I have a large access table that I need to pull specific data from with a query.
I need to get a list of all the IDs that meet a specific criteria, i.e. 3 months in a row with a cage number less than 50.
The SQL code I'm currently working with is below, but it only gives me which months of the past 3 had a cage number below 50.
SELECT [AbBehWeeklyMonitor Database].AnimalID, [AbBehWeeklyMonitor Database].Date, [AbBehWeeklyMonitor Database].Cage
FROM [AbBehWeeklyMonitor Database]
WHERE ((([AbBehWeeklyMonitor Database].Date)>=DateAdd("m",-3,Date())) AND (([AbBehWeeklyMonitor Database].Cage)<50))
ORDER BY [AbBehWeeklyMonitor Database].AnimalID DESC;
I would need it to look at the past 3 months for each ID, and only output if all 3 met the specific criteria, but I'm not sure where to go from here.
Any help would be appreciated.
Data Sample:
Date
AnimalID
Cage
6/28/2022
12345
50
5/19/2021
12345
32
3/20/2008
12345
75
5/20/2022
23569
4
8/20/2022
23569
4
5/20/2022
44444
71
8/1/2012
44444
4
4/1/2022
78986
30
1/20/2022
78986
1
9/14/2022
65659
59
8/10/2022
65659
48
7/14/2022
65659
30
6/14/2022
95659
12
8/14/2022
91111
51
7/14/2022
91111
5
6/14/2022
91111
90
8/14/2022
88888
4
7/14/2022
88888
5
6/14/2022
88888
15
Consider:
Query1:
SELECT AnimalID, Count(*) AS Cnt
FROM Table1
WHERE (((Cage)<50) AND (([Date]) Between #6/1/2022# And #8/31/2022#))
GROUP BY AnimalID
HAVING (((Count(*))=3));
Query2
SELECT Table1.*
FROM Query1 INNER JOIN Table1 ON Query1.AnimalID = Table1.AnimalID
WHERE ((([Date]) Between #6/1/2022# And #8/31/2022#));
Output:
Date AnimalID Cage
6/14/2022 65659 12
7/14/2022 65659 30
8/10/2022 65659 48
6/14/2022 88888 15
7/14/2022 88888 5
8/14/2022 88888 4
Date is a reserved word and really should not use reserved words as names.
Related
I am having difficulty figuring out this dang problem. From the data and queries I have given below I am trying to see the email address that has rented the most movies during the month of September.
There are only 4 relevant tables in my database and they have been anonymized and shortened:
Table "cust":
cust_id
f_name
l_name
email
1
Jack
Daniels
jack.daniels#google.com
2
Jose
Quervo
jose.quervo#yahoo.com
5
Jim
Beam
jim.beam#protonmail.com
Table "rent"
inv_id
cust_id
rent_date
10
1
9/1/2022 10:29
11
1
9/2/2022 18:16
12
1
9/2/2022 18:17
13
1
9/17/2022 17:34
14
1
9/19/2022 6:32
15
1
9/19/2022 6:33
16
3
9/1/2022 18:45
17
3
9/1/2022 18:46
18
3
9/2/2022 18:45
19
3
9/2/2022 18:46
20
3
9/17/2022 18:32
21
3
9/19/2022 22:12
10
2
9/19/2022 11:43
11
2
9/19/2022 11:42
Table "inv"
mov_id
inv_id
22
10
23
11
24
12
25
13
26
14
27
15
28
16
29
17
30
18
31
19
31
20
32
21
Table "mov":
mov_id
titl
rate
22
Anaconda
3.99
23
Exorcist
1.99
24
Philadelphia
3.99
25
Quest
1.99
26
Sweden
1.99
27
Speed
1.99
28
Nemo
1.99
29
Zoolander
5.99
30
Truman
5.99
31
Patient
1.99
32
Racer
3.99
and here is my current query progress:
SELECT cust.email,
COUNT(DISTINCT inv.mov_id) AS "Rented_Count"
FROM cust
JOIN rent ON rent.cust_id = cust.cust_id
JOIN inv ON inv.inv_id = rent.inv_id
JOIN mov ON mov.mov_id = inv.mov_id
WHERE rent.rent_date BETWEEN '2022-09-01' AND '2022-09-31'
GROUP BY cust.email
ORDER BY "Rented_Count" DESC;
and here is what it outputs:
email
Rented_Count
jack.daniels#google.com
6
jim.beam#protonmail.com
6
jose.quervo#yahoo.com
2
and what I want it to be outputting:
email
jack.daniels#google.com
jim.beam#protonmail.com
From the results I am actually getting I have a tie for first place (Jim and Jack) and that is fine but I would like it to list both tieing email addresses not just Jack's so you cant do anything with rows or max I don't think.
I think it must have something to do with dense_rank but I don't know how to use that specifically in this scenario with the count and Group By?
Your creativity and help would be appreciated.
You're missing the FETCH FIRST ROWS WITH TIES clause. It will work together with the ORDER BY clause to get you the highest values (FIRST ROWS), including ties (WITH TIES).
SELECT cust.email
FROM cust
INNER JOIN rent
ON rent.cust_id = cust.cust_id
INNER JOIN inv
ON inv.inv_id = rent.inv_id
INNER JOIN mov
ON mov.mov_id = inv.mov_id
WHERE rent.rent_date BETWEEN '2022-09-01' AND '2022-09-31'
GROUP BY cust.email
ORDER BY COUNT(DISTINCT inv.mov_id) DESC
FETCH FIRST 1 ROWS WITH TIES
I have a table named orders in a Postgres database that looks like this:
customer_id order_id order_date price product
1 2 2021-03-05 15 books
1 13 2022-03-07 3 music
1 14 2022-06-15 900 travel
1 11 2021-11-17 25 books
1 16 2022-08-03 32 books
2 4 2021-04-12 4 music
2 7 2021-06-29 9 music
2 20 2022-11-03 8 music
2 22 2022-11-07 575 travel
2 24 2022-11-20 95 food
3 3 2021-03-17 25 books
3 5 2021-06-01 650 travel
3 17 2022-08-17 1200 travel
3 19 2022-10-02 6 music
3 23 2022-11-08 70 food
4 9 2021-08-20 3200 travel
4 10 2021-10-29 2750 travel
4 15 2022-07-15 1820 travel
4 21 2022-11-05 8000 travel
4 25 2022-11-29 27 books
5 1 2021-01-04 3 music
5 6 2021-06-09 820 travel
5 8 2021-07-30 19 books
5 12 2021-12-10 22 music
5 18 2022-09-19 20 books
Here's a SQL Fiddle: http://sqlfiddle.com/#!17/262fc/1
I'd like to return the average money spent by customers per product, but only consider orders within the first 12 months of a given customer's first purchase within the given product group. (yes, this is challenging!)
For example, for customer 1, order ID 2 and order ID 11 would be factored into the average for books(because order ID 11 took place less than 12 months after customer 1's first order for books, which was order ID 2), but order ID 16 would not be factored into the average (because 8/3/22 is more than 12 months from customer 1's first purchase for books, which took place on 3/5/21).
Here is a matrix showing which orders would be included within a given product (denoted by "yes"):
The desired output would look as follows:
average_spent
books 22.20
music 7.83
travel 1530.71
food 82.50
How would I do this?
Thanks in advance for any assistance you can give!
You can use a subquery to check whether or not to include a product's price in the summation:
select o.product, sum(o.price)/count(*) val from orders o
where o.order_date < (select min(o1.order_date) from orders o1 where
o1.product = o.product and o.user_id = o1.user_id) + interval '12 months'
group by o.product
See fiddle
I have a problem with my BigQuery select, I need to get the max value for the column (students) for each day.
SELECT EXTRACT(DATE FROM timestamp) as date, ARRAY_LENGTH(student_ids) as students from analytics.daily_active_students_count order by timestamp desc
Row
Date
Students
1
2022-05-16
72
2
2022-05-16
33
3
2022-05-16
12
4
2022-05-15
10
5
2022-05-15
84
6
2022-05-15
8
7
2022-05-14
92
8
2022-05-14
105
9
2022-05-14
12
Query should remove duplicated rows for days and take only rows with max number of students.
I want my output looks like this:
Row
Date
Students
1
2022-05-16
72
2
2022-05-15
84
3
2022-05-14
105
Problem was that my backend used different timezone. I solved this issue with casting timestamp:
DATE(DATETIME(TIMESTAMP, "Europe/Zagreb")) as date
I have a count of a top 2
My table has this data
Name Age price visited size
Jon 34 53 2018-01-01 9
Don 22 70 2018-03-01 15
Pete 76 12 2018-11-09 7
Jon 34 55 2018-09-13 9
Paul 90 64 2018-07-08 6
Pete 76 31 2018-03-25 7
Jon 75 34 2018-06-06 8
select top 2
name,
count(name) as cnt
from
tbl1
group by name
order by cnt desc
Which returns my top 2 names
Jon 3
Pete 2
This name will change dynamically as the query is run depending on who has made the most visits in total (this is very simplified the actual table has 1000's of entries).
What I would like to do is then use the result of that query to get the following all of which needs to be in a single query;
Name Age price visited size
Jon 34 53 2018-01-01 9
Jon 34 55 2018-09-13 9
Jon 75 34 2018-06-06 8
Pete 76 12 2018-11-09 7
Pete 76 31 2018-03-25 7
In summary, count who has visited the most and then display all the records under those names.
Thanks in advance
Here's one option using in:
select *
from yourtable
where name in (
select top 2 name
from yourtable
group by name
order by count(*) desc
)
order by name
Online Demo
I have a data table that has annual data points and quarterly data points. I want to subtract the quarterly data points from the corresponding prior annual entry, e.g. Annual 2014 - Q3 2014, using t-SQL. I have an id variable for each entry, plus a reconcile id variable that shows which quarterly entry corresponds to which annual entry. See below:
CurrentDate PreviousDate Value Entry Id Reconcile Id Annual/Quarterly
9/30/2012 9/30/2011 112 2 3 Annual
9/30/2013 9/30/2012 123 1 2 Annual
9/30/2014 9/30/2013 123.5 9 1 Annual
12/31/2013 9/30/2014 124 4 1 Quarterly
3/31/2014 12/31/2013 124.5 5 1 Quarterly
6/30/2014 3/31/2014 125 6 1 Quarterly
9/30/2014 6/30/2014 125.5 7 1 Quarterly
12/31/2014 9/30/2014 126 10 9 Quarterly
3/31/2015 12/31/2014 126.5 11 9 Quarterly
6/30/2015 3/31/2015 127 12 9 Quarterly
For example, Reconcile ID 9 for the quarterly entries corresponds to Entry ID 9, which is an annual entry.
I have code to just subtract the prior entry from the current entry, but I cannot figure out how to subtract quarterly entries from annual entries where the Entry ID and Reconcile ID are the same.
Here is the code I am using, which is resulting in the right calculation, but increasing the number of results by many rows. I have also tried this as an inner join. I only want the original 10 rows, plus a new difference column:
SELECT DISTINCT T1.[EntryID]
, [T1].[RECONCILEID]
, [T1].[CurrentDate]
, [T1].[Annual_Quarterly]
, [T1].[Value]
, [T1].[Value]-T2.[Value] AS Difference
FROM Table T1
LEFT JOIN Table T2 ON T2.EntryID = T1.RECONCILEID;
Your code should be fine, here's the results I'm getting:
EntryId Annual_Quarterly CurrentDate ReconcileId Value recVal diff
2 Annual 9/30/2012 3 112
1 Annual 9/30/2013 2 123 112 11
9 Annual 9/30/2014 1 123.5 123 0.5
4 Quarterly 12/31/2013 1 124 123 1
5 Quarterly 3/31/2014 1 124.5 123 1.5
6 Quarterly 6/30/2014 1 125 123 2
7 Quarterly 9/30/2014 1 125.5 123 2.5
10 Quarterly 12/31/2014 9 126 123.5 2.5
11 Quarterly 3/31/2015 9 126.5 123.5 3
12 Quarterly 6/30/2015 9 127 123.5 3.5
with your data and this SQL:
SELECT
tr.EntryId,
tr.Annual_Quarterly,
tr.CurrentDate,
tr.ReconcileId,
tr.Value,
te.Value AS recVal,
tr.[VALUE]-te.[VALUE] AS diff
FROM
t AS tr LEFT JOIN
t AS te ON
tr.ReconcileId = te.EntryId
ORDER BY
tr.Annual_Quarterly,
tr.CurrentDate;
Your question is a bit vague as far as how you're wanting to subtract these values, but this should give you some idea.
Select T1.*, T1.Value - Coalesce(T2.Value, 0) As Difference
From Table T1
Left Join Table T2 On T2.[Entry Id] = T1.[Reconcile Id]