Pattern match using regexp_extract_all - sql

Question

I am trying to build a array from this string and need help with pattern on regexp_extract_all.
Here is my input string contains keyword value pairs
BEGIN
DECLARE p_JSON STRING DEFAULT """
{
"instances": [{
"LT_20MN_SalesContrctCnt": 388.0,
"Pyramid_Index": '',
"MARKET": "'Growth Markets','Europe'",
"SERVICE_DIM": "'S&C','F&M'",
"SG_MD": "'All Service Group'"
}]}
""";
SELECT split(x,":")[OFFSET(0)] as keyword, split(x,":")[OFFSET(1)] keyword_value
FROM unnest(split(REGEXP_REPLACE(JSON_EXTRACT(p_JSON, '$.instances'),r'([\'\"\[\]{}])', ''))) as x
END;
The above SQL is failing at SPLIT due to , with in the data.
All I am trying to do here is build a two columns Keyword and value.
The idea here is if I can extract each row using REGEXP_EXTRACT_ALL with out the last "," then I should be able to split into keyword and keyword_value columns. Btw the names or number of keywords/values are not fixed.
Intended output from REGEXP_EXTRACT_ALL:
"LT_20MN_SalesContrctCnt": 388.0
"Pyramid_Index": ''
"MARKET": "'Growth Markets','Europe'"
"SERVICE_DIM": "'S&C','F&M'"
"SG_MD": "'All Service Group'"
Appreciate if you can suggest a better way to handle this.
Thanks in advance.

Answer 1

Using your sample data, I just added an extra REGEXP_REPLACE to replace ," to #" so we can avoid splitting using ,. See approach below:
SELECT
SPLIT(arr,":")[OFFSET(0)] as keyword,
SPLIT(arr,":")[OFFSET(1)] as keyword_value,
FROM sample_data,
UNNEST(SPLIT(REGEXP_REPLACE(REGEXP_REPLACE(JSON_EXTRACT(p_JSON, '$.instances'),r'[\[\]{}]',''),r',"','#"'),'#')) arr
Output: