Is it Possible to set "Windows On-Screen Keyboard" as an input in sg.InputText field ( PySimpleGUI)? - input

Question

Dears,
Is it Possible to set "Windows On-Screen Keyboard" as an input in sg.InputText field?
Thanks in advance
enter image description here ==> The Code
enter image description here ==> Desired Output
enter image description here ==> Split Keyboard to lines using "Menu Option"

Answer 1

Here's the demo code for you. Some functions for backspace key not built under PySimpleGUI, so tkinter code is required, like element.widget. The event for button 'OK' not included here. You can replace the keyboard string with yours.
import PySimpleGUI as sg
keys = ["QWERTYUIOP", "ASDFGHJKL", "ZXCVBNM"]
chars = ''.join(keys)
lines = list(map(list, keys))
lines[0] += ["\u232B", "Esc"]
col = [[sg.Push()] + [sg.Button(key) for key in line] + [sg.Push()] for line in lines]
layout = [
[sg.Text("Username"), sg.Push(), sg.Input(key="Username")],
[sg.Text("Password"), sg.Push(), sg.Input(key="Password")],
[sg.Push(), sg.Button("OK"), sg.Button("Cancel"),sg.Push(), sg.Button("Keyboard")],
[sg.pin(sg.Column(col, visible=False, expand_x=True, key='Column', metadata=False), expand_x=True)],
]
window = sg.Window('ACCESS', layout)
while True:
event, values = window.read()
if event in (sg.WIN_CLOSED, "Cancel"):
break
elif event == "Keyboard":
visible = window["Column"].metadata = not window["Column"].metadata
window["Column"].update(visible=visible)
elif event in chars:
element = window.find_element_with_focus()
if isinstance(element, sg.Input):
if element.widget.select_present():
element.widget.delete(sg.tk.SEL_FIRST, sg.tk.SEL_LAST)
element.widget.insert(sg.tk.INSERT, event)
elif event == "\u232B":
element = window.find_element_with_focus()
if element.widget.select_present():
element.widget.delete(sg.tk.SEL_FIRST, sg.tk.SEL_LAST)
else:
insert = element.widget.index(sg.tk.INSERT)
if insert > 0:
element.widget.delete(insert-1, insert)
window.close()
With MenuOption element, there's option enable_events, so tkinter call required here. There are three-line different keyboard, so each Column element for each keyboard line.
import PySimpleGUI as sg
def callback(var, index, mode):
window.write_event_value("Optionmenu", window['Optionmenu'].TKStringVar.get())
keys = ["QWERTYUIOP", "ASDFGHJKL", "ZXCVBNM"]
chars = ''.join(keys)
lines = list(map(list, keys))
lines[0] += ["\u232B", "Esc"]
layout = [
[sg.Text("Username"), sg.Push(), sg.Input(key="Username")],
[sg.Text("Password"), sg.Push(), sg.Input(key="Password")],
[sg.Push(), sg.Button("OK"), sg.Button("Cancel"),sg.Push(), sg.OptionMenu([f"Keyboard Line {i+1}" for i in range(3)], key='Optionmenu')],
[sg.Column([[sg.Push()] + [sg.Button(key) for key in line] + [sg.Push()]], key=f"Keyboard Line {i+1}", expand_x=True, visible=False) for i, line in enumerate(lines)],
]
window = sg.Window('ACCESS', layout, finalize=True)
window['Optionmenu'].TKStringVar.trace("w", callback) # enable events
keyboard = None
while True:
event, values = window.read()
if event in (sg.WIN_CLOSED, "Cancel"):
break
elif event == "Optionmenu":
if keyboard is not None:
window[keyboard].update(visible=False)
keyboard = values["Optionmenu"]
window[keyboard].update(visible=True)
elif event in chars:
element = window.find_element_with_focus()
if isinstance(element, sg.Input):
if element.widget.select_present():
element.widget.delete(sg.tk.SEL_FIRST, sg.tk.SEL_LAST)
element.widget.insert(sg.tk.INSERT, event)
elif event == "\u232B":
element = window.find_element_with_focus()
if element.widget.select_present():
element.widget.delete(sg.tk.SEL_FIRST, sg.tk.SEL_LAST)
else:
insert = element.widget.index(sg.tk.INSERT)
if insert > 0:
element.widget.delete(insert-1, insert)
window.close()