Find last translate - xslt-1.0

I have the following xml:
<item>value 1,value 2,value3,</item>
I would now like to achieve the following via an output via xslt:
<item>value 1,value 2,value3</item>
So remove the last comma. Can you help me?

Use this template:
<xsl:template match="item">
<xsl:copy>
<xsl:choose>
<xsl:when test="substring(.,string-length(.))=','">
<xsl:value-of select="substring(.,1,string-length(.)-1)"/>
</xsl:when>
<xsl:otherwise>
<xsl:apply-templates select="node()"/>
</xsl:otherwise>
</xsl:choose>
</xsl:copy>
</xsl:template>
It will only remove the last char when it is a comma.

Related

xslt 1.0 Replace several characters [duplicate]

How do you replace an xml value, for example:
<name>Linda O'Connel</name>
to:
<name>Linda O''Connel</name>
via XSLT?
I need this because I have to pass this value in a powershell command line and to other platforms since the "double single quote" is needed to escape the apostrophe/single quotes.
Assuming an XSLT 1.0 processor, you will need to use a recursive named template for this, e.g:
<xsl:template name="replace">
<xsl:param name="text"/>
<xsl:param name="searchString">'</xsl:param>
<xsl:param name="replaceString">''</xsl:param>
<xsl:choose>
<xsl:when test="contains($text,$searchString)">
<xsl:value-of select="substring-before($text,$searchString)"/>
<xsl:value-of select="$replaceString"/>
<!-- recursive call -->
<xsl:call-template name="replace">
<xsl:with-param name="text" select="substring-after($text,$searchString)"/>
<xsl:with-param name="searchString" select="$searchString"/>
<xsl:with-param name="replaceString" select="$replaceString"/>
</xsl:call-template>
</xsl:when>
<xsl:otherwise>
<xsl:value-of select="$text"/>
</xsl:otherwise>
</xsl:choose>
</xsl:template>
Example of call:
<xsl:template match="name">
<xsl:copy>
<xsl:call-template name="replace">
<xsl:with-param name="text" select="."/>
</xsl:call-template>
</xsl:copy>
</xsl:template>
You can also try out the following.
<xsl:variable name="temp">'</xsl:variable>
<name>
<xsl:value-of select="concat(substring-before(name,$temp),$temp,$temp,substring-after(name,$temp))"/>
</name>

How do I use a variable in select in xsl

now
<xsl:for-each select="tm-reg-gaz/trademark/img">
want to change like this.
<xsl:variable name="tag_name">
<xsl:if test="tm-reg-gaz">tm-reg-gaz</xsl:if>
<xsl:if test="mp-tm-reg-gaz">mp-tm-reg-gaz</xsl:if>
</xsl:variable>
<xsl:for-each select="$tag_name/trademark/img">
</xsl:for-each>
I tried these
<xsl:for-each select="$tag_name/trademark/img">
<xsl:for-each select="path[$tag_name]/trademark/img">
<xsl:for-each select="{$tag_name}/trademark/img">
Let me know if it can. Thank you.
You can use select="*[name()=$tagname]/trademark/img".
A better approach is probably
<xsl:variable name="selection" select="tm-reg-gaz|mp-tm-reg-gaz">
<xsl:for-each select="$selection/trademark/img">
</xsl:for-each>
(But the details depend on whether both elements can appear or whether they are mutually exclusive).
Here is my proposal, feel free to shoot it down:
<xsl:variable name="variable" as="node()*">
<xsl:choose>
<xsl:when test="$testme = 'something'">
<xsl:copy-of select="//tm-reg-gaz/trademark/img"/>
</xsl:when>
<xsl:otherwise>
<xsl:copy-of select="//mp-tm-reg-gaz/trademark/img"/>
</xsl:otherwise>
</xsl:choose>
</xsl:variable>
<xsl:for-each select="$variable">
<!-- do something -->
</xsl:for-each>

Unwrap elements with XSLT

I have large and complex documents which contain the following at various places in the document the following fragments
<a>foo<b>bar</b><a>
<a>foo<b>bar</b><b>hello</b><a>
which I want to transform to
<b>foobar<b>
<b>foobar<b><b>hello</b>
Use the following two template matchers:
<xsl:template match="a">
<xsl:apply-templates select="b"/>
</xsl:template>
<xsl:template match="b">
<xsl:copy>
<xsl:if test="position() = 1">
<xsl:value-of select="parent::a/text()"/>
</xsl:if>
<xsl:value-of select="."/>
</xsl:copy>
</xsl:template>

XSLT1 error when get first occurence of a tag

This question (and my problem) is similar to XSLT1 Get the first occurence of a specific tag... But I have an "Undefined variable" error.
I have a XML with refpos attribute, that can be make by this first XSLT,
<xsl:template match="p[#class='ref']">
<xsl:copy>
<xsl:attribute name="refpos">
<xsl:value-of select="position()"/>
</xsl:attribute>
<xsl:apply-templates />
</xsl:copy>
</xsl:template>
<xsl:template match="#*|node()" name="idt">
<xsl:copy><xsl:apply-templates select="#*|node()"/></xsl:copy>
</xsl:template>
Then, I a main (second) XSLT I have,
<xsl:variable name="firstRef">
<xsl:value-of select="(//p[#class='ref'])[1]/#refpos"/>
</xsl:variable>
<xsl:template match="p[#refpos=$firstRef]">
<title><xsl:apply-templates /></title>
</xsl:template>
<xsl:template match="#*|node()" name="idt">
<xsl:copy><xsl:apply-templates select="#*|node()"/></xsl:copy>
</xsl:template>
But here this XSLT not works!!
PS: I also believe that XSLT1 allow us to do everything in one step.
XSLT 1.0 does not allow variable references in template match expressions (XSLT 2.0 does). You'll have to move the check from the predicate inside the template:
<xsl:template match="p">
<xsl:choose>
<xsl:when test="#refpos=$firstRef">
<title><xsl:apply-templates /></title>
</xsl:when>
<xsl:otherwise>
<xsl:call-template name="idt" />
</xsl:otherwise>
</xsl:choose>
</xsl:template>

Sanitizing DB inputs with XSLT

I've been looking for a method to strip my XML content of apostrophes (') since my DBMS is complaining of receiving those.
I need
<name> Jim O'Connor</name>
to become:
<name> Jim O''Connor</name>
By looking at the example described here, that is supposed to replace ' with '', I constructed the following script:
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output omit-xml-declaration="yes" indent="yes" />
<xsl:template match="node()|#*">
<xsl:copy>
<xsl:apply-templates select="node()|#*" />
</xsl:copy>
</xsl:template>
<xsl:template name="sqlApostrophe">
<xsl:param name="string" />
<xsl:variable name="apostrophe">'</xsl:variable>
<xsl:choose>
<xsl:when test="contains($string,$apostrophe)">
<xsl:value-of select="concat(substring-before($string,$apostrophe), $apostrophe,$apostrophe)"
disable-output-escaping="yes" />
<xsl:call-template name="sqlApostrophe">
<xsl:with-param name="string"
select="substring-after($string,$apostrophe)" />
</xsl:call-template>
</xsl:when>
<xsl:otherwise>
<xsl:value-of select="$string"
disable-output-escaping="yes" />
</xsl:otherwise>
</xsl:choose>
</xsl:template>
<xsl:template match="text()">
<xsl:call-template name="sqlApostrophe">
<xsl:with-param name="string" select="."/>
</xsl:call-template>
</xsl:template>
</xsl:stylesheet>
UPDATE: it works fine
Thanks for your help
The main problem is in your last template. As dacracot points out, xsl:apply-templates does not take a name attribute. To call a named template, you'd use xsl:call-template.
If you want to apply your SQL escaping to all text nodes, you could try replacing your last template with something like this:
<xsl:template match="text()">
<xsl:call-template name="sqlApostrophe">
<xsl:with-param name="string" select="."/>
</xsl:call-template>
</xsl:template>
Also, why disable-output-escaping? If the text contains special characters (<, >, &), you'll get malformed XML as the output.
You have a couple of issues syntactically...
You can't have a name attribute on an apply-templates tag.
Your xpath, "node()|#*", is ambiguous.
Have you run this through a debugger? I would suggest Oxygen.