Adjust the size of a chart in Word - vba

I want to create a macro in Microsoft Word, that when I select a chart: allows me to activate the macro, and the height and width automatically change, to take the full width of the sheet, or take only half. For this I was using VBA with the following code:
Sub Resize()
With Selection
If .InlineShapes.Count > 0 Then
With .InlineShapes(1)
If .HasChart Then
With .Chart.ChartArea
.Width = 150
End With
End If
End With
End If
End With
Exit Sub
ErrorHandler:
MsgBox "Incorrect or missing data"
End Sub
The problem occurs when you try to access the property "Width", where you get an error at runtime of code 445 (Object doesn't support this action).

Related

Excel freezes after pasting text to a userform textbox

I have a vba userform text box with,
ControlSource = An Excel Cell
EnterKeyBehavior = True
MultiLine = True
MaxLength = 500
When I copy paste a text in the box such as a random text below:
Where does it come from?
Contrary to popular belief, Lorem Ipsum is not simply random text. It has roots in a piece of classical Latin literature from 45 BC, making it over 2000 years old.
and step away for this text box (by clicking somewhere else such an another text box),
excel freezes (no response, cant open any excel file)
CPU usage for excel gets to ~50% (exceptionally high compared to normal use)
Do you know the reason for this freeze/behaviour?
Code behind the user form:
Private Sub CommandButton_PD_NP_Click()
If Me.Tb_PD_1.Value = "" Or Me.Tb_PD_2.Value = "" Then
MsgBox "Please specify your Business Area and Activity Name.", vbExclamation, "Error!"
Exit Sub
End If
Unload Me
Uf2_Security.Show
End Sub
Private Sub CommandButton_PD_PP_Click()
Unload Me
Uf1_Initiate.Show
End Sub
Private Sub UserForm_Initialize()
With Uf15_Project_Details
.Height = 357
.Left = 0
.StartUpPosition = 2
.Top = 0
.Width = 480
End With
End Sub

Powerpoint 2016 Text Transparency

I need to set the Transparency of Text in a shape via VBA, in fact I need to set the transparency for the whole shape but it's the text I'm stuck with.
I just can't seem to navigate the object model to find the Transparency Property
Function SetTransparency(Value As Single)
On Error GoTo AbortNameShape
If ActiveWindow.Selection.ShapeRange.Count = 0 Then
MsgBox "No Shapes Selected"
Exit Function
End If
With ActiveWindow.Selection.ShapeRange
.Fill.Transparency = Value
.Line.Transparency = Value
.TextFrame.TextRange. **HELP** .Transparency = Value
End With
AbortNameShape:
MsgBox Err.Description
End Function
Google has given me
.TextFrame.TextRange.Characters.Font.Fill.Transparency
From https://www.mrexcel.com/forum/excel-questions/510589-transparent-text-shapes-textbox-1-a.html
But that fails on the .Fill property of Font object not existing. I'm assuming MS have changed the object model in the 10 years that have passed since the answer was given, but I'm stuck for a current approach.
Thanks
Try this (for just the first member of the current selection)
With ActiveWindow.Selection.ShapeRange(1)
With .TextFrame2.TextRange.Font.Fill
.Transparency = 0.5
End With
End With
If you want to iterate through all the shapes in the current selection, you'll want to test each shape to see if .HasTextFrame and .TextFrame.HasText are true before trying to work with the text.

VBA Grey Checkboxes

I would like to grey out my checkboxes in Excel VBA. When using Checkbox.Enabled = False, the checkbox is not editable, but it is also not grey. How do I get the greyed out effect?
Using form controls with Excel 2010. Inserted via developer tab directly into excel worksheet. Not used in a VBA userform.
Thanks!
Whenever anyone says "it is impossible", it hits my stubborn streak. So may I present to you: "The Impossible".
"Visible" and enabled checkbox:
"Disabled" checkbox (you can tweak the degree of visibility by changing values in the code for both color and transparency of the cover shape):
Basic idea: you place a semi transparent shape over the checkbox, and assign a dummy macro to it. Now you can't change the value of the checkbox. The "toggle" button is there to change the state - either place the shapes, or remove them. It uses a global variable to track the current state.
Finally - note that you can't use For Each when you delete (or add) shapes as you should not modify the collection you are iterating over. I circumvented that with a simple "count shapes, then iterate backwards by numerical index".
Is it a hack? You bet! Does it do what you asked? Yes!
Dim checkBoxesVisible As Boolean
Option Explicit
Sub toggleIt()
' macro assigned to "Toggle visibility" button
checkBoxesVisible = Not checkBoxesVisible
toggleCheckboxes checkBoxesVisible
End Sub
Sub grayOut(cb)
' put a "cover" shape over a checkbox
' change the color and transparency to adjust the appearance
Dim cover As Shape
Set cover = ActiveSheet.Shapes.AddShape(msoShapeRectangle, cb.Left, cb.Top, cb.Width, cb.Height)
With cover
.Line.Visible = msoFalse
With .Fill
.Visible = msoTrue
.ForeColor.RGB = RGB(255, 255, 255)
.Transparency = 0.4
.Solid
End With
End With
cover.Name = "cover"
cover.OnAction = "doNothing"
End Sub
Sub doNothing()
' dummy macro to assign to cover shapes
End Sub
Sub unGray(cb)
' find the cover shape for the checkbox passed as the argument
' and delete it
' "correct shape" has the name "cover" and is properly aligned with top left
Dim sh As Shape
For Each sh In ActiveSheet.Shapes
If sh.Name = "cover" And sh.Left = cb.Left And sh.Top = cb.Top Then
sh.Delete
Exit For
End If
Next sh
End Sub
Sub toggleCheckboxes(onOff)
Dim s As Shape
Dim n As Integer, ii As Integer
n = ActiveSheet.Shapes.Count
' loop backwards over shapes: if you do a "For Each" you get in trouble
' when you delete things!
For ii = n To 1 Step -1
Set s = ActiveSheet.Shapes(ii)
If s.Type = msoFormControl Then
If s.FormControlType = xlCheckBox Then
If onOff Then
unGray s
Else
grayOut s
End If
End If
End If
Next ii
End Sub
A slight hack - but the following does work. I created a simple userform with two controls - a regular checkbox (CheckBox1), and a button I called "DisableButton" with the following code:
Private Sub DisableButton_Click()
CheckBox1.Enabled = Not (CheckBox1.Enabled)
If CheckBox1.Enabled Then
CheckBox1.ForeColor = RGB(0, 0, 0)
Else
CheckBox1.ForeColor = RGB(128, 128, 128)
End If
End Sub
When I clicked the button, the checkbox was grayed out and unavailable. Clicking it again "brought it back to life". I think this is the effect you were looking for. If it's not - that's what comments are for.
Here is what it looks like:
I am afraid it is impossible what you are trying to do within a worksheet. You can refer to the Floris' answer if you are using an UserForm.
For more details on the properties of (Form/worksheet) check boxes see MSDN
Maybe this is what you want.
Private Sub CheckBox1_Click()
If CheckBox1.Value = True Then
CheckBox2.Value = False
CheckBox2.Enabled = False
CheckBox2.ForeColor = rgbBlue
Else
CheckBox2.Visible = True
CheckBox2.ForeColor = rgbAntiqueWhite
CheckBox2.Enabled = True
End If
Code tels that when checkbox1 is checked, checkbox2 is disabled; unchecked and the forecollor changes. the colors can be what you want.
Did this with the checkboxes directly in the excel worksheet.
Based on Floris' idea.
The code assumes all the controls are on ActiveSheet and they are called CheckBox1 and CheckBox2, if not, change it accordingly.
You can call this when you click on CheckBox1 or you can call it from another sub, with an optional ticked status (True/False) to check or uncheck CheckBox1.
Draw an object on top of CheckBox2 and name it "mask" (you can name it anything else but then you have to change the code accordingly)
Give mask the same fill color as your background color and opacity of around 50%.
Public Sub CheckBox1_Click(Optional ticked As Variant)
Application.ScreenUpdating = False
ActiveSheet.Unprotect
If Not IsMissing(ticked) Then
If ticked = True Then ActiveSheet.Shapes("CheckBox1").OLEFormat.Object.Value = 1 Else ActiveSheet.Shapes("CheckBox1").OLEFormat.Object.Value = -4146
End If
If ActiveSheet.Shapes("CheckBox1").OLEFormat.Object.Value > 0 Then
ActiveSheet.Shapes("mask").OLEFormat.Object.ShapeRange.ZOrder msoSendToBack
Else
ActiveSheet.Shapes("mask").OLEFormat.Object.ShapeRange.ZOrder msoBringToFront
End If
ActiveSheet.Protect DrawingObjects:=True, Contents:=True, Scenarios:=True
Application.ScreenUpdating = True
End Sub
Now each time you tick CheckBox1, mask comes to front to hide CheckBox2 and when you untick it, mask goes to back to unhide it. Since it is opaque, it gives you the greyed out effect and you don't even have to worry about enable/disable either.
Worksheet should be protected so that user can't accidentally move or edit mask, but should be unprotected for SendToBack/BringToFront to work, so the code does that. Please check the protection settings at the Application.Protect part.

(Excel VBA) If Cell Value equals "" Then Show/Hide Images

I am working on a Excel Spreadsheet that when a dropdown box value is selected an image will pop up, and if another value is selected it will hide the current image and pop up the image related to the selection. I have found a few methods that are just too time consuming using just the sheet and positioning of the image using coordinates; that's not exactly the route I would like to go.I have done a quite a bit of research before using StackOverflow, and nothing seemed to work thus far. Below is what I am trying to achieve. I am trying to keep all the images within the spreadsheet which adds another level of challenge, but I believe there is a way to do this because excel assigns the image a number when inserted EX. Picture 9.
Sub Main()
If Range(G11).Value = "anything" Then
Picture1 show
Picture2 hide
End If
End Sub
Any Help is greatly appreciated. Thanks
Rather than hiding/moving/reducing the size of the unwanted pic, why not simply delete it?
Logic:
Save all your images in a temp sheet. When ever a relevant picture is supposed to be shown, get it from the temp sheet and delete the previous.
Here is an example.
Sub Sample()
Select Case Range("G11").Value
Case "Picture 1": ShowPicture ("Picture 1")
Case "Picture 2": ShowPicture ("Picture 2")
Case "Picture 3": ShowPicture ("Picture 3")
Case "Picture 4": ShowPicture ("Picture 4")
End Select
End Sub
Sub ShowPicture(picname As String)
'~~> The reason why I am using OERN is because it is much simpler
'~~> than looping all shapes and then deleting them. There could be
'~~> charts, command buttons and other shapes. I will have to write
'~~> extra validation code so that those shapes are not deleted.
On Error Resume Next
Sheets("Sheet1").Shapes("Picture 1").Delete
Sheets("Sheet1").Shapes("Picture 2").Delete
Sheets("Sheet1").Shapes("Picture 3").Delete
Sheets("Sheet1").Shapes("Picture 4").Delete
On Error GoTo 0
Sheets("Temp").Shapes(picname).Copy
'<~~ Alternative to the below line. You may re-position the image
'<~~ after you paste as per your requirement
Sheets("Sheet1").Range("G15").Select
Sheets("Sheet1").Paste
End Sub
Snapshot of temp sheet
Here is a solution using the Visible property of the object.
I used this to show a picture based on a value in a field.
The field had a formula that resulted in either "good" or "bad".
If its value was "good", I wanted to show one picture; for "bad", another picture should show; and they should never show at the same time.
The field needed to update its value whenever a user refreshed a pivot table, so I put the code in that method of the worksheet where the pivot table and picture were to appear.
Private Sub Worksheet_PivotTableUpdate(ByVal Target As PivotTable)
'hide both pictures by loopng through all the shapes on the sheet
Dim s As Shape
For Each s In ActiveSheet.Shapes
'hide the shape if it is a picture, leave other shapes on the page visible.
If s.Type = msoPicture Then s.Visible = msoFalse
Next
Dim judgement As String
'The field whose value tells what picture to use is a one-cell named range called "judgement"
judgement = Range("judgement")
'you need to know which picture is which.
If judgement = "Good" Then ActiveSheet.Shapes("Picture 8").Visible = True
If judgement = "Bad" Then ActiveSheet.Shapes("Picture 1").Visible = True
End Sub
Sub hidePicture(myImage)
ActiveSheet.Shapes.Range(Array(myImage)).Select
Selection.ShapeRange.Height = 0
Selection.ShapeRange.Width = 0
End Sub
Sub showPicture(myImage)
ActiveSheet.Shapes.Range(Array(myImage)).Select
Selection.ShapeRange.Height = 200
Selection.ShapeRange.Width = 300
End Sub
Handy tip: record macro and look at the code it generates!
Might be better just to move your pictures "off screen", particularly if they're of different sizes.
Sub Tester()
ShowPicture "Picture 3"
End Sub
Sub ShowPicture(PicName As String)
Dim s As Shape
For Each s In ActiveSheet.Shapes
With s
.Top = IIf(.Name = PicName, 100, 100)
.Left = IIf(.Name = PicName, 100, 1000)
End With
Next s
End Sub

CircleInvalid and ClearCircle methods for a particular cell in excel vba 2007

I am using data validation in excel 2007. I am using this code to make invalid data marked with red circle.
Private Sub Worksheet_Change(ByVal Target As Range)
Dim rc As Integer
Range(Target.Address).Select
ActiveSheet.ClearCircles
ActiveSheet.CircleInvalid
If Not Range(Target.Address).Validation.Value Then
rc = MsgBox("Data Validation errors exist! " & Range
(Target.Address).Validation.ErrorMessage & " Please correct circled entries!", vbCritical, "Failure")
Exit Sub
End If
End Sub
As you can see in the code when I put wrong data then first of that specific range is going to selected and then all invalid data is marked with red circle.
But I want that only that specific cell should be marked with red not all data .
Thanks.
You can try this code from an Excel MVP:
Dim TheCircledCell As Range
Sub CircleCells(CellToCircle As Range)
If Not CellToCircle Is Nothing Then
With CellToCircle
If .Count > 1 Then Exit Sub
Set TheCircledCell = CellToCircle
.Validation.Delete
.Validation.Add xlValidateTextLength, xlValidAlertInformation, xlEqual, 2147483647#
.Validation.IgnoreBlank = False
.Parent.CircleInvalid
End With
End If
End Sub
Sub ClearCircles()
If Not TheCircledCell Is Nothing Then
With TheCircledCell
.Validation.Delete
.Parent.ClearCircles
End With
End If
End Sub
Note that you can't use the Excel standard Validation function on these cells.
[Source and explanation of the code]