Query to get First Value and Second value with Filter - sql

Question

I have the following need but I am not able to get an effective query:
ID
DATE
PARCEL
STATUS
TYPE
DT_PAY
DT
1
2021-10-15
28
3
R
2021-10-15
2021-10-15
2
2021-11-15
29
0
R
1900-01-01
2021-11-15
3
2021-12-15
30
3
R
2021-12-15
2021-12-15
4
2022-01-15
31
3
R
2022-01-15
2022-01-15
5
2022-02-15
32
3
R
2022-02-15
2022-02-15
6
2022-03-15
33
0
R
1900-01-01
2022-03-15
7
2022-04-15
34
0
R
1900-01-01
2022-04-15
8
2022-05-15
35
0
R
1900-01-01
2022-05-15
9
2022-06-15
36
0
R
1900-01-01
2022-06-15
10
2022-07-15
37
3
R
2022-07-15
2022-07-15
With the data in the table above you would need the following result:
ID
DATE
PARCEL
STATUS
TYPE
DT_PAY
DT
6
2022-03-15
33
0
R
1900-01-01
2022-03-15
2
2021-11-15
29
0
R
1900-01-01
2021-11-15
It is necessary to list the first occurrence of a line where STATUS = 0 appears after a line with STATUS = 3 appears, and the second time this occurs after another line appears with STATUS = 3 as well, but being from the most current to the oldest date, in this case the date 2022-03-15 is more current and the date 2021-11-15 is more old one that meets the STATUS = 0 filter appears after a line with STATUS = 3 appears
My query only works to find STATUS=3, but needed it to be the same for STATUS=0
with TopDates as
(select row_number() over (order by DT desc) as Row, *
from DBO.TABLE
WHERE DT < GETDATE ()
AND DT_PAY <> '1900-01-01'
AND STATUS = '3'
)
select
TB.ID
,TB.DATE
,TB.PARCEL
,TB.STATUS
,TB.DT_PAY
,TB.DT
from TopDates TB
where Row<=2

Answer 1

Just add an OR clause in there?
Or am I not understanding you correctly?
`with TopDates as
(select row_number() over (order by DT desc) as Row, *
from DBO.TABLE
WHERE DT < GETDATE ()
AND DT_PAY <> '1900-01-01'
AND STATUS = '3'
OR STATUS = '0'
)
select
TB.ID
,TB.DATE
,TB.PARCEL
,TB.STATUS
,TB.DT_PAY
,TB.DT
from TopDates TB
where Row<=2