Need a resource not Selenium documentation or W3C website, all there is information about Java, Python codes. I need to see how to use FindElement(By) in VBA or
.FindElementByCss("li > div > a=[href]").Click
The most useful site with examples I found is https://endtest.io/guides/blog/2020/07/31/a-practical-guide-for-finding-elements-with-selenium/
You were close enough. As an example for the following HTML:
<li>
<div>
Stack Overflow
</div>
</li>
To identify the desired element you can use either of the following locator strategies:
Using FindElementByCss:
.FindElementByCss("li > div > a[href]")
Using FindElementByCss (canonically):
.FindElementByCss("li > div > a[href*='stackoverflow']")
Using FindElementByXPath (canonically):
.FindElementByXPath("//li/div/a[#href=\"https://stackoverflow.com\"]")
Related
Quick one, i am trying to avoid using xpath and using css selectors due to performance issues xpath can have so i would like to know the right approach of locating for example "A" in the list
<div class="input-search-suggests" xpath="1">
<div class="input-search-suggests-item">A</div>
<div class="input-search-suggests-item">B</div>
<div class="input-search-suggests-item">C</div>
</div>
Currently i am locating A using xpath / span but it would be indeed sufficient locating all elements and then grabbing A from the list that have same class which is "input-search-suggests-item"
#FindBy(xpath = "//span[contains(text(),'A')]")
CSS_SELECTOR does not have support for direct text what xpath has.
What this means is, for the below xpath
xpath = "//span[contains(text(),'A')]"
based on text A you can not write a css selector.
Instead to locate A using css selector, you can do :
div.input-search-suggests > div.input-search-suggests-item
In Selenium something like this :
#FindBy(cssSelector= "div.input-search-suggests > div.input-search-suggests-item")
Even though it will have 3 matching nodes, but findElement will take the first web element.
Also you may wanna look at nth-child(n)
div.input-search-suggests > nth-child(1)
to make use of index to locate A, B, C
Here is the Reference Link
Unable to find CSS selector using :contains().
I have followed the instructions from https://www.browserstack.com/guide/css-selectors-in-selenium
at #5 – Inner text
but still, no result is shown, Can someone please help me/Tell me how to find Web element using text, CSS only
Here is Sample Dom
<ul id='id'>
<li class='class'>
<a class='class_class2' href="/Myaccount/summary">"Summary"</a>
<li class='class'>
<a class='class_class2' href="/Myaccount/Profile">"Profile"</a>
</ul>
Here : a:contains('Summary')
https://developer.mozilla.org/en-US/docs/Web/CSS/Reference
https://stackoverflow.com/a/4781167/6793637
Contains: is no longer available
you should use xpath to find elements using innerText
xpath:
//a[contains(text(),"Summary")]
You can get exact match as
//a[text()="Summary"]
The :contains pseudo-class isn't in the CSS Spec and is not supported by either Firefox or Chrome (even outside WebDriver).
You can find a couple of relevant detailed discussion in:
selenium.common.exceptions.InvalidSelectorException with "span:contains('string')"
Finding link using text in CSS Selector is not working
Alternative
To locate the element with text as Summary you can use either of the following css-selectors:
Using first-child:
ul#id li:first-child > a
Using nth-child():
ul#id > li:nth-child(1) > a
tl; dr
References:
CSS selector :contains doesn't work with Selenium 2.0a7
css pseudo-class :contains() no longer allows anchors
I am inspecting one button element from a web page using chrome driver and selenium. And the html code for the particular button is:
<div class="label text-left text-link link-blue text-
uppercase">Financial Statement Analysis <span class="count">(2)</span>
</div>
I have tried different element options like find element by name, xpath, link text etc. But none of them unable to locate the element.
What will be the element to locate the button. ?
try Xpath :
//span[contains(#class,'count') and text() = '(2)']
You can try with this css selector :
div.label.text-left.text-link.link-blue.text-.uppercase
To locate the element with text as Financial Statement Analysis (2) you can use the following solution:
Java Solution:
WebElement elem = driver.findElement(By.xpath("//div[#class='label text-left text-link link-blue text-uppercase'][contains(.,'Financial Statement Analysis')]"));
Please help me to create the Xpath for the following. I am using Selenium webdriver and have only IE browser. Following is the HTML:
<A
title=""
href="javascript:Plg({u:'/epace/starintfc.html?module=RUN_EVENT',p:0,nw:'0'});"
p="eagle/pace/pace"
la=""
ml="%09NULL%09PLUGIN%09%2fepace%2fstarintfc.html%3fmodule%3dRUN_EVENT%09%09%09%09%09%09%09%09%09%09"
t="Plugin" gh="" g="Data Steward"
pc="Eagle/PACE/PACE Components"
ivname=""
><IMG id=Item.Img
class=link
src="/tpe/modules/site/img/menu_plugin.gif">Run An Event</A>
As I prefer CSS over xPath because of it's simplicity, I will provide both the CSS and xPath solution:
Remember that you want to get the attribute of the elements that have the most specificity. The answers below are the best of my ability, to determine which have the most specificity. (see here if you want to learn more about CSS and specificity of elements)
If you are trying to select the first <a> element...
CSS:
a[href*='RUN_EVENT']
xPath:
//a[contains(#href, 'RUN_EVENT')]
If you are trying to select the <img> that is inside of the <a> tag...
CSS:
a[href*='RUN_EVENT'] > img
xPath:
//a[contains(#href, 'RUN_EVENT')]/img
My guess is that you want the first one since it's a link, and I assume you want to invoke a click on it.
The some part of the html of the webpage which I'm testing looks like this
<div id="twoWideCallouts">
<div class="callout">
<a target="_blank" href="http://facebook.com">Facebook</a>
</div>
<div class="callout last">
<a target="_blank" href="http://youtube.com">Youtube</a>
</div>
I've to check using selenium that when I click on text, the URL opened is the same that is given in href and not error page.
Using Xpath I've written the following command
//i is iterator
selenium.getAttribute("//div[contains(#class, 'callout')]["+i+"]/a/#href")
However, this is very slow and for some of the links doesn't work. By reading many answers and comments on this site I've come to know that CSS loactors are faster and cleaner to maintain so I wrote it again as
css = div:contains(callout)
Firstly, I'm not able to reach to the anchor tag.
Secondly, This page can have any number of div where id = callout. Using xpathcount i can get the count of this, and I'll be iterating on that count and performing the href check. How can something similar be done using CSS locator?
Any help would be appreciated.
EDIT
I can click on the link using the locator css=div.callout a, but when I try to read the href value using String str = "css=div.callout a[href]";
selenium.getAttribute(str);. I get the Error - element not found. Console description is given below.
19:12:33.968 INFO - Command request: getAttribute[css=div.callout a[href], ] on session
19:12:33.993 INFO - Got result: ERROR: Element css=div.callout a[href not found on session
I tried to get the href attribute using xpath like this
"xpath=(//div[contains(#class, 'callout')])["+1+"]/a/#href" and it worked fine.
Please tell me what should be the corresponding CSS locator for this.
It should be -
css = div:contains(callout)
Did you notice ":" instead of "." you used?
For CSSCount this might help -
http://www.eviltester.com/index.php/2010/03/13/a-simple-getcsscount-helper-method-for-use-with-selenium-rc/
#
On a different note, did you see proposal of new selenium site on area 51 - http://area51.stackexchange.com/proposals/4693/selenium.
#
To read the sttribute I used css=div.callout a#href and it worked. The problem was with use of square brackets around attribute name.
For the first part of your question, anchor your identifier on the hyperlink:
css=a[href=http://youtube.com]
For achieving a count of elements in the DOM, based on CSS selectors, here's an excellent article.