Using query results as In clause parameter - sql

Question

I know I've seen this before, but can't come up with the search terms to find it.
I have a CTE returning a comma separated list from the below table:
Table
Create table Table
(
ID Number
, Name varchar2(100)
);
insert all
into Table (ID, Name) values (1, 'Alex')
into Table (ID, Name) values (2, 'Amy')
into Table (ID, Name) values (3, 'Jim')
select * from dual;
ID
Name
1
Alex
2
Amy
3
Jim
select substr(
listagg(Table.ID || ',') within group (order by null)
, 1
, length(listagg(Table.ID || ',') within group (order by null)) - 1
) IDs
from Table
where Name like 'A%'
Which gives me the results: 1,2
I'm trying to use this result in a query's in clause:
with CTE as
(
select substr(
listagg(tbl.ID || ',') within group (order by null)
, 1
, length(listagg(tbl.ID || ',') within group (order by null)) - 1
) IDs
from Table
where Name like 'A%'
)
select *
from Table
where cast(ID as varhcar2(1000)) in (select IDs from CTE) --Use results here
--believe the cast is required to compare, otherwise get a ORA-01722: invalid number
Which I want to return:
ID
Name
1
Alex
2
Amy
How can I use the CTE's resulting IDs string as the parameter of my in clause?

Answer 1

I'm afraid I don't understand your "problem". CTE is really strange; SUBSTR of something? Why? LISTAGG returns the same result anyway. Then you want to ... what? split that result so that you could use it in another query? As if you want to make it as complex as possible (and beyond) to solve something "simple". Therefore: what real problem are you trying to solve?
Anyway, here you go: you'll have to split aggregated string into rows if you want to use it in IN clause:
SQL> with CTE as
2 (select listagg(ID || ',') within group (order by null) IDs
3 from Test
4 where Name like 'A%'
5 )
6 select *
7 from Test
8 where id in (select regexp_substr(IDs, '[^,]+', 1, level)
9 from CTE
10 connect by level <= regexp_count(IDS, ',') + 1
11 );
ID NAME
---------- ----------
1 Alex
2 Amy
SQL>
The same result is returned by a simple
SQL> select *
2 from Test
3 where Name like 'A%';
ID NAME
---------- ----------
1 Alex
2 Amy
SQL>
That's why I asked: what problem are you trying to solve?
[EDIT] As of trailing comma: there's none, at least not any Oracle version I used (11g, 12c, 18cXE, 21cXE):
SQL> select listagg(id, ',') within group (order by null) result from test;
RESULT
------------------------------
1,2,3
SQL> select listagg(name, ',') within group (order by null) result from test;
RESULT
------------------------------
Alex,Amy,Jim
SQL>