records which are missing from VALUES. Replacing the INNER JOIN with LEFT JOIN may give the result you are looking for.
I have the following table which contains ID's and UserId's.
ID UserID
1111 11
1111 300
1111 51
1122 11
1122 22
1122 3333
1122 45
I'm trying to count the distinct number of 'IDs' so that I get a total, but I also need to get a total of ID's that have also seen the that particular ID as well... To get the ID's, I've had to perform a subquery within another table to get ID's, I then pass this into the main query... Now I just want the results to be displayed as follows.
So I get a Total No for ID and a Total Number for Users ID - Also would like to add another column to get average as well for each ID
TotalID Total_UserID Average
2 7 3.5
If Possible I would also like to get an average as well, but not sure how to calculate that. So I would need to count all the 'UserID's for an ID add them altogether and then find the AVG. (Any Advice on that caluclation would be appreciated.)
Current Query.
SELECT DISTINCT(a.ID)
,COUNT(b.UserID)
FROM a
INNER JOIN b ON someID = someID
WHERE a.ID IN ( SELECT ID FROM c WHERE GROUPID = 9999)
GROUP BY a.ID
Which then Lists all the IDs and COUNT's all the USERID.. I would like a total of both columns. I've tried warpping the query in a
SELECT COUNT(*) FROM (
but this only counts the ID's which is great, but how do I count the USERID column as well
You seem to want this:
SELECT COUNT(DISTINCT a.ID), COUNT(b.UserID),
COUNT(b.UserID) * 1.0 / COUNT(DISTINCT a.ID)
FROM a INNER JOIN
b
ON someID = someID
WHERE a.ID IN ( SELECT ID FROM c WHERE GROUPID = 9999);
Note: DISTINCT is not a function. It applies to the whole row, so it is misleading to put an expression in parentheses after it.
Also, the GROUP BY is unnecessary.
The 1.0 is because SQL Server does integer arithmetic and this is a simple way to convert a number to a decimal form.
You can use
SELECT COUNT(DISTINCT a.ID) ...
to count all distinct values
Read details here
I believe you want this:
select TotalID,
Total_UserID,
sum(Total_UserID+TotalID) as Total,
Total_UserID/TotalID as Average
from (
SELECT (DISTINCT a.ID) as TotalID
,COUNT(b.UserID) as Total_UserID
FROM a
INNER JOIN b ON someID = someID
WHERE a.ID IN ( SELECT ID FROM c WHERE GROUPID = 9999)
) x
I want to get all the possible type from a table and then count the rows under a group who has this type.
To better illustrate consider the following table.
Object (o)
id name group_id type
-----------------------------------------------------------
1 Computer 100 A
2 Monitor 100 A
3 Chair 100 B
4 Table 100 B
5 Telephone 100 C
6 Notebook 200 D
7 Pen 200 D
8 Wire 100 E
What I want to get is the following result:
group_id type total
-------------------------------
100 A 2
100 B 2
100 C 1
100 D 0
100 E 1
The group_id doesn't have to be included in the result, I just wanted to let you see here that I'm using a WHERE clause in my query. Basically I only want the results for group | 100 but I want the counts for all type.
Using my query below
SELECT o.group_id, o.type, COUNT(*) AS total
FROM object o
WHERE o.group_id = 100
GROUP BY o.type
I only get the following result:
group_id type total
-------------------------------
100 A 2
100 B 2
100 C 1
100 E 1
You will notice that I am missing the row for type | D. I also want to include that.
You can use the following query:
SELECT 100 AS group_id,
o.type,
COUNT(CASE WHEN o.group_id = 100 THEN 1 END) AS total
FROM object o
GROUP BY o.type
This query groups by type and uses conditional aggregation so as to count the rows under each group who have type = 100.
The problem is that Type D is not returned in the query for that ID, so it is not included in the groupings. To do this, we need to get the list of ALL Types in the table, then do the counts for your ID in the table. Something like this:
SELECT o_list.type, COUNT(o.id) AS total
FROM object o
RIGHT OUTER JOIN ( SELECT DISTINCT type from object ) o_list on o_list.type = o.type
WHERE o.group_id = 100
GROUP BY o_list.type
Giorgos's version is, arguably, cleaner to read and will always run in one full scan of the table. Mine is more complex, but if there are indexes on group_id and type, will run on index scans and so may be significantly faster on a large data set.
And you get to see that there are always options on how to solve a problem. :)
Since Type isn't in group 100 I first get a distinct set of types, then join back to objects since you want 100 for type D, I always show 100 when the type doesn't exist.
SELECT coalesce(O.Group_ID,100) as Group_ID, T.Type, count(O.Group_ID) as Total
FROM (Select Distinct Type from object) T
LEFT JOIN Object O
on T.Type = O.Type
GROUP BY coalesce(O.Group_ID,100), T.Type
I have a table called RESULTS with this structure :
resultid,winner,type
And a table called TICKETS with this structure :
resultid,ticketid,bet,sum_won,status
And I want to show each row from table RESULTS and for each result I want to calculate the totalBet and Sum_won using the values from table TICKETS
I tried to make some joins,some sums,but I cant get what I want.
SELECT *,COALESCE(SUM(tickets.bet),0) AS totalbets,
COALESCE(SUM(tickets.sum_won),0) AS totalwins
FROM `results` NATURAL JOIN `tickets`
WHERE tickets.status<>0
GROUP BY resultid
Please give me some advice.
I want to display something like this
RESULT WINNER TOTALBETS TOTALWINS
1 2 431 222
2 3 0 0
3 1 23 0
4 1 324 111
Use:
SELECT r.*,
COALESCE(x.totalbet, 0) AS totalbet,
COALESCE(x.totalwins, 0) AS totalwins
FROM RESULTS r
LEFT JOIN (SELECT t.resultid,
SUM(t.bet) AS totalbet,
SUM(t.sum_won) AS totalwins
FROM TICKETS t
WHERE t.status != 0
GROUP BY t.resultid) x ON x.resultid = r.resultid
I don't care for the NATURAL JOIN syntax, preferring to be explicit about how to JOIN/link tables together.
SELECT *, COALESCE(SUM(tickets.bet),0) AS totalbets,
COALESCE(SUM(tickets.sum_won),0) AS totalwins
FROM `results` NATURAL JOIN `tickets`
WHERE tickets.status<>0
GROUP BY resultid
Try to replace the first * with resultid. If this helps, then add more columns to SELECT and add them to GROUP BY at the same time.
database table like this
============================
= suburb_id | value
= 1 | 2
= 1 | 3
= 2 | 4
= 3 | 5
query is
SELECT COUNT(suburb_id) AS total, suburb_id
FROM suburbs
where suburb_id IN (1,2,3,4)
GROUP BY suburb_id
however, while I run this query, it doesn't give COUNT(suburb_id) = 0 when suburb_id = 0
because in suburbs table, there is no suburb_id 4, I want this query to return 0 for suburb_id = 4, like
============================
= total | suburb_id
= 2 | 1
= 1 | 2
= 1 | 3
= 0 | 4
A GROUP BY needs rows to work with, so if you have no rows for a certain category, you are not going to get the count. Think of the where clause as limiting down the source rows before they are grouped together. The where clause is not providing a list of categories to group by.
What you could do is write a query to select the categories (suburbs) then do the count in a subquery. (I'm not sure what MySQL's support for this is like)
Something like:
SELECT
s.suburb_id,
(select count(*) from suburb_data d where d.suburb_id = s.suburb_id) as total
FROM
suburb_table s
WHERE
s.suburb_id in (1,2,3,4)
(MSSQL, apologies)
This:
SELECT id, COUNT(suburb_id)
FROM (
SELECT 1 AS id
UNION ALL
SELECT 2 AS id
UNION ALL
SELECT 3 AS id
UNION ALL
SELECT 4 AS id
) ids
LEFT JOIN
suburbs s
ON s.suburb_id = ids.id
GROUP BY
id
or this:
SELECT id,
(
SELECT COUNT(*)
FROM suburb
WHERE suburb_id = id
)
FROM (
SELECT 1 AS id
UNION ALL
SELECT 2 AS id
UNION ALL
SELECT 3 AS id
UNION ALL
SELECT 4 AS id
) ids
This article compares performance of the two approaches:
Aggregates: subqueries vs. GROUP BY
, though it does not matter much in your case, as you are querying only 4 records.
Query:
select case
when total is null then 0
else total
end as total_with_zeroes,
suburb_id
from (SELECT COUNT(suburb_id) AS total, suburb_id
FROM suburbs
where suburb_id IN (1,2,3,4)
GROUP BY suburb_id) as dt
#geofftnz's solution works great if all conditions are simple like in this case. But I just had to solve a similar problem to generate a report where each column in the report is a different query. When you need to combine results from several select statements, then something like this might work.
You may have to programmatically create this query. Using left joins allows the query to return rows even if there are no matches to suburb_id with a given id. If your db supports it (which most do), you can use IFNULL to replace null with 0:
select IFNULL(a.count,0), IFNULL(b.count,0), IFNULL(c.count,0), IFNULL(d.count,0)
from (select count(suburb_id) as count from suburbs where id=1 group by suburb_id) a,
left join (select count(suburb_id) as count from suburbs where id=2 group by suburb_id) b on a.suburb_id=b.suburb_id
left join (select count(suburb_id) as count from suburbs where id=3 group by suburb_id) c on a.suburb_id=c.suburb_id
left join (select count(suburb_id) as count from suburbs where id=4 group by suburb_id) d on a.suburb_id=d.suburb_id;
The nice thing about this is that (if needed) each "left join" can use slightly different (possibly fairly complex) query.
Disclaimer: for large data sets, this type of query might have not perform very well (I don't write enough sql to know without investigating further), but at least it should give useful results ;-)