I am trying to convert an integer to a date or a date to an integer so I can compare two columns. I'm using teradata and have been struggling with Invalid Date [Error 2665] when trying to cast either to the other format. The formats are:
20220830 Type D
2022-08-05 Type DA
Methods I've tried:
SELECT cast((20220830 - 19000000) as date)
SELECT CAST(TRIM(20201231) AS DATE FORMAT 'YYYYMMDD')
select cast(2022-08-05 as Integer Format '99999999')
Select Convert(DATETIME, LEFT(20130101, 8))
SELECT CAST(CAST(20220830 AS CHAR(8)) AS DATE FORMAT 'YYYYMMDD')
select cast(test_date as date format'YYYYMMDD')
from
(SELECT cast (integer_date as char(8)) as test_date
from example)t1
Any insights into why these methods aren't working would be a great help
Select cast((column_name)-19000000 as date). Mistake was in trying to format such as Select cast((column_name)-19000000 as date format 'YYYY-MM-DD)
Related
I created a partition projection in Athena named 'dt', which is a STRING and contains date information in the format 2020/12/11/20.
I'm running the following query in Athena
SELECT
DATE_FORMAT(dt, '%Y-%m') as dt,
count(*) as "total_visualization",
count(*)/cast(date_format(DATE '{END_DATE}', '%d') as integer) as "average_dia"
FROM
user.dashborad
WHERE
event = 'complete'
AND dt BETWEEN DATE '{START_DATE}' and DATE '{END_DATE}'
GROUP BY 1;
The resulting raw query received by Athena is:
DATE_FORMAT(dt, '%Y-%m') as dt,
count(*) as "total_visualization",
count(*)/cast(date_format(DATE '2022-08-08', '%d') as integer) as "average_day"
FROM user.dashborad
WHERE event = 'complete' AND dt BETWEEN DATE '2022-08-01' and DATE '2022-08-08'
GROUP BY 1;
However, I get the following error:
Error querying the database: SYNTAX_ERROR: line 2:62: Cannot check if varchar is BETWEEN date and date.
I've tried to find a workaround in an attempt to convert it into a date format using date_parse but it didn't work. And with str_to_date I get this error:
SYNTAX_ERROR: line 2:2: Function str_to_date not registered
Is there any other way I can modify the query to convert 'dt' from a varchar into a format Athena understands?
It is always a bad idea to store a date in a string instead of using the appropriate data type. You even call the column dt which suggests a datetime. This makes it harder to spot inappropriate handling.
Here
AND dt BETWEEN DATE '{START_DATE}' and DATE '{END_DATE}'
you compare a string with dates. Thus you rely on the DBMS guessing the string's date format correctly. Don't do this. Convert the string explicitely to a date, because you know the format. Or, as 'YYYY-MM-DD' is comparable, work with the strings right away:
AND dt BETWEEN '{START_DATE}' and '{END_DATE}'
Here
DATE_FORMAT(dt, '%Y-%m')
you invoke a date function on a string. This means the DBMS must again guess your format, convert your string into a date accordingly and then invoke the function to convert the date into a string. Instead, just use the appropriate string function on the string:
SUBSTR(dt, 1, 7)
The complete query:
SELECT
SUBSTR(dt, 1, 7) AS year_month,
COUNT(*) AS total_visualization,
COUNT(*) / CAST(SUBSTR('{END_DATE}', 9, 2)) AS INTEGER) AS average_dia
FROM
user.dashborad
WHERE
event = 'complete'
AND dt BETWEEN '{START_DATE}' and '{END_DATE}'
GROUP BY SUBSTR(dt, 1, 7)
ORDER BY SUBSTR(dt, 1, 7);
I have Time column in BigQuery, the values of which look like this: 2020-09-01-07:53:19 it is a STRING format. I need to extract just the date. Desired output: 2020-09-01.
My query:
SELECT
CAST(a.Time AS date) as Date
from `table_a`
The error message is: Invalid datetime string "2020-09-02-02:17:49"
You could also use the parse_datetime(), then convert to a date.
with temp as (select '2020-09-02-02:17:49' as Time)
select
date(parse_datetime('%Y-%m-%d-%T',Time)) as new_date
from temp
How about just taking the left-most 10 characters?
select substr(a.time, 1, 10)
If you want this as a date, then:
select parse_date('%Y-%m-%d', substr(a.time, 1, 10))
select STR_TO_DATE('2020-09-08 00:58:09','%Y-%m-%d') from DUAL;
or to be more specific as your column do as:
select STR_TO_DATE(a.Time,'%Y-%m-%d') from `table_a`;
Note: this format is applicable where mysql is supported
I have 4 CTE's in this table and the third one contains a DATETIME converted to VARCHAR (with format based on the requirement) as startDate in DD/MM/YYYY format. The last cte does calculations based on the data generated and one of the columns needs to store YYYYMM date based on startDate.
The problem it's getting the year and the month from this converted DATETIME, using convert() it shows this:
IDPER
-------
01/01/ --DD/MM/
These 2 show YYYYMM correctly when startDate isn't converted:
Select *, left(convert(nvarchar(6),new_ini,112),6) as IDPER from table
Select *, convert(nvarchar(6),new_ini,112) as IDPER from table
How could I get YYYYMM format having startDate converted? Or what could be a more smart approach to the requirement
If you have a string in the format DD/MM/YYYY and you want YYYYMM, then use string operations:
select right(new_ini, 4) + substring(new_ini, 4, 2)
You should be storing date values as dates or a related type, not as string. But given that you have already stored this as a string, string operations can do what you need.
My way would be slightly different
SELECT CONVERT(NVARCHAR(6), CONVERT(DATE, new_ini, 103), 112);
Here, I first converted it to date and then formatted to YYYYMMDD and taken 6 chars only
declare #date DATE = GETDATE();
select REPLACE(LEFT(CONVERT(DATE,#date,112),8),'-','') -- 1st approach
select FORMAT(#date,'yyyyMM') --2nd approach
In SQL. How to convert a column A from (YYYY-MM-DD) to (YYYYMM)? I want to show the dates in YYYYMM format instead of YYYY-MM-DD.
Data type is TIMESTAMP. Using Teradata Studio 15.10.10.
For Teradata either use
to_char(tscol, 'YYYYMM') -- varchar result
or
extract(year from tscol) * 100 + extract(month from tscol) -- integer result
In Teradata you can format dates pretty much at will. To get YYYYMM, you would use
select <your date> (format 'yyyymm') (char(6))
Your date column needs to be actual date for this, not a string.
There are 3 functions you'll need.
MONTH() function. Returns the MONTH for the date within a range of 1 to 12 ( January to December). It Returns 0 when MONTH part for the date is 0.
YEAR() function. Returns a 4 digit YEAR.
CONCAT() function is used to concatenate two or more strings together.
So here's an example of combining the 3 functions.
SELECT CONCAT(YEAR('1969-02-18'),MONTH('1969-02-18'))
or you can do it in one with
select DATE_FORMAT('1969-02-18','%Y%m')
So to answer your question if it is referring to column A, you can use
SELECT DATE_FORMAT(A,'%Y%m')
SQL Fiddle:
http://www.sqlfiddle.com/#!9/a6c585/48362
You can use DATEPART to get the year and month parts of the date, cast to a varchar, pad and the concaternate.
SELECT DATEPART(YEAR,GETDATE())
SELECT DATEPART(MONTH,GETDATE())
SELECT CAST(DATEPART(YEAR,GETDATE()) AS VARCHAR(4)) + RIGHT('00' + CAST(DATEPART(MONTH,GETDATE()) AS VARCHAR(2)),2)
I'm trying to convert an integer field to an actual date field. Someone created a "date" field that just sticks in a "date" that is actually an integer. I'm trying to convert it to an actual date.
I have tried the following to no avail:
CAST(CAST(last_purch_date AS CHAR) AS DATE) as Create,
CAST( last_purch_date as datetime) as Created,
convert(datetime,last_purch_date) as Created1,
ISDATE(CONVERT(CHAR(8),last_purch_date)) as PleaseDearGodWORK
Simple cast as date could work
Select cast(cast(20161011 as varchar(8)) as date)
Returns
2016-10-11
If your data is suspect, you could also use Try_Convert()
Select Try_Convert(date,cast(2610 as varchar(8)))
Returns
NULL
SELECT convert(date,CONVERT(varchar(8),[columname],101))