I am asking for help with this item. I am a novice to SQL and not very sure how to handle this problem I appreciate any help from the forum.
I have a table that is updated multiple times a day. I would like to create a view that only displays the last update that was made for a given day.
Here is a sample of the data
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This is the desired result of the SQL Query when the data set provided has been queries
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As I understood you want to get the last record of every day.
Just group it by day
You will have to use EXTRACT to do it
Example: EXTRACT(DAY FROM DATE)
Then select the max time from the column where you have the time of the day. If you dont have the time in a different column you will also need to extract it.
SELECT MAX(TIME_COLUMN) FROM `TABLE_NAME`
GROUP BY EXTRACT(DAY FROM DATE)
SELECT MAX (your_date) AS "Max Date"
FROM your_table
Related
I have this table
I want to create a query that will return data in the following format:
date (just a day), sms_number, etc...
So I want to unite rows from the 1st table by days and return statistics for it, for example amount of sms (rows) for one day (for example for 2020-07-07, time should not be taken into account).
How do I do this using SQL (provide an example)?
Try the following:
select DATE_FORMAT(date_,'%Y-%m-%d') AS
date_, count(date_) as sms_number from
sms_logs
group by DATE_FORMAT(date_,'%Y-%m-%d')
order by date_ DESC
See a MySQL demo from db-fiddle.
I'm using SQL Server to COUNT some data which originates from a HTML table. I want to COUNT total rows in the database based on today's date. And then after the date hits tomorrow's date, to set the COUNT value back to zero and to restart the count back from the start.
Is there a query that can help me fetch data based on current date and time?
Something like this:
SELECT COUNT(data_id)
FROM table1
WHERE clock_time BETWEEN 000000 AND 235959
AND date_time IS TODAY's DATE (or something like that)
GROUP BY XXX
ORDER BY XXX
After the clock hits tomorrow's date, I want to reset the COUNT back to zero, and to start a new count back from 00:00:00.
I know there is NOW() query but as far as I know it only shows the date.
Someone told me I could use WHERE DATE(date)=CURDATE() but the SQL Server won't work with that.
Thank you...
You can use convert function like this
where convert(Date,date_time)= CONVERT(Date,GETDATE())
Need not to use time as you want today's data.
Try this one
SELECT COUNT(data_id) FROM table1
WHERE convert(date,date_time) = getdate()
I have a table named Sales and a column within it named Date. I'm simply trying to find how many sales were made on a specific date. My intuition was to use something like this:
SELECT COUNT(Date) FROM Sales WHERE Date='2015-04-04'
this should count all sales that were made on that date, but that returns 0. What am I doing wrong?
While it is difficult to be precise without table definitions or an indication of what RDBMS you are using, it is likely that Date is a time/date stamp, and that the result you want would be obtained either by looking for a range from the beginning of the day to the end of the day in your WHERE clause, or by truncating Date down to a date without the time before comparing it to a date.
Try the below once.
select count(*) from <t.n> where date like '2015-04-04%';
When you want to find the count of rows based on a field (Date) You need to Group By over it like this:
SELECT Date, COUNT(*)
FROM Sales
GROUP BY Date
Now you have all count of rows for each Date.
Type and Value of Date is important in the result of the above query.
For example in SQL Server your best try is to convert a DateTime field to varchar and then check it as the result of CONVERT like this:
SELECT COUNT(*)
FROM Sales
WHERE CONVERT(VARCHAR, Date, 111) = '2015/04/04'
I've got a table with purchase orders stored in it. Each row has a timestamp indicating when the order was placed. I'd like to be able to create a report indicating the number of purchases each day, month, or year. I figured I would do a simple SELECT COUNT(xxx) FROM tbl_orders GROUP BY tbl_orders.purchase_time and get the value, but it turns out I can't GROUP BY a timestamp column.
Is there another way to accomplish this? I'd ideally like a flexible solution so I could use whatever timeframe I needed (hourly, monthly, weekly, etc.) Thanks for any suggestions you can give!
This does the trick without the date_trunc function (easier to read).
// 2014
select created_on::DATE from users group by created_on::DATE
// updated September 2018 (thanks to #wegry)
select created_on::DATE as co from users group by co
What we're doing here is casting the original value into a DATE rendering the time data in this value inconsequential.
Grouping by a timestamp column works fine for me here, keeping in mind that even a 1-microsecond difference will prevent two rows from being grouped together.
To group by larger time periods, group by an expression on the timestamp column that returns an appropriately truncated value. date_trunc can be useful here, as can to_char.
I have an SQLite database with the following fields for example:
date (yyyymmdd fomrat)
total (0.00 format)
There is typically 2 months of records in the database. Does anyone know a SQL query to find a weekly average?
I could easily just execute:
SELECT COUNT(1) as total_records, SUM(total) as total FROM stats_adsense
Then just divide total by 7 but unless there is exactly x days that are divisible by 7 in the db I don't think it will be very accurate, especially if there is less than 7 days of records.
To get a daily summary it's obviously just total / total_records.
Can anyone help me out with this?
You could try something like this:
SELECT strftime('%W', thedate) theweek, avg(total) theaverage
FROM table GROUP BY strftime('%W', thedate)
I'm not sure how the syntax would work in SQLite, but one way would be to parse out the date parts of each [date] field, and then specifying which WEEK and DAY boundaries in your WHERE clause and then GROUP by the week. This will give you a true average regardless of whether there are rows or not.
Something like this (using T-SQL):
SELECT DATEPART(w, theDate), Avg(theAmount) as Average
FROM Table
GROUP BY DATEPART(w, theDate)
This will return a row for every week. You could filter it in your WHERE clause to restrict it to a given date range.
Hope this helps.
Your weekly average is
daily * 7
Obviously this doesn't take in to account specific weeks, but you can get that by narrowing the result set in a date range.
You'll have to omit those records in the addition which don't belong to a full week. So, prior to summing up, you'll have to find the min and max of the dates, manipulate them such that they form "whole" weeks, and then run your original query with a WHERE that limits the date values according to the new range. Maybe you can even put all this into one query. I'll leave that up to you. ;-)
Those values which are "truncated" are not used then, obviously. If there's not enough values for a week at all, there's no result at all. But there's no solution to that, apparently.