Table 1
where we have ID as primary key and his own salary
ID
Name
Salary
1
" X "
500
2
" Y "
1000
3
" Z "
1500
table 2
where we have data from the payment system
ID
Date
Salary
1
" 6/22/2020 "
500
2
" 6/25/2020 "
1000
3
" 8/05/2021 "
1500
i want a query to compare items from table 2 with table 1 where my goal is to make sure every employee gets his exact salary paid as it in table 1
example
employee "1" with salary 500 let say on a month he received only 300 want to retrieve employee
* preferred : calculate how many months out of his employment time where he didn't get his exact salary and calculate how much difference $
* Note : the employee might get paid less or more than his salary
Something like this should do it:
select
t1.salary as t1_salary,
t2.*
from
t1 left outer join t2 on t1.id = t2.id
Join tables on ID and put the difference into the where clause.
Sample data (you have it & you don't have to type that):
SQL> with
2 table1 (id, name, salary) as
3 (select 1, 'x', 500 from dual union all
4 select 2, 'y', 1000 from dual
5 ),
6 table2 (id, datum, salary) as
7 (select 1, date '2022-01-01', 500 from dual union all
8 select 1, date '2022-02-01', 300 from dual union all
9 select 1, date '2022-03-01', 500 from dual union all
10 select 1, date '2022-04-01', 700 from dual union all
11 select 2, date '2022-01-01', 1000 from dual union all
12 select 2, date '2022-02-01', 1000 from dual union all
13 select 2, date '2022-03-01', 900 from dual union all
14 select 2, date '2022-04-01', 1200 from dual
15 )
Query begins here:
16 select a.id,
17 a.name,
18 b.datum,
19 b.salary - a.salary as difference
20 from table1 a join table2 b on a.id = b.id
21 where b.salary - a.salary <> 0;
ID NAME DATUM DIFFERENCE
---------- ---- ---------- ----------
1 x 01.02.2022 -200
1 x 01.04.2022 200
2 y 01.03.2022 -100
2 y 01.04.2022 200
SQL>
Related
I have table like this:
id
name
contact
1
A
65489
1
A
1
A
45564
2
B
3
C
12345
3
C
1234
4
D
32
4
D
324
I only want users who have no contact or the contact length is not five.
If the user has two or more contacts and the length of one of them is five and the rest is not, then such users should not be included in the table.
so,If the customer has at least one contact length of five, I do not want that.
so, i want table like this:
id
name
contact
2
B
4
D
32
4
D
324
Can you halp me?
You could actually do a range check here:
SELECT id, name, contact
FROM yourTable t1
WHERE NOT EXISTS (
SELECT 1
FROM yourTable t2
WHERE t2.id = t1.id AND TO_NUMBER(t2.contact) BETWEEN 10000 AND 99999
);
Note that if contact already be a numeric column, then just remove the calls to TO_NUMBER above and compare directly.
Yet another option:
SQL> with test (id, name, contact) as
2 (select 1, 'a', 65879 from dual union all
3 select 1, 'a', null from dual union all
4 select 1, 'a', 45564 from dual union all
5 select 2, 'b', null from dual union all
6 select 3, 'c', 12345 from dual union all
7 select 3, 'c', 1234 from dual union all
8 select 4, 'd', 32 from dual union all
9 select 4, 'd', 324 from dual
10 )
11 select *
12 from test a
13 where exists (select null
14 from test b
15 where b.id = a.id
16 group by b.id
17 having nvl(max(length(b.contact)), 0) < 5
18 );
ID N CONTACT
---------- - ----------
2 b
4 d 32
4 d 324
SQL>
COUNT analytic function can also be used to get the job done.
select id, name, contact
from (
select id, name, contact
, count( decode( length(contact), 5, 1, null ) ) over( partition by id, name ) cnt
from YourTable
)
where cnt = 0
demo
Need a query to get the Employee name, total fuel used by each employee.
If fuel is not used by an employee then the second column should have a
text “No fuel used”.
These are the following two tables:
Table1: EmployeeID, FirstName
1 Vikas
2 nikita
3 Ashish
4 Nikhil
5 anish
Table2: ID, Fuel
1 10
2 9
3 8
4 6
5 12
6 11
7 10
8 9
9 8
10 10
11 9
12 12
13 7
14 15
where The column table2.ID is a foreign key to table1.EmployeeID.
This is code which I have written, Which is most probably wrong.
select ID, FirstName, sum(table2.Fuel) sum_fuel
from table2,table1
where EmployeeID=ID IN (
select ID, coalesce(ID, 'No-fuel used') as ID
from table1 t1
left join table2 t2 on t2.ID = t1.EmployeeID
)
group by fuel
order by ID DESC;
As you can see from two tables that employee with from 1 to 5 of table1 are in table2. So for these employee I need to show total fuel used by every individual. And for employee with ID from 6 to 14 are not available in table1 so for these employee “No fuel used” message should be printed.
You can use a left join. This way, whenever the Id values for tables don't match you'll get null values for sum(fuel) value, and will assign the string 'No fuel used'for sum_fuel column by using nvl() function:
with table1( EmployeeID, FirstName ) as
(
select 1,'Vikas' from dual union all
select 2,'nikita' from dual union all
select 3,'Ashish' from dual union all
select 4,'Nikhil' from dual union all
select 5,'anish' from dual union all
select 15,'pratteek' from dual
), table2( ID, Fuel ) as
(
select 1, 10 from dual union all
select 2, 9 from dual union all
select 3, 8 from dual union all
select 4, 6 from dual union all
select 5, 12 from dual union all
select 6, 11 from dual union all
select 7, 10 from dual union all
select 8, 9 from dual union all
select 9, 8 from dual union all
select 10, 10 from dual union all
select 11, 9 from dual union all
select 12, 12 from dual union all
select 13, 7 from dual union all
select 14, 15 from dual
)
select EmployeeID, FirstName, nvl(to_char(sum(t2.Fuel)),'No fuel used') as sum_fuel
from table1 t1
left join table2 t2
on t1.EmployeeID = t2.ID
group by EmployeeID, FirstName
order by EmployeeID desc;
EMPLOYEEID FIRSTNAME SUM_FUEL
---------- --------- ------------
15 pratteek No fuel used
5 anish 12
4 Nikhil 6
3 Ashish 8
2 nikita 9
1 Vikas 10
Demo
This may work---
SELECT ID
, FirstName
, CASE
WHEN SUM(f.Fuel) > 0 THEN CAST(SUM(f.Fuel) AS NVARCHAR(25))
ELSE 'No fuel used'
END sum_fuel
FROM #emp e
LEFT JOIN #fuel f ON e.EmployeeID = f.id
GROUP BY ID,FirstName
ORDER BY ID DESC
I'm newbie in SQL Developer.
I have a query result like the above image.
I want to know how to sum all values with Flag = 1 and to subtract all the values With Flag = 2 in order to obtain a total result?
With a little help of DECODE, here's how:
SQL> with test (value, flag) as
2 (select 100, 2 from dual union -- sum of flag 2 values = 600
3 select 200, 2 from dual union
4 select 300, 2 from dual union
5 --
6 select 700, 1 from dual union -- sum of flag 1 values = 1500
7 select 800, 1 from dual
8 )
9 select sum(decode(flag, 1, value, 0)) sum_1,
10 sum(decode(flag, 2, value, 0)) sum_2,
11 --
12 sum(decode(flag, 1, value, 0)) - sum(decode(flag, 2, value, 0)) result
13 from test;
SUM_1 SUM_2 RESULT
---------- ---------- ----------
1500 600 900
SQL>
I have two tables Sales and Charges.
Tables having data as:
'Sales' 'Charges'
SID F_AMT SID C_AMT
1 100 1 10
1 100 1 10
1 100 1 20
1 200 2 20
2 200 2 10
2 300 3 20
4 300 3 30
4 300 3 10
4 300 5 20
4 200 5 10
I want the output as below:
SID Total_Fees Total_charges
1 500 40
2 500 30
3 0 60
4 1100 0
5 0 30
Assuming you want to do it for the whole tables this is the simplest approach:
Select Sid
, Sum(f_amt) as total_fees
, Sum(c_amt) as total_charges
From ( select sid, f_amt, 0 as c_amt
From sales
Union all
select sid, 0 as f_amt, c_amt
From charges
)
Group by sid
Use full join and nvl():
select sid, nvl(sum(f_amt), 0) fees, nvl(sum(c_amt), 0) charges
from sales s
full join charges c using (sid)
group by sid
order by sid
Demo:
with sales(sid, f_amt) as (
select 1, 100 from dual union all select 1, 100 from dual union all
select 1, 100 from dual union all select 1, 200 from dual union all
select 2, 200 from dual union all select 2, 300 from dual union all
select 4, 300 from dual union all select 4, 300 from dual union all
select 4, 300 from dual union all select 4, 200 from dual ),
charges (sid, c_amt) as (
select 1, 10 from dual union all select 1, 10 from dual union all
select 1, 20 from dual union all select 2, 20 from dual union all
select 2, 10 from dual union all select 3, 20 from dual union all
select 3, 30 from dual union all select 3, 10 from dual union all
select 5, 20 from dual union all select 5, 10 from dual )
select sid, nvl(sum(f_amt), 0) fees, nvl(sum(c_amt), 0) charges
from sales s
full join charges c using (sid)
group by sid
order by sid
Output:
SID FEES CHARGES
------ ---------- ----------
1 1500 160
2 1000 60
3 0 60
4 1100 0
5 0 30
You could use conditional aggregation:
SELECT SID,
COALESCE(SUM(CASE WHEN t=1 THEN AMT END),0) AS Total_Fees,
COALESCE(SUM(CASE WHEN t=2 THEN AMT END),0) AS Total_Charges
FROM (SELECT SID, F_AMT AS AMT, 1 AS t
FROM Sales
UNION ALL
SELECT SID, C_AMT AS AMT, 2 AS t
FROM Charges) sub
GROUP BY SID
ORDER BY SID;
DB Fiddle Demo
Suppose I have an SQL (Oracle Toad) table named "test", which has the following fields and entries (dates are in dd/mm/yyyy format):
id ref_date value
---------------------
1 01/01/2014 20
1 01/02/2014 25
1 01/06/2014 3
1 01/09/2014 6
2 01/04/2015 7
2 01/08/2015 43
2 01/09/2015 85
2 01/12/2015 4
I know from how the table has been created that, since there are value entries for id = 1 for February 2014 and June 2014, the values for March through May 2014 must be 0. The same applies to July and August 2014 for id = 1, and for May through July 2015 and October through November 2015 for id = 2.
Now, if I want to calculate, say, the median of the value column for a given id, I will not arrive at the correct result using the table as it stands - as I'm missing 5 zero entries for each id.
I would therefore like to create/use the following (potentially just temporary table)...
id ref_date value
---------------------
1 01/01/2014 20
1 01/02/2014 25
1 01/03/2014 0
1 01/04/2014 0
1 01/05/2014 0
1 01/06/2014 3
1 01/07/2014 0
1 01/08/2014 0
1 01/09/2014 6
2 01/04/2015 7
2 01/05/2015 0
2 01/06/2015 0
2 01/07/2015 0
2 01/08/2015 43
2 01/09/2015 85
2 01/10/2015 0
2 01/11/2015 0
2 01/12/2015 4
...on which I could then compute the median by id:
select id, median(value) as med_value from test group by id
How do I do this? Or would there be an alternative way?
Many thanks,
Mr Clueless
In this solution, I build a table with all the "needed dates" and value of 0 for all of them. Then, instead of a join, I do a union all, group by id and ref_date and ADD the values in each group. If the date had a row with a value in the original table, then that's the resulting value; and if it didn't, the value will be 0. This avoids a join. In almost all cases a union all + aggregate will be faster (sometimes much faster) than a join.
I added more input data for more thorough testing. In your original question, you have two id's, and for both of them you have four positive values. You are missing five values in each case, so there will be five zeros (0) which means the median is 0 in both cases. For id=3 (which I added) I have three positive values and three zeros; the median is half of the smallest positive number. For id=4 I have just one value, which then should be the median as well.
The solution includes, in particular, an answer to your specific question - how to create the temporary table (which most likely doesn't need to be a temporary table at all, but an inline view). With factored subqueries (in the WITH clause), the optimizer decides if to treat them as temporary tables or inline views; you can see what the optimizer decided if you look at the Explain Plan.
with
inputs ( id, ref_date, value ) as (
select 1, to_date('01/01/2014', 'dd/mm/yyyy'), 20 from dual union all
select 1, to_date('01/02/2014', 'dd/mm/yyyy'), 25 from dual union all
select 1, to_date('01/06/2014', 'dd/mm/yyyy'), 3 from dual union all
select 1, to_date('01/09/2014', 'dd/mm/yyyy'), 6 from dual union all
select 2, to_date('01/04/2015', 'dd/mm/yyyy'), 7 from dual union all
select 2, to_date('01/08/2015', 'dd/mm/yyyy'), 43 from dual union all
select 2, to_date('01/09/2015', 'dd/mm/yyyy'), 85 from dual union all
select 2, to_date('01/12/2015', 'dd/mm/yyyy'), 4 from dual union all
select 3, to_date('01/01/2016', 'dd/mm/yyyy'), 12 from dual union all
select 3, to_date('01/03/2016', 'dd/mm/yyyy'), 23 from dual union all
select 3, to_date('01/06/2016', 'dd/mm/yyyy'), 2 from dual union all
select 4, to_date('01/11/2014', 'dd/mm/yyyy'), 9 from dual
),
-- the "inputs" table constructed above is for testing only,
-- it is not part of the solution.
ranges ( id, min_date, max_date ) as (
select id, min(ref_date), max(ref_date)
from inputs
group by id
),
prep ( id, ref_date, value ) as (
select id, add_months(min_date, level - 1), 0
from ranges
connect by level <= 1 + months_between( max_date, min_date )
and prior id = id
and prior sys_guid() is not null
),
v ( id, ref_date, value ) as (
select id, ref_date, sum(value)
from ( select id, ref_date, value from prep union all
select id, ref_date, value from inputs
)
group by id, ref_date
)
select id, median(value) as median_value
from v
group by id
order by id -- ORDER BY is optional
;
ID MEDIAN_VALUE
-- ------------
1 0
2 0
3 1
4 9
If ref_date is date and is second
with int1 as (select id
, max(ref_date) as max_date
, min(ref_date) as min_date from test group by id )
, s(n) as (select level -1 from dual connect by level <= (select max(months_between(max_date, min_date)) from int1 ) )
select i.id
, add_months(i.min_date,s.n) as ref_date
, nvl(value,0) as value
from int1 i
join s on add_months(i.min_date,s.n) <= i.max_date
LEFT join test t on t.id = i.id and add_months(i.min_date,s.n) = t.ref_date
And with median
with int1 as (select id
, max(ref_date) as max_date
, min(ref_date) as min_date from test group by id )
, s(n) as (select level -1 from dual connect by level <= (select max(months_between(max_date, min_date)) from int1 ) )
select i.id
, MEDIAN(nvl(value,0)) as value
from int1 i
join s on add_months(i.min_date,s.n) <= i.max_date
LEFT join test t on t.id = i.id and add_months(i.min_date,s.n) = t.ref_date
group by i.id