I have added a blank column to my query, so when I export the results the user can use the blank column to manually input their drivepath to use for their mailmerge automation. The code below achieves that.
SELECT
NULL as WordDocPath
I want to take this one step further by adding the drive path text as the Null Column's default value so the user doesn't have to copy and paste 10k rows on the exported file.
How do I add the drivepath (C:\Users...) as a default value, text formatted?
While I'm at it.. would also like to add a FileName column the combines the text from other existing columns.
Example:
SELECT
Lastname
EmployeeID
Region
Result wanted: Doe_123456_REGION_LetterTitle
The Letter Title is not pulled from the table, it's just a text string.
How do I add the drivepath (C:\Users...) as a default value
By selecting it, instead of null:
select 'C:\Users...' as drivepath
from ...
add a FileName column the combines the text from other existing columns
That's concatenation.
select lastname ||'_'|| employeeID ||'_' || 'LetterTitle' as result
from ...
Related
I have a table that has some rows with normal JSON and some with escaped values in the JSON field (backslashes)
id
obj
1
{"is_from_shopping_bag":true,"products":[{"price":{"amount":"18.00","currency":"USD","offset":100,"amount_with_offset":"1800"},"product_id":"1234","quantity":1}],"source":"cart"}
2
{"is_from_shopping_bag":"","products":"[{\ "product_id\ ":\ "2345\ ",\ "price\ ":{\ "currency\ ":\ "USD\ ",\ "amount\ ":\ "140.00\ ",\ "offset\ ":100},\ "quantity\ ":1}]"}
(Note: I needed to include a space after the backslashes in the above table so that they would show up in the github generated markdown table -- my actual table does not include those spaces between the backslash and the quote character)
I am doing a sql query in Hive to get the 'currency' field.
Currently I can run
SELECT
id,
JSON_EXTRACT(obj, '$.products[0].price.currency')
FROM my_table
Which will give me the correct output for the first row, but gives me a NULL in the second row
id
obj
1
"USD"
2
NULL
What is the best way to get currency field from the second row? Is there a way to clean up the field and remove the backslashes before trying to JSON_EXTRACT the relevant data?
I could use REPLACE to swap the '\ ' for '', but is that the most efficient method?
Replace \" with " using regexp_replace like this:
regexp_replace(obj,'\\\\"','"')
I have a SQL Server table that contains an nvarchar(max) column (MyText) containing sentences. I need to identify all instances of a particular phrase in all rows of the (MyText) column. Once identified I want to replace all instances with different text.
Thanks,
Brad
select cust_div, cust_seral
from [dbo].[lveIntake_closing_scripts]
where close_script like '%LMLSUnit%LMLSUnit.com%'
To count how many instances of the source string is contained within each row, you need to replace each instance with a string that is one character shorter, then subtract that length of the resultant string from the length of the original string. Like this:
select
cust_div
, cust_seral
, len(close_script) - len(replace(close_script, 'LMLSUnit.com','LMLSUnit.co'))
from [dbo].[lveIntake_closing_scripts]
where close_script like '%LMLSUnit%LMLSUnit.com%'
I have a postgres table which contains rows that each hold multiple lines of text (split by new lines), for example...
The table name is formats, column is called format, an example format (1 table row) would look like the following:
list1=text1;
list2=text2;
list3=text3;
etc etc
I would like a way to identify the list2 string and then append additional text to the end of the same line.
So the outcome would be:
list1=text1;
list2=test2;additionaltext
list3=text3;
I have tried the below to try and pull in the 'capture string' into the replace string but have been unsuccessful so far.
regexp_replace(format, 'list2=.*', '\1 additionaltext','n');
To capture a pattern, you must enclose it in parenthesis.
regexp_replace(format, '(list2=.*)', '\1additionaltext', 'n')
Hey all I'm trying to parse out any duplicates in an access database. I want the database to be usable for the access illiterate and therefore I am trying to set up queries that can be run without any understanding of the program.
My database is setup where there are occasionally special characters attached to the entries in the Name field. I am interested in checking for duplicate entries based of the fields field1 and name. How can I include the counts for entries with special characters with their non-special character counterparts? Is this possible in a single step or do I need to add a step where I clean the data first?
Currently my code (shown below) only returns counts for entries not including special characters.
SELECT
table.[field1],
table.[Name],
Count(table.[Name]) AS [CountOfName]
FROM
table
GROUP BY
table.[field1],
table.[Name]
HAVING
(((table.[Name]) Like "*") AND ((Count(table.[Name]))>1));
I have tried adding a leading space to the Like statement (Like " *"), but that returns zero results.
P.S. I have also tried the Replace statement to replace the special characters, but that did not work.
field1 ##
1234567
1234567
4567890
4567890
name ##
brian
brian
ted
ted‡
Results
field1
1234567
name
brian
countofname
2
GROUP BY works by placing rows into groups where values are the same. So, when you run your query on your data and it groups by field1 and name, you are saying "Put these records into groups where they share a common field1 and name value". If you want 4567890, ted and 4567890, ted† to show in the same group, and thus have a count of 2, both the field1 and name have to be the same.
If you only have one or two possible special characters on the end of the names, you could potentially use Replace() or Substring() to remove all the special chars from the end of the names, but remember you must also GROUP BY the new expression you create; you can't GROUP BY the original name field or you won't get your desired count. You could also create another column that contains a sanitized name, one without any special character on the end.
I don't have Access installed, but something like this should do it:
SELECT
table.[field1],
Replace(table.[Name], "†", "") AS Name,
Count(table.[Name]) AS [CountOfName]
FROM
table
GROUP BY
table.[field1],
Replace(table.[Name], "†", "")
I have the following data in my "Street_Address_1" column:
123 Main Street
Using Postgresql, how would I write a query to update the "Street_Name" column in my Address table? In other words, "Street_Name" is blank and I'd like to populate it with the street name value contained in the "Street_Address_1" column.
From what I can tell, I would want to use the "regexp_matches" string method. Unfortunately, I haven't had much luck.
NOTE: You can assume that all addresses are in a "StreetNumber StreetName StreetType" format.
If you just want to take Street_Address_1 and strip out any leading numbers, you can do this:
UPDATE table
SET street_name = regexp_replace(street_address_1, '^[0-9]* ','','');
This takes the value in street_address_1 and replaces any leading string of numbers (plus a single space) with an empty string (the fourth parameter is for optional regex flags like "g" (global) and "i" (case-insensitive)).
This version allows things like "1212 15th Street" to work properly.
Something like...:
UPDATE table
SET Street_Name = substring(Street_Address_1 FROM '^[0-9]+ ([a-zAZ]+) ')
See relevant section from PGSQL 8.3.7 docs, the substring form is detailed shortly after the start of the section.