I would not be able to do what I want :(, I explain:
I have two tables:
Table1
Table2
I am looking for a query where I can get FALSE/(FALSE+TRUE).
So far I managed to do it over the total using this:
select
(select count(*) from (select Drink from Table1
where Drink=False)) as F,
(select count(*) from (select Drink from Table1
where Drink=True)) as T,
(F/(F+T)) as total
With that I can get the total of the column I want, I just have to change, if I want, Drink-->Food.
But now I would like the final result by Country, that is, something similar to this:
Expected result
In order not to break the forum rules, I'll leave what I've tried so far:
select * from (select distinct t2.Country_Name, count(t1.Drink)
from Table 1 t1
left join Table 2 t2 on t2.Country_ID=t1.Country_ID
where Drink=False
group by t2.Country_Name) as F
union
select * from (select distinct t2.Country_Name, count(t1.Drink)
from Table 1 t1
left join Table 2 t2 on t2.Country_ID=t1.Country_ID
where Drink=True
group by t2.Country_Name) as T
But it doesn't even bring me what I expect :(
I don't know if it helps much, but I'm using Snowflake
Any help is welcome. Thank you!
The first query could be simpliefied using COUNT_IF:
SELECT COUNT_IF(Drink=False)/COUNT(*)
FROM Table1;
Grouped by Country:
SELECT t2.Country_Name, COUNT_IF(t1.Drink=False)/COUNT(*)
FROM Table1 AS t1
JOIN Table2 AS t2
ON t2.Country_ID=t1.Country_ID
GROUP BY t2.Country_Name;
Related
I have multiple SELECT queries which is ran against different tables.
The output of all the queries have the same number of rows (every query when ran individually will have the same number of rows). Is there a way I can combine the output of all these queries into a single result? (Keep out from first query and add the output of next query as a column to the output of the next query). I dont want to save these tables into database as I am just doing some validation testing.
Example:
SELECT AAA,BBB,CCC FROM Table1
SELECT Table2.DDD, Table1.AAA
FROM Table2
INNER JOIN Table1
ON Table1.AAA = Table2.AAA
I tried writing combining the query as
SELECT Table1.AAA,Table1.BBB,Table1.CCC,T1.DDD
FROM Table1,
(SELECT Table2.DDD, Table1.AAA
FROM Table2
INNER JOIN Table1
ON Table1.AAA = Table2.AAA)T1
I tried doing the above combined query, but instead of getting 11 rows as output (both queries above had result of 11 rows), I am getting 35 rows as output.
Hope the question made sense!
You'll need to specify a criteria to match each row the first query with which row of the second query.
If, for example, the column AAA is unique in both queries and you want to match rows with the same values you could do:
select a.*, b.*
from (
SELECT AAA,BBB,CCC FROM Table1
) a
full join join (
SELECT Table2.DDD, Table1.AAA
FROM Table2
INNER JOIN Table1
ON Table1.AAA = Table2.AAA
) b on b.aaa = a.aaa
If there aren't any clear matching rules, you can produce an artificial row number on each result set and use it to match rows. For example:
select
a.aaa, a.bbb, a.ccc,
b.ddd, b.aaa
from (
SELECT AAA, BBB, CCC,
row_number() over(order by aaa) as rn
FROM Table1
) a
full join join (
SELECT Table2.DDD, Table1.AAA,
row_number() over(order by table1.aaa, table2.ddd) as rn
FROM Table2
INNER JOIN Table1
ON Table1.AAA = Table2.AAA
) b on b.rn = a.rn
If you have several results and want to have all of them as additional columns you can simply use ",":
create table temp1 as select '1' as c1 from DUAL;
create table temp2 as select '2' as c2 from DUAL;
create table temp3 as select '3' as c3 from DUAL;
select a.c1, b.c2, c.c3 from temp1 a, (select c2 from temp2) b, (select c3 from temp3) c;
An alternative could also be that you want to have all the results as additional rows then you would use UNION ALL between the individual results.
We have two tables table1 and table2
Table 1
Table 2
We need the resultant table as :
All this should be done in a single SQL query
Thanks in advance.
I think you can make it without the second query, I tested it and returned your expected values.
select table_2.id_pro,
product_name,
SUM(1) as Quantity,
priceprod,
SUM(1) * priceprod as 'quantity * priceprod'
from Table_2
inner join Table_1 t1 on table_2.id_pro = t1.id_pro
group by table_2.id_pro, product_name, priceprod
And my SqlFiddle test http://sqlfiddle.com/#!3/08c2ef/1
I believe this should be what you need, or fairly close anyway! You need to group up your results from your first table to get your quantity value and then join those results to your second table to be able to create your desired output.
SELECT t1.id_pro,
t2.product_name,
s.Quantity,
t2.priceperprod,
s.Quantity * t2.priceperprod
FROM table_2 t2
INNER JOIN (
SELECT COUNT(*) AS Quantity,
t.id_pro
FROM table_1 t
GROUP BY t.id_pro
) t1 ON t2.id_pro = t1.id_pro
i believe that this is correct, i just JOIN the two tables AND used group by then count how many records each group, i hope this will help you, thanks.
SELECT
A.id_pro,
A.product_name,
(count(*)) AS Quantity,
A.priceperprod,
(COUNT(*) * A.priceperprod) AS Total
FROM table_2 A
LEFT JOIN table_1 B
ON B.id_pro = A.id_pro
GROUP BY A.id_pro
Guess this should be helpful to you.
SELECT A.PRODUCT_CODE, A.PRODUCT_NAME, B.QUANTITY,
A.PRICE PRICE_PER_PRODUCT,
(B.QUANTITY * A.PRICE) TOTAL_PRICE FROM
TABLE2 A,
(SELECT X.PRODUCT, COUNT(X.PRODUCT) QUANTITY FROM TABLE1 AS X
GROUP BY X.PRODUCT) as B
WHERE A.PRODUCT_CODE = B.PRODUCT
ORDER BY A.PRODUCT_CODE
Am doing following :
Taking the entire TABLE2 aliased as A
Getting the products and its corresponding count using group by and aliasing it as B
Selecting corresponding fields from table_Aliases A and B provided A's ProductCode and B's Products are same.
I want a query which will give me desired output ,I am using following query
select table1.name1,table2.address
from table1 join table2
on(table1.key=table2.key);
it is giving me result After join nut I only need single row for each key.
Any help will be appreciated.
If any combination is allowed but only one row for each key then try this:
select table1.name1, MAX(table2.address) address
from table1
join table2
on table1.key=table2.key
group by table1.name1
try like this
select *
from (select table2.address,
rank() over ( partition by table1.name1 order by table1.key) rn
from table1 join table2 on(table1.key=table2.key))
where rn = 1
I have two database for which I want to compare the amount of times a case appears.
TAB1:
ID Sequence
A2D 1
A2D 2
A2D 3
A3D 1
TAB2:
ID Sequence
A2D 1
A2D 2
A3D 1
A3D 2
Now, for this example, I am trying to get this result:
ID Table1 Table2
A2D 3 2
A3D 1 2
I have tried these code without any success:
SELECT R1.ID as ID, COUNT(R1.ID) as Table1,
COUNT(R2.ID) as Table2
FROM TAB1 AS R1, TAB2 AS R2
WHERE R1.ID = R2.ID
GROUP BY R1.ID
This one gave me wrong count values...
Also, this one simply crash:
select
(
select count(*) as Table1
from TAB1
where ID = R1.ID
),(
select count(*) as Table2
from TAB2
where ID= R1.ID
)
FROM TAB1 AS R1
As you can see though, I am trying to have my criteria dynamic. Most examples I found were including basic hard-coded criteria. But for my case, I want the query to look at my first table ID, count the amount of time it appears, do it for the 2nd table with the same ID, then move on to the next ID.
If my question lacks information or is confusing just ask me, I'll do my best to be more precise.
Thanks in advance !
Here I am using a UNION ALL as a subquery
SELECT ID, SUM(T1) AS Table1, SUM(T2) AS Table2
FROM
(SELECT ID, COUNT(ID) AS T1, 0 AS T2 FROM TAB1 GROUP BY ID
UNION ALL
SELECT ID, 0 AS T1, COUNT(ID) AS T2 FROM TAB2 GROUP BY ID)
GROUP BY ID
HAVING SUM(T1)>0 AND SUM(T2)>0
I used a different approach, but unfortunately I have to use two queries, i still don't know if they can be combined together. The first one is just for making sums of both tables, and combining the results:
SELECT "Tab1" AS [Table], Tab1.ID, Count(*) AS Total
FROM Tab1
GROUP BY "Tab1", Tab1.ID
UNION SELECT "Tab2" AS [Table], Tab2.ID, Count(*) AS Total
FROM Tab2
GROUP BY "Tab2", Tab2.ID
and, since Access supports Pivot queries, you can use this:
TRANSFORM Sum(qrySums.[Total]) AS Total
SELECT qrySums.[ID]
FROM qrySums
GROUP BY qrySums.[ID]
PIVOT qrySums.[Table];
Not sure if I understand your question, but you could try something like this:
SELECT DISTINCT t.ID,
(SELECT COUNT(ID) FROM R1 WHERE ID = t.ID) AS table1,
(SELECT COUNT(ID) FROM R2 WHERE ID = t.ID) AS table2
FROM table1 t
To get the desired results, I broke it down into two sub-queries (R1SQ and R2SQ) and a main UNION query - R1R2 that uses inner, left and right joins to include all row entries including those rows that do not appear in both tables:
R1SQ
SELECT R1.Builder, Count(R1.Builder) AS Table1
FROM R1
GROUP BY R1.Builder;
R2SQ
SELECT R2.Builder_E, Count(R2.Builder_E) AS Table2
FROM R2
GROUP BY R2.Builder_E;
R1R2
SELECT R1SQ.Builder, R1SQ.Table1, R2SQ.Table2
FROM R1SQ INNER JOIN R2SQ ON R1SQ.Builder = R2SQ.Builder_E
UNION
SELECT R1SQ.Builder, R1SQ.Table1, 0 AS Table2
FROM R1SQ LEFT JOIN R2SQ ON R1SQ.Builder = R2SQ.Builder_E
WHERE (((R2SQ.Builder_E) Is Null))
UNION
SELECT R2SQ.Builder_E, 0 AS Table1, R2SQ.Table2
FROM R1SQ RIGHT JOIN R2SQ ON R1SQ.Builder = R2SQ.Builder_E
WHERE (((R1SQ.Builder) Is Null))
ORDER BY R1SQ.Builder;
If I run the two statements in batch will they return one table to two to my sqlcommand object with the data merged. What I am trying to do is optimize a search by searching twice, the first time on one set of data and then a second on another. They have the same fields and I’d like to have all the records from both tables show and be added to each other. I need this so that I can sort the data between both sets of data but short of writing a stored procedure I can’t think of a way of doing this.
Eg. Table 1 has columns A and B, Table 2 has these same columns but different data source. I then wan to merge them so that if a only exists in one column it is added to the result set and if both exist it eh tables the column B will be summed between the two.
Please note that this is not the same as a full outer join operation as that does not merge the data.
[EDIT]
Here's what the code looks like:
Select * From
(Select ID,COUNT(*) AS Count From [Table1]) as T1
full outer join
(Select ID,COUNT(*) AS Count From [Table2]) as T2
on t1.ID = T2.ID
Perhaps you're looking for UNION?
IE:
SELECT A, B FROM Table1
UNION
SELECT A, B FROM Table2
Possibly:
select table1.a, table1.b
from table1
where table1.a not in (select a from table2)
union all
select table1.a, table1.b+table2.b as b
from table1
inner join table2 on table1.a = table2.a
edit: perhaps you would benefit from unioning the tables before counting. e.g.
select id, count() as count from
(select id from table1
union all
select id from table2)
I'm not sure if I understand completely but you seem to be asking about a UNION
SELECT A,B
FROM tableX
UNION ALL
SELECT A,B
FROM tableY
To do it, you would go:
SELECT * INTO TABLE3 FROM TABLE1
UNION
SELECT * FROM TABLE2
Provided both tables have the same columns
I think what you are looking for is this, but I am not sure I am understanding your language correctly.
select id, sum(count) as count
from (
select id, count() as count
from table1
union all
select id, count() as count
from table2
) a
group by id