I need to make a built-in counter of the number of things through the Map in the Map.
initialization:
var Items = mapOf<Map<String, Item>, Int>()
Example of interaction
for(i in item)
if (this.UnitInventory.Items.containsKey(Pair(i.Name, i) as Map<String, Item>))
this.UnitInventory.Items[Pair(i.Name, i)]++
else
this.UnitInventory.Items += mapOf(Pair(Pair(i.Name, i) as Map<String, Item>, 1))
How to properly write part this.UnitInventory.Items[Pair(i.Name, i)]++?
Like Tenfour04 says in the comments, this is kinda brittle - but so long as you're using immutable Maps as keys it's probably ok? Anyway, if that's what you want, you can do this:
// this -outer- map needs to be mutable (since you'll be adding new counts)
val items = mutableMapOf<Map<String, Int>, Int>()
// make some map keys to count
val someMap = mapOf("One" to 1)
val someOtherMap = mapOf("Two" to 2, "Three" to 3)
val stuff = listOf(someMap, someOtherMap, someMap)
// add them to the counts
stuff.forEach { item ->
// update the current count, defaulting to zero if it doesn't exist yet
items[item] = items.getOrDefault(item, 0) + 1
}
println(items)
>> {{One=1}=2, {Two=2, Three=3}=1}
Related
Is it possible to access the whole Pair of a map, not only the key or a value?
Let's say we have a map
map = mapOf(Pair("Example1", 1), Pair("Example2", 2), Pair("Example3",
3))
I would like to access the second pair and put it into a variable, something like I would do with a list:
val ex2 = map[1] #this would result with {"Example2", 2}
And then i would be able to access the pair's key/value like:
ex2.key / ex2.value
More specifically, I would like to use this in my function to return a specific pair of the map.
Not sure if this would help
val mapString = mutableMapOf(1 to "Person", 2 to "Animal")
val (id, creature) = 1 to mapString.getValue(1)
Log.e("MapPair", "$id, $creature")
prints
1, Person
or if you're iterating through the entire map
mapString.forEach {
val (id, creature) = it.key to it.value
Log.e("MapPair", "$id : $creature")
}
prints
1 : Person
2 : Animal
or using Pair
val key = 1
val pair = Pair(key, mapString.getValue(key))
Log.e("MapPair", "$pair")
prints
(1, Person)
or if you're iterating through the entire map using Pair
mapString.forEach {
val pair = Pair(it.key, it.value)
Log.e("MapPair", "$pair")
}
prints
(1, Person)
(2, Animal)
Update: For iterating through the map you can also go with Destructuring Declarations
val mapString = mutableMapOf(1 to "Person", 2 to "Animal")
for ((key, value) in mapString) {
Log.e("MapComponents", "$key, $value")
}
From your comment, it seems like you want to fetch the key corresponding to a given value.
val map = mapOf("Chicken" to 20, "Egg" to 10, "Bread" to 5)
val valueToFind = 20
val key = map.toList().find { it.second == valueToFind }?.first
println(key)
Output:
Chicken
If the value doesn't exist, it will give null.
I'm working on an algorithm type challenge, and i am debugging via print statements and i can't seem to figure out why the the values for keys are not what i am expecting
var mapNums = mutableMapOf<Int, Int>()
//imaginary array
//var nums = [34,28,11,21,3,34,8,7,34,7,31,7,3,28,18]
var count = 0
for (n in nums) {
if (mapNums.containsKey(n)) {
count ++
mapNums[n] = count
} else if (!mapNums.containsKey(n)) {
count = 1
mapNums[n] = count
}
}
println(mapNums)
//prints {34=2, 28=4, 11=1, 21=1, 3=3, 8=1, 7=2, 31=1, 18=1}
as you can see the key and values aren't what theyre supposed to be and i am not sure why.
You can use the following code to generate the desired map:
val nums = intArrayOf(34, 28, 11, 21, 3, 34, 8, 7, 34, 7, 31, 7, 3, 28, 18).toList()
println(nums.groupingBy { it }.eachCount())
try it yourself
Here groupingBy creates a Grouping source using the same element as the key selector. Then eachCount groups elements from the Grouping source by key and counts elements in each group.
You can also refer the documentation for more info about groupingBy and eachCount.
It's because you reuse the same count variable outside of the loop so it keeps incrementing from different keys.
Instead you should get the current count from the map, then put it back one higher:
val nums = intArrayOf(34,28,11,21,3,34,8,7,34,7,31,7,3,28,18)
val mapNums = mutableMapOf<Int, Int>()
for (n in nums) {
val count = mapNums[n] ?: 0
mapNums[n] = count + 1
}
println(mapNums) // {34=3, 28=2, 11=1, 21=1, 3=2, 8=1, 7=3, 31=1, 18=1}
Firstly check n number is contain this map as key, if found then increment 1 its value using plus method. If not found any value from the map, it will null and check if null and set 1.
var mapNums = mutableMapOf<Int, Int>()
//imaginary array
var nums = arrayOf(34,28,11,21,3,34,8,7,34,7,31,7,3,28,18)
for (n in nums) {
mapNums[n] = mapNums[n]?.plus(1) ?: 1
}
println(mapNums)
I have the following code snippet
val cachedNews = listOf(News(9, "https://009"), News(8, "https://234"), News(7, "https://345"))
val freshNews = listOf(News(1, "https://123"), News(2, "https://234"), News(3, "https://345"))
val result = freshNews.filter {fresh -> filter(cachedNews, fresh)}
private fun filter(cached: List<News>, fresh: News): Boolean {
cached.forEach { cachedItem ->
if (cachedItem.url == fresh.url) return true
}
return false }
When the code runs if cachedItem.url == fresh.url the list is filtered and the result is a list where the urls of the two lists are identical. However when i reverse equality like so cachedItem.url != fresh.url the list is not filtered at all. The sequence of execution changes.
When using the == sign, the first item of freshNews is compared with the first Item of cachedNews after that the secondItem of freshNews is compared with secondItem of cachedNews and so on.
When I use the != sign the all items of freshNews are compared against only the firstItem of cachedNews ??
Am I missing something or is my code just wrong?
I'm not sure what the specific problem is because your approach is quite confusing. Your custom filter function is actually more like a contains function.
What might be useful is to:
Extract the cached URLs to a set
Filter the new results by URLs that are not in the set.
fun main() {
val cachedNews = listOf(News(9, "https://009"), News(8, "https://234"), News(7, "https://345"))
val freshNews = listOf(News(1, "https://123"), News(2, "https://234"), News(3, "https://345"))
val cachedUrls = cachedNews.map { it.url }.toSet()
val result = freshNews.filterNot { cachedUrls.contains(it.url) }
println(result)
}
Result:
[News(id=1, url=https://123)]
In Kotlin, how can I take the first n elements of this array:
val allColours = arrayOf(
Pair(Color.RED, Color.WHITE),
Pair(Color.RED, Color.BLACK),
Pair(Color.YELLOW, Color.BLACK),
Pair(Color.GREEN, Color.WHITE),
Pair(Color.BLUE, Color.WHITE),
Pair(Color.BLUE, Color.WHITE),
Pair(Color.CYAN, Color.BLACK),
Pair(Color.WHITE, Color.BLACK))
So how can I fill pegColours with the first say 3 Pairs?
var pegColours: Array<Pair<Color,Color>> = //???
I tried allColours.take but it gave an error:
Expecting an element
You need to specify the number of items you want to take.
allColours.take(3)
For a random number of random indices, you can use the following:
val indexes = arrayOf(2, 4, 6)
allColours.filterIndexed { index, s -> indexes.contains(index) }
Note that you can write an extension method for this:
fun <T> Array<T>.filterByIndices(vararg indices: Int) = filterIndexed { index, _ -> indices.contains(index) }
Alternatively, if the indices are consecutive, you can use slice:
allColours.slice(1..3)
The problem with your code that you create pairs with color constants which are Ints (allColours has type Array<Pair<Int, Int>>), but you expect Array<Pair<Color, Color>>. What you have to do is change type pegColours type and use take:
var pegColours: Array<Pair<Int, Int>> = allColours.take(3).toTypedArray()
Also you have to call toTypedArray() cause Array.take returns List rather than Array. Or you can change pegColours type as following:
var pegColours: List<Pair<Int, Int>> = allColours.take(3)
I know you already proposed the usage of take, but alternatively ranges and a simple map also help to write idiomatic code as shown next:
var pegColours = (0 until 3)
.map { allColours[it] }
.toTypedArray()
You are very close :)
val allColours = arrayOf("red", "blue", "green")
kotlin.io.println(allColours.take(2))
Will give you first two elements ["red", "blue"]
You have to specify the number of elements you want to take from the array
I have a string array and an integer array. How do I create a map using the first as keys and the second as values?
val keys = arrayOf("butter", "milk", "apples")
val values = arrayOf(5, 10, 42)
val map: Map<String, Int> = ???
How to convert List to Map in Kotlin? doesn't solve this problem; I have 2 arrays and want a single map.
You can zip together the arrays to get a list of pairs (List<Pair<String, Int>>), and then use toMap to get your map.
Like this:
val keys = arrayOf("butter", "milk", "apples")
val values = arrayOf(5, 10, 42)
val map: Map<String, Int> =
keys.zip(values) // Gives you [("butter", 5), ("milk", 10), ("apples", 42)]
.toMap() // This is an extension function on Iterable<Pair<K, V>>
According to kotlin
Constructing Collections
-> creating a short-living Pair object, is not recommended only if performance isn't critical and to quote: "To avoid excessive memory usage, use alternative ways. For example, you can create a mutable map and populate it using the write operations. The apply() function can help to keep the initialization fluent here."
since I'm not much of an expert I run on to these code and maybe this should work better?:
val numbersMap = mutableMapOf<String,Int>()
.apply{ for (i in 1.. 5) this["key$i"] = i }
println(numbersMap)
//result = {key1=1, key2=2, key3=3, key4=4}
or to adjust it to question above - something like this:
val keys = arrayOf("butter", "milk", "apples")
val values = arrayOf(5, 10, 42)
val mapNumber = mutableMapOf<String, Int>()
.apply { for (i in keys.indices) this[keys[i]] = values[i] }
println(mapNumber)