extract nested values as a list - sql

Question

I have a table with a column "TAGS". Each row in this column has a bunch of dictionaries separated by commas. It looks like this:
{
"id": "334",
"name": "A",
"synonyms": "tul",
"path": [
"179",
"1689",
]
},
{
"id": "8999",
"name": "B",
"synonyms": "hh",
"path": [
"1098",
"167",
]
}
I want to create a new column "NAMES" that contains a list of all names. For example this:
NAMES
["A", "B"]
Select * from TAGS_TABLE
How can I do this?

Answer 1

Well your data is "almost" JSON, so if we convert it to json, we can then parse it, and flatten it:
with data as (
select parse_json('['||column1||']') as json from values
('{
"id": "334",
"name": "A",
"synonyms": "tul",
"path": [
"179",
"1689",
]
},
{
"id": "8999",
"name": "B",
"synonyms": "hh",
"path": [
"1098",
"167",
]
}'),
('{
"id": "334",
"name": "C",
"synonyms": "tul",
"path": [
"179",
"1689",
]
},
{
"id": "8999",
"name": "D",
"synonyms": "hh",
"path": [
"1098",
"167",
]
}')
)
select array_agg(f.value:name) within group (order by f.index) as output
from data d,
lateral flatten(input=>d.json) f
group by f.seq
order by f.seq
gives:
OUTPUT
[ "A", "B" ]
[ "C", "D" ]
REGEXP_SUBSTR_ALL
As already given to you in your other question...
select regexp_substr_all(column1, '"name"\\s*:\\s*"([^"]*)"',1,1,'e') as answer
from data;