Hello I am trying to get the MIN and MAX values from the array and it always returns "0" despite anything. My code:
Dim MachineCapacitySmallestArray() As Variant
MachineCapacitySmallestArray = thisworkbook.worksheets(1).range("C25:D25")
SmallestCapacity = Application.Min(MachineCapacitySmallestArray)
in range I have natural numbers
I tried formatting those cells to numbers etc. but nothing works. What is the mistake I'm making and how to fix it?
According to the comments, it seems that your problem is your data, you have likely strings in your cell, not numbers (maybe somehow imported?)
As already mentioned, changing the cell format doesn't change the content of a cell, it just defines how to display data. The number 3.14 can be displayed as 3, as 3.140000, as 00003.14 or as 3.14E+00, nothing changes it's value. However, a String '3.14 is a combination of the characters 3, ., 1 and 4 and has nothing to do with a number. Setting a cell format after the value is in the cell will not convert it to a number.
If you read your data into VBA, VBA will get the exact values from Excel and in your case, you will have to convert it into numbers manually, for example with the following routine. The On Error Resume Next will prevent a type mismatch if a cell doesn't contain something that can be converted into a number.
Sub ArrToNumber(ByRef arr)
Dim i As Long, j As Long
For i = LBound(arr, 1) To UBound(arr, 1)
For j = LBound(arr, 2) To UBound(arr, 2)
On Error Resume Next
arr(i, j) = CDbl(arr(i, j))
On Error GoTo 0
Next
Next
End Sub
Now just add a call to this routine to your code. If you want to have the numbers also in Excel, remove the comment sign from the last statement.
Dim MachineCapacitySmallestArray() As Variant
MachineCapacitySmallestArray = thisworkbook.worksheets(1).range("C25:D25")
ArrToNumber MachineCapacitySmallestArray
SmallestCapacity = Application.Min(MachineCapacitySmallestArray)
' thisworkbook.worksheets(1).range("C25:D25") = MachineCapacitySmallestArray
Related
I have declared an array as such Dim rArray() As Variantbut when i try and use the values that is stored in it (as shown below) I get a subscript out of range error. The UBound(rArray)and LBound(rArray) both returns values 14 and 1, but the error occurs at the Debug.Print line.
If I use the for statement as below
For Each rArr in rArray
then it works without issues, but for the purposes I am creating this array I need the flexibility to select each item stored in that order- meaning I need to refer to them using subscripts.
I have tried multiple ways to try and solve this with no luck and spend almost half my day on this one issue. Could anyone point out what I need to change to get this to work.
Set rng = Range("D4", Range("D4").End(xlDown))
rng.NumberFormat = "0"
rArray = rng.Value
For x = UBound(rArray) To LBound(rArray) Step -1
Debug.Print rArray(x)
Next x
Edit: another fact worth mentioning is that he array is declared and used within a Function but it is not passed from or to the function. Can't arrays be declared and used in Functions?
When you assign worksheet values to a variant array, you always end up with a 2-D array that is 1 based (e.g. 1 to something, 1 to something; never 0 to something, 0 to something). If you are getting values from a single column the second Rank is merely 1 to 1.
This can be proven with the following.
Dim x As Long, rArray As Variant, rng As Range
Set rng = Range("D4", Range("D4").End(xlDown))
rng.NumberFormat = "0" 'don't really understand why this is here
rArray = rng.Value
Debug.Print LBound(rArray, 1) & ":" & UBound(rArray, 1)
Debug.Print LBound(rArray, 2) & ":" & UBound(rArray, 2)
For x = UBound(rArray, 1) To LBound(rArray, 1) Step -1
Debug.Print rArray(x, 1)
Next x
So you need to ask for the element in the first rank of the array; it is insufficient to just ask for the element.
I'm trying to find "blocks" in the worksheet that have dates in the A-column. A block is seperated by lines as you can see from the picture. The whole file is full of these blocks but I only need the blocks that have dates in the A-column. Just to be clear I don't just need the rows with the dates but the full block that contains the date.
A block in my files for example is the Range A172:G192.
Picture of the file:
[![enter image description here][1]][1]
How should I continue after selecting the first block? I probably should use the Find function starting from row 184 or the row of ResultDown variable moving down the sheet on "A" Column. However the row needs to be dynamic, so I can use it for the next block. Also I have no idea how many blocks there will be, so I would like to hear from you how to solve this aswell.
I would like to save all the blocks as different variables and then hide all the blocks in the worksheet and then just unhide the blocks that I stored in the variables.
My biggest problem is the last row.
Result2 = Range(Cells(StartcellRow, 1), Cells(1000, 1)).Find(What:="**/**/****", After:=Range(Cells(StartcellRow, 1))).Select
I keep getting an runtime error 1004
Public Sub FB_MAKRO()
Dim FBwb As Workbook
Dim FBsht As Worksheet
Dim ACol As Range
'Set variables for workbook and sheet
Set FBwb = Workbooks.Open(Filename:="C:\Users\l000xxx\Desktop\Makrot\FORCED BALANCE MAKRO\FB HARJOITUS.xls")
Set FBsht = FBwb.Sheets("Forced Balance")
Set ACol = FBsht.Range("A1:A1000")
'I want ACol variable to be the entire A-Column. Any ideas?
'For some reason the range function is not working here?
'This locates the date in A'column, so I can select the correct block
Result = Range("A3:A1000").Find(What:="**/**/****", After:=Range("A3")).Address
'This is the top left corner of the Block1 selection
ResultUp = Range(Result).End(xlUp).Offset(-1, 0).Address
Range(ResultUp).End(xlDown).Select
Range(ActiveCell, ActiveCell).End(xlDown).Select
'The ResultsDownLastRow variable is for Block2 find function
'ResultDown is the bottom right corner of the Block1
ResultsDownLastRow = Range(ActiveCell, ActiveCell).End(xlDown).Address
ResultDown = Range(ActiveCell, ActiveCell).End(xlDown).Offset(-2, 6).Address
'First Block assigned. I plan to use this in the end when I hide everything and then unhide these blocks
Block1 = Range(ResultUp, ResultDown).Select
' NEXT BLOCK STARTS HERE
'StartCellRow is the cell that the find function should start looking for Block2
'Result2 is the find function for Block2
StartcellRow = Range(ResultsDownLastRow).Row
Result2 = Range(Cells(StartcellRow, 1), Cells(1000, 1)).Find(What:="**/**/****", After:=Range(Cells(StartcellRow, 1))).Select
End Sub
'This returns value 194
StartcellRow = Range(ResultsDownLastRow).Row MsgBox StartcellRow
'This should work but doesn't. I get a syntax error
Range(Cells(StartcellRow &","& 1),Cells(1000 & "," & 1)).Find(What:="**/**/****", After:=Range(Cells(StartcellRow& ","& 1)).Select
This doesn't work either
'StarcellRow gives out value of 194
StartcellRow = Range(ResultsDownLastRow).Row
Result2 = Range("A&:StartcellRow:A648").Find(What:="**/**/****", After:=Range("A&:StartcellRow")).Select
This doesn't give me a syntax error but it's not working
I would search for all currency header and store their rownumber into an array. For each rownumber in the array i would look into the cell below (rownumber + 1). when there is a date in the cell, i would set the range in the following way:
set rangeWithDate = Range(Cells(actualRowNumberInArray - 1, 1), Cells(nextRowNumberInArray - 2, 7))
Array:
Dim array1() As long
Redim array1(5)
For i = 1 To 5
array(i) = i
Next i
Redim array1(10) ' changes the "length" of the array, but deletes old entries
For i = 1 To 10
Feld1(i) = i
Next i
Redim Preserve array1(15) ' changes the "length" of the array without deleting old entries
I am trying to add the data in the two cells of the excel sheet but even if the excel cell is of the type number it does not add up the cells. It seems that there is space infornt of the number that it does not add....image is below.
Is there a vba code to remove this space from each of the cell if its presesnt.
I have exported the excel from a pdf.
Excel will attempt to convert any value to a number if you apply an operator to it, and this conversion will handle spaces. So you can use =A1*1 or A1+0 to convert a value in A1 to a number, or something like this within a function =SUM(IFERROR(A1*1,0)).
That kind of implicit conversion automatically performs a trim(). You can also do this conversion explicitly by using the funciton N(), or NumberValue() for newer versions of Excel. However, as others have pointed out, many characters won't be automatically handled and you may need to use Substitute() to remove them. For instance, Substitute(A1,160,"") for a non-breaking space, a prime suspect because of its prevalence in html. The Clean() function can give you a shortcut by doing this for a bunch of characters that are known to be problematic, but it's not comprehensive and you still need to add your own handling for a non-breaking space. You can find the ASCII code for any specific characters that are grieving you by using the Code() function... for instance Code(Mid(A1,1,1))
Character Handling UDF
The UDF below gives flexibility to the character handling approach by allowing multiple characters to be removed from every cell in a range, and produces a result that can be used as an argument. For example, Sum(RemoveChar(A1:A5,160)) would remove all non-breaking spaces from the range being summed. Multiple characters can removed by being specified in either a range or array, for example Sum(RemoveChar(A1:A5,B1:B3)) or Sum(RemoveChar(A1:A5,{160,150})).
Function RemoveChar(R As Range, ParamArray ChVal() As Variant)
Dim x As Variant
Dim ResVals() As Variant
ReDim ResVals(1 To R.Count)
'Loop through range
For j = 1 To R.Count
x = R(j).Value2
If x <> Empty Then
'Try treating character argument as array
'If that fails, then try treating as Range
On Error Resume Next
For i = 1 To UBound(ChVal(0))
x = Replace(x, Chr(ChVal(0)(i)), "")
Next
If Err = 92 Then
Err.Clear
For Each Rng In ChVal(0)
x = Replace(x, Chr(Rng.Value2), "")
Next
End If
Err.Raise (Err)
On Error GoTo 0
'If numeric then convert to number
'so that numbers will be treated as such
'when array is passed as an argument
If IsNumeric(x) Then
ResVals(j) = Val(x)
Else
ResVals(j) = x
End If
End If
Next
'Return array of type variant
RemoveChar = ResVals
End Function
Numeric Verifying UDF
The drawback with replacing characters is that it's not comprehensive. If you want something that's more of a catch-all, then perhaps something like this.
Function GetNumValues(R As Range)
Dim c, temp As String
Dim NumVals() As Double
ReDim NumVals(1 To R.Count)
'Loop through range
For j = 1 To R.Count
'Loop through characters
'Allow for initial short-circuit if already numeric
For i = 1 To Len(R(j).Value2)
c = Mid(R(j).Value2, i, 1)
'If character is valid for number then include in temp string
If IsNumeric(c) Or c = Application.DecimalSeparator Or c = Application.ThousandsSeparator Then
temp = temp + c
End If
Next
'Assign temp string to array of type double
'Use Val() function to convert string to number
NumVals(j) = Val(temp)
'Reset temp string
temp = Empty
Next
'Return array of type double
GetNumValues = NumVals
End Function
I am struggling with a common problem involving an apparent Excel 255-character-limit. I encounter an error when attempting to return a variant-array from a Function to the selected range on the worksheet. When each of the cells in the Function's returning array are under 255 characters, they post to the sheet just as they should: one element appears in each cell within the selected range. However, if any element in my returning variant array is longer than 255 characters I get a Value! error. These errors are bad because I need my long elements and want to keep the data together!
Versions of this problem appear over and over again in many forums, yet I am able to find a clear simple, all-purpose solution for returning variant arrays to the selected range (not necessarily containing formulas) when the array cells exceed 255 characters. My largest elements are around 1000, but it would be better if the solution could accommodate elements up to 2000 characters.
Preferably, I want this to be implemented with a function, or lines of additional code which can be added to my function (not a subroutine). My reason for wanting to avoid subroutines: I do not want to have to hard-code any ranges. I want this to be flexible and for the output location to be dynamically based on my current selection.
Please, if you can help find a way to produce a function, which takes a Variant Array as input, and which maintains the desired array:cell 1:1 relationship, I'd appreciate it greatly.
So this function with short cells works:
Function WriteUnder255Cells()
Dim myArray(3) As Variant 'this the variant array I will attempt to write
' Here I fill each element with less than 255 characters
' it should output them if you call the function properly.
myArray(0) = "dog"
myArray(1) = "cat"
myArray(2) = "bird"
myArray(3) = "fly"
WriteUnder255Cells = Application.Transpose(myArray())
End Function
But this fuction, with cells exceeding 255 will not output.
Function WriteOver255Cells()
Dim myArray(3) As Variant 'this the variant array I will attempt to write
' Here I fill each element with more than 255 characters
' exceeding the 255-character limit causes the VALUE! errors when you output them
myArray(0) = "ThequickbrownfoxjumpedoverthelazydogThequickbrownfoxjumpedoverthelazydogThequickbrownfoxjumpedoverthelazydogThequickbrownfoxjumpedoverthelazydogThequickbrownfoxjumpedoverthelazydogThequickbrownfoxjumpedoverthelazydogThequickbrownfoxjumpedoverthelazydogThequickbrownfoxjumpedoverthelaxydog"
myArray(1) = "ThequickbrownfoxjumpedoverthelazydogThequickbrownfoxjumpedoverthelazydogThequickbrownfoxjumpedoverthelazydogThequickbrownfoxjumpedoverthelazydogThequickbrownfoxjumpedoverthelazydogThequickbrownfoxjumpedoverthelazydogThequickbrownfoxjumpedoverthelazydogThequickbrownfoxjumpedoverthelazydog"
myArray(2) = "ThequickbrownfoxjumpedoverthelazydogThequickbrownfoxjumpedoverthelazydogThequickbrownfoxjumpedoverthelazydogThequickbrownfoxjumpedoverthelazydogThequickbrownfoxjumpedoverthelazydogThequickbrownfoxjumpedoverthelazydogThequickbrownfoxjumpedoverthelazydogThequickbrownfoxjumpedoverthelazydog"
myArray(3) = "ThequickbrownfoxjumpedoverthelazydogThequickbrownfoxjumpedoverthelazydogThequickbrownfoxjumpedoverthelazydogThequickbrownfoxjumpedoverthelazydogThequickbrownfoxjumpedoverthelazydogThequickbrownfoxjumpedoverthelazydogThequickbrownfoxjumpedoverthelazydogThequickbrownfoxjumpedoverthelazydog"
WriteOver255Cells = Application.Transpose(myArray())
End Function
This is how you produce the output and results:
First you need to create the two modules(to insert one function into each module, paste the code from one into the respective module). To run "WriteUnder255Cells()", select an area of 4 rows x 1 column on the sheet (this where you return the module) and type "=WriteUnder255Cells()" into the formula bar (do not enter the quotes). Note these are called like array formulas, so instead of hitting (enter) to create the output, you need to hit (control + shift + enter). Repeat the same process for WriteOver255Cells() to produce the errors.
Here are some documents/forums discussions which address it. The solutions seem to be either overly specific or clunky because they evoke subroutines (which I want to avoid):
https://support.microsoft.com/en-us/kb/213841
http://www.mrexcel.com/forum/excel-questions/852781-visual-basic-applications-evaluate-method-255-character-limit.html
Excel: Use formula longer that 255 characters
VBA code error when array value exceeds 255 characters
http://dailydoseofexcel.com/archives/2005/01/10/entering-long-array-formulas-in-vba/
https://forums.techguy.org/threads/solved-vba-access-to-excel-255-char-limit-issue.996495/
http://www.mrexcel.com/forum/excel-questions/494675-255-character-cell-limit-visual-basic-applications-workaround.html
Array formula with more than 255 characters
http://www.mrexcel.com/forum/excel-questions/388250-size-limit-transferring-variant-range-excel-2007-a.html
This works for me:
Function Over255()
Dim myArray(3) As String '<<<<< not variant
myArray(0) = String(300, "a")
myArray(1) = String(300, "b")
myArray(2) = String(300, "c")
myArray(3) = String(300, "d")
'Over255 = Application.Transpose(myArray())
Over255 = TR(myArray)
End Function
'like Application.Transpose...
Function TR(arrIn) As String()
Dim arrOut() As String, r As Long, ln As Long, i As Long
ln = (UBound(arrIn) - LBound(arrIn)) + 1
ReDim arrOut(1 To ln, 1 To 1)
i = 1
For r = LBound(arrIn) To UBound(arrIn)
arrOut(i, 1) = arrIn(r)
i = i + 1
Next r
TR = arrOut
End Function
Seems like you need to return a string array and Application.Transpose doesn't do that
While I roughly understood my coding at the time of writing it awhile back, I have since forgotten how to interpret the first few parts of it (in bold).
Why 'as long'? My understanding is that this is used when the variable is only to take larger integer values. Since the share values contain several decimals, I am not sure why I chose this over 'double'.
Why/when do we dim a variable as a 'range', and why do we use 'set' at all? My limited understanding of the purpose of the set function is to assign values to 'object' variables. Why is the 'range' an 'object'?
I have completely forgot what the line Set stockValue = Range("B5:B" & lastStockprice) is doing, especially the ampersand.
I've no idea what is going on here:
ReDim stockPrice(stockValue.Count - 1)
For Each cell In stockValue
stockPrice(cell.Row - 5) = cell.Value
Next
Sub MovingAverage()
Dim CumulSum() As Double
Dim MovingAv() As Double
RowCountA = Range("StockPrice").Rows.Count
RowCountB = Range("MovingAv").Rows.Count
ReDim CumulSum(RowCountB)
Dim stockPrice As Variant
Dim lastStockprice **As Long**
lastStockprice = Cells(Rows.Count, "B").End(xlUp).Row
Dim stockValue **As Range**
**Set stockValue = Range("B5:B" & lastStockprice)**
**ReDim stockPrice(stockValue.Count - 1)
For Each cell In stockValue
stockPrice(cell.Row - 5) = cell.Value
Next**
For i = 0 To RowCountB - 1
For k = 0 To 9
CumulSum(i) = CumulSum(i) + stockPrice(i + k)
Next k
Next i
For i = 1 To RowCountB
Range("MovingAv").Cells(i) = CumulSum(i - 1) / 10
Next i
End Sub
If someone could please explain the bolded code for me (I've a very basic knowledge of VBA that extends about as far as matrix multiplication, basic functions and double arrays), it would be greatly appreciated. :)
Dim lastStockprice **As Long**
lastStockprice = Cells(Rows.Count, "B").End(xlUp).Row
This has to be long because we are trying to find the last row in Col B. This is to make the code compatible with xl2007+ (Where there are 1048576 rows). You can see this link on how to get the last row.
Why is the 'range' an 'object'?
See this link. Also see this.
I have completely forgot what the line Set stockValue = Range("B5:B" & lastStockprice) is doing, especially the ampersand.
As mentioned earlier lastStockprice is the last row and & is used to concatenate so that we can set our range. Let's say the last row is 20 then the above code can be written as
Set stockValue = Range("B5:B" & 20)
'OR
Set stockValue = Range("B5:B20")
I've no idea what is going on here: ReDim stockPrice(stockValue.Count - 1)
What the code is trying to do is dynamically increase the size of the array so that it can store more values to it. REDIM (Re-Dimension) I would recommend seeing this link
FOLLOWUP (From comments)
I understand all of it now except this part: For Each cell In stockValue stockPrice(cell.Row - 5) = cell.Value Next**
What that piece of code is doing is looping through every cell in the range stockvalue and then storing the cell value in the array stockPrice
Ex: Let's say we have a range, A1:B2
When we say For each cell in Range("A1:B2"), we are telling the code to loop through every cell in that range (A1, A2, B1, B2)