Hello i am Working Push Notification with the help of this https://github.com/zo0r/react-native-push-notification my notification is working fine but i want to navigate the the screen when i tap on notification ! my notifiaction working fine please help me out with any suggestion i used stack navigator in my routes
onNotification: function (notification) {
console.log("NOTIFICATIONss:", notification);
if (notification.userInteraction) {
console.log("Clicked on Notification"). // here i clicked on notification
this.props.navigation.push("Home"). // here i want navigation
}
if (!notification.userInteraction) {
PushNotification.localNotification({
foreground:false,
channelId: notification.channelId,
channelName: "xShare", //
title: notification.title,
message: notification.message,
largeIconUrl: notification.smallIcon,
onOpen: () => { this.props.navigation.navigate("ActiveNeed") },//nothing working
})
notification.finish(PushNotificationIOS.FetchResult.NoData);
}
},`
If your app is opened through clicking on the notification bubble, the navigation props should be unavailable when the onNotification() function runs.
Therefore, please create a navigation reference for the app. You may follow the guidelines by React-Navigation for more details.
https://reactnavigation.org/docs/navigating-without-navigation-prop
You can use the following code for navigation in onNotification() after you added the navigation-reference.
import * as RootNavigation from './path/to/RootNavigation.js';
RootNavigation.navigate('TargetPage', { someParams: 'someValue' });
Related
I setup notification system with firebase and react native. It's working fine, but when i receive notification in any state of app(killed, fore or background) and do click notification push me to home screen. I want to go on notification screen when someone click on notification.
How it will possible?
First, you have to add a Firebase Notification listener at the top-level component. I'll suggest placing it in App.js.
Foreground Listener
Background Listener
After that, You have to navigate to a particular screen with the help of a navigation prop. if you place the listener at App.js then you will not have access to the navigation prop since App.js will return the navigation container.
For that, you have to create one helper function like this navigation without prop
e.g.
export const App = () => {
messaging().setBackgroundMessageHandler(async remoteMessage => {
navigate('Notification'); //navigate to notification screen
});
const unsubscribe = messaging().onMessage(async remoteMessage => {
//generate local notification using your preferred library
//handle navigation
})
return <RootNavigator />;
};
I am working on react native application and my requirement is to launch specific screen on Notification received.
Notification is working fine in all state i.e. Foreground or background.
I am using below library:
react-navigation
#react-native-firebase/messaging
react-native-push-notification
Below is the code for handling notification :
messaging().setBackgroundMessageHandler(async remoteMessage => {
console.log('Message handled in the background!', remoteMessage);
let text = {
title: remoteMessage.data.title,
body: remoteMessage.data.body,
}
notif.cancelAll();
notif.localNotif(text);
NavigationService.navigate('Contact', { userName: 'Lucy' })
});
Also wrote a navigation code on notification received method referring
https://reactnavigation.org/docs/4.x/navigating-without-navigation-prop
I can see app navigate to particular screen but its not launching app.
Can anyone help me with this?
I'm using this package for implementing local push notification:
https://github.com/zo0r/react-native-push-notification
I'm using action button like this to show buttons in my notification along with a text and a title:
PushNotification.localNotification({
...
actions: '["Yes", "No"]'
})
I wanted to know how I can call a function when user clicks on of these actions and app becomes visible?
I've tried PushNotification.configure in my componentDidMount method in my home screen like this but nothing comes up in the console:
PushNotification.configure({
// (required) Called when a remote or local notification is opened or received
onNotification: function(notification) {
console.log("NOTIFICATION:", notification);
if (notification.userInteraction) {
console.log("NOTIFICATION:");
}
// process the notification
}
});
I got it working.
In your App.js you need to set popInitialNotification to true. Something like this:
async componentDidMount() {
PushNotification.configure({
// (required) Called when a remote or local notification is opened or received
onNotification: function(notification) {
console.log("NOTIFICATION:", notification.action);
},
// IOS ONLY (optional): default: all - Permissions to register.
permissions: {
alert: true,
badge: true,
sound: true
},
// Should the initial notification be popped automatically
// default: true
popInitialNotification: true,
/**
* (optional) default: true
* - Specified if permissions (ios) and token (android and ios) will requested or not,
* - if not, you must call PushNotificationsHandler.requestPermissions() later
*/
requestPermissions: true
});
}
notification.action will gibe you the label of the button clicked.
In your button/app active event you forgot to call to schedule the notification and actually set when it will arise, so you need to
PushNotification.localNotificationSchedule(details: Object)
Schedule it for now with the same id, then your notification will come up immediately.
See all options for scheduling here
import PushNotificationAndroid from 'react-native-push-notification'
(function() {
// Register all the valid actions for notifications here and add the action handler for each action
PushNotificationAndroid.registerNotificationActions(['Accept','Reject','Yes','No']);
DeviceEventEmitter.addListener('notificationActionReceived', function(action){
console.log ('Notification action received: ' + action);
const info = JSON.parse(action.dataJSON);
if (info.action == 'Accept') {
// Do work pertaining to Accept action here
} else if (info.action == 'Reject') {
// Do work pertaining to Reject action here
}
// Add all the required actions handlers
});
})();
DO NOT USE .configure() INSIDE A COMPONENT, EVEN App
If you do, notification handlers will not fire, because they are not loaded. Instead, use .configure() in the app's first file, usually index.js.
It's mentioned in the documentation.
Try to follow their example for implementation It will help you to setup in your project.
I have integrated with OneSignal in my app for push notification, right now I need to handle when user click on the notification.
When user click on the notification, App have to go to screen that have defined in OneSignal but instead of immediately go to defined screen, it land on main screen until receiving event from OneSignal (onOpened event) complete.
constructor(props) {
super(props);
OneSignal.addEventListener('received', this.onReceived);
OneSignal.addEventListener('opened', this.onOpened);
OneSignal.addEventListener('ids', this.onIds);
}
onOpened(openResult) {
const data = openResult.notification.payload.additionalData;
if(data.screen) {
navigationService.navigate(data.screen);
}
}
Do we have any way to let it go direct to defined screen? Thanks
You can use componentWillmount
componentWillmount(openResult) {
this.onOpened(openResult);
}
I am using react native v0.45.1.
How can I add to my application notification (no matter if the app is in the background or foreground) that the user can remove only after click an acknowledge button.
I don't want the user to swipe the notification aside without notice it.
how can it be done?
I am not sure https://github.com/wix/react-native-notifications will do what I need.
Edit
I want to have a notification that will act like:
'USB debugging connected
'Touch to disable USB debugging'
The notification can't be removed unless the user actively do something, in my case it will be 'click' on a button
after a lot of digging the solution I implemented was:
setting repeat interval for the notification.
for android:
repeatType: 'time',
repeatTime: timeSpan,
for iOS:
repeatType: 'minute',
when the user click the notification (decided its not the right approached to add actions - buttons - to notification):
PushNotification.configure({
onNotification: (notification) => {
console.log('NOTIFICATION:', notification);
const clicked = notification.userInteraction;
if (clicked) {
if (Platform.OS === 'ios') {
PushNotification.cancelLocalNotifications({ id: notification.data.id });
} else {
PushNotification.cancelLocalNotifications({ id: notification.id });
}
}
},
});
I am aware that this might not be the exact answer to this question. However,
I was looking for a similar solution earlier; how to remove notifications that hasn't been dismissed or opened by a user.
Sometimes the user might open the application / screen, without clicking on the notification. The notification will still be displayed in that case.
Using React Native with Expo, this is the solution I created for removing old notifications created using their Push Notification API.
import * as Notifications from "expo-notifications";
//...
// Remove notifications that exists for this conversation!
useEffect(() => {
Notifications.getPresentedNotificationsAsync().then(res => {
for (let k in res) {
if (
res[k].request.content.data &&
res[k].request.content.data.screen === "Conversations" &&
res[k].request.content.data.conversationId === conversationId
) {
Notifications.dismissNotificationAsync(res[k].request.identifier);
console.log("removed a notification for this conversation");
}
}
});
}, []);
By using the data sent to the Push Notification API, we can determine which notifications should be removed. in this case all notifications containing a conversationId matching the current value from the route are dismissed.