SQL Aggregate Over Date Range - sql

Question

Whoever answers this thank you so, so much!
Here's a little snippet of my data:
DATE Score Multiplier Weighting
2022-01-05 3 4 7
2022-01-05 4 7 8
2022-01-06 5 2 4
2022-01-06 3 4 7
2022-01-06 4 7 8
2022-01-07 5 2 4
Each row of this data is when something "happened" and multiple events occur during the same day.
What I need to do is take the rolling average of this data over the past 3 months.
So for ONLY 2022-01-05, my weighted average (called ADJUSTED) would be:
DATE ADJUSTED
2022-01-05 [(3*4) + (4*7)]/(7+8)
Except I need to do this over the previous 3 months (so on Jan 5, 2022, I'd need the rolling weighted average -- using the "Weighting" column -- over the preceding 3 months; can also use previous 90 days if that makes it easier).
Not sure if this is a clear enough description, but would appreciate any help.
Thank you!

Answer 1

IF I have interpreted this correctly I believe a GROUP BY query will meet the need:
sample data
CREATE TABLE mytable(
DATE DATE NOT NULL
,Score INTEGER NOT NULL
,Multiplier INTEGER NOT NULL
,Weighting INTEGER NOT NULL
);
INSERT INTO mytable(DATE,Score,Multiplier,Weighting) VALUES ('2022-01-05',3,4,7);
INSERT INTO mytable(DATE,Score,Multiplier,Weighting) VALUES ('2022-01-05',4,7,8);
INSERT INTO mytable(DATE,Score,Multiplier,Weighting) VALUES ('2022-01-06',5,2,4);
INSERT INTO mytable(DATE,Score,Multiplier,Weighting) VALUES ('2022-01-06',3,4,7);
INSERT INTO mytable(DATE,Score,Multiplier,Weighting) VALUES ('2022-01-06',4,7,8);
INSERT INTO mytable(DATE,Score,Multiplier,Weighting) VALUES ('2022-01-07',5,2,4);
query
select
date
, sum(score) sum_score
, sum(multiplier) sum_multiplier
, sum(weighting) sum_weight
, (sum(score)*1.0 + sum(multiplier)*1.0) / (sum(weighting)*1.0) ADJUSTED
from mytable
group by date
result
+------------+-----------+----------------+------------+-------------------+
| date | sum_score | sum_multiplier | sum_weight | ADJUSTED |
+------------+-----------+----------------+------------+-------------------+
| 2022-01-05 | 7 | 11 | 15 | 1.200000000000000 |
| 2022-01-06 | 12 | 13 | 19 | 1.315789473684210 |
| 2022-01-07 | 5 | 2 | 4 | 1.750000000000000 |
+------------+-----------+----------------+------------+-------------------+
db<>fiddle here
Note: I have not attempted to avoid possible divide by 0 or any NULL value problems in the query ablove