Trying to get wiki data for nuclear power plant, in that I am unable to get install capacity unit(megawatt)
SELECT ?ps ?wdLabel ?ps_Label ?pq ?wdpqLabel ?pq_Label {
VALUES (?item) {(wd:Q32159)}
?item ?p ?statement .
?statement ?ps ?ps_ .
?wd wikibase:claim ?p.
?wd wikibase:statementProperty ?ps.
OPTIONAL {
?statement ?pq ?pq_ .
?wdpq wikibase:qualifier ?pq .
}
SERVICE wikibase:label { bd:serviceParam wikibase:language "en" }
} ORDER BY ?wd ?statement ?ps_
Related
I am getting timeout on below query.
Can anyone please help me to optimize it?
SELECT ?human ?humanLabel ?alternative ?humanDescription ?birth_date ?image ?occupationLabel ?nationalityLabel ?sex_or_genderLabel ?date_of_death WHERE {
?human wdt:P31 wd:Q5.
?human wdt:P18 ?image.
?human p:P569/psv:P569 ?birth_date_node.
?birth_date_node wikibase:timeValue ?birth_date.
optional {?human wdt:P106 ?occupation.}
optional {?human wdt:P27 ?nationality.}
OPTIONAL {?human wdt:P21 ?sex_or_gender.}
OPTIONAL {?human wdt:P570 ?date_of_death.}
OPTIONAL {?human skos:altLabel ?alternative.}
FILTER (year(?birth_date) >= 1981).
FILTER (year(?birth_date) < 1982).
SERVICE wikibase:label {
bd:serviceParam wikibase:language "en" .
}
}
ORDER BY ?name
I am trying to query all the cats breeds (wd:Q43577) along with the list of cats that belong to. Below, you will find my solution. The result of my solution is not relevant and contains a redundancy. Therefore, I need your help to find the best solution. (to execute this query, you have to use this link).
SELECT ?CatsBreedsID ?CatsBreedsName ?CategoryID ?CategoryName ?CatsID ?CatsName where {
?CatsBreedsID wdt:P31 wd:Q43577.
OPTIONAL{
?CatsBreedsID wdt:P279 ?CategoryID.
?CatsID wdt:P31 ?CategoryID.
}
SERVICE wikibase:label {
bd:serviceParam wikibase:language "en".
?CatsBreedsID rdfs:label ?CatsBreedsName .
?CategoryID rdfs:label ?CategoryName .
?CatsID rdfs:label ?CatsName.
}
}
You should use the GROUP_CONCAT function if I understand your question correctly.
Try a query like this:
SELECT ?CatsBreedsID ?CatsBreedsName ?CategoryID ?CategoryName
(GROUP_CONCAT(DISTINCT ?CatsID; SEPARATOR=', ') AS ?CatsID_List)
(GROUP_CONCAT(DISTINCT ?CatsName; SEPARATOR=', ') AS ?CatsName_List)
WHERE {
?CatsBreedsID wdt:P31 wd:Q43577.
OPTIONAL{
?CatsBreedsID wdt:P279 ?CategoryID.
?CatsID wdt:P31 ?CategoryID.
}
SERVICE wikibase:label {
bd:serviceParam wikibase:language "en".
?CatsBreedsID rdfs:label ?CatsBreedsName .
?CategoryID rdfs:label ?CategoryName .
?CatsID rdfs:label ?CatsName.
}
} GROUP BY ?CatsBreedsID ?CatsBreedsName ?CategoryID ?CategoryName
For a given property like 'occupation (P106)', I want to retrieve all its aliases like: profession, job, work, career, employment, craft. All of this is present on the properties wikidata page, under 'Also known as'. How can I go about retrieving this using SPARQL?
I tried using the following query.
SELECT ?predicate ?object WHERE {
wdt:P106 wdt:P1449 ?predicate . //Nickname
wdt:P106 wdt:P734 ?predicate . //Family Name
wdt:P106 wdt:P735 ?predicate . //Given Name
wdt:P106 skos:altLabel ?predicate .
SERVICE wikibase:label { bd:serviceParam wikibase:language "en". }
}
SELECT ?altLabel
{
VALUES (?wd) {(wd:P106)}
?wd skos:altLabel ?altLabel .
FILTER (lang(?altLabel) = "en")
}
or
SELECT ?altLabel
{
VALUES (?wdt) {(wdt:P106)}
?wd wikibase:directClaim ?wdt .
?wd skos:altLabel ?altLabel .
FILTER (lang(?altLabel) = "en")
}
These paragraphs provide some explanation:
Truthy statements
Properties
Predicates
Update
You still could use the label service:
SELECT ?wdAltLabel
{
VALUES (?wdt) {(wdt:P106)}
?wd wikibase:directClaim ?wdt .
SERVICE wikibase:label { bd:serviceParam wikibase:language "en". }
}
My objective is to create a sparql query that retrieves a list of cast and crew and it's wikidata type ("director", "screenwriter", "cast member", ...)
So far I have this:
SELECT ?titleLabel ?castLabel ?property ?propertyLabel
WHERE {
?title wdt:P345 "tt0848228".
?title wdt:P57 ?cast.
?property wikibase:propertyType ?propertyType.
SERVICE wikibase:label { bd:serviceParam wikibase:language "en". }
}
The output I want to achive is a table with rows like:
"The Avengers", "Joss Whedon", "wd:P57", "director"
...
I came up with this query:
SELECT ?titleLabel ?castLabel ?property ?propLabel
WHERE {
?title wdt:P345 "tt0848228".
# take all claims on this movie
?title ?property ?cast .
# that involve a human
?cast wdt:P31 wd:Q5 .
# get the property label
# see https://www.wikidata.org/wiki/Wikidata:SPARQL_query_service/queries#Adding_labels_for_properties
hint:Query hint:optimizer "None" .
?prop wikibase:directClaim ?property .
SERVICE wikibase:label { bd:serviceParam wikibase:language "en". }
}
I'm trying to retrieve some information from Wikidata and I have found interesting to collect the aliases of the voices. For examples Francesco Totti is also known as il Capitano or er Pupone :
I'm trying to retrieve all the serie a's football players with this sparql query:
SELECT ?subject ?nomeLabel ?cognomeLabel ?subjectLabel WHERE {
?subject wdt:P31 wd:Q5.
?subject p:P54 ?team .
?team ps:P54 wd:""" + team_code +""" .
FILTER NOT EXISTS { ?team pq:P582 ?end
}
OPTIONAL{
?subject wdt:P735 ?nome .
?subject wdt:P734 ?cognome .
}
SERVICE wikibase:label { bd:serviceParam wikibase:language "it". }
}
ORDER BY (?cognomeLabel)
How I can modify my query to take also the aliases?
Thanks
I have attempted a query with various labels. Here just for Roma:
SELECT distinct ?subject ?subjectLabel ?nomeLabel ?cognomeLabel ?nickname ?alternative ?subjectAltLabel WHERE {
?subject wdt:P31 wd:Q5.
?subject p:P54 ?team .
?team ps:P54 wd:Q2739 .
FILTER NOT EXISTS { ?team pq:P582 ?end . }
OPTIONAL { ?subject wdt:P735 ?nome . }
OPTIONAL { ?subject wdt:P734 ?cognome . }
OPTIONAL { ?subject wdt:P1449 ?nickname . }
OPTIONAL { ?subject skos:altLabel ?alternative . }
SERVICE wikibase:label { bd:serviceParam wikibase:language "it,en,fr". }
}
ORDER BY (?cognomeLabel)
I believe the P1449 property should be the most appropriate property to store an alias/nickname, but it does not seem to be used that much for football players. I just added "il Capitano" to Francesco Totti. Beyond that one there does not seem to be other nicknames for Roma players.
The "Also known as" label (in the right column) is not necessarily the nickname, but may be a spelling variation.
Something more generic if someone is interested in all properties that will return only the english also known as:
SELECT ?property ?propertyLabel ?propertyDescription (GROUP_CONCAT(DISTINCT(?altLabel); separator = ", ") AS ?altLabel_list) WHERE {
?property a wikibase:Property .
OPTIONAL { ?property skos:altLabel ?altLabel . FILTER (lang(?altLabel) = "en") }
SERVICE wikibase:label { bd:serviceParam wikibase:language "en" .}
}
GROUP BY ?property ?propertyLabel ?propertyDescription
LIMIT 5000
Another more simple example for male actors with itemAltLabel :
#Male Actors
SELECT ?item ?itemLabel ?itemAltLabel
WHERE
{
?item wdt:P21 wd:Q6581097.
?item wdt:P106 wd:Q33999.
SERVICE wikibase:label { bd:serviceParam wikibase:language "en". }
}