Removing text between 2 specific colored brackets - vba

Question

I am trying to create a VBA code for word that will search for a specific colored square bracket and then search for the corresponding closing bracket of that color and delete all text between these 2 colored bracket.
The code will search for a green square opening bracket then search for the green closing bracket and delete everything in between which in this case will be "brown fox". I will then add update the code for the color of the red bracket and have it delete everything between the red bracket. I have found the following code from another question on this site and this does work 90% but i cant get it to search for the specific colored bracket.
I tried
.Format = True + .Font.Color = WdColorRed
but it doesnt pick it up. Any help is appreciated. Thanks
Sub FindSquareBracketPairs()
Dim rngFind As Word.Range
Dim sOpen As String, sClose As String
Dim sFindTerm As String
Dim bFound As Boolean, lPosOpen As Long
Set rngFind = ActiveDocument.Content
sOpen = "["
sClose = "]"
sFindTerm = "\[*\] "
With rngFind.Find
.ClearFormatting
.Text = "\[*\] "
.Forward = True
.Wrap = Word.WdFindWrap.wdFindStop
.MatchWildcards = True
bFound = .Execute
Do While bFound
lPosOpen = NumberOfCharInRange(rngFind, sOpen)
rngFind.Delete
rngFind.Collapse wdCollapseEnd
bFound = .Execute
Loop
End With
End Sub
'Checks whether there's more than one instance of searchTerm in the rng.Text
'For each instance above one, move the Start point of the range
'To the position of that instance until no more are "found".
'Since the Range is passed ByRef this will change the original
'range's position in the calling procedure.
Function NumberOfCharInRange(ByRef rng As Word.Range, _
ByRef searchTerm As String) As Long
Dim lCountChars As Long, lCharPos As Long
Dim s As String
s = rng.Text
Do
lCharPos = InStr(s, searchTerm)
If lCharPos > 1 Then
lCountChars = lCountChars + 1
rng.Start = rng.Start + lCharPos
End If
s = Mid(s, lCharPos + 1)
Loop Until lCharPos = 0
NumberOfCharInRange = lCountChars
End Function

Answer 1

You'll want to get the Color from the Font of the range. Then use this website to use decimal you get or transfer/convert to hex or rgb someway. There are also constants in VBA such as wdRed but, it's the word red whatever that is.
Sub FindSquareBracketPairs()
Dim rngFind As Range
Dim sOpen As String, sClose As String
Dim sFindTerm As String
Dim bFound As Boolean, lPosOpen As Long
Set rngFind = ActiveDocument.Range
sOpen = "["
sClose = "]"
sFindTerm = "\[*\] "
For Each rng In ActiveDocument.StoryRanges
For Each rngChar In rng.Characters
Dim fnt As Font
Set fnt = rngChar.Font
Dim clr As WdColor
clr = rngChar.Font.Color
Next
Next
With rngFind.Find
'.ClearFormatting
.Text = "\[*\] "
.Forward = True
.Wrap = Word.WdFindWrap.wdFindStop
.MatchWildcards = True
bFound = .Execute
Do While bFound
lPosOpen = NumberOfCharInRange(rngFind, sOpen)
'Check if the first and last brackets are whatever color is passed here.
If (IsSurroundedByColor(wdColorRed, rngFind.Characters.First, rngFind.Characters(rngFind.Characters.Count - 1))) Then
rngFind.Delete
End If
rngFind.Collapse wdCollapseEnd
bFound = .Execute
Loop
End With
End Sub
Function IsSurroundedByColor(ByRef chkingClr As WdColor, ByRef frstChr As Range, ByRef lstChr As Range) As Boolean
IsSurroundedByColor = (frstChr.Font.Color = chkingClr And lstChr.Font.Color = chkingClr)
End Function