Get current and previous value in flow's collect - kotlin

I need to handle current and previous value in flow collect, so I need some operator that acts like that:
----A----------B-------C-----|--->
---(null+A)---(A+B)---(B+C)--|--->
One idea is something like:
fun <T: Any> Flow<T>.withPrevious(): Flow<Pair<T?, T>> = flow {
var prev: T? = null
this#withPrevious.collect {
emit(prev to it)
prev = it
}
}
But this way there is no control over a context in which first flow will be executed. Is there more flexible solution?

Flows are sequential, so you can use a variable to store the previous value:
coroutineScope.launch {
var prevValue = null
flow.collect { newValue ->
// use prevValue and newValue here
...
// update prevValue
prevValue = newValue
}
}

There's an operator which makes this very easy: runningFold
The docs have an example on how to use it to collect each emission of a flow; this can be easily adapted to fit our needs
data class History<T>(val previous: T?, val current: T)
// emits null, History(null,1), History(1,2)...
fun <T> Flow<T>.runningHistory(): Flow<History<T>?> =
runningFold(
initial = null as (History<T>?),
operation = { accumulator, new -> History(accumulator?.current, new) }
)
// doesn't emit until first value History(null,1), History(1,2)...
fun <T> Flow<T>.runningHistoryAlternative(): Flow<History<T>> =
runningHistory().filterNotNull()
You might need to tweak nullabilities to fit your usecase

Related

What are differents between assign data directly and emit data for a Flow? [duplicate]

What is the difference between using value and emit functions on a MutableStateFlow?
fun main() = runBlocking {
val mutable = MutableStateFlow(0)
launch {
mutable.collect {
println(it)
}
}
mutable.value = 1
mutable.emit(2)
}
emit() is a suspend function that wraps a call to set the value:
override suspend fun emit(value: T) {
this.value = value
}
So the difference is that value lets you set the value even when not in a coroutine. emit() exists so MutableStateFlow can inherit from MutableSharedFlow.
Source code here.

How to find last node that satisfies where predicate in singly linked list?

write a method "lastWhere" that accepts a function called "where" of type (T) -> Boolean. The method returns the last element of type T to which the "where" function applies. If no matching element is found, null is returned.
call the method "lastwhere" on the linked list below. Find the last game that is more than 10 euros.
So far I've got this Code going for me.
I assume the only important piece of Code I need to edit is the "fun lastWhere" for task number 1)
the second task wants me to implement a way on the main function to find the last Game that is cheaper than 10 Euros.
class LinkedList<T> {
data class Node<T>(val data: T, var next: Node<T>?)
private var first: Node<T>? = null
override fun toString(): String = first?.toString() ?: "-"
fun isEmpty() = first == null
fun addLast(data: T) {
if (first == null) {
first = Node(data, first)
return
}
var runPointer = first
while (runPointer?.next != null) {
runPointer = runPointer.next
}
runPointer?.next = Node(data, null)
}
fun lastWhere (where: (T) -> Boolean): T? { // "where" function needs to be implemented
if (isEmpty()) return null
else {
var runPointer = first
while (runPointer?.next != null ) {
runPointer = runPointer.next
}
return runPointer?.data
}
}
}
data class Game(val title: String, val price: Double)
fun main() {
val list = LinkedList<Game>()
list.addLast(Game("Minecraft", 9.99))
list.addLast(Game("Overwatch", 29.99))
list.addLast(Game("Mario Kart", 59.99))
list.addLast(Game("World of Warcraft", 19.99))
var test = list.lastWhere ({it.price >= 10.00}) // This is probably wrong too, since I haven't got task 1) working
println (test)
}
Would appreciate any help!
Since you only store a reference to first node, you don't have any choice but to start at first and iterate. you will also have to keep a reference to last item that satisfied the where predicate, and keep updating this reference with every iteration.
fun lastWhere (where: (T) -> Boolean): T? {
var runPointer = first
var item: T? = null // init item to null, if nothing is found we return null
while (runPointer != null ) {
// For every node, execute the where function and if it returns true
// then update the return value
if(where(runPointer.data)) { item = runPointer.data }
runPointer = runPointer.next
}
return item
}

LiveData Transformation to StateFlow / SharedFlow

What is the equivalent code for this live data transformation in StateFlow / SharedFlow?
val myLiveData: LiveData<MyLiveData> = Transformations
.switchMap(_query) {
if (it == null) {
AbsentLiveData.create()
} else {
repository.load()
}
Basically, I want to listen to every query changes to react what to return. So, anything similar to that using StateFlow / SharedFlow is welcome.
First, create an helper extension function:
fun <R> Flow<R>.toStateFlow(coroutineScope: CoroutineScope, initialValue: R) = stateIn(coroutineScope, SharingStarted.Lazily, initialValue)
Use mapLatest{} for Transformations.map():
val studentNames = _students.mapLatest { students ->
students.map { "${it.name}" }
}.toStateFlow(uiScope, emptyList()) //uiScope is viewModelScope
Use flatMapLatest{} for Transformations.switchMap():
val asteroids = _asteroidFilter.flatMapLatest { filter ->
asteroidRepository.getAsteroidsFlow(filter)
}.toStateFlow(uiScope, emptyList())
Use combine() for MediatorLiveData:
val sumScore = combine(_team1Score, _team2Score) { score1, score2 ->
score1 + score2
}.toStateFlow(uiScope, 0)
switchMap is deprecated in flows and should use either of flatMap, transform or transformLatest to convert one type of flows to others. An example for that would be
val myFlow = flowOf<Int>().transform<Int, String> { flowOf("$it") }}
I guess you can use same logic for StateFlow or SharedFlows.

Is there a way to distinguish between a function argument's default value having been passed explicitly or implicitly in Kotlin?

Assuming a kotlin function like this:
fun f(p1: T1? = null, p2: T2? = null, ..., pN: TN? = null) {
// ...
}
Can the above function's implementation distinguish between the following two calls, where the first one passed p1 = null implicitly, and the second one passed it explicitly?
f() // Implicit
f(null) // Explicit
f(p1 = null) // Explicit
Note: There could be arbitrary numbers of parameters
No, it cannot distinguish between those cases.
You could distinguish between them if you added a distinct overload, however.
Although I'd rather not use that approach in production, you could do something like I've done in the following snippet:
object Default {
val defaultMapping = mutableMapOf<KClass<*>, Any?>()
inline fun <reified T> get(): T? =
T::class.let {
defaultMapping[it] ?: it.java.constructors.getOrNull(0)?.let { c ->
try {
// NOTE: for now only parameterles constructor will work
c.newInstance()
} catch (e: Exception) {
e.printStackTrace()
null
}.also { v ->
defaultMapping[it] = v
}
} ?: run {
defaultMapping[it] = null
null
}
} as? T
inline fun <reified T> T.isDefault(): Boolean = defaultMapping[T::class] == this
}
inline fun <reified T> foo(bar: T? = Default.get()) {
if (bar?.isDefault() == true) println("bar: default is in use")
else println("bar: $bar")
}
fun main() {
foo<Any>()
foo(Default.get<Any>())
foo<Any>(null)
foo<Any>(bar = null)
foo(Any())
val a = Any()
foo(a)
foo(bar = a)
}
Note, that I have not polished the code in any way. Some parts are leftovers from several attempts (e.g. the part about the constructors.getOrNull(0)) and I don't intend to improve that.
Also: This simple approach only works with default constructors (see it.newInstance()) on the JVM. So that's no multi-platform solution in any way.
The result is something like
bar: default is in use
bar: default is in use
bar: null
bar: null
bar: java.lang.Object#41906a77
bar: java.lang.Object#4b9af9a9
bar: java.lang.Object#4b9af9a9
Again: Keep in mind, this is very simplistic, don't use that in production!

Taking sequence elements fulfilling a predicate then continuing from there in Kotlin

In Kotlin sequences have a takeWhile function that will let you take items as long as they adhere to a given predicate. What I'd like to do is take items according to that predicate, use them in some way, then alter the predicate and take the next "batch". So far I haven't really found a way of doing this purely with what sequences and iterators offer.
Following snippet of code illustrates the problem. The primeGenerator() function returns a Sequence of prime (Long) numbers. Suppose that I want to make lists with each list having prime numbers with the same number of digits. On creating each list I'd use it for some purpose. If the list conforms to what I was searching the iteration can end, otherwise move onto the next list.
val primeIt = primeGenerator().iterator()
var digits = 1
var next: Long? = null
val currentList = ArrayList<Long>()
while (digits < 4) {
next?.also { currentList.add(it) }
next = primeIt.next()
if (next.toString().length > digits) {
println("Primes with $digits: $currentList")
currentList.clear()
digits++
}
}
In this case it ends once the number of digits exceeds 3. This works fine, but I was wondering if there is some way to achieve the same with operations chained purely on the sequence or an iterator of it. Basically chunking the sequence but based on a predicate rather than a set size. The prime number example above is just for illustration, I'm after the general principle, not something that'd only work for this case.
There are no such functions in standard library for large (or infinite) sequences, but you may write such function by yourself (although it requires some extra code):
class BufferedIterator<T>(private val iterator: Iterator<T>) : Iterator<T> {
var current: T? = null
private set
var reachedEnd: Boolean = false
private set
override fun hasNext(): Boolean = iterator.hasNext().also { reachedEnd = !it }
override fun next(): T = iterator.next().also { current = it }
}
fun <T> Iterator<T>.buffered() = BufferedIterator(this)
fun <T> BufferedIterator<T>.takeWhile(predicate: (T) -> Boolean): List<T> {
val list = ArrayList<T>()
if (reachedEnd) return list
current?.let {
if (predicate(it)) list += it
}
while (hasNext()) {
val next = next()
if (predicate(next)) list += next
else break
}
return list
}
fun main() {
val sequence = sequence {
var next = 0
while (true) {
yield(next++)
}
}
val iter = sequence.iterator().buffered()
for (i in 0..3) {
println(iter.takeWhile { it.toString().length <= i })
}
}
With this approach you can easily work even with infinite sequences.
I believe there is a way to accomplish what you want using the standard library. Limit the sequence first and then groupBy the number of digits.
val Int.numberOfDigits
get() = this.toString().length
sequenceOf(1,22,333).takeWhile{ it.numberOfDigits < 3 }.groupBy{ it.numberOfDigits }.values
If you want to avoid the eager evaluation of groupBy you could use groupingBy instead and then reduce potentially leaving the accumulator blank.
ardenit's answer seems like the best reusable approach. Since taking "chunks" of a sequence requires some state it doesn't seem likely something easily done in a purely functional manner. Delegating the state to a separate class enveloping the sequence makes sense.
Here's a small snippet showing what I ended up using. This assumes the sequence will not be empty and is (technically) infinite or further results aren't requested at some point.
class ChunkedIterator<T>(seq: Sequence<T>) {
private val it = seq.iterator()
var next: T = it.next()
fun next(predicate: (T) -> Boolean): List<T> {
val result = ArrayList<T>();
while (predicate.invoke(next)) {
result.add(next)
next = it.next();
}
return result
}
}
one way you could achieve this is by getting an iterator from your your original sequence and then building a new sequence out of it for each "take" -
val itr = seq.iterator()
val batch1 = itr.asSequence().takeWhile { predicate1(it) }.toList()
val batch2 = itr.asSequence().takeWhile { predicate2(it) }.toList()