How to delete 1 character in SQL - sql

ID column has some values starting with ' and some do not. How can I use function to delete all ' in ID Column.
Thanks a lot!


You should provide your attempts next time, that shows you're actually trying to achieve something on your own but here you go:
update <your_table> t
-- desired columns go here
set t.id = regexp_replace(t.id, '^''{1}', '')
-- can be omitted if you want to scan all records
where t.id like '''%';
If you want to replace all quote characters you can do this:
update <your_table> t
-- desired columns go here
set t.id = replace(t.id, '''', '')
where t.id like '''%';

Related

Inserting space between the string (SQL Server)

I have a table called Manufacturers which contains a column Name with a data type of Varchar(100) that has 5761 entries such as XYZ(XYZ Corp).
I wish to insert a space between the Z and the (.
I have seen the STUFF and LEFT commands but can't seem to figure out if they apply to my scenario.

You can try the REPLACE (Transact-SQL)
function as shown below.
update <yourTableName>
set <yourColumName> = replace(<yourColumName>, '(', ' ( ')
where <put the conditions here>
Here is an implementation to you.
create table test (Name varchar(20))
insert into test values ('XYZ(XYZ Corp)')
--selecting before update
select * from test
--updating the record
update test
set Name = replace(Name, '(', ' (')
where name like '%(%' --Here you can add the conditions as you want to restrict the number of rows to be updated based on the available data or the patterns.
--selecting after update
select * from test
Live Demo

I would recommend:
update Manufacturers
set name = replace(name, '(', ' (')
where name like '%[^ ](%';
This will only update rows where there is not already a space before the open paren.
Note: If you have multiple open parens, it will update all of them. If that is an issue, ask a new question with appropriate sample data.

SQL server trimming string

I have a query, I want to Trim a column and get the only Right side values:
Here in the pic the result is like SubAccountCode and SubaccountName but user has entered code and name in SubaccountName. I want to trim the codes from Subaccountname and update the table. T
The query I have tried is mentioned below, but I think it's not so working:
Select Substring(Subaccountname,8,20)as Name from #temp

There are several ways to do this.
When looking at your example data the easiest way would be using an replace() in the update statement.
Syntax:
REPLACE ( string_expression , string_pattern , string_replacement )
Example:
UPDATE table_name
SET column2 = replace([column2], [column1], '')
What this does it updates the column2 with the value from column2 where the value from column1 is replaced with '' nothing. In your example this does leave you with an unwanted space in front. You could trim this or try as followed:
UPDATE Test
SET [SubAccountName] = replace([SubAccountName], [SubAccountCode] + ' ', '')
If the SubAccountCode could be different from the code in the SubAccountName and you only want to remove the first 8 characters (if you are sure it is always the first 8) you can use:
UPDATE YourTable SET SubAccountName = RIGHT(SubAccountName, LEN(SubAccountName) - 7)
Example script:
create table test (
SubAccountName varchar(100),
SubAccountCode varchar(100)
)
insert into test (SubAccountCode, SubAccountName) VALUES
(1234567, '1234567 AUBC' ),
(1234467, '1234467 AUBC' ),
(1235567, '1235567 AUBC' )
select * from test -- Check that the data is like your example.
UPDATE Test SET SubAccountName = RIGHT(SubAccountName, LEN(SubAccountName) - 8)
select * from test -- Check that the result is like your wanted result.
drop table test -- Cleanup the test table.

This code will work for you.
UPDATE TableName SET SubaccountName = REPLACE(LTRIM(RTRIM(SubaccountName)),LTRIM(RTRIM(SubAccountCode)),'')

How to replace underscore with a blank space with a regular expression in SQL

I'm trying to insert post codes into my database but getting rid of the underscores.
I have a table called FeedDataSetMapping that is used to map the fields before they get inserted:
INSERT INTO FeedDataSetMapping (
[source_field]
,[database_field]
,[template_id]
,[conversion_id]
,[order_id]
,[values_group]
,[direct_value]
,[value_regex]
,[condition_regex]
,[split_separator]
,[enclosing_character]
,[cumulative_field]
,[cumulative_format])
VALUES
('manufacturerId','manufacturer_Id',#template_id,0,0,null,null,null,null,null,null,null,null),
('dealership','leasing_broker_name',#template_id,0,0,null,null,null,null,null,null,null,null),
('manufacturersDealerId','supplier_ref',#template_id,0,0,null,null,19,null,null,null,null,null),
('address1','address1',#template_id,0,0,null,null,null,null,null,null,null,null),
('address2','address2',#template_id,0,0,null,null,null,null,null,null,null,null),
('postcode','post_code',#template_id,0,0,null,null,null,null,null,null,null,null),
('telephone','telephone',#template_id,0,0,null,null,null,null,null,null,null,null),
('fax','fax_number',#template_id,0,0,null,null,null,null,null,null,null,null),
('email','email',#template_id,0,0,null,null,null,null,null,null,null,null),
('website','web_address',#template_id,0,0,null,null,null,null,null,null,null,null),
('NewCarSales','service_mask',#template_id,0,0,null,1,null,'^(?!(?i:^0$|^n$|^no$|^f$|^false$|^$))',null,null,1,null),
('UsedCarSales','service_mask',#template_id,0,0,null,2,null,'^(?!(?i:^0$|^n$|^no$|^f$|^false$|^$))',null,null,1,null),
('Servicing','service_mask',#template_id,0,0,null,8,null,'^(?!(?i:^0$|^n$|^no$|^f$|^false$|^$))',null,null,1,null),
('Repairs','service_mask',#template_id,0,0,null,16,null,'^(?!(?i:^0$|^n$|^no$|^f$|^false$|^$))',null,null,1,null),
('Longitude','longitude',#template_id,0,0,null,null,null,null,null,null,null,null),
('Latitude','latitude',#template_id,0,0,null,null,null,null,null,null,null,null)
This already contains some condition regex that in case that this field contains some text it converts it to true or false respectively.
What I need is a condition_regex that gets rid of these underscores and replaces it with a blank space i.e: 'GDB_A45' to 'GDB A45'. I don't know much about regex so any idea would be greatly appreciated. Thanks in advance!

SQL Server does not have much of regular expression support, but in this case I don't think you need it. You can do a simple replace:
UPDATE mytable
SET mycolumn = REPLACE(mycolumn, '_', ' ')
WHERE mycolumn LIKE '%[_]%'
To do this while updating you can use INSERT ... SELECT instead of INSERT ... VALUES:
INSERT INTO mytable (mycolumn)
SELECT REPLACE('my data 1', '_', ' ') UNION
SELECT REPLACE('my data 2', '_', ' ') UNION
SELECT REPLACE('my_data_3', '_', ' ') UNION
...
There will be some maximum number of unions you can do, so you should split your inserts into batches with this method.
Or, you could define a trigger on the target table that will do the job for you:
CREATE TRIGGER mytrigger ON mytable
AFTER INSERT AS
BEGIN
UPDATE mytable
SET mytable.mycolumn = REPLACE(i.mycolumn, '_', ' ')
FROM mytable
INNER JOIN inserted i
ON i.id = mytable.id
AND i.mycolumn LIKE '%[_]%'
END
... where it is assumed your table has a primary key named id.

Well after been thinking a while I got to the conclusion that would be easier if I replace the underscore from the scraped data during the scraping (in the c# code) before I generate the XML file. That would avoid me a lot of headaches. Anyway thank you for your help guys ;)

How to replace duplicate words in a column with just one word in SQL Server

I have a few million strings that relate to file paths in my database;
due to a third party program these paths have become nested like below:
C:\files\thirdparty\thirdparty\thirdparty\thirdparty\thirdparty\thirdparty\unique_bit_here\
I want update the entries so that thirdparty\thirdparty\etc becomes \thirdparty.
I have tried this code:
UPDATE table
SET Field = REPLACE(Field, 'tables\thirdparty\%thirdparty\%\', 'tables\thirdparty\')

WHILE EXISTS (SELECT * FROM table WHERE Field LIKE '%\thirdparty\thirdparty\%')
BEGIN
UPDATE table SET Field = REPLACE(Field, '\thirdparty\thirdparty\', '\thirdparty\')
END

So do you want something like this?
SELECT SUBSTRING('tables\thirdparty\%thirdparty\%\',0,CHARINDEX('\','tables\thirdparty\%thirdparty\%\',0)) + '\thirdparty\'
OR
UPDATE table
SET Field = REPLACE(Field, Field, (SELECT SUBSTRING(Field,0,CHARINDEX('\',Field,0)) + '\thirdparty\'))

You can avoid using a loop with the following technique:
Update TABLE
SET Field = left(Field,charindex('*',replace(Field, 'thirdparty\', '*'))-1)+'thirdparty\'+right(Field,charindex('*',reverse(replace(Field, 'thirdparty\', '*')))-1)

Its too late, but I just guess if I want replace a single word in repeating multiple time same word as he want. This will replace all with append a single time '\thirdparty'...
Check this.
Declare #table table(Field varchar(max))
insert into #table values('C:\files\thirdparty\thirdparty\thirdparty\thirdparty\thirdparty\thirdparty\unique_bit_here\')
,('C:\files\thirdparty\thirdparty\thirdparty\thirdparty\thirdparty\thirdparty\unique_bit_here\1')
,('C:\files\thirdparty\thirdparty\thirdparty\thirdparty\thirdparty\thirdparty\unique_bit_here\2')
,('C:\files\thirdparty\thirdparty\thirdparty\thirdparty\thirdparty\thirdparty\unique_bit_here\3')
,('C:\files\thirdparty\thirdparty\thirdparty\thirdparty\thirdparty\thirdparty\unique_bit_here\4')
UPDATE #table
SET Field = SUBSTRING (Field, 1, CHARINDEX('\thirdparty', Field ) ) + 'thirdparty\'
--replace (Field , 'thirdparty\' ,'')
+ reverse( SUBSTRING ( REVERSE(Field), 1, CHARINDEX(reverse('\thirdparty'), REVERSE(Field) )-2 ) )
--REPLACE(Field, 'tables\thirdparty\%thirdparty\%\', 'tables\thirdparty\')
select * from #table

Oracle Update Column LTRIM and RTRIM

I am wish to update my database data in SQL Developer using
UPDATE TABLE_NAME SET COLUMN_NAME = LTRIM(RTRIM(COLUMN_NAME))
But it does not take any effect even the msg of "rows updated" is displayed. The leading and trailing white spaces still exist behind every strings.
Any ideas?

Do you commit after update?
update tableName set col1 = trim(col1);
commit;

I had the same problem on two different tables. One the first table trim was ok, on the second no effect, the spaces were still there!
The difference was that in the first table I was using varchar2(30) and in the second table (where trim didn't work) I had char(30)
After modifying the second table from char(30) to varchar2(30) trim worked as expected.

Try this
UPDATE TABLE_NAME SET COLUMN_NAME = TRIM(COLUMN_NAME);
Trim Reference

Have you tried REGEXP_REPLACE(your column name, '\s*', '') ?
ex: UPDATE TABLE_NAME SET COLUMN_NAME = REGEXP_REPLACE(COLUMN_NAME, '\s*', '')

You get a message saying that n rows are updated because there are n rows in your table and you are applying the update to all of them.
To limit the update to only those rows where the update will have an effect, use:
UPDATE TABLE_NAME
SET COLUMN_NAME = LTRIM(RTRIM(COLUMN_NAME))
WHERE COLUMN_NAME != LTRIM(RTRIM(COLUMN_NAME));