There is 1 record having duplicate values except in 1 column having x and y
record status
XXXXXXXXXX A
XXXXXXXXXX B
Need to pull A only and remove the other duplicate B
Select record
case
when status in ("'a', 'b'") then ('a')
from xyz
Let suppose you have data as below where Status is repeating for First column
but you are interesting in the status which is of having lower value as given below:
In this case following SQL may help. Here, we are partitioning on key field and ordering the Status so that we can apply filter on rank to get desired result.
WITH sampleData AS
(SELECT '1234' as Field1, 'A' as STATUS UNION ALL
SELECT '1234', 'C' UNION ALL
SELECT '5678', 'A' UNION ALL
SELECT '5678', 'B' )
select * except(rank) from (
select *, rank() over (partition by Field1 order by STATUS ASC) rank from sampleData)
where rank = 1
order by Field1
Consider below approach
select * from sampledata
qualify 1 = row_number() over win
window win as (partition by field1 order by if(status='A',1,2) )
if applied to sample data in your question - output is
Related
My Input data (data in table is):
I have this requirement where I need to find first and last entry as well as first entered and last entered/modified.
When I have a query like (Not exact query - this query is BIG MESS, I am simplifying for sake of PoC):
Select field1, field2, min(EnteredDate), max(EnteredDate) from table where field = <fieldvalue> group by field1 AND EnteredBy
Don't ask me why we are grouping by "EnteredBy", this is the mess I am dealing and done by former team.
Right now the results are something like
Actually the output of the query should be like below:
Can someone please provide guidance on how I can achieve this? Thank you!
Expected output in text format:
Field1 Field2 First entered by First entered date Last entered By Last Entered Date
1 hello User1 3/9/2022 User2 3/11/2022
2 somenew User2 3/10/2022 User1 3/11/2022
To get the first / last rows' values with some specified ordering, use the window functions first_value / last_value
The window frame clause must be specified explicitly for LAST_VALUE to work since the default frame is RANGE UNBOUNDED PRECEDING AND CURRENT ROW, which always yields the current row for LAST_VALUE.
DISTINCT drops all duplicate rows in the following query and returns only 1 row for each combination of field1, field2
SELECT DISTINCT
field1
, field2
, FIRST_VALUE(entered_by) OVER w first_entered_by
, FIRST_VALUE(entered_date) OVER w first_entered_date
, LAST_VALUE(entered_by) OVER w last_entered_by
, LAST_VALUE(entered_date) OVER w last_entered_date
FROM mytable
WINDOW w AS (
PARTITION by field1, field2
ORDER BY entered_date
ROWS BETWEEN UNBOUNDED PRECEDING AND UNBOUNDED FOLLOWING
)
ORDER BY field1
Here's a DB Fiddle illustrating how to do it with sample data & set up code
I have two tables, one with a single row for each "batch_number" and another with defect details for each batch. The first table has a "defect_of_interest" column which I would like to link to one of the columns in the second table. I am trying to write a query that would then pick the maximum value in that dynamically linked column for any "unit_number" in the "batch_number".
Here is the SQLFiddle with example data for each table: http://sqlfiddle.com/#!9/a1c27d
For example, the maximum value in the DEFECT_DETAILS.SCRATCHES column for BATCH_NUMBER = A1 is 12.
Here is my desired output:
BATCH_NUMBER DEFECT_OF_INTEREST MAXIMUM_DEFECT_COUNT
------------ ------------------ --------------------
A1 SCRATCHES 12
B3 BUMPS 4
C2 STAINS 9
I have tried using the PIVOT function, but I can't get it to work. Not sure if it works in cases like this. Any help would be much appreciated.
If the number of columns is fixed (it seems to be) you can use CASE to select the specific value according to the related table. Then aggregating is simple.
For example:
select
batch_number,
max(defect_of_interest) as defect_of_interest,
max(defect_count) as maximum_defect_count
from (
select
d.batch_number,
b.defect_of_interest,
case when b.defect_of_interest = 'SCRATCHES' then d.scratches
when b.defect_of_interest = 'BUMPS' then d.bumps
when b.defect_of_interest = 'STAINS' then d.stains
end as defect_count
from defect_details d
join batches b on b.batch_number = d.batch_number
) x
group by batch_number
order by batch_number;
See Oracle example in db<>fiddle.
I have a simple inline view that contains 2 columns.
-----------------
rn | val
-----------------
0 | A
... | ...
25 | Z
I am trying to select a val by matching the rn randomly by using the dbms_random.value() method as in
with d (rn, val) as
(
select level-1, chr(64+level) from dual connect by level <= 26
)
select * from d
where rn = floor(dbms_random.value()*25)
;
My expectation is it should return one row only without failing.
But now and then I get multiple rows returned or no rows at all.
on the other hand,
>>select floor(dbms_random.value()*25) from dual connect by level <1000
returns a whole number for each row and I failed to see any abnormality.
What am I missing here?
The problem is that the random value is recalculated for each row. So, you might get two random values that match the value -- or go through all the values and never get a hit.
One way to get around this is:
select d.*
from (select d.*
from d
order by dbms_random.value()
) d
where rownum = 1;
There are more efficient ways to calculate a random number, but this is intended to be a simple modification to your existing query.
You also might want to ask another question. This question starts with a description of a table that is not used, and then the question is about a query that doesn't use the table. Ask another question, describing the table and the real problem you are having -- along with sample data and desired results.
I have a table that looks like this:
Column A | Column B | Counter
---------------------------------------------
A | B | 53
B | C | 23
A | D | 11
C | B | 22
I need to remove the last row because it's cyclic to the second row. Can't seem to figure out how to do it.
EDIT
There is an indexed date field. This is for Sankey diagram. The data in the sample table is actually the result of a query. The underlying table has:
date | source node | target node | path count
The query to build the table is:
SELECT source_node, target_node, COUNT(1)
FROM sankey_table
WHERE TO_CHAR(data_date, 'yyyy-mm-dd')='2013-08-19'
GROUP BY source_node, target_node
In the sample, the last row C to B is going backwards and I need to ignore it or the Sankey won't display. I need to only show forward path.
Removing all edges from your graph where the tuple (source_node, target_node) is not ordered alphabetically and the symmetric row exists should give you what you want:
DELETE
FROM sankey_table t1
WHERE source_node > target_node
AND EXISTS (
SELECT NULL from sankey_table t2
WHERE t2.source_node = t1.target_node
AND t2.target_node = t1.source_node)
If you don't want to DELETE them, just use this WHERE clause in your query for generating the input for the diagram.
If you can adjust how your table is populated, you can change the query you're using to only retrieve the values for the first direction (for that date) in the first place, with a little bit an analytic manipulation:
SELECT source_node, target_node, counter FROM (
SELECT source_node,
target_node,
COUNT(*) OVER (PARTITION BY source_node, target_node) AS counter,
RANK () OVER (PARTITION BY GREATEST(source_node, target_node),
LEAST(source_node, target_node), TRUNC(data_date)
ORDER BY data_date) AS rnk
FROM sankey_table
WHERE TO_CHAR(data_date, 'yyyy-mm-dd')='2013-08-19'
)
WHERE rnk = 1;
The inner query gets the same data you collect now but adds a ranking column, which will be 1 for the first row for any source/target pair in any order for a given day. The outer query then just ignores everything else.
This might be a candidate for a materialised view if you're truncating and repopulating it daily.
If you can't change your intermediate table but can still see the underlying table you could join back to it using the same kind of idea; assuming the table you're querying from is called sankey_agg_table:
SELECT sat.source_node, sat.target_node, sat.counter
FROM sankey_agg_table sat
JOIN (SELECT source_node, target_node,
RANK () OVER (PARTITION BY GREATEST(source_node, target_node),
LEAST(source_node, target_node), TRUNC(data_date)
ORDER BY data_date) AS rnk
FROM sankey_table) st
ON st.source_node = sat.source_node
AND st.target_node = sat.target_node
AND st.rnk = 1;
SQL Fiddle demos.
DELETE FROM yourTable
where [Column A]='C'
given that these are all your rows
EDIT
I would recommend that you clean up your source data if you can, i.e. delete the rows that you call backwards, if those rows are incorrect as you state in your comments.
We have a table with following data
Id,ItemId,SeqNumber;DateTimeTrx
1,100,254,2011-12-01 09:00:00
2,100,1,2011-12-01 09:10:00
3,200,7,2011-12-02 11:00:00
4,200,5,2011-12-02 10:00:00
5,100,255,2011-12-01 09:05:00
6,200,3,2011-12-02 09:00:00
7,300,0,2011-12-03 10:00:00
8,300,255,2011-12-03 11:00:00
9,300,1,2011-12-03 10:30:00
Id is an identity column.
The sequence for an ItemId starts from 0 and goes till 255 and then resets to 0. All this information is stored in a table called Item. The order of sequence number is determined by the DateTimeTrx but such data can enter any time into the system. The expected output is as shown below-
ItemId,PrevorNext,SeqNumber,DateTimeTrx,MissingNumber
100,Previous,255,2011-12-01 09:05:00,0
100,Next,1,2011-12-01 09:10:00,0
200,Previous,3,2011-12-02 09:00:00,4
200,Next,5,2011-12-02 10:00:00,4
200,Previous,5,2011-12-02 10:00:00,6
200,Next,7,2011-12-02 11:00:00,6
300,Previous,1,2011-12-03 10:30:00,2
300,Next,255,2011-12-03 16:30:00,2
We need to get those rows one before and one after the missing sequence. In the above example for ItemId 300 - the record with sequence 1 has entered first (2011-12-03 10:30:00) and then 255(2011-12-03 16:30:00), hence the missing number here is 2. So 1 is previous and 255 is next and 2 is the first missing number. Coming to ItemId 100, the record with sequence 255 has entered first (2011-12-02 09:05:00) and then 1 (2011-12-02 09:10:00), hence 255 is previous and then 1, hence 0 is the first missing number.
In the above expected result, MissingNumber column is the first occuring missing number just to illustrate the example.
We will not have a case where we would have a complete series reset at one time i.e. it can be either a series rundown from 255 to 0 as in for itemid 100 or 0 to 255 as in ItemId 300. Hence we need to identify sequence missing when in ascending order (0,1,...255) or either in descending order (254,254,0,2) etc.
How can we accomplish this in a t-sql?
Could work like this:
;WITH b AS (
SELECT *
,row_number() OVER (ORDER BY ItemId, DateTimeTrx, SeqNumber) AS rn
FROM tbl
), x AS (
SELECT
b.Id
,b.ItemId AS prev_Itm
,b.SeqNumber AS prev_Seq
,c.ItemId AS next_Itm
,c.SeqNumber AS next_Seq
FROM b
JOIN b c ON c.rn = b.rn + 1 -- next row
WHERE c.ItemId = b.ItemId -- only with same ItemId
AND c.SeqNumber <> (b.SeqNumber + 1)%256 -- Seq cycles modulo 256
)
SELECT Id, prev_Itm, 'Previous' AS PrevNext, prev_Seq
FROM x
UNION ALL
SELECT Id, next_Itm ,'Next', next_Seq
FROM x
ORDER BY Id, PrevNext DESC
Produces exactly the requested result.
See a complete working demo on data.SE.
This solution takes gaps in the Id column into consideration, as there is no mention of a gapless sequence of Ids in the question.
Edit2: Answer to updated question:
I updated the CTE in the query above to match your latest verstion - or so I think.
Use those columns that define the sequence of rows. Add as many columns to your ORDER BY clause as necessary to break ties.
The explanation to your latest update is not entirely clear to me, but I think you only need to squeeze in DateTimeTrx to achieve what you want. I have SeqNumber in the ORDER BY additionally to break ties left by identical DateTimeTrx. I edited the query above.