example:
a variable
val str = readln().replace("[^A-Za-z0-9 ] \\s+".toRegex(),"").trim()
should read multiple lines of input value, input value will be like this
heading
----------
topic1
topic2
or like this
heading
-------
a) topic1
b) topic2
input may contain special characters or tabs or spaces we need to remove them also
I don't know what your Regex is trying to do, but that's not really your question.
How do you know when the user has finished their input - a special word or an empty line?
Assuming an empty line, here's how you can get all the content
println("Enter something:")
var lines = ""
do {
val line = readLine()
lines += "${clean(line)}\n"
} while (!line.isNullOrBlank())
println("User input:\n$lines")
private fun clean(line: String?): String? {
return line?.replace("[^A-Za-z0-9 ] \\s+".toRegex(),"")?.trim()
}
Related
Is there an easier approach to convert an Intellij IDEA environment variable into a list of Tuples?
My environment variable for Intellij is
GROCERY_LIST=[("egg", "dairy"),("chicken", "meat"),("apple", "fruit")]
The environment variable gets accessed into Kotlin file as String.
val g_list = System.getenv("GROCERY_LIST")
Ideally I'd like to iterate over g_list, first element being ("egg", "dairy") and so on.
And then ("egg", "dairy") is a tuple/pair
I have tried to split g_list by comma that's NOT inside quotes i.e
val splitted_list = g_list.split(",(?=(?:[^\\\"]*\\\"[^\\\"]*\\\")*[^\\\"]*\$)".toRegex()).toTypedArray()
this gives me first element as [("egg", second element as "dairy")] and so on.
Also created a data class and tried to map the string into data class using jacksonObjectMapper following this link:
val mapper = jacksonObjectMapper()
val g_list = System.getenv("GROCERY_LIST")
val myList: List<Shopping> = mapper.readValue(g_list)
data class Shopping(val a: String, val b: String)
You can create a regular expression to match all strings in your environmental variable.
Regex::findAll()
Then loop through the strings while creating a list of Shopping objects.
// Raw data set.
val groceryList: String = "[(\"egg\", \"dairy\"),(\"chicken\", \"meat\"),(\"apple\", \"fruit\")]"
// Build regular expression.
val regex = Regex("\"([\\s\\S]+?)\"")
val matchResult = regex.findAll(groceryList)
val iterator = matchResult.iterator()
// Create a List of `Shopping` objects.
var first: String = "";
var second: String = "";
val shoppingList = mutableListOf<Shopping>()
var i = 0;
while (iterator.hasNext()) {
val value = iterator.next().value;
if (i % 2 == 0) {
first = value;
} else {
second = value;
shoppingList.add(Shopping(first, second))
first = ""
second = ""
}
i++
}
// Print Shopping List.
for (s in shoppingList) {
println(s)
}
// Output.
/*
Shopping(a="egg", b="dairy")
Shopping(a="chicken", b="meat")
Shopping(a="apple", b="fruit")
*/
data class Shopping(val a: String, val b: String)
Never a good idea to use regex to match parenthesis.
I would suggest a step-by-step approach:
You could first match the name and the value by
(\w+)=(.*)
There you get the name in group 1 and the value in group 2 without caring about any subsequent = characters that might appear in the value.
If you then want to split the value, I would get rid of start and end parenthesis first by matching by
(?<=\[\().*(?=\)\])
(or simply cut off the first and last two characters of the string, if it is always given it starts with [( and ends in )])
Then get the single list entries from splitting by
\),\(
(take care that the split operation also takes a regex, so you have to escape it)
And for each list entry you could split that simply by
,\s*
or, if you want the quote character to be removed, use a match with
\"(.*)\",\s*\"(.*)\"
where group 1 contains the key (left of equals sign) and group 2 the value (right of equals sign)
validValueType.ValueTypeGroup
["\"is_enabled\": false", "\"value\":\"OUT\""]
failedRecord.record
{"email":"test#gmail.com","source":"web","value":"OUT","reate_date":"2022-09-29T03:42:09.976-05:00","is_undeliverable":false}
fun publishAlert(failedRecord: Record<String>) {
if (validValueType.ValueTypeGroup.contains(failedRecord.record)) {
// do stuff
} else {
// no match do other stuff
}
}
In the list above there are two strings I want to check for when this function receives a record.
The failedRecord.record string does contain what I want "value":"OUT" and it's also within the list above. So why is contains not working here? it keeps bouncing out to the else statement.
You can use any() in the list and pass a predicate:
{x -> searchString.contains(x)}
The searchString.contains() will search x as a substring inside searchString for each x representing the elements in the list
var list = listOf("\"is_enabled\": false", "\"value\":\"OUT\"")
println(list)
println(list::class.qualifiedName)
println() // empty newline
var searchString = "{\"email\":\"test#gmail.com\",\"source\":\"web\",\"value\":\"OUT\",\"create_date\":\"2022-09-29T03:42:09.976-05:00\",\"is_undeliverable\":false}";
println(searchString)
println(searchString::class.qualifiedName)
println() // empty newline
println(list.any{x -> searchString.contains(x)});
Output
["is_enabled": false, "value":"OUT"]
java.util.Arrays.ArrayList
{"email":"test#gmail.com","source":"web","value":"OUT","create_date":"2022-09-29T03:42:09.976-05:00","is_undeliverable":false}
kotlin.String
true
I have a reference string on which the allowed characters are listed. Then I also have input strings, from which not allowed characters should be replaced with a fixed character, in this example "0".
I can use filter but it removes the characters altogether, does not offer a replacement. Please note that it is not about being alphanumerical, there are ALLOWED non-alphanumerical characters and there are not allowed alphanumerical characters, referenceStr happens to be arbitrary.
var referenceStr = "abcdefg"
var inputStr = "abcqwyzt"
inputStr = inputStr.filter{it in referenceStr}
This yields:
"abc"
But I need:
"abc00000"
I also considered replace but it looks more like when you have a complete reference list of characters that are NOT allowed. My case is the other way around.
Given:
val referenceStr = "abcd][efg"
val replacementChar = '0'
val inputStr = "abcqwyzt[]"
You can do this with a regex [^<referenceStr>], where <referenceStr> should be replaced with referenceStr:
val result = inputStr.replace("[^${Regex.escape(referenceStr)}]".toRegex(), replacementChar.toString())
println(result)
Note that Regex.escape is used to make sure that the characters in referenceStr are all interpreted literally.
Alternatively, use map:
val result = inputStr.map {
if (it !in referenceStr) replacementChar else it
}.joinToString(separator = "")
In the lambda decide whether the current char "it" should be transformed to replacementChar, or itself. map creates a List<Char>, so you need to use joinToString to make the result a String again.
I am trying to replace a few sub strings inside a string. But my code doesn't seem to work.
val listOfMaleWords = listOf(" him", " he", " his")
val listOfFemaleWords = listOf(" her", " she", " her")
fun modifyIdeaForGender(rawIdea : String, desiredGender : String): String {
var theRawIdea = rawIdea
if (desiredGender == "FEMALE") {
println("desired gender is FEMALE")
listOfMaleWords.forEachIndexed { index, element ->
theRawIdea.replace(element, listOfFemaleWords[index])
}
} else {
println("desired gender is MALE")
listOfFemaleWords.forEachIndexed { index, element ->
theRawIdea.replace(element, listOfMaleWords[index])
}
}
return theRawIdea
}
fun main() {
var sampleString : String = "Tell him, he is special"
println(modifyIdeaForGender(sampleString, "FEMALE"))
}
Expected Output :
"Tell her, she is special"
Current Output :
"Tell him, he is special" // no change
Whats wrong with my code? The current output doesn't replace the string characters at all.
replace returns a new String that you are discarding immediately. It does not mutate theRawIdea itself, so you should assign it back to theRawIdea yourself. For example:
theRawIdea = theRawIdea.replace(element, listOfFemaleWords[index])
Though this would modify theRawIdea as you desire, it wouldn't replace the pronouns correctly. Once it replaces the "him"s with "her"s, it would try to replace the "he"s with "she"s. But note that "he" a substring of "her"! So this would produce:
Tell sher, she is special
This could be fixed by reordering the lists, putting the "he"-"she" pair first, or by using regex, adding \b word boundary anchors around the words:
// note that you should not have spaces before the words if you decide to use \b
val listOfMaleWords = listOf("him", "he", "his")
val listOfFemaleWords = listOf("her", "she", "her")
...
theRawIdea = theRawIdea.replace("\\b$element\\b".toRegex(), listOfFemaleWords[index])
Note that this doesn't account for capitalisation or the fact that changing from female gender pronouns to male ones is inherently broken. Your current code would change all her to him. It would require some more complicated natural language processing to accurately do this task in general.
Taking all that into account, I've rewritten your code with zip:
fun modifyMaleIdeaToFemaleGender(rawIdea : String): String {
var theRawIdea = rawIdea
// if you really want to do the broken female to male case, then this would be
// listOfFemaleWords zip listOfMaleWords
// and the loop below can stay the same
val zipped = listOfMaleWords zip listOfFemaleWords
zipped.forEach { (target, replacement) ->
theRawIdea = theRawIdea.replace("\\b$target\\b".toRegex(), replacement)
}
return theRawIdea
}
You can also use fold to avoid reassigning theRawIdea:
fun modifyIdeaToFemaleGender(rawIdea : String): String {
val zipped = listOfMaleWords zip listOfFemaleWords
return zipped.fold(rawIdea) { acc, (target, replacement) ->
acc.replace("\\b$target\\b".toRegex(), replacement)
}
}
Your code assumes that the replace() method performs an in-place mutation of the string. However, the string with the replaced values are returned by the replace(). So you need to change your code to contain something like:
theRawIdea = theRawIdea.replace(element, listOfFemaleWords[index])
To do this, you will have to use a conventional loop instead of listOfMaleWords.forEachIndexed style looping.
So i have a string text = "" and when i want to increment i use text+= "something", but i need to make a break line because i will write that text a couple times repeated, but when i do text+="\n" it adds the spaces between the "something" texts but after that it adds another space that i dont want.
I would not do it iteratively. So instead of using a loop, you can use joinToString for that, like this:
lines.joinToString(separator = "\n")
val result = string.substringBeforeLast("\n")
This might help!
fun main() {
var string=""
for (line in 0 until 4){
string += "Something"
if (line!=3){
string+="\n"
}
}
print(string)
}