I need to calculate the time differences on a given day. I tried something like that but not works.
CONVERT(TIME, DATEADD(MINUTE, DATEDIFF(MI, MIN(CreatedOn),
MAX(CreatedOn)), 0), 108) AS WorkingTime
Thanks guys
You can try this way, since you don't show the error you get I don't know what detail you can have, but to get the time difference you can get it like this as I leave you here below
DECLARE #MaxDate DATETIME=DATEADD(HOUR,20,GETDATE()) --here you could get the maximum of your table separately
DECLARE #MinDate DATETIME=GETDATE() --here you could get the minimum of your table separately
SELECT DATEDIFF(MINUTE,#MinDate,#MaxDate) AS WorkingTime
https://dbfiddle.uk/?rdbms=sqlserver_2019&fiddle=09128de0d996e85a21992197b524a208
Your question is not entirely clear, but I think this is what you're trying to do.
SELECT CAST(WorkingTime AS DATE),
MIN(WorkingTime) AS min,
MAX(WorkingTime) AS max,
DATEADD(HOUR, DATEDIFF(HOUR, 0, MIN(WorkingTime)), 0) AS truncatedmin,
DATEDIFF(MINUTE,DATEADD(HOUR, DATEDIFF(HOUR, 0, MIN(WorkingTime)), 0),MAX(WorkingTime)) AS [difference]
FROM YourTable
GROUP BY CAST(WorkingTime AS DATE)
The column called "difference" should show the number of minutes difference between the truncatedmin and max columns.
From this column I need to calculate the working time for each day, for this I need to select the first time on a given day and then round it to the full hour (06:08:20 to 06:00:00) and then calculate the differences between the last time in day, which will give me the working time in minutes.
My column
Related
I'm trying to find a way to calculate minutes between 2 times using DATEDIFF
SELECT DATEDIFF(minute, CAST('05:00:00' AS time), CAST('23:59:00' AS time))
This returns 1139 which is correct but when I do
SELECT DATEDIFF(minute, CAST('05:00:00' AS time), CAST('00:37:00' AS time))
I get -263.
I have different data with different end dates in my database, and my question is how can I use single query to calculate the minutes correctly for both the cases?
There is no issue in this case.
5 AM is after Midnight (and 37 minutes).
Every day starts at 00:00:00.000 and ends up at 23:59:59.999.
Because you specified only the time, it cannot understand that you need the day after.
I suggest you to specify the date as well:
SELECT DATEDIFF(minute, CAST('2022-11-22 05:00:00' AS datetime), CAST('2022-11-23 00:37:00.000' AS datetime))
I need to group data in intervals of 15 (or X) minutes in sql.
For example, i have the next scenario.
The result that i expect to obtain is
I tried using Lag function but i dont get what i want, because it add interval to each row and continues grouping.
Thanks in advance and apologies for my bad english.
If you want the intervals to be calendar based -- i.e. four per hour starting at 0, 15, 30, and 45 minutes, then you can use:
select id, min(begin_date), max(begin_date)
from t
group by id, convert(date, begin_date),
datepart(hour, begin_date), datepart(minute, begin_date) / 15;
Note that begin date and end date have the same value, so I just used begin_date in this answer.
I am new to tableau and i need to find all row set filter on basis of given time frame and then grouping the result of same minute.I can crack this problem in Sql as following
select count(x)
from table t
where datediff(30, min, date)
group by datepart(min, date)
How to fix it in tableau ?
I'm not really sure of what you want but this will give you the number of record per minute, for the records whose date is in the last 30 minutes:
select datepart(MI, date) , COUNT(*) as NumberOfRecordsInMinute
from table t
where date >= dateADD(MI, -30, getdate())
group by datepart(MI, date)
order by datepart(MI, date)
It isn't obvious what your SQL is trying to do here as the standard SQL datediff function works like this datediff(datepart,startdate,enddate) and returns the difference between two dates in the units specified.
If that is what you want, then the Tableau function datediff does much the same job and datediff('minute',start date,enddate) will return the number of minutes between two datetimes and it will be grouped already because the result is discrete.
You can then count the number of records matching each minute difference.
Using SQL Server: I am trying to find all records prior to the first day of the current month and set this as a parameter in an SSRS report (so I can't use a static value).
So, I need all records prior to the first day of the each current month going forward in column CREATEDDATETIME ('yyyy-mm-dd').
I have seen a lot of threads on how to find records for a specific month and various other searches but none specifically related to the above. Interested to see if the EOMONTH function will be of use here.
Thanks for the help and advice.
Here is an expression to use EOMONTH() function with optional parameter -1.
Explanations:
DateAdd: add 1 day to expression
getdate is current date
EOMONTH is end day of a given month; however, if you put an optional integer -1, this would mean last month
Thus: first day of current month is add one day to end of day last month
SELECT DATEADD(DAY,1,EOMONTH(getdate(),-1));
Result: 2018-04-01
SO in your query:
select *
from table
where CREATEDDATETIME < DATEADD(DAY,1,EOMONTH(getdate(),-1));
I would use datefromparts():
select t.*
from t
where CREATEDDATETIME < datefromparts(year(getdate()), month(getdate()), 1);
There's already two other answers that work, but for completeness here is a third common technique:
SELECT *
FROM [table]
WHERE CREATEDDATETIME < dateadd(month, datediff(month,0, current_timestamp), 0)
You might also get answers suggesting you build the date using strings. Don't do that. It's both the least efficient and most error prone option you could use.
all three answers are great, how ever you may find that it will select all the data prior to the 1st day of the current month until the 1st Createdate. This could cause the report to take forever to run, Maybe building in a limitation to the code I would use something like this to build a report that gives details for last month only.
Select [columns]
from [source]
where [Createdate] between
/*First day of last Month*/
DATEADD(mm, DATEDIFF(mm, 0, Getdate())-1, 0 and
/*First day of this Month*/
dateadd(mm,datediff(mm,0,Getdate()),0)
I wish to convert the dates from each column to minutes, sum all the minutes and find the average time between each row. I have to fetch the data from a SQL database and display the final amount of minutes in a textbox.
Thanks for any help!
-Remi
Edit:
I solved this problem like this:
SELECT Datediff(minute, startdate, enddate) FROM «table-name»»)
Answer:
I solved this problem like this: SELECT Datediff(minute, startdate, enddate) FROM «table-name»»)