I have a question
I want to join two tables (Table1 and Table2) on custID column.
However for the join to work I need to edit Table1s custID column vlaues by removing the first two characters ('CC') and replacing them with 0s so the final output is padded to 8 digits.
So if Table1 had a value in custID of CC34054 then this would need to be converted to 00034054 for the join to identify that value in Table2.custID. If for instance the custID value in Table1 was CC3356, the value would need to be revised to 00003356 for the join to match.
Ive made some tables below so I can illustrate what I mean.
Table1
CustID
CC34054
CC3356
CC87901
Table2
CustID
00034054
00003356
00087901
I hope this makes sense. thanks!
One option is to replace CC with an empty string and apply LPAD function to fill up to 8 characters with zeros; do it either in JOIN or - possibly - by updating table1 (so join would then look simpler, just on a.custid = b.custid).
Sample data:
SQL> with
2 table1 (custid, name) as
3 (select 'CC34054', 'Little' from dual union all
4 select 'CC3356' , 'Scott' from dual
5 ),
6 table2 (custid, surname) as
7 (select '00034054', 'Foot' from dual union all
8 select '00003356', 'Tiger' from dual
9 )
Query:
10 select b.custid, a.name, b.surname
11 from table1 a join table2 b on
12 lpad(replace(a.custid, 'CC', ''), 8, '0') = b.custid;
CUSTID NAME SURNAME
-------- ------ ----------
00034054 Little Foot
00003356 Scott Tiger
SQL>
Another way to do it is to use SubStr() function to remove the first two characters (either they are 'CC' or anything else) and then do the Lpad to the length of 8 with '0' characters:
Select b.CUSTID
From tbl_1 a
Inner Join tbl_2 b on (Lpad(SubStr(a.CUSTID, 3), 8, '0') = b.CUSTID)
Regards...
I think no need to replace or pad leading characters, rather trim for both CustID columns if the data model is fixed throughout the whole table such as
SELECT *
FROM Table1 t1
JOIN Table2 t2
ON LTRIM(t1.CustID,'C') = LTRIM(t2.CustID,'0')
in which using only single characters as the second arguments would be sufficient.
Demo
Related
I am learning PL/SQL and struck at a problem statement where the result required is a specific string from select statement which is stored as row value in a table.
Example
select distinct ID from emp, order where emp.ID = order.ID and (emp.type = 1 or emp.type = 100010 )
The above mentioned select statement is stored as a row entity in Table3 .
Problem Statement :
The Requirement is to extract both 1 and 100010 and store them in a character variable to get the English Description of 1 and 100010 from Table4
Can anyone help me in writing the RegX or suggest me some different approach for the problem statement.
Note : Their are multiple table2.column3 in a single SQL statement and the max length for ID is 6 and the minimum is 1
Edits : Updated the Example Statement
That's pretty much a dummy example. If table and column names aren't really table1 or column2 but something more meaningful (and don't contain any numbers), then that's rather simple:
SQL> with test (col) as
2 (select 'select distinct ID from emp, order where emp.ID = order.ID and (emp.type = 1 or order.code = 100010 )' from dual)
3 select regexp_substr(col, '\d+', 1, 1) first_number,
4 regexp_substr(col, '\d+', 1, 2) second_number
5 from test;
FIRST_NUMBER SECOND_NUMBER
--------------- ---------------
1 100010
SQL>
If, on the other hand, table or column names really have numbers, then it isn't that simple.
I have a table in a database and one of the columns of the table is of the format AAA-BBBBBBB-CCCCCCC(in the table below column Id) where A, B and C are all numbers (0-9). I want to write a SELECT query such that for this column I only want the values in the format BBBBBBB-CCCCCCC. I am new to SQL so not sure how to do this. I tried using SPLIT_PART on - but not sure how to join the second and third parts.
Table -
Id
Name
Age
123-4567890-1234567
First Name
199
456-7890123-4567890
Hulkamania
200
So when the query is written the output should be like
Output
4567890-1234567
7890123-4567890
As mentioned in the request comments, you should not store a combined number, when you are interested in its parts. Store the parts in separate columns instead.
However, as the format is fixed 'AAA-BBBBBBB-CCCCCCC', it is very easy to get the substring you are interested in. Just take the string from the fifth position on:
select substr(col, 5) from mytable;
You can select the right part of a column starting at the 4th character
SELECT RIGHT(Id, LEN(Id)-4) AS TrimmedId;
Another option using regexp_substr
with x ( c1,c2,c3 ) as
(
select '123-4567890-1234567', 'First Name' , 199 from dual union all
select '456-7890123-4567890', 'Hulkamania' , 200 from dual
)
select regexp_substr(c1,'[^-]+',1,2)||'-'||regexp_substr(c1,'[^-]+',1,3) as result from x ;
Demo
SQL> with x ( c1,c2,c3 ) as
(
select '123-4567890-1234567', 'First Name' , 199 from dual union all
select '456-7890123-4567890', 'Hulkamania' , 200 from dual
)
select regexp_substr(c1,'[^-]+',1,2)||'-'||regexp_substr(c1,'[^-]+',1,3) as result from x ; 2 3 4 5 6
RESULT
--------------------------------------------------------------------------------
4567890-1234567
7890123-4567890
SQL>
I am new to sql and are trying to combine a column value from three different tables and combine to one row in DB2 Warehouse on Cloud. Each table consists of only one row and unique column name. So what I want to is just join these three to one row their original column names.
Each table is built from a statement that looks like this:
SELECT SUM(FUEL_TEMP.FUEL_MLAD_VALUE) AS FUEL
FROM
(SELECT ML_ANOMALY_DETECTION.MLAD_METRIC AS MLAD_METRIC, ML_ANOMALY_DETECTION.MLAD_VALUE AS FUEL_MLAD_VALUE, ML_ANOMALY_DETECTION.TAG_NAME AS TAG_NAME, ML_ANOMALY_DETECTION.DATETIME AS DATETIME, DATA_CONFIG.SYSTEM_NAME AS SYSTEM_NAME
FROM ML_ANOMALY_DETECTION
INNER JOIN DATA_CONFIG ON
(ML_ANOMALY_DETECTION.TAG_NAME =DATA_CONFIG.TAG_NAME AND
DATA_CONFIG.SYSTEM_NAME = 'FUEL')
WHERE ML_ANOMALY_DETECTION.MLAD_METRIC = 'IFOREST_SCORE'
AND ML_ANOMALY_DETECTION.DATETIME >= (CURRENT DATE - 9 DAYS)
ORDER BY DATETIME DESC)
AS FUEL_TEMP
I have tried JOIN, INNER JOIN, UNION/UNION ALL, but can't get it to work as it should. How can I do this?
Use a cross-join like this:
create table table1 (field1 char(10));
create table table2 (field2 char(10));
create table table3 (field3 char(10));
insert into table1 values('value1');
insert into table2 values('value2');
insert into table3 values('value3');
select *
from table1
cross join table2
cross join table3;
Result:
field1 field2 field3
---------- ---------- ----------
value1 value2 value3
A cross join joins all the rows on the left with all the rows on the right. You will end up with a product of rows (table1 rows x table2 rows x table3 rows). Since each table only has one row, you will get (1 x 1 x 1) = 1 row.
Using UNION should solve your problem. Something like this:
SELECT
WarehouseDB1.WarehouseID AS TheID,
'A' AS TheSystem,
WarehouseDB1.TheValue AS TheValue
FROM WarehouseDB1
UNION
SELECT
WarehouseDB2.WarehouseID AS TheID,
'B' AS TheSystem,
WarehouseDB2.TheValue AS TheValue
FROM WarehouseDB2
UNION
WarehouseDB3.WarehouseID AS TheID,
'C' AS TheSystem,
WarehouseDB3.TheValue AS TheValue
FROM WarehouseDB3
Ill adapt the code with your table names and rows if you tell me what they are. This kind of query would return something like the following:
TheID TheSystem TheValue
1 A 10
2 A 20
3 B 30
4 C 40
5 C 50
As long as your column names match in each query, you should get the desired results.
Please advise me on the following question:
I have two tables in an Oracle db, one that contains full numbers and the other that contains parts of them.
Table 1:
12323543451123
66542123345345
16654232423423
12534456353451
64565463345231
34534512312312
43534534534533
Table 2:
1232
6654212
166
1253445635
6456546
34534
435345
Could you please suggest a query that joins these two tables and shows the relation between 6456546 and 64565463345231, for example. The main thing is that Table 2 contains a lot more data than Table 1, and i need to find all the substrings from Table 2 that are not present in Table 1.
Thanks in advance!
Try this:
with t as (
select 123 id from dual union all
select 567 id from dual union all
select 891 id from dual
), t2 as (
select 1112323 id from dual union all
select 32567321 id from dual union all
select 44891555 id from dual
)
select t.id, t2.id
from t, t2
where t2.id||'' like '%'||t.id||'%'
You could try using the CONTAINS operator like this :
SELECT * FROM Table2 JOIN Table1 ON Table1.id=Table2.id
WHERE NOT CONTAINS (Table2.data, Table1.data)
Are numbers from table two in a set place in table 1? For example is the 1232 in the same place each time or do you have to search a sting for the numbers. If it's set you could use an inline select or a temp table and create a substring of the string your searching and then join the table or temp table on that field.
you first need to say if the number in Table 1 and 2 are repeated, if is not then I think this query would help you:
SELECT *
FROM Table_1
JOIN Table_2 ON Table_1.ID = Table_2.ID
WHERE Table_2.DATA LIKE Table_1.DATA
I've read and read and read but I haven't found a solution to my problem.
I'm doing something like:
SELECT a
FROM t1
WHERE t1.b IN (<external list of values>)
There are other conditions of course but this is the jist of it.
My question is: is there a way to show which in the manually entered list of values didn't find a match? I've looked but I can't find and I'm going in circles.
Create a temp table with the external list of values, then you can do:
select item
from tmptable t
where t.item not in ( select b from t1 )
If the list is short enough, you can do something like:
with t as (
select case when t.b1='FIRSTITEM' then 1 else 0 end firstfound
case when t.b1='2NDITEM' then 1 else 0 end secondfound
case when t.b1='3RDITEM' then 1 else 0 end thirdfound
...
from t1 wher t1.b in 'LIST...'
)
select sum(firstfound), sum(secondfound), sum(thirdfound), ...
from t
But with proper rights, I would use Nicholas' answer.
To display which values in the list of values haven't found a match, as one of the approaches, you could create a nested table SQL(schema object) data type:
-- assuming that the values in the list
-- are of number datatype
create type T_NumList as table of number;
and use it as follows:
-- sample of data. generates numbers from 1 to 11
SQL> with t1(col) as(
2 select level
3 from dual
4 connect by level <= 11
5 )
6 select s.column_value as without_match
7 from table(t_NumList(1, 2, 15, 50, 23)) s -- here goes your list of values
8 left join t1 t
9 on (s.column_value = t.col)
10 where t.col is null
11 ;
Result:
WITHOUT_MATCH
-------------
15
50
23
SQLFiddle Demo
There is no easy way to convert "a externally provided" list into a table that can be used to do the comparison. One way is to use one of the (undocumented) system types to generate a table on the fly based on the values supplied:
with value_list (id) as (
select column_value
from table(sys.odcinumberlist (1, 2, 3)) -- this is the list of values
)
select l.id as missing_id
from value_list l
left join t1 on t1.id = l.id
where t1.id is null;
There are ways to get what you have described, but they have requirements which exceed the statement of the problem. From the minimal description provided, there's no way to have the SQL return the list of the manually-entered values that did not match.
For example, if it's possible to insert the manually-entered values into a separate table - let's call it matchtbl, with the column named b - then the following should do the job:
SELECT matchtbl.b
FROM matchtbl
WHERE matchtbl.b NOT IN (SELECT distinct b
FROM t1)
Of course, if the data is being processed by a programming language, it should be relatively easy to keep track of the set of values returned by the original query, by adding the b column to the output, and then perform the set difference.
Putting the list in an in clause makes this hard. If you can put the list in a table, then the following works:
with list as (
select val1 as value from dual union all
select val2 from dual union all
. . .
select valn
)
select list.value, count(t1.b)
from list left outer join
t1
on t1.b = list.value
group by list.value;