How to use Intelijj Idea replace tool without changing middle text - intellij-idea

I want to be able to replace some specific strings without changing the middle text.
For example I have code like these in my projects:
<div>{example1}</div>
<div>{example2}</div>
<div>{example3}</div>
after using replace function i want to have this:
<span>example1</span>
<span>example2</span>
<span>example3</span>
since i want to replace all of them at once i can't use replace two times.
I want something like <div>{PreserveHereWhateverItIs}</div> => PreserveHereWhateverItIs
.It will be very useful to replace them at once. Because there are other code i don't want to replace. I am using intelijj idea replace tool. This is not a programming language question. Is there a way to achieve this?

Related

LabVIEW Inserting/overwriting text into existing string

I was wondering if folks have found a reliable way to inject text into an existing string. Some context, I'm writing data to a string indicator formatted like a table, and I wanted to inject values into so they maintain a specific format, spacing-wise. Writing to a table would definitely be easier, however I am porting a legacy program and wanted to provide familiarity to the end user.
Essentially, I want to do the equivalent of typing into a .txt file with the INSERT function enabled, where it just overwrites the content already in the string. Example below (dashes added to show spacing) of how it is currently looking when I inject the values with hard coded spacing:
Time---value---avg. value---result
60------10---------20---------PASS
120------11---------20---------PASS
180------9---------15---------FAIL
I'd prefer it to look more lined up, like below:
Time---value---avg. value---result
60------10---------20---------PASS
120-----11---------20---------PASS
180-----9--------- 15---------FAIL
Writing my application using LabVIEW 2019
Edit: Header will obviously not change, only each subsequent line where the values can result in entries not looking lined up
What about "Replace Substring" function (https://zone.ni.com/reference/en-XX/help/371361R-01/glang/replace_substring/)? Doesn't it meet your requirements?
The diagram below outputs 01234999990123PASS890123456789. The values of the integer and the word PASS are added replacing characters in the existing string, exactly like overstrike would do.

regex limitations within live template / can use live-template functions as replacement?

I'm removing builder pattern on multiple places. Following example would help me with the task, but mainly I'd like to learn how to use live templates more.
Preexisting code:
Something s = s.builder
.a(...)
.b(bbb)
.build();
and I'd like to remove it to:
Something s = new Something();
s.setA(...);
s.setB(bbb);
part of it can be trivially done using intellij regex, pattern: \.(.*)$ and replacement .set\u$1. Well it could be improved, but lets keep it simple.
I can create surround live template using variable:
regularExpression(SELECTION, "\\.(.*)", "\\u$1")
but \\u will be evaluated as u.
question 1: is it possible to get into here somehow \u functionality?
but I might get around is differently, so why not try to use live temlate variable:
regularExpression(SELECTION, "\\.(.)(.*)", concat(capitalize($1), "$2"))
but this does not seem to work either. .abc is replaced to bc
question 2: why? How would correct template look like? And probably, if it worked, this would behave incorrectly for multiline input. How to make it working and also for multiline inputs?
sorry for questions, I didn't find any harder examples of live templates than trivial replacements.
No, there is no \u functionality in the regularExpression() Live Template macro. It is just a way to call String.replaceAll(), which doesn't support \u.
You can create a Live Template like this:
set$VAR$
And set the following expression for the $VAR$ variable:
capitalize(regularExpression(SELECTION, "\\.(.*)", "$1"))

What is the correct way to use multiple variables in a Text element?

I can't seem to find the "correct" way to use multiple variables in a React Native Text element.
I have the users first, and the last name as separate object values and I want to show them in the same Text element.
<Text>{props.user.firstName} {props.user.lastName}</Text>
This works fine, but ESLint doesn't like it. (jsx-one-expression-per-line).
If I put them on separate lines, then I can't figure out where to put the empty space in between first and last name.
<Text>
{props.user.firstName}
{props.user.lastName}
</Text>
There's an empty space after {props.user.firstName}, but ESLint doesn't like that either (no-trailing-spaces).
So I'm asking whether there is a correct way to achieve the result that I want without changing ESLint configuration or creating a separate variable.
You're looking for template literals.
You can nest your variables like so:
<Text>`${props.user.firstName} ${props.user.lastName}`</Text>

Find All in a Textbox

I am working on an application to search for and build a list of all the times a string (or variable of) is in a text file. Kind of like a Find All function in a text editor that I can build a list with the info that is found, such as
S350
S250
S270
S5000
What can I use to do this search? It will have one value that does not change (The S in this case) followed by up to 4 digits
RegEx seems like a good choice.
Something like.. S(\d{1,4})? might work for you.
Expresso is my preferred regular expression composer.

Change Url using Regex

I have url, for example:
http://i.myhost.com/myimage.jpg
I want to change this url to
http://i.myhost.com/myimageD.jpg.
(Add D after image name and before point)
i.e I want add some words after image name and before point using regex.
What is the best way do it using regex?
Try using ^(.*)\.([a-zA-Z]{3,5}) and replacing with \1D\2. I'm assuming the extension is 3-5 alphanumeric numbers but you can modify it to suit. E.g. if it's just jpg images then you can put that instead of the [a-zA-Z]{3,5}.
Sounds like a homework question given the solution must use a regex, on that assumption here is an outline to get you going.
If all you have is a URL then #mathematical.coffee's solution will suit. However if you have a chunk of text within which is one or more URLs and you have to locate and change just those then you'll need something a little more involved.
Look at the structure of a URL: {protocol}{address}{item}; where
{protocol} is "http://", "ftp://" etc.;
{address} is a name, e.g. "www.google.com", or a number, e.g. "74.125.237.116" - there will always be at least one dot in the address; and
{item} is "/name" where name is quite flexible - there will be zero or more items, you can think of them as directories and a file but this isn't strictly true. Also the sequence of items can end in a "/" (including when there are zero of them).
To make a regex which matches a URL start by matching each part. In the case of the items you'll want to match the last in the sequence separately - you'll have zero or more "directories" and one "file", the latter must be of the form "name.extension".
Once you have regexes for each part you just concatenate them to produce a regex for the whole. To form the replacement pattern you can surround parts of your regex with parentheses and refer to those parts using \number in the replacement string - see #mathematical.coffee's solution for an example.
The best way to learn regexs is to use an editor which supports them and just experiment. The exact syntax may not be the same as NSRegularExpression but they are mostly pretty similar for the basic stuff and you can translate from one to another easily.