Total hours worked for employees in 2018 and 2019 - sql

I am new to stackoverflow and new to sql. I have employee timesheets which has a unique id and hours works by employees. I was wondering if theres a way to calculate the sum of the hours for each employee in 2018.
I dont know if this query is too basic but what i have so far is this:
select distinct PersonId, SUM(reghours) as '2018'
from TimeSheetsView
where left(yearweek,4)='2018'
group by PersonId, reghours

If you wanted to sum up both 2018 and 2019 in their own columns you could use a case statement to target those specific records in 2018 and 2019 placing them in their own column. You don't need a distinct with the group by either and like Mitch said you don't need that reghours it will split aggregation.
In the THEN piece it will sum up that field and ELSE is 0 so it won't obviously sum up any other rows that don't meet that condition.
Select PersonId
, SUM(CASE WHEN left(yearweek,4)='2018' THEN reghours ELSE 0 END) as '2018_RegHours'
, SUM(CASE WHEN left(yearweek,4)='2019' THEN reghours ELSE 0 END) as '2019_RegHours'
from TimeSheetsView
where left(yearweek,4) IN ('2018', '2019')
group by PersonId

Related

SQL help to display no. of openings for all branches for each month of a year

Hi I need to generate a SSRS report to show how many centers got opened for each month in a calendar year under each branch. report will have 13 columns, first column being all the branches in each row and remaining 12 columns will have months of an year as header. I'm trying to get a result of each branch having no. of openings per month, so I can feed SSRS to display in tabular format. If a branch doesnt have any openings for any month, I need to display 0.
Branch table
=============
Branchid
Branchname
CenterOpen table
================
CenterOpenID
BranchID
CenterOpenDate
below is the SQL I had written
WITH months(MonthNumber) AS (
SELECT
1
UNION ALL
SELECT
MonthNumber + 1
FROM
months
WHERE
MonthNumber < 12
),
cteBranch(BranchID, BranchName, TargetOpenDate, Month, Count) as (
SELECT
B.BranchID,
B.BranchName,
CS.TargetOpenDate,
MONTH(CS.TargetOpenDate) as Month,
count(Month(CS.TargetOpenDate)) as Count
FROM
Branch B
left join goal.CenterOpenSchedule CS ON CS.BranchID = B.BranchID
GROUP BY
B.BranchID,
B.BranchName,
CS.TargetOpenDate,
MONTH(CS.TargetOpenDate)
)
select
*
from
months
cross join cteBranch
order by
BranchID asc,
MonthNumber asc
If I use cross join, months are repeating for each branch, how to resolve this? your help is highly appreciated.
Not sure which database you are on.
There are different ways to extract month/year from date.
Based on your example SQL, I'm going to use MONTH()
select branchName,
count(case when month(centerOpenDate) = 1 then branchId end) Jan_Count
...
...
count(case when month(centerOpenDate) = 12 then branchId end) Dec_Count
from Branch b
join CenterOpen co
on (b.BranchId = co.BranchId)
where year(centerOpenDate) = <your year filter>
group by branchName
This will take care of your below requirements:
" first column being all the branches in each row and remaining 12 columns will have months of an year as header."
and also -
"If a branch doesnt have any openings for any month, I need to display 0."
Your question is not explicit, but you seem to want a single year -- so you need to filter on the year.
The rest is basically conditional aggregation:
select b.branchName,
sum(case when month(co.centerOpenDate) = 1 then 1 else 0 end) as jan,
sum(case when month(co.centerOpenDate) = 2 then 1 else 0 end) as feb,
. . .
sum(case when month(co.centerOpenDate) = 12 then 1 else 0 end) as dec
from Branch b join
CenterOpen co
on b.BranchId = co.BranchId
where year(co.centerOpenDate) = #year
group by b.branchName

How to get the asked columns for each customers

I have this table called table a
I need to get the CustomerID, sum(Income) of 2015, sum(Income) of 2016, did he ever bought productId A (boolean), is the total sum(income)> 1000 (boolean), number of total InvoiceID
all that in one query and the results should be with 1 row per customer.
please help I don't even know how to start!
This is basically conditional aggregation:
select customerid,
sum(case when extract(year from date) = 2015 then sales end) as sales_2015,
sum(case when extract(year from date) = 2016 then sales end) as sales_2016,
max( product = 'A' ) as ever_bought_a,
sum(income) > 1000 as sum_exceeds_1000,
count(*) as num_invoices
from t
group by customerid;
You haven't specified a database, so this is really psuedocode. You'll need to adapt it for your particular database.

SQL count records depending on criteria

I have a table which has account information for each individual working day. Each record shows the balance on the account for that particular day. I need to create a field that has a running count on how many days it has been since the balance on that particular account was zero.
For example: I have an account which is number 00000001. It was opened a week ago. The database has created a record for the account for last Tuesday, Wednesday, Thursday, Friday and Monday. The account did not have a balance until Friday and the balance was the same for Monday. I want the field to show '2' as a result. Further to this if the balance drops to '0' today, I need the count to reset on the next record and start again if the account has a balance the following day. There are several accounts in this table so I need this to work for each one individually.
Below is as far as I have got:
SELECT
pos.EffDate,
cus.CNA1,
pos.ACNO,
pos.CCY,
pos.LDBL,
pos.LDBLUSD,
MIN(pos3.effdate) AS 'First Post Date',
pos3.Balcount
FROM[dbo].[Account] AS pos
JOIN [dbo].[Customer] AS cus ON ((pos.CNUM=cus.CUST_NO) AND (cus.effdate=pos.effdate))
LEFT JOIN (SELECT pos2.effdate, pos2.ACNO, SUM(CASE pos2.LDBL WHEN 0 THEN 0 ELSE 1 END) AS 'Balcount' FROM [dbo].[Account] AS pos2 GROUP BY pos2.ACNO, pos2.Effdate HAVING pos2.effdate BETWEEN pos2.effdate AND MIN(pos2.effdate)) pos3 ON pos3.ACNO = pos.ACNO
WHERE pos.effdate >='1 Dec 2015' AND pos.Effdate <'30 Dec 2015'
AND pos.srcsys = 'MP_UK'
AND pos.LDBL <= 0
AND pos.CNUM <> '000020'
AND pos.intbear <> 'N'
AND pos.blockdeb IS null
GROUP BY pos.EffDate,cus.CNA1,pos.ACNO,pos.CCY,pos.LDBL,pos.LDBLUSD, pos3.Balcount
ORDER BY 1,2,3
If you need me to clarify anything please let me know. All help is greatly appreciated.
Thanks,
Ben
Basically, you want to group the data, based on the number of time the account is zero before a given row. Then, within each group, you want to enumerate the records.
In SQL Server 2012+, you can do these things with window functions. I am not sure exactly what your sample query has to do with the question, but here is the basic idea:
select a.*, row_number() over (partition by cust_no, grp order by eff_date) as seqnum
from (select a.*,
sum(case when balance = 0 then 1 else 0 end) over
(partition by cust_no order by eff_date) as grp
from Account a
) a;
In earlier versions of SQL Server, you can do something very similar using apply.

T-SQL query to select last 3 months of data, last years month, averages of this month and average of all months

I have a table with columns Category, Date, Monthly_Revenue.
I need a query that will select Todays_Month, Last_Month, 2 months prior, Last_years_Month, average of today's month, average of all months.
This query is needed grouped by category.
Example :
Category | Sept, 2012 | Aug, 2012| Jul, 2012 | Sept, 2011 | Average of Sept | Avg all Mo
Being fairly new to SQL I still haven't got it yet. I figured see if somebody out there could take a crack at it. Thanks.
Sample data
'Burger' '9/1/2012' '500'
'Fries' '10/1/2012 '300'
'Burger' '6/1/2011' '250'
you need something along these lines .Not the optimum solution but will give you a start
.This is a static solution but it looks like you may want a dynamic solution
*not tested
SELECT
Category
,[Sep 2012]=SUM(CASE WHEN YEAR(TranDate)= YEAR(GETDATE()) AND MONTH(TranDate)= MONTH(GETDATE()) THEN Amount ELSE NULL END)
,[Aug 2012]=SUM(CASE WHEN YEAR(TranDate)= YEAR(DATEADD(month,-1,GETDATE())) AND MONTH(TranDate)= MONTH(DATEADD(month,-1,GETDATE())) THEN Amount ELSE NULL END)
,[Jul 2012]=SUM(CASE WHEN YEAR(TranDate)= YEAR(DATEADD(month,-2,GETDATE())) AND MONTH(TranDate)= MONTH(DATEADD(month,-2,GETDATE())) THEN Amount ELSE NULL END)
,[AVG Sep 2012]=AVG(CASE WHEN YEAR(TranDate)= YEAR(GETDATE()) AND MONTH(TranDate)= MONTH(GETDATE()) THEN Amount ELSE NULL END)
,[AVG 12 months]=AVG(CASE WHEN TranDatee > CAST(DATEADD(year,-1,GETDATE()) AS DATE) THEN Amount ELSE NULL END)/12
FROM Table1
GROUP BY Category,Amount

Sql query for monthly/yearly report

I have got a Sales table which has fields like
upgrade[yes/no]
date upgraded[datetime]
user[username]
What I want to run a query and show upgrades monthly and yearly wise , for instance i want to generate a report like Jan 2012 [total upgrades made 30, user1 made 10 upgrades , user 2 made 15 upgrades, similarly
user 3 made 5 upgrades. Similarly I want to acheive that for yearly basis too.
Using SSRS, you could generate multiple groupings fairly easily and display all of this information at-a-glance.
In a vanilla T-SQL query, you can do it like this:
SELECT
YEAR(s.[date upgraded]),
s.[user],
COUNT(*) AS [total upgrades]
FROM [Sales] s
WHERE s.[upgrade] = 'yes'
GROUP BY s.[user], YEAR(s.[date upgraded]) WITH ROLLUP
ORDER BY YEAR(s.[date upgraded]), s.[user]
SELECT
MONTH(s.[date upgraded]),
s.[user],
COUNT(*) AS [total upgrades]
FROM [Sales] s
WHERE s.[upgrade] = 'yes'
GROUP BY s.[user], MONTH(s.[date upgraded]) WITH ROLLUP
ORDER BY MONTH(s.[date upgraded]), s.[user]
SELECT USERNAME,
CONVERT(CHAR(7), DATE_FIELD,120) AS MONTH,
SUM(CASE WHEN UPGRADE = 'YES' THEN 1 ELSE 0 END) UPGRADED
FROM TABLE
GROUP BY USERNAME, CONVERT(CHAR(7), DATE_FIELD,120)