Fill in the date gaps from the stuff - sql

Question

I have this result, [year.month week] with my query below
[2021.12 51],[2021.12 53],[2022.01 1],[2022.01 2],[2022.01 3],[2022.01 5],[2022.01 6],[2022.02 10]
My goal is to fill in the gaps of the week, for example:
[2021.12 51],**[2021.12 52]**,[2021.12 53],[2022.01 1],[2022.01 2],[2022.01 3],**[2022.01 4]**,[2022.01 5],[2022.01 6],**[2022.01 7]**,**[2022.01 8]**,**[2022.01 9]**,[2022.02 10]
How could I do this with my query below:
DECLARE
#startdate datetime,
#enddate datetime,
#paramdef nvarchar(max)
set #startdate = '2021-01-01 00:00:00.000';
set #enddate = GETDATE();
set #paramdef = '#startdate datetime, #enddate datetime';
SELECT STUFF
(
(
SELECT
',' + QUOTENAME( S_FORMATTED_WEEK_MONTH )
FROM
MONITORING
WHERE
S_DATE_TO >= #startdate AND
S_DATE_TO <= #enddate
GROUP BY
S_FORMATTED_WEEK_MONTH
ORDER BY
CAST( REPLACE( SUBSTRING(S_FORMATTED_WEEK_MONTH, 1, 7), '.', '' ) AS INT ),
CAST( REPLACE( SUBSTRING(S_FORMATTED_WEEK_MONTH, 8, 9), '.', '' ) AS INT )
FOR XML PATH(''), TYPE
).value('.', 'NVARCHAR(MAX)') ,1,1,''
)

Answer 1

you can use the below calendar table approach to get the list of weeknumbers as per your format.
DECLARE #StartDate DATE = '2021-01-01'
DECLARE #EndDate DATE = getdate()
;WITH Cal(n) AS
(
SELECT 0 UNION ALL SELECT n + 1 FROM Cal
WHERE n < DATEDIFF(DAY, #StartDate, #EndDate)
),
FnlDt(d,y,m,w) AS
(
SELECT DATEADD(DAY, n, #StartDate)
, year(DATEADD(DAY, n, #StartDate))
, month(DATEADD(DAY, n, #StartDate))
, datepart(week,DATEADD(DAY, n, #StartDate)) FROM Cal
)
select
string_agg(weekarr,',') as concat_weekarr
from
(SELECT concat('[',y,'.',m,' ',w,']') as weekarr
FROM fnlDt
group by y,m,w
) as dt
option(maxrecursion 32767)
[2021.1 1],[2021.1 2],[2021.1 3],[2021.1 4],...