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I have a table which has a column in which I am storing a comma separated text with single quotes for each of the comma separated values. These values are employee IDs. This is how it looks
Now, I have a SQL query wherein I need to put the value from this column into a SQL IN operator. Something like this:
select *
from EMPLOYEE_MASTER
where EMPLOYEEID IN (select CM_CONFIG_VALUE
from ADL_CONFIG_MAST_T
where CM_CONFIG_KEY like 'ATT_BIOMETRIC_OU_ID'
)
But this, does not work, the query when executed returns 0 rows whereas if I execute the query normally like below, it works.
select *
from EMPLOYEE_MASTER
where EMPLOYEEID IN('9F3DD4B791554DDE','C9B90D62851D43AB','828CB9E6204B4DDC')
Please suggest what I should do here. I have tried using substring to remove the first and the last character as well assuming that single quotes might be the issue, but that does not work either.
select * from EMPLOYEE_MASTER where EMPLOYEEID IN(select EMPLOYEEID from ADL_CONFIG_MAST_T where CM_CONFIG_KEY like 'ATT_BIOMETRIC_OU_ID')
column should be same in where COLUMNNAME IN (select COLUMNNMAE from tablename)
You can create a temp varible and then use exec command to get the desired result.
declare #temp varchar(200)
select #temp=CM_CONFIG_VALUE
from ADL_CONFIG_MAST_T
where CM_CONFIG_KEY like 'ATT_BIOMETRIC_OU_ID'
exec('select *
from EMPLOYEE_MASTER
where EMPLOYEEID IN (' + #temp + ')')
Try This:
DECLARE #ID VARCHAR(500);
DECLARE #Number VARCHAR(500);
DECLARE #comma CHAR;
SET #comma = ','
SET #ID = (select CM_CONFIG_VALUE
from ADL_CONFIG_MAST_T
where CM_CONFIG_KEY like %ATT_BIOMETRIC_OU_ID% + #comma);
Create table #temp (EMPLOYEEID varchar(500))
WHILE CHARINDEX(#comma, #ID) > 0
BEGIN
SET #Number = SUBSTRING(#ID, 0, CHARINDEX(#comma, #ID))
SET #ID = SUBSTRING(#ID, CHARINDEX(#comma, #ID) + 1, LEN(#ID))
Insert into #temp
select #Number
END
select *
from EMPLOYEE_MASTER
where EMPLOYEEID IN(select EMPLOYEEID from #temp)
The reason you are not getting it in your query is because your inner query returns only one row. So your query searches for '9F3DD4B791554DDE','C9B90D62851D43AB','828CB9E6204B4DDC' as as single record.
If your compatibility level is greater than or equal to 130 you can use STRING_SPLIT() function. Then your query would be
SELECT *
FROM EMPLOYEE_MASTER
WHERE EMPLOYEEID IN
(SELECT value AS empid
FROM ADL_CONFIG_MAST_T CROSS APPLY string_split(CM_CONFIG_VALUE, ',' )
WHERE CM_CONFIG_KEY LIKE 'ATT_BIOMETRIC_OU_ID' )
What this actually does is, it splits the CM_CONFIG_VALUE with ',' and returns them as rows. This is the value column I have referred. Then you use them with the IN clause.
Hope this helps!
Direct IN condition will not work here. You have split your string before searching. You can do that with XML options in SQL SERVER 2014
SELECT *
FROM EMP
WHERE EMPID IN (
SELECT a.c.value('.', 'VARCHAR(1000)')
FROM (
SELECT x = CAST('<a>' +
REPLACE(REPLACE(CM_CONFIG_VALUE , ',', '</a><a>'),'''','') + '</a>' AS XML )
FROM ADL_CONFIG_MAST_T
-- WHERE <your_condition>
) m
CROSS APPLY x.nodes('/a') a(c))
CHECK DEMO HERE
For the version 2016 and above you can use STRING_SPLIT with Compatibility level 130
I have two columns in a table. I want to merge them into a single column, but the merge should be done taking alternate characters from each columns.
For example:
Column A --> value (1,2,3)
Column B --> value (A,B,C)
Required result - (1,A,2,B,3,C)
It should be done without loops.
You need to make use of the UNION and get a little creative with how you choose to alternate. My solution ended up looking like this.
SELECT ColumnA
FROM Table
WHERE ColumnA%2=1
UNION
SELECT ColumnB
FROM TABLE
WHERE ColumnA%2=0
If you have an ID/PK column that could just as easily be used, I just didn't want to assume anything about your table.
EDIT:
If your table contains duplicates that you wish to keep, use UNION ALL instead of UNION
Try This;
SELECT [value]
FROM [Table]
UNPIVOT
(
[value] FOR [Column] IN ([Column_A], [Column_B])
) UNPVT
If you have SQL 2016 or higher you can use:
SELECT QUOTENAME(STRING_AGG (cast(a as varchar(1)) + ',' + b, ','), '()')
FROM test;
In older versions, depending on how much data you have in your tables you can also try:
SELECT QUOTENAME(STUFF(
(SELECT ',' + cast(a as varchar(1)) + ',' + b
FROM test
FOR XML PATH('')), 1, 1,''), '()')
Here you can try a sample
http://sqlfiddle.com/#!18/6c9af/5
with data as (
select *, row_number() over order by colA) as rn
from t
)
select rn,
case rn % 2 when 1 then colA else colB end as alternating
from data;
The following SQL uses undocumented aggregate concatenation technique. This is described in Inside Microsoft SQL Server 2008 T-SQL Programming on page 33.
declare #x varchar(max) = '';
declare #t table (a varchar(10), b varchar(10));
insert into #t values (1,'A'), (2,'B'),(3,'C');
select #x = #x + a + ',' + b + ','
from #t;
select '(' + LEFT(#x, LEN(#x) - 1) + ')';
The following query returns the results shown below:
SELECT
ProjectID, newID.value
FROM
[dbo].[Data] WITH(NOLOCK)
CROSS APPLY
STRING_SPLIT([bID],';') AS newID
WHERE
newID.value IN ('O95833', 'Q96NY7-2')
Results:
ProjectID value
---------------------
2 Q96NY7-2
2 O95833
2 O95833
2 Q96NY7-2
2 O95833
2 Q96NY7-2
4 Q96NY7-2
4 Q96NY7-2
Using the newly added STRING_AGG function (in SQL Server 2017) as it is shown in the following query I am able to get the result-set below.
SELECT
ProjectID,
STRING_AGG( newID.value, ',') WITHIN GROUP (ORDER BY newID.value) AS
NewField
FROM
[dbo].[Data] WITH(NOLOCK)
CROSS APPLY
STRING_SPLIT([bID],';') AS newID
WHERE
newID.value IN ('O95833', 'Q96NY7-2')
GROUP BY
ProjectID
ORDER BY
ProjectID
Results:
ProjectID NewField
-------------------------------------------------------------
2 O95833,O95833,O95833,Q96NY7-2,Q96NY7-2,Q96NY7-2
4 Q96NY7-2,Q96NY7-2
I would like my final output to have only unique elements as below:
ProjectID NewField
-------------------------------
2 O95833, Q96NY7-2
4 Q96NY7-2
Any suggestions about how to get this result? Please feel free to refine/redesign from scratch my query if needed.
Use the DISTINCT keyword in a subquery to remove duplicates before combining the results: SQL Fiddle
SELECT
ProjectID
,STRING_AGG(value, ',') WITHIN GROUP (ORDER BY value) AS
NewField
from (
select distinct ProjectId, newId.value
FROM [dbo].[Data] WITH(NOLOCK)
CROSS APPLY STRING_SPLIT([bID],';') AS newID
WHERE newID.value IN ( 'O95833' , 'Q96NY7-2' )
) x
GROUP BY ProjectID
ORDER BY ProjectID
You can use distinct in the subquery used for the apply:
SELECT d.ProjectID,
STRING_AGG( newID.value, ',') WITHIN GROUP (ORDER BY newID.value) AS
NewField
FROM [dbo].[Data] d CROSS APPLY
(select distinct value
from STRING_SPLIT(d.[bID], ';') AS newID
) newID
WHERE newID.value IN ( 'O95833' , 'Q96NY7-2' )
group by projectid;
This is a function that I wrote that answers the OP Title:
Improvements welcome!
CREATE OR ALTER FUNCTION [dbo].[fn_DistinctWords]
(
#String NVARCHAR(MAX)
)
RETURNS NVARCHAR(MAX)
WITH SCHEMABINDING
AS
BEGIN
DECLARE #Result NVARCHAR(MAX);
WITH MY_CTE AS ( SELECT Distinct(value) FROM STRING_SPLIT(#String, ' ') )
SELECT #Result = STRING_AGG(value, ' ') FROM MY_CTE
RETURN #Result
END
GO
Use like:
SELECT dbo.fn_DistinctWords('One Two Three Two One');
As #SeanLange pointed out in the comments, this is a terrible way to pull out the data, but if you had to, just make it 2 separate queries as follows:
SELECT
ProjectID
,STRING_AGG( val, ',') WITHIN GROUP (ORDER BY val) AS NewField
FROM
(
SELECT DISTINCT
ProjectID
,newID.value AS val
FROM
[dbo].[Data] WITH(NOLOCK)
CROSS APPLY STRING_SPLIT([bID],';') AS newID
WHERE
newID.value IN ('O95833' , 'Q96NY7-2')
) t
GROUP BY
ProjectID
That should do it.
Another possibility to get unique strings from STRING_AGG would be to perform these three steps after fetching the comma separated string:
Split the string (STRING_SPLIT)
Select DISTINCT from the splits
Apply STRING_AGG again to a select with a group on a single key
Example:
(select STRING_AGG(CAST(value as VARCHAR(MAX)), ',')
from (SELECT distinct 1 single_key, value
FROM STRING_SPLIT(STRING_AGG(CAST(customer_division as VARCHAR(MAX)), ','), ','))
q group by single_key) as customer_division
Here is my improvement on #ttugates to make it more generic:
CREATE OR ALTER FUNCTION [dbo].[fn_DistinctList]
(
#String NVARCHAR(MAX),
#Delimiter char(1)
)
RETURNS NVARCHAR(MAX)
WITH SCHEMABINDING
AS
BEGIN
DECLARE #Result NVARCHAR(MAX);
WITH MY_CTE AS ( SELECT Distinct(value) FROM STRING_SPLIT(#String,
#Delimiter) )
SELECT #Result = STRING_AGG(value, #Delimiter) FROM MY_CTE
RETURN #Result
END
You can make a distinct view of the table, that holds the aggregate values, that is even simpler:
Create Table Test (field1 varchar(1), field2 varchar(1));
go
Create View DistinctTest as (Select distinct field1, field2 from test group by field1,field2);
go
insert into Test Select 'A', '1';
insert into Test Select 'A', '2';
insert into Test Select 'A', '2';
insert into Test Select 'A', '2';
insert into Test Select 'D', '1';
insert into Test Select 'D', '1';
select string_agg(field1, ',') from Test where field2 = '1'; /* duplicates: A,D,D */;
select string_agg(field1, ',') from DistinctTest where field2 = '1'; /* no duplicates: A,D */;
Oracle (since version 19c) suports listagg (DISTINCT ..., but Microsoft SQL Server not probably.
It's my data and every ThroughRouteSid record has the same pattern.
six number and five comma. then I just want to get three and five
number into two record to template Table and get the same Count()
value to these two record.
For example: First record in the picture.
ThroughRouteSid(3730,2428,2428,3935,3935,3938,) Count(32).
I want a result like this:
2428 32 3935 32
I get What number I want.become two record and both have same Count value into template table
you can use XML to get your result, please refer below sample code -
create table #t1( ThroughRouteSid varchar(500) , Cnt int)
insert into #t1
select '3730,2428,2428,3935,3935,3938,' , len('3730,2428,2428,3935,3935,3938,')
union all select '1111,2222,3333,4444,5555,6666,' , len('1111,2222,3333,4444,5555,6666,')
select cast( '<xml><td>' + REPLACE( SUBSTRING(ThroughRouteSid ,1 , len(ThroughRouteSid)-1),',','</td><td>') + '</td></xml>' as xml) XmlData , Cnt
into #t2 from #t1
select XmlData.value('(xml/td)[3]' ,'int' ), Cnt ,XmlData.value('(xml/td)[5]' ,'int' ), Cnt
from #t2
First create the function referring How to Split a string by delimited char in SQL Server. Then try Querying the following
select (SELECT CONVERT(varchar,splitdata) + ' '+ Convert(varchar, [Count])+' ' FROM (select splitdata, ROW_NUMBER() over (ORDER BY (SELECT 100)) row_no
from [dbo].[fnSplitString](ThroughRouteSid,',')
where splitdata != '') as temp where row_no in (2,5)
for xml path('')) as col1 from [yourtable]
If you are using SQL Server 2016 you can do something like this:
create table #temp (ThroughRouteSid varchar(1024),[Count] int)
insert into #temp values
('3730,2428,2428,3935,3935,3938,',32),
('730,428,428,335,935,938,',28)
select
spt.value,
t.[Count]
from #temp t
cross apply (
select value from STRING_SPLIT(t.ThroughRouteSid,',') where LEN(value) > 0
)spt
May someone please help me for this strange scenario. i have a data as given below.
DECLARE #TABLE TABLE
(
ID INT,
PHONE001 VARCHAR(500)
)
INSERT TEST
SELECT 1,'01323840261,01323844711' UNION ALL
SELECT 2,'' UNION ALL
SELECT 3,',01476862000' UNION ALL
SELECT 4,'01233625418,1223822583,125985' UNION ALL
SELECT 5,'2089840022,9.99021E+13'
and i am trying to put in seperate column for each comma value. the max number of column depends on the largest comma seperated string.
Expected Output
1|01323840261|01323844711|''
2|''|''|''
3|01476862000|''|''|
4|01233625418|1223822583|125985|
5|2089840022|9.99021E+13|''|
try
select id,T.c.value('t[1]','varchar(50)') as col1,
T.c.value('t[2]','varchar(50)') as col2 ,
T.c.value('t[3]','varchar(50)') as col3 from
(select id,cast ('<t>'+ replace(PHONE001,',','</t><t>') +'</t>'
as xml) x
from #TABLE) a cross apply x.nodes('.') t(c)