I have a CTE that contains lots of joins and condition (mydashboard) and
I am trying to join the CTE to another table and show an additional column with the count of the second table.
What am I doing wrong?
select *, count(t_KPIRespConn.RespID)
from mydashboard
join t_kpirespconn on mydashboard.kpicodeid = t_kpirespconn.kpicodeid
group by mydashboard.KPIcodeID
Column 'mydashboard.code' is invalid in the select list because it is not contained in either an aggregate function or the GROUP BY clause.
Thanks
You will need to group by all non aggregated fields, meaning all fields in the SELECT list that are not used in an aggregate function, in your case, all field besides t_KPIRespConn.RespID.
Solution 1:
select field1, field2, field3,... fieldN, count(t_KPIRespConn.RespID)
from mydashboard
join t_kpirespconn on mydashboard.kpicodeid = t_kpirespconn.kpicodeid
group by mydashboard.KPIcodeID, field1, field2, field3, ...fieldN
Using a window function basically achieves the same thing but it is less verbose. You are not required to GROUP BY as the window function aggregates the values on the partition specified. For COUNT() you can specify OVER(), which means the entire results set in the group.
Solution 2:
select *,
count(*) OVER() //<-- Use this if you want the count of all records
from mydashboard
join t_kpirespconn on mydashboard.kpicodeid = t_kpirespconn.kpicodeid
Use the same window function but narrow the partition to any grouping you would like. In this case, the counts would pertain to all records with matching t_KPIRespConn.RespID values.
Solution 3:
select *, count(*) OVER(PARTITION BY t_KPIRespConn.RespID) //<-- Use this if you want the count of all records with the same t_KPIRespConn.RespID
from mydashboard
join t_kpirespconn on mydashboard.kpicodeid = t_kpirespconn.kpicodeid
select * .. group by mydashboard.KPIcodeID is your true issue. When you run aggregate functions, you must explicitly supply any columns that are non-aggregated in the select list in the group by. This will work
select mydashboard.KPIcodeID, count(t_KPIRespConn.RespID)
from mydashboard
join t_kpirespconn on mydashboard.kpicodeid = t_kpirespconn.kpicodeid
group by mydashboard.KPIcodeID
Related
The following code works fine:
SELECT name, (SELECT count(item_id) FROM bids WHERE item_id = items.id)
FROM items;
However, when I add
SELECT name, (SELECT count(item_id) FROM bids WHERE item_id = items.id)
FROM items
GROUP BY name;
I get ERROR: subquery uses ungrouped column "items.id" from outer query
Can anyone tell me why this is happening? Thanks!
If you GROUP BY name then any other columns you select from items must have an aggregate function applied. That's what GROUP BY means.
In your case, you are using another column from items -- id -- in a correlated scalar subquery. That's not an aggregate function, and id is not in the GROUP BY clause, so you get an error.
You could instead GROUP BY name, id. That should give you the same results as the first query, and is probably pointless.
If you actually have multiple rows in items with the same value for name, and you want to group the results of the scalar subquery for those values, you need to specify how to group them. Perhaps you want the total of the subquery results for each value of name. If so, I think you could do:
SELECT name, SUM(SELECT count(item_id) FROM bids WHERE item_id = items.id))
FROM items
GROUP BY name;
(I'm not positive about the specific syntax as I don't have a Postgres instance to test against.)
A clearer way to express it might be:
SELECT name, SUM(bid_count)
FROM (
SELECT name, (SELECT count(item_id) FROM bids WHERE item_id = items.id) AS bid_count
FROM items
)
GROUP BY name
Join the tables then perform the GROUP BY:
select i.name, count(b.item_id)
from items i
inner join bids b
on b.item_id = i.id
group by i.name
db<>fiddle here
I have read in various websites about the count() function but I still cannot make this work.
I made a small table with (id, name, last name, age) and I need to retrieve all columns plus a new one. In this new column I want to display how many times a name shows up or repeats itself in the table.
I have made test and can retrieve but only COLUMN NAME with the count column, but I haven't been able to retrieve all data from the table.
Currently I have this
select a.n_showsup, p.*
from [test1].[dbo].[person] p,
(select count(*) n_showsup
from [test1].[dbo].[person])a
This gives me all data on output but on the column n_showsup it gives me just the number of rows, now I know this is because I'm missing a GROUP BY but then when I write group by NAME it shows me a lot of records. This is an example of what I need:
You can use window functions, if you RDBMS supports them:
select t.*, count(*) over(partition by name) n_showsup
from mytable t
Alternatively, you can join the table with an aggregation query that counts the number of occurences of each name:
select t.*, x.n_showsup
from mytable t
inner join (select name, count(*) n_showsup from mytable group by name) x
on x.name = t.name
While the window function approach (#GMB's answer) is the right way to go, thinking through this from a subquery approach (like you were headed towards) would look something like:
select p.*, a.n_showsup
from [test1].[dbo].[person] p
INNER JOIN (
select name, count(*) n_showsup
from [test1].[dbo].[person]
GROUP BY name
) a ON p.name = a.name
This is VERY close to what you had, the difference is that we are grouping that subquery by name (so we get a count by name) and we can use that in the join criteria which we do with the ON clause on that INNER JOIN.
You should really never ever use a comma in your FROM clause. Instead use a JOIN.
I don't understand why I can't use this in my code :
SELECT MAX(SMTHNG), COUNT(MAX(SMTHNG))
FROM SomeTable;
Searched for an answer but didn't find it in documentation about these aggregate functions.
Also I get an SQL-compiler error "Invalid column name "SMTHNG"".
You want to know what the maximum SMTHNG in the table is with:
SELECT MAX(SMTHNG) FROM SomeTable;
This is an aggregation without GROUP BY and hence results in one single row containing the maximum SMTHNG.
Now you also want to know how often this SMTHNG occurs and you add COUNT(MAX(SMTHNG)). This, however, does not work, because you can not aggregate an aggregate directly.
This doesn't work either:
SELECT ANY_VALUE(max_smthng), COUNT(*)
FROM (SELECT MAX(smthng) AS max_smthng FROM sometable) t;
because the sub query only contains one row, so it's too late to count.
So, either use a sub query and select from the table again:
SELECT ANY_VALUE(smthng), COUNT(*)
FROM sometable
WHERE smthng = (SELECT MAX(smthng) FROM sometable);
Or count per SMTHNG before looking for the maximum. Here is how to get the counts:
SELECT smthng, COUNT(*)
FROM sometable
GROUP BY smthng;
And the easiest way to get the maximum from this result is:
SELECT TOP(1) smthng, COUNT(*)
FROM sometable
GROUP BY smthng
ORDER BY COUNT(*) DESC;
First of all, please read my comment.
Depending on what you're trying to achieve, the statement have to be changed.
If you want to count the highest values in SMTHNG field, you may try this:
SELECT T1.SMTHNG, COUNT(T1.SMTHNG)
FROM SomeTable T1 INNER JOIN
(
SELECT MAX(SMTHNG) AS A
FROM SomeTable
) T2 ON T1.SMTHNG = T2.A
GROUP BY T1.SMTHNG;
use cte like below or subquery
with cte as
(
select count(*) as cnt ,col from table_name
group by col
) select max(cnt) from cte
you can not use double aggregate function at a time on same column
I wrote SQL query in which I have one inner query and one outer query, My outer query produces the result on behalf of inner query, now I need to find the no of rows returning by my outer query, so what I did, I enclosed it inside another select statement and use count() function which produces the result, but i need to know more precise way to calculate the row count, please see my below query and suggest me the best way to do the same.
SELECT count(*) FROM (
SELECT
COUNT(*) NO_OF_EMP
,SUM(tbl.AMOUNT) TOTAL_AMOUNT
,tbl.YYYYMM
,tbl.DATA_PICKED_BY_NAME
,MIN(DATA_PICKED_DATE) DATA_PICKED_DATE
,ROW_NUMBER() OVER (ORDER BY tbl.REFERENCE_ID) AS ROW_NUM
FROM (
SELECT
SALARY_REPORT_ID
,EMP_NAME
,EMP_CODE
,PAY_CODE
,PAY_CODE_NAME
,AMOUNT
,PAY_MODE
,PAY_CODE_DESC
,YYYYMM
,REMARK
,EMP_ID
,PRAN_NUMBER
,PF_NUMBER
,PRAN_NO
,ATTOFF_EMPCODE
,DATA_PICKED_DATE
,DATA_PICKED_BY
,DATA_PICKED_BY_NAME
,SUBSTR(REFERENCE_ID,0,3) REFERENCE_ID
FROM SALARY_DETAIL_REPORT_HISTORY
WHERE PAY_CODE=999
AND REFERENCE_ID LIKE '202%'
) tbl
GROUP BY tbl.REFERENCE_ID,tbl.YYYYMM,tbl.DATA_PICKED_BY_NAME
order by tbl.YYYYMM
)mytbl1
Select count distinct of the most abbreviated version of a single value of your group values from your original query:
SELECT count(distinct SUBSTR(REFERENCE_ID,0,3) || YYYYMM || DATA_PICKED_BY_NAME)
FROM SALARY_DETAIL_REPORT_HISTORY
WHERE PAY_CODE=999
AND REFERENCE_ID LIKE '202%'
When I try to use the following SELECT statement:
SELECT [lots of columns]
FROM Client, Customer, Document, Group
WHERE [some conditions]
GROUP BY Group.id
SQL Server complains that the columns I selected are not part of the GROUP BY statement nor an aggregate function. Am I using GROUP BY wrong? What should I be using instead?
To return all single occurences of a group by field, together with associated field values, write a query like:
select group_field,
max(other_field1),
max(other_field2),
...
from mytable1
join mytable2 on ...
group by group_field
having count(*) = 1;
Yes, you are using GROUP BY incorrectly. The point of using GROUP BY is to use aggregate functions. If you have no aggregrate functions you probably want SELECT DISTINCT instead.
SELECT DISTINCT
col1,
col2,
-- etc
coln
FROM Client
JOIN Customer ON ...
JOIN Document ON ...
JOIN [Group] ON ...
WHERE ...
My first guess would be that the problem is that you have table called Group, which I believe is a reserved word in SQL. Try wrapping the Group name with ' '
You want to group by all columns you are selecting that is not in an aggregate funcion.
SELECT ProductName, ProductCategory, SUM(ProductAmount)
FROM Products
GROUP BY ProductName, ProductCategory
This will give you a disticnt result of Product names and categories with the sum total of product amount in all aggregate child records for that group.