Select max value from a table and increment it in another - sql

I'm struggling with a sql query, and will appreciate any help.
I have two tables, they both have a sort column. The first one looks like this:
person_id
image_name
sort_number
739
chest.png
1
739
legs.png
2
And the second table like this
person_id
advert
sort_number
739
house.png
1
739
car.png
2
I want to be able to select the max sort_number from the table1 and make the first sort_number in table2 (house.png) to become 3, and the sort_number for car.png) to become 4.
Essentially, what I'm looking to achieve is an insert statement that selects from table2 and insert into table1, but I need the sort_number not to have duplicate, so the starting sort_number from the table2 should be the max of table1+1...and so on. If table1 does not have the person, I simply insert and not change the sort_number value.
I would appreciate of someone can help me please.

Here's one way:
With grouped as
(Select person_id, max(sort_num) as maxsort
From table1
Group by person_id)
Select t2.person_id, t2.advert, t2.sort_num + coalesce(g.maxsort,0) as newsortnum
From table t2
Left join grouped g on t2.person_id = g.person_id
This will get max value of sort number for each key in the first table, and then attempt to join the second table to this grouped dataset. If there is a match, you add your second table's value to the max, and retain the value from the second table otherwise.

You could try using UNION ALL and ROW_NUMBER:
WITH CTE AS
(
SELECT
person_id,
image_name,
sort_number,
1 sort_table
FROM dbo.Table1 t1
UNION ALL
SELECT
person_id,
advert,
sort_number,
2
FROM dbo.Table2 t2
)
SELECT
person_id,
image_name,
ROW_NUMBER() OVER(PARTITION BY person_id ORDER BY sort_table, sort_number) sort_number
FROM CTE
;

insert into table2(person_id, advert, sort_number)
select table1.person_id, table1.image_name, table1.sort_number + table2.sort_number
from table1
join table2
on 1 = 1
left join table2 newer
on table2.sort_number < newer.sort_number
left join table1 mismatch
on table2.person_id = mistmatch.person_id and table2.advert = mismatch.image_name
where newer.person_id is null and mismatch.person_id is null
Firs join: we need to pair table1 and table2
Second join: we make sure that table2 record in the pair is the newest
Third join: we make sure that we do not insert what's already there.

Related

Joining and grouping to equate on two tables

I've tried to minify this problem as much as possible. I've got two tables which share some Id's (among other columns)
id id
---- ----
1 1
1 1
2 1
2
2
Firstly, I can get each table to resolve to a simple count of how many of each Id there is:
select id, count(*) from tbl1 group by id
select id, count(*) from tbl2 group by id
id | tbl1-count id | tbl2-count
--------------- ---------------
1 2 1 3
2 1 2 2
but then I'm at a loss, I'm trying to get the following output which shows the count from tbl2 for each id, divided by the count from tbl1 for the same id:
id | count of id in tbl2 / count of id in tbl1
==========
1 | 1.5
2 | 2
So far I've got this:
select tbl1.Id, tbl2.Id, count(*)
from tbl1
join tbl2 on tbl1.Id = tbl2.Id
group by tbl1.Id, tbl2.Id
which just gives me... well... something nowhere near what I need, to be honest! I was trying count(tbl1.Id), count(tbl2.Id) but get the same multiplied amount (because I'm joining I guess?) - I can't get the individual representations into individual columns where I can do the division.
This gives consideration to your naming of tables -- the query from tbl2 needs to be first so the results will include all records from tbl2. The LEFT JOIN will include all results from the first query, but only join those results that exist in tbl1. (Alternatively, you could use a FULL OUTER JOIN or UNION both results together in the first query.) I also added an IIF to give you an option if there are no records in tbl1 (dividing by null would produce null anyway, but you can do what you want).
Counts are cast as decimal so that the ratio will be returned as a decimal. You can adjust precision as required.
SELECT tb2.id, tb2.table2Count, tb1.table1Count,
IIF(ISNULL(tb1.table1Count, 0) != 0, tb2.table2Count / tb1.table1Count, null) AS ratio
FROM (
SELECT id, CAST(COUNT(1) AS DECIMAL(18, 5)) AS table2Count
FROM tbl2
GROUP BY id
) AS tb2
LEFT JOIN (
SELECT id, CAST(COUNT(1) AS DECIMAL(18, 5)) AS table1Count
FROM tbl1
GROUP BY id
) AS tb1 ON tb1.id = tb2.id
(A subqquery with a LEFT JOIN will allow the query optimizer to determine how to generate the results and will generally outperform a CROSS APPLY, as that executes a calculation for every record.)
Assuming your expected results are wrong, then this is how I would do it:
CREATE TABLE T1 (ID int);
CREATE TABLE T2 (ID int);
GO
INSERT INTO T1 VALUES(1),(1),(2);
INSERT INTO T2 VALUES(1),(1),(1),(2),(2);
GO
SELECT T1.ID AS OutID,
(T2.T2Count * 1.) / COUNT(T1.ID) AS OutCount --Might want a CONVERT to a smaller scale and precision decimal here
FROM T1
CROSS APPLY (SELECT T2.ID, COUNT(T2.ID) AS T2Count
FROM T2
WHERE T2.ID = T1.ID
GROUP BY T2.ID) T2
GROUP BY T1.ID,
T2.T2Count;
GO
DROP TABLE T1;
DROP TABLE T2;
You can aggregate in subqueries and then join:
select t1.id, t2.cnt * 1.0 / t1.cnt
from (select id, count(*) as cnt
from tbl1
group by id
) t1 join
(select id, count(*) as cnt
from tbl2
group by id
) t2
on t1.id = t2.id

DISTINCT based on ID between Two table and SUM of the other exiting column in SQL

SELECT
SUM(amount), (DISTINCT table1.id)
FROM
table1
INNER JOIN
table2 ON table1.id = table2.id IS NULL;
Table1 id amount Table2 id product
1 40 5 10
2 364.25 2 20
3 704.5 8 30
4 404.5 3 40
5 580.5 2 20
The id is not unique or primary ------------------first i need to ignore all double entry ID from table2 then match id from table2 to table1 after that those ids will be match i need total of amount figure amount is a column name i will not calculate single the data will be more than 20000. please help me if you can
First compare match table2 id with table1 id if found any id match then those id amount need to be SUM i mean total. here match id is 2 and 3 according to table2 and then we will add this 2 and 3 id amount so result will be 364.25+704.5=1068.75 i am looking the result how can i do it using mysql.
I am trying to DISTINCT based on ID between two tables and SUM of the other existing column we have in table1. Can somebody help me how to do it?
Based on your latest comment try this
SELECT
SUM(amount)
FROM
table1
INNER JOIN
(Select Distinct ID From table2) T2 ON table1.id = T2.id
Lets leave a matter of performance beyond the topic:)
So according to this:
First compare match table2 id with table1 id if found any id match
then those id amount need to be SUM i mean total
it is possible to use correlated subquery:
select sum(t1.amount)
from table1 t1
where exists (select 1 from table2 t2 where t2.id = t1.id)
From what I understood, you need common IDs from both table and corresponding sum of amount.
SELECT
SUM(amount)
FROM
table1
WHERE
id IN (SELECT id
FROM table2);

Join table on Count

I have two tables in Access, one containing IDs (not unique) and some Name and one containing IDs (not unique) and Location. I would like to return a third table that contains only the IDs of the elements that appear more than 1 time in either Names or Location.
Table 1
ID Name
1 Max
1 Bob
2 Jack
Table 2
ID Location
1 A
2 B
Basically in this setup it should return only ID 1 because 1 appears twice in Table 1 :
ID
1
I have tried to do a JOIN on the tables and then apply a COUNT but nothing came out.
Thanks in advance!
Here is one method that I think will work in MS Access:
(select id
from table1
group by id
having count(*) > 1
) union -- note: NOT union all
(select id
from table2
group by id
having count(*) > 1
);
MS Access does not allow union/union all in the from clause. Nor does it support full outer join. Note that the union will remove duplicates.
Simple Group By and Having clause should help you
select ID
From Table1
Group by ID
having count(1)>1
union
select ID
From Table2
Group by ID
having count(1)>1
Based on your description, you do not need to join tables to find duplicate records, if your table is what you gave above, simply use:
With A
as
(
select ID,count(*) as Times From table group by ID
)
select * From A where A.Times>1
Not sure I understand what query you already tried, but this should work:
select table1.ID
from table1 inner join table2 on table1.id = table2.id
group by table1.ID
having count(*) > 1
Or if you have ID's in one table but not the other
select table1.ID
from table1 full outer join table2 on table1.id = table2.id
group by table1.ID
having count(*) > 1

How to compare tables and find duplicates and also find columns with different value

I have the following tables in Oracle 10g:
Table1
Name Status
a closed
b live
c live
Table2
Name Status
a final
b live
c live
There are no primary keys in both tables, and I am trying to write a query which will return identical rows without looping both tables and comparing rows/columns. If the status column is different then the row in the Table2 takes presedence.
So in the above example my query should return this:
Name Status
a final
b live
c live
Since you have mentioned that there are no Primary Key on both tables, I'm assuming that there maybe a possibility that a row may exist on Table1, Table2, or both. The query below uses Common Table Expression and Windowing function to get such result.
WITH unionTable
AS
(
SELECT Name, Status, 1 AS ordr FROM Table1
UNION
SELECT Name, Status, 2 AS ordr FROM Table2
),
ranks
AS
(
SELECT Name, Status,
ROW_NUMBER() OVER (PARTITION BY NAME ORDER BY ordr DESC) rn
FROM unionTable
)
SELECT Name, Status
FROM ranks
WHERE rn = 1
SQLFiddle Demo
Something like this?
SELECT table1.Name, table2.Status
FROM table1
INNER JOIN table2 ON table1.Name = table2.Name
By always returning table2.Status you've covered both the case when they're the same and when they're different (essentially it doesn't matter what the value of table1.Status is).

mysql - union tables by unique field

I have two tables with the same structure:
id name
1 Merry
2 Mike
and
id name
1 Mike
2 Alis
I need to union second table to first with keeping unique names, so that result is:
id name
1 Merry
2 Mike
3 Alis
Is it possible to do this with MySQL query, without using php script?
This is not a join (set multiplication), this is a union (set addition).
SELECT #r := #r + 1 AS id, name
FROM (
SELECT #r := 0
) vars,
(
SELECT name
FROM table1
UNION
SELECT name
FROM table2
) q
This will select all names from table1 and combine those with all the names from table2 which are not in table1.
(
select *
from table1
)
union
(
select *
from table2 t2
left join table1 t1 on t2.name = t1.name
where t1.id is null
)
Use:
SELECT a.id,
a.name
FROM TABLE_A a
UNION
SELECT b.id,
b.name
FROM TABLE_B b
UNION will remove duplicates.
As commented, it all depends on what your 'id' means, cause in the example, it means nothing.
SELECT DISTINCT(name) FROM t1 JOIN t2 ON something
if you only want the names
SELECT SUM(something), name FROM t1 JOIN t2 ON something GROUP BY name
if you want to do some group by
SELECT DISTINCT(name) FROM t1 JOIN t2 ON t1.id = t2.id
if the id's are the same
SELECT DISTINCT COALESCE(t1.name,t2.name) FROM
mytable t1 LEFT JOIN mytable t2 ON (t1.name=t2.name);
will get you a list of unique names from the 2 tables. If you want them to get new ids (like Alis does in your desired results), that's something else and requires the answers to a couple of questions:
do any of the names need to maintain their previous id. And if they do, which table's id should be preferred?
why do you have 2 tables with the same structure? ie what are you trying to accomplish when you generate the unique name list?