DateDiff In months between two different types date formats - sql

I have two date formats, EndDate in YYYYMMDD format and another Monthfirstdate in YYYY-MM-DD FORMAT. I need to get the difference between these two dates.
SET NOCOUNT ON
SET TRANSACTION ISOLATION LEVEL READ UNCOMMITTED
DECLARE #Date DATE = dbo.value('DATE')
SELECT
E.EmployeeID
,E.StartDateKey
,E.EndDateKey
,E.FromDateKey
,E.ToDateKey
INTO #Employee
FROM
dbo.Employee E
---clean--
DECLARE #StartDate DATE = (SELECT DATEADD(YY, DATEDIFF(YY, 0, #Date) - 1, 0))
DECLARE #EndDate DATE = DATEADD(S, -1, DATEADD(MM, DATEDIFF(MM, 0, #Date) + 3, 0))
SELECT
E.EmployeeID
,CAST(CONVERT(VARCHAR(10), E.StartDateKey, 112) AS INT) AS _EmployeeStartDateKey
,CAST(CONVERT(VARCHAR(10), E.EndDateKey, 112) AS INT) AS _EmployeeFinishDateKey
,CAST(CONVERT(VARCHAR, D.MonthFirstDay, 112) AS INT) AS _DateKey
,???? AS [Tenure]
FROM #Employee AS E
INNER JOIN dbo.Date D ON
D.DateKey BETWEEN E.FromDateKey AND E.ToDateKey
WHERE
D.DateKey BETWEEN #tartDate AND #EndDate
AND D.DayOfMonth = 1

You can try below query in SQL Server:
DECLARE
#firstDate DATETIME = '2022-12-01',
#dateinStringFormat VARCHAR(20)= '20121201',
#endDate DATETIME;
--Converting date string to Datetime format(YYYY-MM-DD)
SELECT #endDate = CONVERT(CHAR(10), CONVERT(datetime, #dateinStringFormat), 120);
--Now, Calculating the date difference in Month
SELECT DATEDIFF(MONTH, #endDate, #firstDate) AS DateDiff;

Related

Monthly wise count using date calculation

I have the table named company with columns company name, create date, etc.
I want to get the count of companies created for this month.
I have the stored procedure for weekly wise count
CREATE PROCEDURE [dbo].[pr_NewCmpCount]
#StartDate DATETIME = NULL --'20130508'
, #EndDate DATETIME = NULL --'20130515'
AS
BEGIN
DECLARE #DateDiff INT
, #MainDate DATETIME
IF #StartDate IS NULL AND #EndDate IS NULL
BEGIN
IF (DATEPART(dw,GETDATE()) > 3)
SET #DateDiff = 0
ELSE
SET #DateDiff = 6
SET #MainDate = DATEADD (MINUTE, -30, DATEADD (HOUR, -5, DATEADD(wk, DATEDIFF(wk,#DateDiff,GETDATE()), 0)))
SELECT #StartDate = DATEADD (MINUTE, -30, DATEADD (HOUR, -5, DATEADD(wk, DATEDIFF(wk,0,#MainDate), -5)))
SELECT #EndDate = DATEADD (MINUTE, -30, DATEADD (HOUR, -5, DATEADD(wk, DATEDIFF(wk,0,#MainDate), 2)))
SELECT CONVERT (VARCHAR, Count(*)) AS [Count]
, CONVERT (DATE, DATEADD (DD, 1, #StartDate)) AS [StartDate]
, CONVERT (DATE, #EndDate) AS [EndDate]
FROM
Company WITH(NOLOCK)
WHERE CreateDate >= #StartDate
AND CreateDate < #EndDate
END
ELSE
IF ((CONVERT (DATE, #StartDate) < CONVERT (DATE, #EndDate)) AND (CONVERT (DATE, #EndDate) < CONVERT (DATE, GETDATE())))
BEGIN
SET #StartDate = CONVERT (DATE, #StartDate)
SET #EndDate = CONVERT (DATE, #EndDate)
SELECT #StartDate = DATEADD (MINUTE, -30, DATEADD (HOUR, -5, #StartDate))
SELECT #EndDate = DATEADD (MINUTE, 30, DATEADD (HOUR, 18, #EndDate))
SELECT CONVERT (VARCHAR, Count(*)) AS [Count]
, CONVERT (DATE, DATEADD (DD, 1, #StartDate)) AS [StartDate]
, CONVERT (DATE, #EndDate) AS [EndDate]
FROM
Company WITH(NOLOCK)
WHERE CreateDate >= #StartDate
AND CreateDate < #EndDate
END
ELSE
SELECT 'Please Run After Tuesday of Every Week or Given the Valid Date' [Count]
, CONVERT (DATE, #StartDate) AS [StartDate]
, CONVERT (DATE, #EndDate) AS [EndDate]
END
Output for this stored procedure is
Count Startdate EndDate
10 2016-03-13 2016-03-22
Expected output
Count Startdate EndDate
20 2016-02-01 2016-02-29
Where do I need to modify in my stored procedure to get monthly wise count?
Something like this:
DECLARE #StartDt Date
DECLARE #EndDt date
SELECT #StartDt,#EndDt,Count(*) AS TotalCompanies FROM company
WHERE [create date] BETWEEN #StartDt AND #EndDt
I skipped the stored procedure formatting for simplicity.

Find the Same day of Previous Year Given by Current Year Date in SQL Server

I am working with SQL Server, The scenario is to find out the Same Day's Date of Previous Year as of Today's Day.
Suppose 2014-03-06 is Today Date and Day is Thursday I want to Find the Same day in Previous lies in the same week .which is 2013-03-07
can any body help?
HERE is what i Have Written:
DECLARE #DateFrom AS DATETIME
DECLARE #DateTo AS DATETIME
SET #DateFrom = '2014-01-01'
SET #DateTo = '2014-02-10'
DECLARE #Count AS INT
SET #Count = DATEDIFF(DAY, #DateFrom, #DateTo)
CREATE TABLE #current_year /*This Year*/
(
[Date] DATETIME ,
WeekNum INT,
[Day] VARCHAR(20),
Data INT
)
CREATE TABLE #last_year /*This Year -1*/
(
[Date] DATETIME ,
WeekNum INT,
[Day] VARCHAR(20),
Data INT
)
WHILE ( #Count > 0 )
BEGIN
INSERT INTO #current_year
VALUES ( CONVERT(VARCHAR(10), #DateFrom, 101),
DATEPART(week,#DateFrom),
DATENAME(weekday, #DateFrom),#Count)
INSERT INTO #last_year
VALUES ( CONVERT(VARCHAR(10), DATEADD(YEAR, -1, #DateFrom), 101),
DATEPART(week,DATEADD(YEAR,1,#DateFrom)),
DATENAME(weekday, DATEADD(YEAR, -1, #DateFrom)),#Count)
SET #DateFrom = DATEADD(day, 1, #DateFrom)
SET #Count = #Count - 1
END
SELECT * from #current_year
SELECT * from #last_year
SELECT CONVERT(varchar(10),#current_year.[Date],111) AS CYDate,
--ISNULL(CONVERT(varchar(10),#last_year.[Date],111) ,/*CONVERT(varchar(10),DateAdd(dd, 1, DATEADD(yy, -1, #current_year.Date)),111)*/) AS LYDate
--CONVERT(varchar(10),#last_year.[Date],111) AS LYDate
Coalesce(CONVERT(varchar(10),#last_year.[Date],111) ,DateAdd(dd, 1, DATEADD(yy, -1, #current_year.Date))) AS LYDate,
#current_year.Data AS CD,
#last_year.Data AS LD
FROM #current_year
--LEFT JOIN #last_year ON #last_year.WeekNum = #current_year.WeekNum
-- AND #last_year.[Day] = #current_year.[Day]
Left JOIN #last_year ON #last_year.WeekNum = DatePart(wk, GETDATE())
DROP TABLE #current_year
DROP TABLE #last_year
Here is the Output:
Here is the output after adding your solution, now in left join it excludes (NULL) data of previous year
Basically you need to find difference in days between same dates in this and previous years, then understand "day difference" by mod 7, and sum it with date in previous year:
DECLARE #now DATETIME
SET #now = '2014-03-06'
SELECT CAST (DATEADD(YEAR, -1, #now) + (CAST (#now as INT) - CAST (DATEADD(YEAR, -1, #now) AS INT)) % 7 AS DATE)
Returns
2013-03-07
Try
DECLARE #now Date
SET #now = '2014-06-03'
SELECT DATEADD(week, -52, #now)
SELECT DateName(dw, DATEADD(yy, -1, GETDATE()))
gives Wednesday
SELECT DateName(dw, DateAdd(dd, 1, DATEADD(yy, -1, GETDATE())))
gives Thursday
edit:
SELECT DateAdd(dd, 1, DATEADD(yy, -1, GETDATE()))
gives '2013-03-07 17:30:16.590'
you need to cast the date as per you requirement..
update:
change this part with,
Left JOIN #last_year ON #last_year.WeekNum = DatePart(wk, GETDATE())
in your case:
Left JOIN #last_year ON DatePart(wk, #last_year.[Date]) = DatePart(wk, #current_year.[Date])
update 2:
Left JOIN #last_year ON (MONTH(#last_year.[Date])=MONTH(#current_year.[Date]) and Day(#last_year.[Date])=Day(#current_year.[Date]))
Output:
or
output:
Left JOIN #last_year ON (#last_year.WeekNum = #current_year.WeekNum and #last_year.[Day] = #current_year.[Day])
choose which ever is your required output.
DECLARE #Date DATE = '2014-03-06'
SELECT DATEADD(WEEK,-52,#Date)
Retrun value :
2013-03-07

Returns date range by quarter?

I am looking for a query that can returns a series of date range that is one quarter long.
For example, if the input is 2/1/2013 and 3/31/2014, then the output would look like:
start end
2/1/2013 4/30/2013
5/1/2013 7/31/2013
8/1/2013 10/31/2013
11/1/2013 1/31/2014
2/1/2014 3/31/2014
Notice that the last quarter is only 2 months long. Thanks for help in advance.
Just want to add that this is what I did after I did a bit of googling. I was thinking of some more efficient way but I think this is sufficient for my purpose. The first part is to populate a date table, the second part to calculate the quarter range.
DECLARE #StartDate SMALLDATETIME
DECLARE #EndDate SMALLDATETIME
SET #StartDate = '1/1/2011'
SET #EndDate = '12/31/2011'
-- creates a date table, not needed if there is one already
DECLARE #date TABLE ( [date] SMALLDATETIME )
DECLARE #offset INT
SET #offset = 0
WHILE ( #offset < DATEDIFF(dd, #StartDate, DATEADD(dd, 1, #EndDate)) )
BEGIN
INSERT INTO #date ( [date] )
VALUES ( DATEADD(dd, #offset, #StartDate) )
SELECT #offset = #offset + 1
END ;
WITH dateCTE
AS ( SELECT ROW_NUMBER() OVER ( ORDER BY [date] ASC ) AS qID ,
[date] AS qStart ,
CASE WHEN DATEADD(dd, -1, DATEADD(q, 1, [date])) > #EndDate
THEN #EndDate
ELSE DATEADD(dd, -1, DATEADD(q, 1, [date]))
END AS qEnd
FROM #date
WHERE [date] = #StartDate
OR ( DATEDIFF(mm, #StartDate, [date]) % 3 = 0
AND DATEPART(dd, [date]) = DATEPART(dd,
#StartDate)
)
)

SQL convert DATETIME TO VARCHAR?

I am working on a query something require DATE!!
DECLARE #YesterDay DATETIME, #Today DATETIME
SET #YesterDay = DateAdd(DD, DateDiff(DD, 0, GETDATE())-1, 0)
SET #Today = DateAdd(DD, DateDiff(DD, 0, GETDATE()), 0)
select #YesterDay = convert(varchar, getdate()-1 , 110)
select #Today = convert(varchar, getdate() , 110)
EXEC #return_value = [dbo].[post_sec_admin_list_user_log]
#pDateFr = #YesterDay ,
#pDateTo = #Today,
#pName = '',
#pSec = NULL
#DateFr is varchar(50)
#DateT0 is varchar(50)
the #dateFr and #dateTo are both varchar..
And I try to execute it, it print the time format as this 2011-06-09 16:15:38.927
error statement
The conversion of a varchar data type to a datetime data type resulted in an out-of-range value.
Additionally, the varchar format I need is MM-DD-YYYY
Anyone know where is my error at?
thanks
Your code is confusing:
DECLARE #YesterDay DATETIME, #Today DATETIME
SET #YesterDay = DateAdd(DD, DateDiff(DD, 0, GETDATE())-1, 0)
SET #Today = DateAdd(DD, DateDiff(DD, 0, GETDATE()), 0)
select #YesterDay = convert(varchar, getdate()-1 , 110)
select #Today = convert(varchar, getdate() , 110)
So you declare it as DATETIME, set value with DateDiff then overwrite that value with an varchar representation of a date that is recalculated using different method.
At line 4 and 5 #Yesterday and #Today variables are still DATETIME, because it's declared that way.
EDIT: As mentioned in the comment to my answer you need a variable to pass to the procedure.
So the correct fix would be to declare the variables as VARCHAR(50) at the beginning and do the conversion directly.
DECLARE #YesterDay VARCHAR(50), #Today VARCHAR(50)
SELECT #YesterDay = convert(varchar(50), dateadd(dd, -1, getdate()) , 110)
SELECT #Today = convert(varchar(50), getdate() , 110)
And then call the procedure the way you did originally.
My guess is that getdate()-1 part is wrong.
Also, you were making dateadd and datediff why? Try it like this:
SET #YesterDay = dateadd(dd, -1, GETDATE())
SET #Today = GETDATE()
select #YesterDay = convert(varchar(50), dateadd(dd, -1, getdate()) , 110)
select #Today = convert(varchar(50), getdate() , 110)
EXEC #return_value = [dbo].[post_sec_admin_list_user_log]
#pDateFr = #YesterDay ,
#pDateTo = #Today,
#pName = '',
#pSec = NULL

Compare current date with stored datetime using month an year only

Using SQL Server 2005 I have a field that contains a datetime value.
What I am trying to do is create 2 queries:
Compare to see if stored datetime is of the same month+year as current date
Compare to see if stored datetime is of the same year as current date
There is probably a simple solution but I keep hitting brick walls using various samples I can find, any thoughts?
Thanks in advance.
Compare the parts of the date:
WHERE YEAR( columnName ) = YEAR( getDate() )
While the other answers will work, they all suffer from the same problem: they apply a transformation to the column and therefore will never utilize an index on that column.
To search the date without a transformation, you need a couple built-in functions and some math. Example below:
--create a table to hold our example values
create table #DateSearch
(
TheDate datetime not null
)
insert into #DateSearch (TheDate)
--today
select getdate()
union all
--a month in advance
select dateadd(month, 1, getdate())
union all
--a year in advance
select dateadd(year, 1, getdate())
go
--declare variables to make things a little easier to see
declare #StartDate datetime, #EndDate datetime
--search for "same month+year as current date"
select #StartDate = dateadd(month, datediff(month, 0, getdate()), 0), #EndDate = dateadd(month, datediff(month, 0, getdate()) + 1, 0)
select #StartDate [StartDate], #EndDate [EndDate], TheDate from #DateSearch
where TheDate >= #StartDate and TheDate < #EndDate
--search for "same year as current date"
select #StartDate = dateadd(year, datediff(year, 0, getdate()), 0), #EndDate = dateadd(year, datediff(year, 0, getdate()) + 1, 0)
select #StartDate [StartDate], #EndDate [EndDate], TheDate from #DateSearch
where TheDate >= #StartDate and TheDate < #EndDate
What the statement does to avoid the transformations, is find all values greater-than or equal-to the beginning of the current time period (month or year) AND all values less-than the beginning of the next (invalid) time period. This solves our index problem and also mitigates any issues related to 3ms rounding in the DATETIME type.
SELECT * FROM atable
WHERE
YEAR( adate ) = YEAR( GETDATE() )
AND
MONTH( adate ) = MONTH( GETDATE() )
It sounds to me like DATEDIFF is exactly what you need:
-- #1 same month and year
SELECT *
FROM your_table
WHERE DATEDIFF(month, your_column, GETDATE()) = 0
-- #2 same year
SELECT *
FROM your_table
WHERE DATEDIFF(year, your_column, GETDATE()) = 0
The datepart function lets you pull the bits you need:
declare #d1 as datetime
declare #d2 as datetime
if datepart(yy, #d1) = datepart(yy, #d2) and datepart(mm, #d1) = datepart(mm, #d2) begin
print 'same'
end
You can use something like this
a)
select *
from table
where MONTH(field) = MONTH(GetDATE())
and YEAR(field) = YEAR(GetDATE())
b)
select *
from table
where YEAR(field) = YEAR(GetDATE())