This question already has answers here:
Select top and bottom rows
(9 answers)
Closed 7 months ago.
Question: The information of the youngest and oldest employee at the same time.
I can find information of the youngest or oldest employee, but I can't find information of the youngest and oldest employee at the same time.
My sql query:
-- The information of the oldest employee
Select top 1*
From DIP_Employees1
where DogumTarihi=
(Select Min(DogumTarihi)
From DIP_Employees1
)
-- The information of the youngest employee
Select top 1*
From DIP_Employees1
where DogumTarihi=
(Select Max(DogumTarihi)
From DIP_Employees1
)
How can I combine this two code for at the same time?
You can combine 2 queries that return same columns using UNION statement.
Also it is unnecessary to use subqueries. Instead you can just use order by
SELECT *
FROM (
Select top 1 *
From DIP_Employees1
ORDER BY DogumTarihi ASC
) t1
UNION ALL
SELECT *
FROM (
Select top 1 *
From DIP_Employees1
ORDER BY DogumTarihi DESC
) t2
Another option:
with cte as (
select min(DogumTarihi) as mndg, max(DogumTarihi) as mxdg
from dbo.DIP_Employees1
)
select ...
from dbo.DIP_Employees1 as emp
inner join cte on emp.DogumTarihi = cte.mndg
or emp.DogumTarihi = cte.maxdg
order by ...
;
Notice that some suggestions assume birthdate is unique. However unlikely it might be that multiple persons will have the same birthdate, why assume at all?
Related
This question already has answers here:
Get top 1 row of each group
(19 answers)
Closed 3 years ago.
Anyone can help me the easiest way to distinct one particular field/column but displaying all fields/columns? Please see attached image the data-source, I've tried to query on my own but it displays all the 16 records I'm looking for 6 records only.
USE DBASE;
WITH t1 as (SELECT DISTINCT STATE
FROM DSOURCE),
t2 as (SELECT *
FROM DSOURCE)
SELECT
*
FROM
t1
LEFT JOIN t2 ON t1.STATE=t2.STATE
You want row_number() :
select d.*
from (select d.*, row_number() over (partition by d.state order by d.f) as seq
from dsource d
) d
where d.seq = 1;
row_number() is your saviour here:
;WITH CTE AS
(
SELECT *, ROW_NUMBER() OVER(PARTITION BY STATE ORDER BY B,C,D,E,F) Corr
FROM dsource
)
SELECT *
FROM CTE
WHERE Corr = 1
You clearly want the first row from each `state's data. However, your dataset doesn't have a clear indicator of what is "first". So, you need to take one of two approaches.
If your data actually has an IDENTITY column, you can approach it with a query like this:
SELECT *
FROM DSOURCE d
WHERE ID In (
SELECT MIN(ID)
FROM DSOURCE ds
GROUP BY State
)
If not, you will need to use the row_number() functionality as shown above. #yogesh-sharma has the best example of using the this.
This question already has answers here:
Fetch the rows which have the Max value for a column for each distinct value of another column
(35 answers)
Oracle SQL query: Retrieve latest values per group based on time [duplicate]
(2 answers)
Get value based on max of a different column grouped by another column [duplicate]
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SQL: getting the max value of one column and the corresponding other columns [duplicate]
(2 answers)
Closed 3 years ago.
I am troubled with writing a tricky query.
I have the following table:
For each department I want to print date with largest profit;
I tried coming up with such a query myself:
Select DISTINCT(Name), Date_sale, MAX(A) as B FROM (SELECT
Departments.Name, SALES.Date_sale, SUM(GOODS.Price * SALES.Quantity)
AS A FROM DEPARTMENTS, GOODS, SALES
WHERE DEPARTMENTS.Dept_id = GOODS.Dept_id AND GOODS.Good_id =
SALES.Good_id GROUP BY DEPARTMENTs.Name, SALES.Date_sale)
GROUP BY Name, Date_sale;
But the problem it that departments are printed several times because I groupped by both name and date.
How should I fix it?
You can try below way-
with cte as
(
SELECT
Departments.Name, SALES.Date_sale, SUM(GOODS.Price * SALES.Quantity)
AS profit FROM DEPARTMENTS inner join GOODS on DEPARTMENTS.Dept_id = GOODS.Dept_id
inner join SALES on GOODS.Good_id = SALES.Good_id
GROUP BY DEPARTMENTs.Name, SALES.Date_sale
)A
select * from cte a
where profit =
(select max(profit) from cte b on a.department=b.department)
OR you can use row_number()
select * from
(
select *, row_number() over(partition by department oder by profit desc) as rn
from cte
)A where rn=1
You can write it using ROW_NUMBER which will give a number to each date's total count grouped by the department as following and then you can take the highest sale date using rn = 1
SELECT NAME, DATE_SALE, A
FROM
(
SELECT
DEPARTMENTS.NAME, SALES.DATE_SALE,
ROW_NUMBER() OVER(
PARTITION BY DEPARTMENTS.NAME
ORDER BY SUM(GOODS.PRICE * SALES.QUANTITY) DESC NULLS LAST
) AS RN,
SUM(GOODS.PRICE * SALES.QUANTITY) AS A
FROM DEPARTMENTS
JOIN GOODS ON ( DEPARTMENTS.DEPT_ID = GOODS.DEPT_ID )
JOIN SALES ON ( GOODS.GOOD_ID = SALES.GOOD_ID )
GROUP BY DEPARTMENTS.NAME,
SALES.DATE_SALE
)
WHERE RN = 1;
Important, Use the standard ANSI-joins.
Cheers!!
i would use join-s here as it is needed to pull info from 2 tables linked via the third table.
Something like this (but I have not tested this query, just suggesting an approach):
Select department.name as dept, MAX(sales.quantity) as max_sales, sales.date_sale
from goods
Left outer join departments on departments.dept_id = goods.dept_id
Left outer join sales on sales.good_id = goods.good_id
Group by dept
I need to perform TREAMMEAN in Access, which does not have this function.
In a table I have many Employees, each has many records.
I need to TRIMMEAN Values for each Employee separately.
Following queries perform TOP 10 percent for all records:
qry_data_TOP10_ASC
qry_data_TOP10_DESC
unionqry_TOP10_ASCandDESC
qry_data_ALL_minus_union_qry
After that, I can use Avg (Average).
But I don't know how to do it for each employee.
Visualization:
Note:
This question is edited to simplify problem.
You don't really give information in your pseudo code about your data fields but using your example that DOES have basic field information I can suggest the following should work as you described
It assumes field1 is your unique record ID - but you make no mention of which fields are keys
SELECT AVG(qry_data.field2) FROM qry_data WHERE qry_data.field1 NOT IN
(SELECT * FROM
(SELECT TOP 10 PERCENT qry_data.field1, qry_data.field2
FROM qry_data
ORDER BY qry_data.field2 ASC)
UNION
(SELECT TOP 10 PERCENT qry_data.field1, qry_data.field2
FROM qry_data
ORDER BY qry_data.field2 DESC)
)
This should give you what you want, the two sub-queries should correlate the TOP 10s (ascending and descending) for every employee. The two NOT INs should then remove those from the Table1 records and then you group the Employees and Average the Scores.
SELECT Table1.Employee, AVG(Table1.Score) AS AvgScore
FROM Table1
WHERE ID NOT IN
(
SELECT TOP 10 ID
FROM Table1 a
WHERE a.Employee = Table1.Employee
ORDER BY Score ASC, Employee, ID
)
AND ID NOT IN
(
SELECT TOP 10 ID
FROM Table1 b
WHERE b.Employee = Table1.Employee
ORDER BY Score DESC, Employee, ID
)
GROUP BY Table1.Employee;
This question already has answers here:
Oracle SQL - How to Retrieve highest 5 values of a column [duplicate]
(5 answers)
Oracle SELECT TOP 10 records [duplicate]
(6 answers)
Closed 6 years ago.
i have 2 tables .
abc(CID(pk), cname,)
order(order_id(pk), CID(fk), number_of_rentals)
i want to fetch top 10 customers based on number of rentals.
SELECT cid, sum(no_rentals) as sum
FROM orders
group by cid, no_rentals
order by no_rentals desc;
how can i use rownum function in above query to fetch the desired output
Just wrap your query in:
SELECT * FROM ( your_query ) WHERE ROWNUM <= 10;
However, your query does not look like it is going to do what you intend as the GROUP BY no_renalts will mean that each distinct no_rentals value will be in its own group and you will not sum the values for each customer so you probably don't want to include it in the GROUP BY. Also, if you want to order by the total number of rentals then you want to ORDER BY SUM( no_rentals ) (or by its alias) like this:
SELECT cid,
SUM(no_rentals) as total_no_rentals
FROM orders
GROUP BY cid
ORDER BY total_no_rentals DESC;
Then you can apply the row limit like this:
SELECT *
FROM (
SELECT cid,
SUM(no_rentals) as total_no_rentals
FROM orders
GROUP BY cid
ORDER BY total_no_rentals DESC
)
WHERE ROWNUM <= 10;
This question already has answers here:
How do I find duplicate values in a table in Oracle?
(13 answers)
Closed 7 years ago.
I am writing this query to find duplicate CTN Records in table1. So my thinking is if the CTN_NO appears more than twice or higher , I want it shown in my SELECT * statement output on top.
I tried the following sub-query logic but I need pulls
SELECT *
table1
WHERE S_IND='Y'
and CTN_NO = (select CTN_NO
from table1
where S_IND='Y'
and count(CTN_NO) < 2);
order by 2
Using:
SELECT t.ctn_no
FROM YOUR_TABLE t
GROUP BY t.ctn_no
HAVING COUNT(t.ctn_no) > 1
...will show you the ctn_no value(s) that have duplicates in your table. Adding criteria to the WHERE will allow you to further tune what duplicates there are:
SELECT t.ctn_no
FROM YOUR_TABLE t
WHERE t.s_ind = 'Y'
GROUP BY t.ctn_no
HAVING COUNT(t.ctn_no) > 1
If you want to see the other column values associated with the duplicate, you'll want to use a self join:
SELECT x.*
FROM YOUR_TABLE x
JOIN (SELECT t.ctn_no
FROM YOUR_TABLE t
GROUP BY t.ctn_no
HAVING COUNT(t.ctn_no) > 1) y ON y.ctn_no = x.ctn_no
Try this query.. It uses the Analytic function SUM:
SELECT * FROM
(
SELECT SUM(1) OVER(PARTITION BY ctn_no) cnt, A.*
FROM table1 a
WHERE s_ind ='Y'
)
WHERE cnt > 2
Am not sure why you are identifying a record as a duplicate if the ctn_no repeats more than 2 times. FOr me it repeats more than once it is a duplicate. In this case change the las part of the query to WHERE cnt > 1