Google BigQuery Standard SQL get weight summarize result by group - sql

Question

Original data
structure(list(Year = c(1999, 1999, 1999, 2000, 2000, 2000),
Country = c("a", "b", "b", "a", "a", "b"), number = c(2,
3, 4, 5, 3, 6), result = c(2, 4, 5, 6, 2, 2)), class = c("tbl_df",
"tbl", "data.frame"), row.names = c(NA, -6L))
What I need is
Year Country weightresult
weightresult=result*(number/sum(number_year,country))
with weight result by number and the sum number is according to Year,Country group
the process result is
tructure(list(Year = c(1999, 1999, 1999, 2000, 2000, 2000),
Country = c("a", "b", "b", "a", "a", "b"), number = c(2,
3, 4, 5, 3, 6), result = c(2, 4, 5, 6, 2, 2), weight = c(2,
7, 7, 8, 8, 6), wre = c(2, 1.71428571428571, 2.85714285714286,
3.75, 0.75, 2)), row.names = c(NA, -6L), class = c("tbl_df",
"tbl", "data.frame"))
Finally need is
structure(list(Country = c("a", "a", "b", "b"), Year = c(1999,
2000, 1999, 2000), wre = c(2, 4.5, 4.57142857142857, 2)), class = c("tbl_df",
"tbl", "data.frame"), row.names = c(NA, -4L))
How to get the finally result in Bigquery Standard SQL
SELECT
Year,
Country,
(number/(SUM(number) OVER (PARTITION BY Year, Country))) * result AS wre,
Count(*),
FROM `table`
Where
Year<=2020
GROUP BY Year,Country
ORDER BY Year,Country
And the error is
SELECT list expression references column number which is neither grouped nor aggregated at ...

Answer 1

Use below
select
year,
country,
sum(number * result) / sum(number) as weighted_result
from your_table
where year <= 2020
group by year,country
order by year,country
with output