How can I retrieve rows where BID comes up multiple times in AID
You can see the sample below, AID and BID columns are under the PrimaryID, and BIDs are under AID. I want to come up with an output that only takes records where BIDs had 1 to many relationship with records on AIDs column. Example output below.
I provided a small sample of data, I am trying to retrieve 20+ columns and joining 4 tables. I have unqiue PrimaryIDs and under those I have multiple unique AIDs, however under these AIDs I can have multiple non-unqiue BIDs that can repeatedly come up under different AIDs.
Hive supports window functions. A window function can associate every row in a group with an attribute of the group. Count() being one of the supported functions. In your case you can use that a and select rows for which that count > 1
The partition by clause you specify which columns define the group, tge same way that you would in the more familiar group by clause.
Something like this:
select * from
(
Select *,
count(*) over (partition by primaryID,AID) counts
from mytable
) x
Where counts>1
Related
On a report builder 3.0, i retreived some items and counted them using a Count aggregate. Now i want to order them from highest to lowest. How do i use the ORDER BY function on the aggregated column? The picture below show the a column that i want to ORDER BY it, it is ticked.
Pic
The code is vers simple as shown bellow:
SELECT DISTINCT act_id,NameOfAct,
FROM Acts
Your picture indicates you also want a Total row at the bottom:
SELECT
COALESCE(NameOfAct,'Total') NameOfAct,
COUNT(DISTINCT act_id) c
FROM Acts
GROUP BY ROLLUP(NameOfAct)
ORDER BY
CASE WHEN NameOfAct is null THEN 1 ELSE 0 END,
c DESC;
Result of example data:
NameOfAct count
-------------- -------
Act_B 3
Act_A 2
Act_Z 1
Total 6
Try it with example rows at: http://sqlfiddle.com/#!18/dbd6c/2
I looked at the Pic. So you might have duplicate acts with the same name. And you want to know the number of acts that have the same unique name.
You might want to group the results by name:
GROUP BY NameOfAct
And include the act names and their counts in the query results:
SELECT NameOfAct, COUNT(*) AS ActCount
(Since the act_id column is not included in the groups, you need to omit it in the SELECT. The DISTINCT is also not necessary anymore, since all groups are unique already.)
Finally, you can sort the data (probably descending to get the acts with the largest count on top):
ORDER BY ActCount DESC
Your complete query would become something like this:
SELECT NameOfAct, COUNT(*) AS ActCount
FROM Acts
GROUP BY NameOfAct
ORDER BY ActCount DESC
Edit:
By the way, you use field "act_id" in your SELECT clause. That's somewhat confusing. If you want to know counts, you want to look at either the complete table data or group the table data into smaller groups (with the GROUP BY clause). Then you can use aggregate functions to get more information about those groups (or the whole table), like counts, average values, minima, maxima...
Single record information, like an act's ID in your case, is typically not important if you want to use statistic/aggregate methods on grouped data. Suppose your query returns an act name which is used 10 times. Then you have 10 records in your table, each with a unique act_id, but with the same name.
If you need just one act_id that represents each group / act name (and assuming act_id is an autonumbering field), you might include the latest / largest act_id value in the query using the MAX aggregate function:
SELECT NameOfAct, COUNT(*) AS ActCount, MAX(act_id) AS LatestActId
(The rest of the query remains the same.)
Basically, I'm trying to retrieve only 1 record from a table based on catalog_no and packing_list_no. However, the table I'm retrieving the information from has additional details that I don't need but makes the 1 record I need into 3 distinct records.
I tried summing and grouping the info, but I'm still getting 3 records instead of 1.
Any ideas of how to solve this issue?
Your GROUP BY groups your result on the columns quantity picked, quantity shipped and weight shipped. A different value in any of those columns will result into a different row.
You can drop the GROUP BY clause all together, if the desirable result is the packing list and catalog no that you have specified. You can use the GROUP BY clause to columns that you do not use sum to group the result set.
SELECT catalog_no, sum(qty_picked), sum(qty_shipped), sum(weight_shipped), packing_list_no, bay_no, carrier_code, tracking_no FROM oeorder_shipping
WHERE packing_list_no='CP12618525' AND catalog_no='437656500'
GROUP BY bay_no, carrier_code, tracking_no;
I am trying to select all records in a time-variant Account table for each account with a change in an associated value (e.g. the maturity date). A change in the value will result in the most recent record for an account being end-dated and a new record (containing a new effective date of the following day) being created. The most recent records for accounts in this table have an end-date of 12/31/9000.
For instance, in the below illustration, account 44444444 would not be included in my query result set since it hasn't had a change in the value (and thus also has no additional records aside from the original); however, the other accounts have multiple changes in values (and multiple records), so I would want to see those returned.
I've tried using the row_num function, as well as a reflexive join, but for some reason I'm not getting the expected results. What are some ways to obtain the results I need?
Note: The primary key for this table includes the acct_id and eff_dt. Also, I'm using PostgreSQL in a Greenplum environment.
Here are two types of queries I tried to use but which produced problematic results:
Query 1
Query 2
If you want only the accounts, use aggregation:
select acct_id
from t
group by acct_id
having min(value) <> max(value);
Based on your description, you could also use count(*) >.
If you want the original records, you can use window functions:
select t.*
from (select t.*, count(*) over (partition by acct_id) as cnt
from t
) t
where cnt > 1;
I have a table with an amount column a reference field and an id column. What I need to do is sum the amount based on different combinations of ID's for each reference. There are nine different combinations in total that I then need to insert into a separate table.
The best way I've found to do this is to use a cursor and do each SUM separately, assign the amount to a variable and update the table for each reference and for each combination.
Hope that makes sense!
What I was hoping to find out is - is there a better way to do it?
thanks.
You could so something like:
SELECT SUM(CASE WHEN (Id = 9) THEN Val ELSE 0 END) ConditionalSum
From dbo.Table
You can have many of those SUMs with different conditions in one query.
You can create a table called something like combos with the following columns:
Name of combination
reference id in combination
(and perhaps other useful columns like an id and creation time, but that is not important here).
Insert your combinations into this table, something like:
First10 1
First10 2
...
First10 10
MyFavorite 42
Whatever the pairs are.
Then you can do what you want with a single query:
select c.comboName, sum(val) as ConditionalSum
from t join
combos c
on t.referenceId = c.referenceId
group by c.comboName
Say that I have some SELECT statement:
SELECT id, name FROM people
ORDER BY name ASC;
I have a few million rows in the people table and the ORDER BY clause can be much more complex than what I have shown here (possibly operating on a dozen columns).
I retrieve only a small subset of the rows (say rows 1..11) in order to display them in the UI. Now, I would like to solve following problems:
Find the number of a row with a given id.
Display the 5 items before and the 5 items after a row with a given id.
Problem 2 is easy to solve once I have solved problem 1, as I can then use something like this if I know that the item I was looking for has row number 1000 in the sorted result set (this is the Firebird SQL dialect):
SELECT id, name FROM people
ORDER BY name ASC
ROWS 995 TO 1005;
I also know that I can find the rank of a row by counting all of the rows which come before the one I am looking for, but this can lead to very long WHERE clauses with tons of OR and AND in the condition. And I have to do this repeatedly. With my test data, this takes hundreds of milliseconds, even when using properly indexed columns, which is way too slow.
Is there some means of achieving this by using some SQL:2003 features (such as row_number supported in Firebird 3.0)? I am by no way an SQL guru and I need some pointers here. Could I create a cached view where the result would include a rank/dense rank/row index?
Firebird appears to support window functions (called analytic functions in Oracle). So you can do the following:
To find the "row" number of a a row with a given id:
select id, row_number() over (partition by NULL order by name, id)
from t
where id = <id>
This assumes the id's are unique.
To solve the second problem:
select t.*
from (select id, row_number() over (partition by NULL order by name, id) as rownum
from t
) t join
(select id, row_number() over (partition by NULL order by name, id) as rownum
from t
where id = <id>
) tid
on t.rownum between tid.rownum - 5 and tid.rownum + 5
I might suggest something else, though, if you can modify the table structure. Most databases offer the ability to add an auto-increment column when a row is inserted. If your records are never deleted, this can server as your counter, simplifying your queries.