Group by date and find median of processing time - sql

Question

I select input date and output date from a database. I use a formula to indicate the processing time. Now, I would like the values ​​to be grouped according to the date of receipt and the median of the processing time to be output for all grouped dates of receipt. Something like this:
The data I select:
input date | output date | processing time
2022-01-03 | 2022-01-03 | 0
2022-01-03 | 2022-01-06 | 3
2022-01-03 | 2022-01-11 | 8
2022-01-05 | 2022-01-10 | 5
2022-01-05 | 2022-01-15 | 10
The output I want:
input date | processing time
2022-01-03 | 3
2022-01-05 | 7.5
My SQL Code:
SELECT [received_date]
,CONVERT(date, [exported_on])
,DATEDIFF(day, [received_date], [exported_on]) AS processing_time
FROM [request] WHERE YEAR (received_date) = 2022
GROUP BY received_date, [exported_on]
ORDER BY received_date
How can I do this? Do I need a temp table to do this, or can I modify my query?

Answer 1

You could try using PERCENTILE_CONT
with cte as (
select input_date,
PERCENTILE_CONT(0.5) WITHIN GROUP (ORDER BY processing_time) OVER(PARTITION BY input_date) as Median_Process_Time
FROM tableA
)
SELECT *
FROM cte
GROUP BY input_date, Median_Process_Time
db fiddle
Also you check check out the discussion here How to find the SQL medians for a grouping

Answer 2

Here my solution. Thank you for your help.
SET NOCOUNT ON;
DECLARE #working TABLE(entry_date date, exit_date date, work_time int)
INSERT INTO #working
SELECT [received] AS date_of_entry
,CONVERT(date, [exported]) AS date_of_exit
,DATEDIFF(day, [received], [exported]) AS processing_time
FROM [zsdt].[dbo].[antrag] WHERE YEAR([received]) = 2022 AND scanner_name IS NOT NULL AND exportiert_am IS NOT NULL AND NOT scanner_name = 'AP99'
GROUP BY [received], [exported]
ORDER BY [received] ASC
;WITH CTE AS
( SELECT entry_date,
work_time,
[half1] = NTILE(2) OVER(PARTITION BY entry_date ORDER BY work_time),
[half2] = NTILE(2) OVER(PARTITION BY entry_date ORDER BY work_time DESC)
FROM #working
WHERE work_time IS NOT NULL
)
SELECT entry_date,
(MAX(CASE WHEN Half1 = 1 THEN work_time END) +
MIN(CASE WHEN Half2 = 1 THEN work_time END)) / 2.0
FROM CTE
GROUP BY entry_date;