I have a table like date , sales , region
date
Sales
Region
11/02/2021
20
1
12/02/2021
23
1
13/02/2021
30
2
14/02/2021
50
2
15/02/2021
10
3
16/02/2021
10
3
How to extract sum of sales per region based on weeks (Week starting from Monday to Sunday)
You need to select the week before grouping.
This should work for you:
SELECT DATEPART(week, date) AS Week,
FROM table
GROUP BY DATEPART(week, RegistrationDate);
Related
I have a table that contains the following columns: TrackingStatus, Year, Month, Order, Notes
I need to calculate the total number of tracking status for each year and month.
For example, if the table contains the following orders:
TrackingStatus
Year
Month
Order
Notes
F
2020
1
33
F
2020
1
33
DFF
E
2020
2
36
xxx
A
2021
3
34
X1
A
2021
3
34
DD
A
2021
3
88
A
2021
2
45
The result should be:
• Tracking F , year 2020, month 1 the total will be one (because it's the same year, month, and order).
• Tracking A , year 2021, month 2 the total will be one. (because there is only one record with the same year, month, and order).
• Tracking A , year 2021, month 3 the total will be two. (because there are two orders within the same year and month).
So the expected SELECT output will be like that:
TrackingStatus
Year
Month
Total
F
2020
1
1
E
2020
2
1
A
2021
2
1
A
2021
3
2
I was trying to use group by but then it will count the number of records which in my scenario is wrong.
How can I get the total orders for each month without counting “duplicate” records?
Thank you
You can use a COUNT DISTINCT aggregation function, whereas the COUNT allows you to count the values, but the DISTINCT condition will allow each value only once.
SELECT TrackingStatus,
Year,
Month,
COUNT(DISTINCT Order) AS Total
FROM tab
GROUP BY TrackingStatus,
Year,
Month
ORDER BY Year,
Month
Here you can find a tested solution in a MySQL environment, though this should work with many DBMS.
I am still new in SQL
My Table
Columns: InDate, Sales
I want to compare rolling 12 months from TODAY to PAST 12 MONTHS Sales
What I need:
Current Month | Sale | Past Month | Sale
Nov | $550 | Nov | $450
I can get current 12 rolling months using this query:
SELECT SO_VInv.InvDate
FROM SO_VInv
where SO_VInv.InvDate >= DATEADD(month, -12, GETDATE())
I can get current 24 rolling months using this query:
SELECT SO_VInv.InvDate
FROM SO_VInv
where SO_VInv.InvDate >= DATEADD(month, -24, GETDATE())
But I dont know how to get past rolling 12 months e.g. 2/11/2017 till 2/11/2018 as rolling past 12 months and not with fixed date.
If you have one row per month, use window functions:
SELECT i.InvDate,
i.sale,
SUM(i.sale) OVER (ORDER BY i.InvDate
ROWS BETWEEN 11 PRECEDING AND CURRENT ROW
) as sales_rolling_12
FROM SO_VInv i;
I'd like to find out how many days in a week users have visited my site. For example, 1 day in a week, 2 days in a week, every day of the week (7).
I imagine the easiest way of doing this would be to set the date range and find out the number of days within that range (option 1). However, ideally I'd like the code to understand a week so I can run a number of weeks in one query (option 2). I'd like the users to be unique for each number of days (ie those who have visited 2 days have also visited 1 day but would only be counted in the 2 days row)
In my database (using SQLWorkbench64) I have user ids (id) and date (dt)
I'm relatively new to SQL so any help would be very much appreciated!!
Expected results (based on total users = 5540):
Option 1:
Number of Days Users
1 2000
2 1400
3 1000
4 700
5 300
6 100
7 40
Option 2:
Week Commencing Number of Days Users
06/05/2019 1 2000
06/05/2019 2 1400
06/05/2019 3 1000
06/05/2019 4 700
06/05/2019 5 300
06/05/2019 6 100
06/05/2019 7 40
You can find visitor count between a date range with below script. Its also consider if a visitor visits multi days in the given date range, s/he will be counted for the latest date only from the range-
Note: Dates are used as sample in the query.
SELECT date,COUNT(id)
FROM
(
SELECT id,max(date) date
FROM your_table
WHERE date BETWEEN '04/21/2019' AND '04/22/2019'
GROUP BY ID
)A
GROUP BY date
You can find the Monday of the week of a date and then group by that. After you have the week day there is a series of group by. Here is how I did this:
DECLARE #table TABLE
(
id INT,
date DATETIME,
MondayOfWeek DATETIME
)
DECLARE #info TABLE
(
CommencingWeek DATETIME,
NumberOfDays INT,
Users INT
)
INSERT INTO #table (id,date) VALUES
(1,'04/15/2019'), (2,'07/21/2018'), (3,'04/16/2019'), (4,'04/16/2018'), (1,'04/16/2019'), (2,'04/17/2019')
UPDATE #table
SET MondayOfWeek = CONVERT(varchar(50), (DATEADD(dd, ##DATEFIRST - DATEPART(dw, date) - 6, date)), 101)
INSERT INTO #info (CommencingWeek,NumberOfDays)
SELECT MondayOfWeek, NumberDaysInWeek FROM
(
SELECT id,MondayOfWeek,COUNT(*) AS NumberDaysInWeek FROM #table
GROUP BY id,MondayOfWeek
) T1
SELECT CommencingWeek,NumberOfDays,COUNT(*) AS Users FROM #info
GROUP BY CommencingWeek,NumberOfDays
ORDER BY CommencingWeek DESC
Here is the output from my query:
CommencingWeek NumberOfDays Users
2019-04-14 00:00:00.000 1 2
2019-04-14 00:00:00.000 2 1
2018-07-15 00:00:00.000 1 1
2018-04-15 00:00:00.000 1 1
I was trying to aggregate a 7 days data for FY13 (starts on 10/1/2012 and ends on 9/30/2013) in SQL Server but so far no luck yet. Could someone please take a look. Below is my example data.
DATE BREAD MILK
10/1/12 1 3
10/2/12 2 4
10/3/12 2 3
10/4/12 0 4
10/5/12 4 0
10/6/12 2 1
10/7/12 1 3
10/8/12 2 4
10/9/12 2 3
10/10/12 0 4
10/11/12 4 0
10/12/12 2 1
10/13/12 2 1
So, my desired output would be like:
DATE BREAD MILK
10/1/12 1 3
10/2/12 2 4
10/3/12 2 3
10/4/12 0 4
10/5/12 4 0
10/6/12 2 1
Total 11 15
10/7/12 1 3
10/8/12 2 4
10/9/12 2 3
10/10/12 0 4
10/11/12 4 0
10/12/12 2 1
10/13/12 2 1
Total 13 16
--------through 9/30/2013
Please note, since FY13 starts on 10/1/2012 and ends on 9/30/2012, the first week of FY13 is 6 days instead of 7 days.
I am using SQL server 2008.
You could add a new computed column for the date values to group them by week and sum the other columns, something like this:
SELECT DATEPART(ww, DATEADD(d,-2,[DATE])) AS WEEK_NO,
SUM(Bread) AS Bread_Total, SUM(Milk) as Milk_Total
FROM YOUR_TABLE
GROUP BY DATEPART(ww, DATEADD(d,-2,[DATE]))
Note: I used DATEADD and subtracted 2 days to set the first day of the week to Monday based on your dates. You can modify this if required.
Use option with GROUP BY ROLLUP operator
SELECT CASE WHEN DATE IS NULL THEN 'Total' ELSE CONVERT(nvarchar(10), DATE, 101) END AS DATE,
SUM(BREAD) AS BREAD, SUM(MILK) AS MILK
FROM dbo.test54
GROUP BY ROLLUP(DATE),(DATENAME(week, DATE))
Demo on SQLFiddle
Result:
DATE BREAD MILK
10/01/2012 1 3
10/02/2012 2 4
10/03/2012 2 3
10/04/2012 0 4
10/05/2012 4 0
10/06/2012 2 1
Total 11 15
10/07/2012 1 3
10/08/2012 4 7
10/10/2012 0 4
10/11/2012 4 0
10/12/2012 2 1
10/13/2012 2 1
Total 13 16
You are looking for a rollup. In this case, you will need at least one more column to group by to do your rollup on, the easiest way to do that is to add a computed column that groups them into weeks by date.
Take a lookg at: Summarizing Data Using ROLLUP
Here is the general idea of how it could be done:
You need a derived column for each row to determine which fiscal week that record belongs to. In general you could subtract that record's date from 10/1, get the number of days that have elapsed, divide by 7, and floor the result.
Then you can GROUP BY that derived column and use the SUM aggregate function.
The biggest wrinkle is that 6 day week you start with. You may have to add some logic to make sure that the weeks start on Sunday or whatever day you use but this should get you started.
The WITH ROLLUP suggestions above can help; you'll need to save the data and transform it as you need.
The biggest thing you'll need to be able to do is identify your weeks properly. If you don't have those loaded into tables already so you can identify them, you can build them on the fly. Here's one way to do that:
CREATE TABLE #fy (fyear int, fstart datetime, fend datetime);
CREATE TABLE #fylist(fyyear int, fydate DATETIME, fyweek int);
INSERT INTO #fy
SELECT 2012, '2011-10-01', '2012-09-30'
UNION ALL
SELECT 2013, '2012-10-01', '2013-09-30';
INSERT INTO #fylist
( fyyear, fydate )
SELECT fyear, DATEADD(DAY, Number, DATEADD(DAY, -1, fy.fstart)) AS fydate
FROM Common.NUMBERS
CROSS APPLY (SELECT * FROM #fy WHERE fyear = 2013) fy
WHERE fy.fend >= DATEADD(DAY, Number, DATEADD(DAY, -1, fy.fstart));
WITH weekcalc AS
(
SELECT DISTINCT DATEPART(YEAR, fydate) yr, DATEPART(week, fydate) dt
FROM #fylist
),
ridcalc AS
(
SELECT
ROW_NUMBER() OVER (ORDER BY yr, dt) AS rid, yr, dt
FROM weekcalc
)
UPDATE #fylist
SET fyweek = rid
FROM #fylist
JOIN ridcalc
ON DATEPART(YEAR, fydate) = yr
AND DATEPART(week, fydate) = dt;
SELECT list.fyyear, list.fyweek, p.[date], COUNT(bread) AS Bread, COUNT(Milk) AS Milk
FROM products p
JOIN #fylist list
ON p.[date] = list.fydate
GROUP BY list.fyyear, list.fyweek, p.[date] WITH ROLLUP;
The Common.Numbers reference above is a simple numbers table that I use for this sort of thing (goes from 1 to 1M). You could also build that on the fly as needed.
I have a Datatable with several hundred rows for this year in it. (MS SqlServer 2k8)
I would like to split this data set out into customer enquiries / Month.
What I have so far is;
Select count(id) As Customers, DatePart(month, enquiryDate) as MonthTotal, productCode From customerEnquiries
where enquiryDate > '2012-01-01 00:00:00'
group by productCode, enquiryDate
But this then produces a row for each data item. (Whereas I want a row per month for each data item.)
So how do I change the above query, so that instead of getting
1 1 10
1 1 10
1 1 11
1 2 10
1 2 10
...
I get
2 1 10 <-- 2 enquiries for product code 10 in month 1
1 1 11 <-- 1 enquiries for product code 11 in month 1
2 2 10 <-- 2 enquiries for product code 10 in month 2
etc
And as a bonus question, is there an easy way of naming each month so the output is Jan, Feb, March instead of 1,2,3 in the month column?
Try this
Select count(id) As Customers, DatePart(month, enquiryDate) as MonthTotal, productCode From customerEnquiries
where enquiryDate > '2012-01-01 00:00:00'
group by productCode, DatePart(month, enquiryDate)
This may help you.
For the Bonus, DATENAME(MONTH, enquiryDate) will give you the name of the Month.