This is my table:
id
Total
Date
1
3
410
2
4
121
3
7
630
4
8
629
5
9
101
Date part is saved as int month and day. How to find the total amount made in the previous month of the current month?
Try the following query:
Select Date_/100 as Date_Month, Sum(Total) as MonthlyTotal From YourTable
Where MONTH(GETDATE()) - 1 = (Date_/100)
Group By (Date_/100)
See a demo from db<>fiddle.
I concur with the comments made above. I get it that you can't change the way that you store your "dates" . But you should make whoever made that decision miserable. They are asking for trouble like that.
Having said that -
I rely, here, on the fact that the division of two integers, in SQL Server, if it is not an integer already, is truncated to the next lower integer, and returned as integer.
WITH
-- your input, don't use in final query ...
-- I renamed the third column more aptly to "monthday"
indata(id,Total,monthday) AS (
SELECT 1,3.00,410
UNION ALL SELECT 2,4.55,121
UNION ALL SELECT 3,7.40,630
UNION ALL SELECT 4,8.00,629
)
-- real query starts here - replace following comma with "WITH"
,
per_month AS (
SELECT
monthday / 100 AS monthno
, SUM(total) AS monthtot
FROM indata
GROUP BY monthno
-- ctl monthno | monthtot
-- ctl ---------+----------
-- ctl 1 | 4.55
-- ctl 4 | 3.00
-- ctl 6 | 15.40
)
SELECT
*
FROM per_month
WHERE monthno=MONTH(CURRENT_DATE) - 1;
-- out monthno | monthtot
-- out ---------+----------
-- out 6 | 15.40
Related
I'm trying to build a department level score table based on a deeper product url level score table.
Date is not consecutive
Not all urls got score updates at same day (independent to each other)
dist_url should be running count distinct (cumulative count distinct)
dist urls and urls score >=30 are both count distinct
What I have now is:
Date url Store Dept Page Score
10/1 a US A X 10
10/1 b US A X 30
10/1 c US A X 60
10/4 a US A X 20
10/4 d US A X 60
10/6 b US A X 22
10/9 a US A X 40
10/9 e US A X 10
Date Store Dept Page dist urls urls score >=30
10/1 US A X 3 2
10/4 US A X 4 3
10/6 US A X 4 2
10/9 US A X 5 2
I think the dist_url can be done by using window function, just not sure on query.
Current query is as below, but it's wrong since not cumulative count distinct:
SELECT
bm.AnalysisDate,
su.SoID AS Store,
su.DptCaID AS DTID,
su.PageTypeID AS PTID,
COUNT(DISTINCT bm.SeoURLID) AS NumURLsWithDupScore,
SUM(CASE WHEN bm.DuplicationScore > 30 THEN 1 ELSE 0 END) AS Over30Count
FROM csn_seo.tblBotifyMetrics bm
INNER JOIN csn_seo.tblSEOURLs su
ON bm.SeoURLID = su.ID
WHERE su.DptCaID IS NOT NULL
AND su.DptCaID <> 0
AND su.PageTypeID IS NOT NULL
AND su.PageTypeID <> -1
AND bm.iscompliant = 1
GROUP BY bm.AnalysisDate, su.SoID, su.DptCaID, su.PageTypeID;
Please let me know if anyone has any idea.
Based on your question, you seem to want two levels of logic:
select date, store, dept,
sum(sum(start)) over (partition by dept, page order by date) as distinct_urls,
sum(sum(start_30)) over (partition by dept, page order by date) as distinct_urls_30
from ((select store, dept, page, url, min(date) as date, 1 as start, 0 as start_30
from t
group by store, dept, page, url
) union all
(select store, dept, page, url, min(date) as date, 0, 1
from t
where score >= 30
group by store, dept, page, url
)
) t
group by date, store, dept, page;
I don't understand how your query is related to your question.
Try as I might, I don't get your output either:
But I think you can avoid UNION SELECTs - Does this do what you expect?
NULLS don't figure in COUNT DISTINCTs - and here you can combine an aggregate expression with an OLAP one ...
And Vertica has named windows to increase readability ....
WITH
input(Date,url,Store,Dept,Page,Score) AS (
SELECT DATE '2019-10-01','a','US','A','X',10
UNION ALL SELECT DATE '2019-10-01','b','US','A','X',30
UNION ALL SELECT DATE '2019-10-01','c','US','A','X',60
UNION ALL SELECT DATE '2019-10-04','a','US','A','X',20
UNION ALL SELECT DATE '2019-10-04','d','US','A','X',60
UNION ALL SELECT DATE '2019-10-06','b','US','A','X',22
UNION ALL SELECT DATE '2019-10-09','a','US','A','X',40
UNION ALL SELECT DATE '2019-10-09','e','US','A','X',10
)
SELECT
date
, store
, dept
, page
, SUM(COUNT(DISTINCT url) ) OVER(w) AS dist_urls
, SUM(COUNT(DISTINCT CASE WHEN score >=30 THEN url END)) OVER(w) AS dist_urls_gt_30
FROM input
GROUP BY
date
, store
, dept
, page
WINDOW w AS (PARTITION BY store,dept,page ORDER BY date)
;
-- out date | store | dept | page | dist_urls | dist_urls_gt_30
-- out ------------+-------+------+------+-----------+-----------------
-- out 2019-10-01 | US | A | X | 3 | 2
-- out 2019-10-04 | US | A | X | 5 | 3
-- out 2019-10-06 | US | A | X | 6 | 3
-- out 2019-10-09 | US | A | X | 8 | 4
-- out (4 rows)
-- out
-- out Time: First fetch (4 rows): 45.321 ms. All rows formatted: 45.364 ms
So the question seems to be quite difficult I wonder if I could get some advice from here. I am trying to solve this with SQLite 3. So I have a data format of this.
customer | purchase date
1 | date 1
1 | date 2
1 | date 3
2 | date 4
2 | date 5
2 | date 6
2 | date 7
number of times the customer repeats is random.
so I just want to find whether customer 1's 1st and 2nd purchase date are fallen in between a specific time period. repeat for other customers. only need to consider 1st and 2nd dates.
Any help would be appreciated!
We can try using ROW_NUMBER here:
WITH cte AS (
SELECT *, ROW_NUMBER() OVER (PARTITION BY customer ORDER BY "purchase date") rn
FROM yourTable
)
SELECT
customer,
CAST(MAX(CASE WHEN rn = 2 THEN julianday("purchase date") END) -
MAX(CASE WHEN rn = 1 THEN julianday("purchase date") END) AS INTEGER) AS diff_in_days
FROM cte
GROUP BY
customer;
The idea here is to aggregate by customer and then take the date difference between the second and first purchase. ROW_NUMBER is used to find these first and second purchases, for each customer.
i have table and it has following data:
USERID NAME DATEFROM DATETO
1 xxx 2014-05-10 2014-05-15
1 xxx 2014-05-20 2014-05-25
4 yyy 2014-04-20 2014-04-21
now i have sql query like :
select * from leave where datefrom>='2014-05-01' and dateto<='2014-05-31'
so now i want output :
userid name total_leave_days
1 xxx 12
4 yyy 2
(2014-05-10 - 2014-05-15 )=6 days
(2014-05-20 - 2014-05-25 )=6 days
total = 12 days for useid 1
(2014-04-20 - 2014-04-21)= 2 days for userid 4
how can i calculate this total days .?
Please try:
select
USERID,
NAME,
SUM(DATEDIFF(day, DATEFROM, DATETO)+1) total_leave_days
From leave
group by USERID, NAME
SQL Fiddle Demo
It's important to note that you need "+1" to emulate the expected calculations because there is an inherent assumption of ""start of day" for the Start date and "end of day" for end date - but dbms's don't think that way. a date is always stored as "start of day".
select
USERID
, name
, sum( datediff(day,DATEFROM,DATETO) + 1 ) as leave_days
from leavetable
group by
USERID
, name
produces this:
| USERID | NAME | LEAVE_DAYS |
|--------|------|------------|
| 1 | xxx | 12 |
| 4 | yyy | 2 |
see: http://sqlfiddle.com/#!3/ebe5d/1
You can use DateDiff.
SELECT UserID, Name, SUM(DATEDIFF(DAY, DateFrom, DateTo) + 1) AS total_leave_days
FROM leave
WHERE datefrom >= '2014-05-01' AND dateto <= '2014-05-31'
GROUP BY UserID, Name
The + 1 ,of course, is because DATEDIFF will return the exclusive count, where it sounds like you want the inclusive number of days.
Try this:
select userid, name, sum (1 + datediff(day,datefrom,dateto)) as total_leave_days
from leaves
where datefrom>='2014-05-01' and dateto<='2014-05-31'
group by userid, name
This will sum the total leaves per userid. Note that datediff will give you 5 days difference for the range 2014-05-10 to 2014-05-15, so we need to add 1 to the result to get 6 days i.e. range inclusive of both ends.
Demo
I was trying to aggregate a 7 days data for FY13 (starts on 10/1/2012 and ends on 9/30/2013) in SQL Server but so far no luck yet. Could someone please take a look. Below is my example data.
DATE BREAD MILK
10/1/12 1 3
10/2/12 2 4
10/3/12 2 3
10/4/12 0 4
10/5/12 4 0
10/6/12 2 1
10/7/12 1 3
10/8/12 2 4
10/9/12 2 3
10/10/12 0 4
10/11/12 4 0
10/12/12 2 1
10/13/12 2 1
So, my desired output would be like:
DATE BREAD MILK
10/1/12 1 3
10/2/12 2 4
10/3/12 2 3
10/4/12 0 4
10/5/12 4 0
10/6/12 2 1
Total 11 15
10/7/12 1 3
10/8/12 2 4
10/9/12 2 3
10/10/12 0 4
10/11/12 4 0
10/12/12 2 1
10/13/12 2 1
Total 13 16
--------through 9/30/2013
Please note, since FY13 starts on 10/1/2012 and ends on 9/30/2012, the first week of FY13 is 6 days instead of 7 days.
I am using SQL server 2008.
You could add a new computed column for the date values to group them by week and sum the other columns, something like this:
SELECT DATEPART(ww, DATEADD(d,-2,[DATE])) AS WEEK_NO,
SUM(Bread) AS Bread_Total, SUM(Milk) as Milk_Total
FROM YOUR_TABLE
GROUP BY DATEPART(ww, DATEADD(d,-2,[DATE]))
Note: I used DATEADD and subtracted 2 days to set the first day of the week to Monday based on your dates. You can modify this if required.
Use option with GROUP BY ROLLUP operator
SELECT CASE WHEN DATE IS NULL THEN 'Total' ELSE CONVERT(nvarchar(10), DATE, 101) END AS DATE,
SUM(BREAD) AS BREAD, SUM(MILK) AS MILK
FROM dbo.test54
GROUP BY ROLLUP(DATE),(DATENAME(week, DATE))
Demo on SQLFiddle
Result:
DATE BREAD MILK
10/01/2012 1 3
10/02/2012 2 4
10/03/2012 2 3
10/04/2012 0 4
10/05/2012 4 0
10/06/2012 2 1
Total 11 15
10/07/2012 1 3
10/08/2012 4 7
10/10/2012 0 4
10/11/2012 4 0
10/12/2012 2 1
10/13/2012 2 1
Total 13 16
You are looking for a rollup. In this case, you will need at least one more column to group by to do your rollup on, the easiest way to do that is to add a computed column that groups them into weeks by date.
Take a lookg at: Summarizing Data Using ROLLUP
Here is the general idea of how it could be done:
You need a derived column for each row to determine which fiscal week that record belongs to. In general you could subtract that record's date from 10/1, get the number of days that have elapsed, divide by 7, and floor the result.
Then you can GROUP BY that derived column and use the SUM aggregate function.
The biggest wrinkle is that 6 day week you start with. You may have to add some logic to make sure that the weeks start on Sunday or whatever day you use but this should get you started.
The WITH ROLLUP suggestions above can help; you'll need to save the data and transform it as you need.
The biggest thing you'll need to be able to do is identify your weeks properly. If you don't have those loaded into tables already so you can identify them, you can build them on the fly. Here's one way to do that:
CREATE TABLE #fy (fyear int, fstart datetime, fend datetime);
CREATE TABLE #fylist(fyyear int, fydate DATETIME, fyweek int);
INSERT INTO #fy
SELECT 2012, '2011-10-01', '2012-09-30'
UNION ALL
SELECT 2013, '2012-10-01', '2013-09-30';
INSERT INTO #fylist
( fyyear, fydate )
SELECT fyear, DATEADD(DAY, Number, DATEADD(DAY, -1, fy.fstart)) AS fydate
FROM Common.NUMBERS
CROSS APPLY (SELECT * FROM #fy WHERE fyear = 2013) fy
WHERE fy.fend >= DATEADD(DAY, Number, DATEADD(DAY, -1, fy.fstart));
WITH weekcalc AS
(
SELECT DISTINCT DATEPART(YEAR, fydate) yr, DATEPART(week, fydate) dt
FROM #fylist
),
ridcalc AS
(
SELECT
ROW_NUMBER() OVER (ORDER BY yr, dt) AS rid, yr, dt
FROM weekcalc
)
UPDATE #fylist
SET fyweek = rid
FROM #fylist
JOIN ridcalc
ON DATEPART(YEAR, fydate) = yr
AND DATEPART(week, fydate) = dt;
SELECT list.fyyear, list.fyweek, p.[date], COUNT(bread) AS Bread, COUNT(Milk) AS Milk
FROM products p
JOIN #fylist list
ON p.[date] = list.fydate
GROUP BY list.fyyear, list.fyweek, p.[date] WITH ROLLUP;
The Common.Numbers reference above is a simple numbers table that I use for this sort of thing (goes from 1 to 1M). You could also build that on the fly as needed.
I asked this question in regard to SQL Server, but what's the answer for an Oracle environment (10g)?
If I have a table containing schedule information that implies particular dates, is there a SQL statement that can be written to convert that information into actual rows, using something like MSSQL's Commom Table Expressions, perhaps?
Consider a payment schedule table with these columns:
StartDate - the date the schedule begins (1st payment is due on this date)
Term - the length in months of the schedule
Frequency - the number of months between recurrences
PaymentAmt - the payment amount :-)
SchedID StartDate Term Frequency PaymentAmt
-------------------------------------------------
1 05-Jan-2003 48 12 1000.00
2 20-Dec-2008 42 6 25.00
Is there a single SQL statement to allow me to go from the above to the following?
Running
SchedID Payment Due Expected
Num Date Total
--------------------------------------
1 1 05-Jan-2003 1000.00
1 2 05-Jan-2004 2000.00
1 3 05-Jan-2005 3000.00
1 4 05-Jan-2006 4000.00
2 1 20-Dec-2008 25.00
2 2 20-Jun-2009 50.00
2 3 20-Dec-2009 75.00
2 4 20-Jun-2010 100.00
2 5 20-Dec-2010 125.00
2 6 20-Jun-2011 150.00
2 7 20-Dec-2011 175.00
Your thoughts are appreciated.
Oracle actually has syntax for hierarchical queries using the CONNECT BY clause. SQL Server's use of the WITH clause looks like a hack in comparison:
SELECT t.SchedId,
CASE LEVEL
WHEN 1 THEN
t.StartDate
ELSE
ADD_MONTHS(t.StartDate, t.frequency)
END 'DueDate',
CASE LEVEL
WHEN 1 THEN
t.PaymentAmt
ELSE
SUM(t.paymentAmt)
END 'RunningExpectedTotal'
FROM PaymentScheduleTable t
WHERE t.PaymentNum <= t.Term / t.Frequency
CONNECT BY PRIOR t.startdate = t.startdate
GROUP BY t.schedid, t.startdate, t.frequency, t.paymentamt
ORDER BY t.SchedId, t.PaymentNum
I'm not 100% on that - I'm more confident about using:
SELECT t.SchedId,
t.StartDate 'DueDate',
t.PaymentAmt 'RunningExpectedTotal'
FROM PaymentScheduleTable t
WHERE t.PaymentNum <= t.Term / t.Frequency
CONNECT BY PRIOR t.startdate = t.startdate
ORDER BY t.SchedId, t.PaymentNum
...but it doesn't include the logic to handle when you're dealing with the 2nd+ entry in the chain to add months & sum the amounts. The summing could be done with GROUP BY CUBE or ROLLUP depending on the detail needed.
I don't understand why 5 payment days for schedid = 1 and 7 for scheid = 2?
48 /12 = 4 and 42 / 6 = 7. So I expected 4 payment days for schedid = 1.
Anyway I use the model clause:
create table PaymentScheduleTable
( schedid number(10)
, startdate date
, term number(3)
, frequency number(3)
, paymentamt number(5)
);
insert into PaymentScheduleTable
values (1,to_date('05-01-2003','dd-mm-yyyy')
, 48
, 12
, 1000);
insert into PaymentScheduleTable
values (2,to_date('20-12-2008','dd-mm-yyyy')
, 42
, 6
, 25);
commit;
And now the select with model clause:
select schedid, to_char(duedate,'dd-mm-yyyy') duedate, expected, i paymentnum
from paymentscheduletable
model
partition by (schedid)
dimension by (1 i)
measures (
startdate duedate
, paymentamt expected
, term
, frequency)
rules
( expected[for i from 1 to term[1]/frequency[1] increment 1]
= nvl(expected[cv()-1],0) + expected[1]
, duedate[for i from 1 to term[1]/frequency[1] increment 1]
= add_months(duedate[1], (cv(i)-1) * frequency[1])
)
order by schedid,i;
This outputs:
SCHEDID DUEDATE EXPECTED PAYMENTNUM
---------- ---------- ---------- ----------
1 05-01-2003 1000 1
1 05-01-2004 2000 2
1 05-01-2005 3000 3
1 05-01-2006 4000 4
2 20-12-2008 25 1
2 20-06-2009 50 2
2 20-12-2009 75 3
2 20-06-2010 100 4
2 20-12-2010 125 5
2 20-06-2011 150 6
2 20-12-2011 175 7
11 rows selected.
I didn't set out to answer my own question, but I'm doing work with Oracle now and I have had to learn some new Oracle-flavored things.
Anyway, the CONNECT BY statement is really nice--yes, much nicer than MSSQL's hierchical query approach, and using that construct, I was able to produce a very clean query that does what I was looking for:
SELECT DISTINCT
t.SchedID
,level as PaymentNum
,add_months(T.StartDate,level - 1) as DueDate
,(level * t.PaymentAmt) as RunningTotal
FROM SchedTest t
CONNECT BY level <= (t.Term / t.Frequency)
ORDER BY t.SchedID, level
My only remaining issue is that I had to use DISTINCT because I couldn't figure out how to select my rows from DUAL (the affable one-row Oracle table) instead of from my table of schedule data, which has at least 2 rows. If I could do the above with FROM DUAL, then my DISTINCT indicator wouldn't be necessary. Any thoughts?
Other than that, I think this is pretty nice. Et tu?