I am trying to figure out how this works. My initial date is: "2022-11-06T08:39:16.307Z"
So now I did this:
val sdf = SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss.SSS'Z'")
sdf.timeZone = TimeZone.getTimeZone("UTC")
val time: Long = sdf.parse("2022-11-06T08:39:16.307Z").time
val calendar = Calendar.getInstance()
val currentTime = calendar.timeInMillis
val diff = (currentTime - time) / 1000
Difference is negative number but it should be positive as other date is in past. Yes I hate working with dates in general but can not figure out why it works like this.
I have a Date Range Picker(Material Design) and I want to disable previous dates(so minimum date will be current day), and maximum date will be 6 months later. I tried something like this:
val calendar = Calendar.getInstance()
val constraintsBuilderRange = CalendarConstraints.Builder()
val dateValidatorMin: CalendarConstraints.DateValidator = DateValidatorPointForward.from(calendar.timeInMillis)
val dateValidatorMax: CalendarConstraints.DateValidator = DateValidatorPointBackward.before(calendar.timeInMillis+100000000)
val listValidators = ArrayList<CalendarConstraints.DateValidator>()
listValidators.add(dateValidatorMin)
listValidators.add(dateValidatorMax)
val validators = CompositeDateValidator.allOf(listValidators)
constraintsBuilderRange.setValidator(validators)
val datePicker = MaterialDatePicker.Builder.dateRangePicker()
.setTitleText("Select range")
.setCalendarConstraints(constraintsBuilderRange.build())
.build()
datePicker.show(
this.requireFragmentManager(),"date_range_picker"
)
This worked but I randomly give 100000000 to dateValidatorMax. So how can I achieve 6 months later in milliseconds? And how can I get 1 day before currentDate in dateValidatorMin?
So I solved this problem thanks to Kotlin, there is a really easy method:
val dateValidatorMin: CalendarConstraints.DateValidator = DateValidatorPointForward.from(calendar.timeInMillis - 1.days.toLong(
DurationUnit.MILLISECONDS))
val dateValidatorMax: CalendarConstraints.DateValidator = DateValidatorPointBackward.before(calendar.timeInMillis+ 180.days.toLong(
DurationUnit.MILLISECONDS))
I had a similar problem where I needed only dates in the range from the previous day to 45 days behind the current date to be enabled. That is, today, January 18th, the calendar would only be enabled from 12-05-2022 to 01-17-2023.
I did it like this:
val dateValidatorMin: DateValidator =
DateValidatorPointForward.from(
Calendar.getInstance().timeInMillis - 45.days.toLong(DurationUnit.MILLISECONDS))
val dateValidatorMax: DateValidator =
DateValidatorPointBackward.before(
Calendar.getInstance().timeInMillis - 1.days.toLong(DurationUnit.MILLISECONDS))
val dateValidator: DateValidator = CompositeDateValidator.allOf(listOf(dateValidatorMin, dateValidatorMax))
val constraints: CalendarConstraints =
CalendarConstraints.Builder()
.setValidator(dateValidator)
.build()
val builder = MaterialDatePicker.Builder.dateRangePicker()
.setCalendarConstraints(constraints)
.setTitleText(getString(R.string.label_select_date_range))
val picker = builder.build()
And the result was like this:
Hope this helps.
I have a data class as below in Kotlin.
data class ProductData(
val code: String,
var value: Double)
There are two list for the above data class as
lstToday: List<ProductData> contains such as
("P1", 110)
("P2", 109)
("P3", 102)
("P4", 110)
..... 100+ records
and
lstYesterday: List<ProductData> contains such as
("P1", 112)
("P2", 109)
("P3", 110)
("P4", 90)
..... 100+ records
Both has the identical and exact number of records.
The output I am looking for is as below.
Output 1: Difference between yesterday and today
lstDifference: List<ProductData> contains such as
("P1", -2)
("P2", 0)
("P3", 8)
("P4", -20)
..... 100+ records
Output 2: Today Price and Difference between yesterday and today
using the data class below.
data class ProductDisplayData(
val code: String,
var value: Double,
var diff: Double
)
With list as below
lstDifference: List<ProductData> contains such as
("P1", 112, -2)
("P2", 109, 0)
("P3", 110, 8)
("P4", 90, -20)
..... 100+ records
Can this be achieved using any functions Kotlin, or is it we have loop each element and get the result.
Thanks
I would say this is not the most efficient solution. We're talking 0n ish. This could definitely be optimized. To note, this is fault tolerant of the code itself not being included in both days, and assumes 0 for a non-existent value between days.
Trying to guarantee that both data sets will always be the same, is going to be more maintenance than writing code that will tolerate that mistake.
data class ProductData(
val code: String,
var value: Double
)
val dayOne = listOf(
ProductData("P1", 110.0),
ProductData("P2", 109.0),
ProductData("P3", 102.0),
ProductData("P4", 110.0),
ProductData("P5", 105.0),
ProductData("P6", 104.0),
ProductData("P8", 32.0) // Not in set 2
)
val dayTwo = listOf(
ProductData("P1", 110.0),
ProductData("P2", 109.0),
ProductData("P3", 102.0),
ProductData("P4", 90.0),
ProductData("P5", 49.0),
ProductData("P6", 123.0),
ProductData("P7", 239.0) // Not in set 1
)
fun periodDataDifference(dayOne: List<ProductData>, dayTwo: List<ProductData>): List<ProductData> {
val mapOne = dayOne.associate { it.code to it.value }
val mapTwo = dayTwo.associate { it.code to it.value }
val keys = mapOne.keys + mapTwo.keys
return keys.map { key ->
val first = mapOne[key] ?: 0.0
val second = mapTwo[key] ?: 0.0
ProductData(key, second - first)
}
}
val out = periodDataDifference(dayOne, dayTwo)
println(out)
/*
[ProductData(code=P1, value=0.0),
ProductData(code=P2, value=0.0),
ProductData(code=P3, value=0.0),
ProductData(code=P4, value=-20.0),
ProductData(code=P5, value=-56.0),
ProductData(code=P6, value=19.0),
ProductData(code=P8, value=-32.0), // Set 1 only
ProductData(code=P7, value=239.0)] // Set 2 only
*/
If today and yesterday lists are gonna be same size this is the quickest solution I have
val lstYesterday: List<ProductData> = listOf(
ProductData("P1", 112.0),
ProductData("P2", 109.0),
ProductData("P3", 110.0)
)
val lstToday: List<ProductData> = listOf(
ProductData("P1", 110.0),
ProductData("P2", 109.0),
ProductData("P3", 102.0)
)
val lstDifference: MutableList<ProductData> = mutableListOf()
for ((index,j) in lstToday.withIndex()){
val code = lstToday[index].code
val value = lstToday[index].value-lstYesterday[index].value
lstDifference.add(ProductData(code,value))
}
I'm trying to compare the date of videos on a webpage to today's date. If the difference between the two dates is more than X days, report back as false.
The videos on the webpage have a tag in them which uses the format yyyy-mm-dd
I've got a selector set up to find the videos const videoDate = Selector('OPTA-video').withAttribute('data-secondary-time')
Now how do I set a variable to today's date and compare the two? I'm completely stuck!
I was using Katalon Studio before and here's the groovy script that did the same job:
String videoDate = WebUI.getAttribute(findTestObject('OPTA-video'), 'data-secondary_time')
LocalDate todaysDate = LocalDate.now()
LocalDate videoDateParsed = LocalDate.parse(videoDate, dtf)
if (ChronoUnit.DAYS.between(videoDateParsed, todaysDate) > 1) {
KeywordUtil.markFailed('The videos are 2+ days old.')
} else {
KeywordUtil.logInfo('The videos are up to date.')
}
You can use the getAttribute TestCafe method to access an attribute value. Then, parse the attribute value into the JavaScript Date object:
String videoDate = Selector('OPTA-video').getAttribute('data-secondary-time');
Date videoDateParsed = Date.parse(videoDate);
Date todaysDate = Date.now()
...
In the following thread you can find how to compare Date objects.
This is one of the scripts that I am using.
//getting your XPath test value into a string
String ann_time =
WebUI.getText(findTestObject("ObjectRepository/navigateTOElement/announcements_date"))
//converting time to simple date format
SimpleDateFormat sdf = new SimpleDateFormat('HH:mm')
Date sdf_anntime = sdf.parse(new String(ann_time))
//getting Current time
SimpleDateFormat dateFormatGmt = new SimpleDateFormat('HH:mm')
dateFormatGmt.setTimeZone(TimeZone.getTimeZone('GMT'))
SimpleDateFormat dateFormatLocal = new SimpleDateFormat('HH:mm')
currDate = dateFormatLocal.parse(dateFormatGmt.format(new Date()))
// time gap in long format
long duration = currDate.getTime() - sdf_anntime.getTime()
//time gap to mins
long diffInMinutes = TimeUnit.MILLISECONDS.toMinutes(duration)
//compare time gap with globale variable
if (diffInMinutes < GlobalVariable.News_updated_time) {
log.logInfo("system is getting updated,last updated "+ diffInMinutes + "min ago")
} else {
CustomKeywords.'errorMessage.logFailed.markStepFailed'('from 1 h, system was not updated')
log.logInfo('from '+ diffInMinutes+ 'h, system was not updated')
}
I have a payment check application, in that I get 2 strings:
String contractBegin = "01-01-2018";
String contractEnd = "31-12-2018";
Now every payment must be done the last Friday of the month. I need to calculate those dates and place it in a list or array.
Is there any optimal way to do that using the Java 8 nice features?
I started here:
String contractBegin = "01-01-2018";
String contractEnd = "31-12-2018";
LocalDate contractStart = LocalDate.parse(contractBegin, DateTimeFormatter.ofPattern("dd-MM-yyyy"));
LocalDate contractStop = LocalDate.parse(contractEnd, DateTimeFormatter.ofPattern("dd-MM-yyyy"));
System.out.println(contractStart);
System.out.println(contractStop);
List<LocalDate> payCheck= new ArrayList<>();
for (int i = 0; i < args.length; i++) {
payCheck.add(...) ??
}
I am not sure about your args array. But If you want to get every last friday of month between the contract start and end date. I would do as follow :
String contractBegin = "01-01-2018";
String contractEnd = "31-12-2018";
LocalDate contractStart = LocalDate.parse(contractBegin, DateTimeFormatter.ofPattern("dd-MM-yyyy"));
LocalDate contractStop = LocalDate.parse(contractEnd, DateTimeFormatter.ofPattern("dd-MM-yyyy"));
List<LocalDate> payCheck = new ArrayList<>();
LocalDate payCheckDate = contractStart;
while (payCheckDate.isBefore(contractStop)) {
payCheckDate = payCheckDate
.with(lastDayOfMonth())
.with(previousOrSame(DayOfWeek.FRIDAY));
payCheck.add(payCheckDate);
payCheckDate = payCheckDate.with(TemporalAdjusters.firstDayOfNextMonth());
}
payCheck.forEach(System.out::println);
This gives you every last friday of each month.
Another alternative to #gnostrenoff's answer is to use TemporalAdjusters.lastInMonth() method, which gives you the specified last day of week in the month:
// get the last Friday of the month
payCheckDate = payCheckDate.with(TemporalAdjusters.lastInMonth(DayOfWeek.FRIDAY));
The rest of the while loop is the same as #gnostrenoff's answer.