Counting nulls for each column in table - sql

Question

We want to count how many nulls each column in a table has. There are too many columns to do this one by one, so the following PLSQL procedure was created.
In the first part of the procedure, all column names are obtained. This works, as the dbms_output correctly lists them all.
Secondly, a query inserts the count of null values in the variable 'nullscount'. This part does not work, as the output printed for this variable is always 0, even for columns where we know there are nulls.
Does anyone know how to handle the second part correctly?
Many thanks.
CREATE OR REPLACE PROCEDURE COUNTNULLS AS
nullscount int;
BEGIN
for c in (select column_name from all_tab_columns where table_name = upper('gp'))
loop
select count(*) into nullscount from gp where c.column_name is null;
dbms_output.put_line(c.column_name||' '||nullscount);
end loop;
END COUNTNULLS;

Answer 1

You can get it with just one query like this: this query scans table just once:
DBFiddle: https://dbfiddle.uk/asgrCezT
select *
from xmltable(
'/ROWSET/ROW/*'
passing
dbms_xmlgen.getxmltype(
(
select
'select '
||listagg('count(*)-count("'||column_name||'") as "'||column_name||'"',',')
||' from '||upper('gp')
from user_tab_columns
where table_name = upper('gp')
)
)
columns
column_name varchar2(30) path './name()',
cnt_nulls int path '.'
);
Results:
COLUMN_NAME CNT_NULLS
------------------------------ ----------
A 5
B 4
C 3
Dynamic sql in this query uses (24 chars + column name length) so it should work fine for example for 117 columns with average column name length = 10. If you need more, you can rewrite it a bit, for example:
select *
from xmltable(
'let $cnt := /ROWSET/ROW/CNT
for $r in /ROWSET/ROW/*[name() != "CNT"]
return <R name="{$r/name()}"> {$cnt - $r} </R>'
passing
dbms_xmlgen.getxmltype(
(
select
'select count(*) CNT,'
||listagg('count("'||column_name||'") as "'||column_name||'"',',')
||' from '||upper('gp')
from user_tab_columns
where table_name = upper('gp')
)
)
columns
column_name varchar2(30) path '#name',
cnt_nulls int path '.'
);

Answer 2

create table gp (
id number generated by default on null as identity
constraint gp_pk primary key,
c1 number,
c2 number,
c3 number,
c4 number,
c5 number
)
;
-- add some data with NULLS and numbers
DECLARE
BEGIN
FOR r IN 1 .. 20 LOOP
INSERT INTO gp (c1,c2,c3,c4,c5) VALUES
(CASE WHEN mod(r,2) = 0 THEN NULL ELSE mod(r,2) END
,CASE WHEN mod(r,3) = 0 THEN NULL ELSE mod(r,3) END
,CASE WHEN mod(r,4) = 0 THEN NULL ELSE mod(r,4) END
,CASE WHEN mod(r,5) = 0 THEN NULL ELSE mod(r,5) END
,5);
END LOOP;
END;
/
-- check what is in the table
SELECT * FROM gp;
-- do count of each column
DECLARE
l_colcount NUMBER;
l_statement VARCHAR2(100) := 'SELECT COUNT(*) FROM $TABLE_NAME$ WHERE $COLUMN_NAME$ IS NULL';
BEGIN
FOR r IN (SELECT column_name,table_name FROM user_tab_columns WHERE table_name = 'GP') LOOP
EXECUTE IMMEDIATE REPLACE(REPLACE(l_statement,'$TABLE_NAME$',r.table_name),'$COLUMN_NAME$',r.column_name) INTO l_colcount;
dbms_output.put_line('Table: '||r.table_name||', column'||r.column_name||', COUNT: '||l_colcount);
END LOOP;
END;
/
Table created.
Statement processed.
Result Set 4
ID C1 C2 C3 C4 C5
1 1 1 1 1 5
2 - 2 2 2 5
3 1 - 3 3 5
4 - 1 - 4 5
5 1 2 1 - 5
6 - - 2 1 5
7 1 1 3 2 5
8 - 2 - 3 5
9 1 - 1 4 5
10 - 1 2 - 5
11 1 2 3 1 5
12 - - - 2 5
13 1 1 1 3 5
14 - 2 2 4 5
15 1 - 3 - 5
16 - 1 - 1 5
17 1 2 1 2 5
18 - - 2 3 5
19 1 1 3 4 5
20 - 2 - - 5
20 rows selected.
Statement processed.
Table: GP, columnID, COUNT: 0
Table: GP, columnC1, COUNT: 10
Table: GP, columnC2, COUNT: 6
Table: GP, columnC3, COUNT: 5
Table: GP, columnC4, COUNT: 4
Table: GP, columnC5, COUNT: 0

Answer 3

c.column_name is never null because it's the content of the column "column_name" of the table "all_tab_columns"
not the column of which name is the value of c.column_name, in table gp.
You have to use dynamic query and EXECUTE IMMEDIATE to achieve what you want.