I have seen a lot of questions similar to this but I have yet to see one that goes into detail of how to get records from two years back to today but include the start of the year two years back. Meaning I would like to create a function that will always give me results from January 1st two years back. For this year the results would come from 01-01-2020 to today’s date.
This is what I have so far, but in reality I am using it for a temporary table in my query.
SELECT *
FROM final
WHERE order_date BETWEEN DATEADD(‘year’, -2, current_date) AND current_date
You may use a combination of DATE_TRUNC and DATEADD to find January 1 of two years ago.
SELECT *
FROM final
WHERE order_date BETWEEN DATE_TRUNC('year', DATEADD('year', -2, current_date)) AND current_date;
What you had is close. Just truncate the the year.
You can see what happens in isolation:
select trunc('2021-03-14 08:24:12'::timestamp, 'YEAR');
-- Output: 2021-01-01 00:00:00.000
Adding to your SQL:
SELECT *
FROM final
WHERE order_date
BETWEEN trunc(DATEADD(‘year’, -2, current_date), 'YEAR') AND current_date
It is possible to construct arbitrary date using DATE_FROM_PARTS:
Creates a date from individual numeric components that represent the year, month, and day of the month.
DATE_FROM_PARTS( <year>, <month>, <day> )
For current_date:
SELECT DATE_FROM_PARTS(YEAR(current_date)-2,1,1);
-- 2020-01-01
Full query:
SELECT *
FROM final
WHERE order_date BETWEEN DATE_FROM_PARTS(YEAR(current_date)-2,1,1) AND current_date
This should be enough
where year(current_date)-year(order_date)<=2
But in case you have an order_date from the future
where year(current_date)-year(order_date)<=2 and order_date<=current_date
Related
I'm working on a project with a db that contains a date column for patient visits in the format of %m-%d-yyyy and need to sort so that it only pulls the rows where that date is within the last two weeks. I've tried a few different functions of convert, to_date, and can't seem to get anything to work.
I'm still very new to SQL and I don't know if this is a special case because I'm working with an oracle db
Not the full code, because it has dozens of queries and multiple joins (would that affect the date syntax?) but this is the format I'm trying for...
create table "Visits"
insert into "Visits" (
'John Doe',
'5/24/2021',
'Story about the visit',
'More room for story if needed')
select
"User_Name",
"Visit_Date",
"Visit_Narrative",
"Visit_Narrative_Overflow"
from "Visits"
where "Visits"."Visit_Date" >= TRUNC(SYSDATE) - 14
I'm working on a project with a db that contains a date column for patient visits in the format of %m-%d-yyyy
No, you don't have it in the format mm.dd.yyyy. A DATE data type value is stored within the database as a binary value in 7-bytes (representing century, year-of-century, month, day, hour, minute and second) and this has no format.
need to sort so that it only pulls the rows where that date is within the last two weeks.
You want a WHERE filter:
If you want to have the values that happened in the last 14 days then TRUNCate the current date back to midnight and subtract 14 days:
SELECT visit_date
FROM patient
WHERE visit_date >= TRUNC(SYSDATE) - INTERVAL '14' DAY
or
SELECT visit_date
FROM patient
WHERE visit_date >= TRUNC(SYSDATE) - 14
(or subtract 13 if you want today and 13 days before today.)
If you want it after Monday of last week then TRUNCate to the start of the ISO Week (which is always a Monday) and subtract 7 days:
SELECT visit_date
FROM patient
WHERE visit_date >= TRUNC(SYSDATE, 'IW') - INTERVAL '7' DAY
I ended up figuring it out based on an answer from another forum (linked below);
it appears that my original to_date() was incomplete without a second and operator in my where clause. This code is working perfectly
select
"User_Name",
"Visit_Date",
"Visit_Narrative",
"Visit_Narrative_Overflow"
from "SQLUser"."Visits"
where "SQLUser"."Visits"."Visit_Date" >= to_date('5/10/2021', 'MM/DD/YYYY')
and "SQLUser"."Visits"."Visit_Date" < to_date('5/24/2021', 'MM/DD/YYYY')
I currently have a simple sql script (in Oracle) that updates based a date range >='01JUN13'. I'm trying to modify this script to automatically update based on the last two years based on today's date. So the next month, I need the last two years of data greater than or equal to July 2013. Thanks.
It's not entirely clear from your question whether you want the date range to start from exactly two years ago, to the day , or from the start of the month.
Matching to the day:
select * from your_table
where date_col >= add_months(trunc(sysdate), -24)
/
Matching to the first day of the month:
select * from your_table
where date_col >= add_months(trunc(sysdate, 'MON'), -24)
/
I'm trying to go back and retrieve counts for the last 4 full months. This is an example of what I have so far:
SELECT datecolumn, Count(datacolumnA) AS CountOfdatacolumnA, datacolumnB
FROM tableA
WHERE datacolumnB='AA' AND datecolumn >= ADD_MONTHS(CURRENT_DATE, -4)
My results show the last four months plus the current month, October in this case. The problem is that June isn't showing the correct count for the entire month. I'm only getting a partial count for the month.
You need to adjust to the start of the month. You can do this by subtracting the day of the month to get the '0th' of the month and then adding 1 to get the first. (I think dates in teradata are decimals with the int part being number of days since an epoch)
Select
datecolumn,
Count(datacolumnA) As CountOfdatacolumnA,
datacolumnB
From
tableA
Where
datacolumnB='AA' And
datecolumn >=
add_months(current_date, -4)
- extract(day from add_months(current_date, -4)) + 1
I want to calculate the number of years between two dates.
eg :- Select to_date('30-OCT-2013') - TO_date('30-SEP-2014') FROM DUAL;
This would result to 335 days. I want to show this in years, which will be .97 years.
Simply do this(divide by 365.242199):
Select (to_date('30-SEPT-2014') - TO_date('30-OCT-2013'))/365.242199 FROM DUAL;
1 YEAR = 365.242199 days
OR
Try something like this using MONTHS_BETWEEN:-
select floor(months_between(date '2014-10-10', date '2013-10-10') /12) from dual;
or you may also try this:-
SELECT EXTRACT(YEAR FROM date1) - EXTRACT(YEAR FROM date2) FROM DUAL;
On a side note:-
335/365.242199 = 0.917199603 and not .97
I don't know how you figure that's .97 years. Here's what I get:
SQL> SELECT ( TO_date('30-SEP-2014') - to_date('30-OCT-2013')) /
(ADD_MONTHS(DATE '2013-10-30',12) - DATE '2013-10-30') "Year Fraction"
FROM DUAL;
Year Fraction
-------------
0.91780821917
You're going to have to pick a date to base your year calculation on. This is one way to do it. I chose to make a year be the number of days between 10/30/2013 and 10/30/2014. You could also make it a year between 9/30/2013 and 9/30/2014.
As an aside, if you're only interested in 2 decimal places, 365 is pretty much as good as 366.
UPDATE: Used ADD_MONTHS in calculating the denominator. That way you can use the same date for the entire calculation of the number of days in a year.
None of the methods proposed in the other answers give exactly the same answer, look:
with dates as ( select to_date('2013-10-01', 'YYYY-MM-DD') as date1, to_date('2014-09-01', 'YYYY-MM-DD') as date2 from dual)
select months_between(date2, date1)/12 as years_between, 'months_between(date1, date2)' as method from dates
union
select (date2 - date1)/365.242199, '(date2 - date1) / 365.242199' from dates
union
select extract(year from date2) - extract(year from date1), 'extract(year) from date2 - extract(year from date1)' from dates
union
select (date2 - date1) / (ADD_MONTHS(date1 ,12) - date1), '(nb days between date1 and date2) / (nb days in 1 year starting at date1)' from dates
;
gives
YEARS_BETWEEN METHOD
0.9166666666666666666666666666666666666667 months_between(date1, date2)
0.9171996032145234127231831719422979380321 (date2 - date1) / 365.242199
0.9178082191780821917808219178082191780822 nb days date2-date1 / (nb days in 1 year starting at date1)
1 extract(year) from date2 - extract(year from date1)
Why? Because they are all answering slightly different questions.
MONTHS_BETWEEN gives the number of whole months between the 2 dates, and calculates the fractional part as the remainder in days divided by 31.
dividing by 365.242199 assumes that you want the number of solar years between 00:00 on the first date and 00:00 on the second date, to 9 significant figures.
the third method assumes you want to calculate how many calendar days between the two dates, relative to the number of calendar days in the specific year that started on the first date (so the same number of calendar days will give you a different number of years, depending on whether there's a leap day between date1 and the same date on the following year).
the extract(year) approach assumes you want know the difference in whole numbers between the calendar year of the first date and the calendar year of the second date
It's not possible to answer the question perfectly, without knowing which kind of year we are talking about. Do we mean a solar year, or a calendar year, and if we mean a calendar year, do we we want to calculate by months (as if all months were the same length, which they aren't) or by the actual number of days between those dates and in that specific year?
Indeed, if we're talking about calendar years, it's not possible to calculate a fractional number of years in a consistent way at all, since the concept "calendar year" doesn't correspond to a fixed number of days.
The good news is that (aside from the fourth method) all the approaches give the same answer to the first 2 significant figures, as DCookie said. So you can save worrying about what you mean when you say "year", and instead start to think of other concerns such as performance, portability, readability... which also are quite different between these approaches.
I do think though, that whenever a non-programmer asks for something like "the fractional number of years between two dates," they should be punished by being given a detailed explanation of the different ways to calculate it, and why and how they are different, until they agree that it would be better expressed in number of weeks (which at least have the benefit of containing a fixed number of days).
I am working on a homework problem, I'm close but need some help with a data conversion I think. Or sysdate - start_date calculation
The question is:
Using the EX schema, write a SELECT statement that retrieves the date_id and start_date from the Date_Sample table (format below), followed by a column named Years_and_Months_Since_Start that uses an interval function to retrieve the number of years and months that have elapsed between the start_date and the sysdate. (Your values will vary based on the date you do this lab.) Display only the records with start dates having the month and day equal to Feb 28 (of any year).
DATE_ID START_DATE YEARS_AND_MONTHS_SINCE_START
2 Sunday , February 28, 1999 13-8
4 Monday , February 28, 2005 7-8
5 Tuesday , February 28, 2006 6-8
Our EX schema that refers to this question is simply a Date_Sample Table with two columns:
DATE_ID NUMBER NOT Null
START_DATE DATE
I Have written this code:
SELECT date_id, TO_CHAR(start_date, 'Day, MONTH DD, YYYY') AS start_date ,
NUMTOYMINTERVAL((SYSDATE - start_date), 'YEAR') AS years_and_months_since_start
FROM date_sample
WHERE TO_CHAR(start_date, 'MM/DD') = '02/28';
But my Years and months since start column is not working properly. It's getting very high numbers for years and months when the date calculated is from 1999-ish. ie, it should be 13-8 and I'm getting 5027-2 so I know it's not correct. I used NUMTOYMINTERVAL, which should be correct, but don't think the sysdate-start_date is working. Data Type for start_date is simply date. I tried ROUND but maybe need some help to get it right.
Something is wrong with my calculation and trying to figure out how to get the correct interval there. Not sure if I have provided enough information to everyone but I will let you know if I figure it out before you do.
It's a question from Murach's Oracle and SQL/PL book, chapter 17 if anyone else is trying to learn that chapter. Page 559.
you'll want MONTHS_BETWEEN in that numtoyminterval as the product of subtracting two date variables gives the answer in days which isn't usable to you and the reason its so high is you've told Oracle the answer was in years! Also use the fm modifier on the to_char to prevent excess whitespace.
select date_id,
to_char(start_date, 'fmDay, Month DD, YYYY') as start_date,
extract(year from numtoyminterval(months_between(trunc(sysdate), start_date), 'month') )
|| '-' ||
extract(month from numtoyminterval(months_between(trunc(sysdate), start_date), 'month') )
as years_and_months_since_start
from your_table
where to_char(start_date, 'MM/DD') = '02/28';
You can simplify the answer like this
SELECT date_id, start_date, numtoyminterval(months_between(sysdate, start_date), 'month') as "Years and Months Since Start"
FROM date_sample
WHERE EXTRACT (MONTH FROM start_date) = 2 AND EXTRACT (DAY FROM start_date) = 28;