I have been trying to break the datetime in 12 hour chunk in Presto SQL but was unsuccessful.
Raw data table:
datetime
Login
2022-05-08 07:10:00.000
1234
2022-05-09 23:20:00.000
5678
2022-05-09 06:20:00.000
5674
2022-05-08 09:20:00.000
8971
The output table should look like below. I have to get count of login in 12 hour chunks. So, first should be from 00:00:00.000 to 11:59:00:000 and the next chunk from 12:00:00.000 to 23:59:00:000
Output:
datetime
count
2022-05-08 00:00:00.000
2
2022-05-08 12:00:00.000
0
2022-05-09 00:00:00.000
1
2022-05-09 12:20:00.000
1
This should work:
Extract the hour from the timestamp, then integer divide it by 12. That will make it 0 till 11:59, and 1 till 23:59. Then, multiply that back by 12.
Use that resulting integer to DATE_ADD() it with unit 'HOUR' to the timestamp of the row truncated to the day.
SELECT
DATE_ADD('HOUR',(HOUR(ts) / 12) * 12, TRUNC(ts,'DAY')) AS halfday
, SUM(login) AS count_login
FROM indata
GROUP BY
halfday
;
-- out halfday | count_login
-- out ---------------------+-------------
-- out 2022-05-08 00:00:00 | 15879
-- out 2022-05-08 12:00:00 | 5678
This query worked for me.
SELECT
DATE_ADD('HOUR',(HOUR(ts) / 12) * 12, date_trunc('DAY',ts)) AS halfday
, SUM(login) AS count_login
FROM indata
GROUP BY
halfday
;
Related
I need to get last 6 weeks data from some table, right now the logic that I use is this
WEEK([date column]) BETWEEN WEEK(NOW()) - 6 AND WEEK(NOW())
It run as I want, but January is near and I realize that this query will not working as it is. I try to run my query on 15th January 2022, I only get data from 1st January to 15th January when I use my logic.
TGL MINGGU_KE
2022-01-01 | 1
2022-01-02 | 2
2022-01-03 | 2
2022-01-04 | 2
2022-01-05 | 2
2022-01-06 | 2
2022-01-07 | 2
2022-01-08 | 2
2022-01-09 | 3
2022-01-10 | 3
2022-01-11 | 3
2022-01-12 | 3
2022-01-13 | 3
2022-01-14 | 3
2022-01-15 | 3
Can I get the last 6 weeks data including last year?
This is my dbfiddle: https://dbfiddle.uk/o9BeAFJF
You can round the dates to the first day of the week using ROUND, TRUNC or THIS_WEEK
WITH
SEARCH_WEEK (TGL) AS (
VALUES date '2020-12-01'
UNION ALL
SELECT tgl + 1 DAY FROM SEARCH_WEEK WHERE tgl < CURRENT date
),
BASE_DATE (base_date) AS (
VALUES date '2022-01-15'
),
OPTIONS (OPTION, OPTION_BASE_DATE) AS (
SELECT OPTION, option_base_date FROM base_date CROSS JOIN LATERAL (
VALUES
('ROUND D', ROUND(base_date, 'D')),
('ROUND IW', ROUND(base_date, 'IW')),
('ROUND W', ROUND(base_date, 'W')),
('ROUND WW', ROUND(base_date, 'WW')),
('TRUNC D', TRUNC(base_date, 'D')),
('TRUNC IW', TRUNC(base_date, 'IW')),
('TRUNC W', TRUNC(base_date, 'W')),
('TRUNC WW', TRUNC(base_date, 'WW')),
('THIS_WEEK', THIS_WEEK(base_date)),
('THIS_WEEK + 1 DAY', THIS_WEEK(base_date) + 1 DAY)
) a (OPTION, OPTION_BASE_DATE)
)
SELECT
OPTION,
MIN(TGL) BEGIN,
max(tgl) END,
dayname(MIN(TGL)) day_BEGIN,
dayname(max(tgl)) day_end,
days_between(max(tgl), min(tgl)) + 1 duration_in_days
FROM
SEARCH_WEEK
CROSS JOIN options
WHERE
TGL BETWEEN option_base_date - 35 DAYS AND option_base_date + 6 DAYS
GROUP BY OPTION
OPTION
BEGIN
END
DAY_BEGIN
DAY_END
DURATION_IN_DAYS
ROUND D
2021-12-12
2022-01-22
Sunday
Saturday
42
ROUND IW
2021-12-13
2022-01-23
Monday
Sunday
42
ROUND W
2021-12-11
2022-01-21
Saturday
Friday
42
ROUND WW
2021-12-11
2022-01-21
Saturday
Friday
42
THIS_WEEK
2021-12-05
2022-01-15
Sunday
Saturday
42
THIS_WEEK + 1 DAY
2021-12-06
2022-01-16
Monday
Sunday
42
TRUNC D
2021-12-05
2022-01-15
Sunday
Saturday
42
TRUNC IW
2021-12-06
2022-01-16
Monday
Sunday
42
TRUNC W
2021-12-11
2022-01-21
Saturday
Friday
42
TRUNC WW
2021-12-11
2022-01-21
Saturday
Friday
42
fiddle
you can use dateadd to get first day of week six weeks ago like this:
Select * from tableName
where [dateColumn] between dateadd(WEEK,-6,getdate()) and getdate()
You can use DATEADD to get last 6 weeks of data as follows:
Select * from [TableName] where [DateColumn] between
DATEADD(WEEK,-6,GETDATE()) and GETDATE();
I am trying to create a table in Snowflake with 15 mins interval. I have tried with generator, but that's not give in the 15 minutes interval. Are there any function which I can use to generate and build this table for couple of years worth data.
Such as
Date
Hour
202-03-29
02:00 AM
202-03-29
02:15 AM
202-03-29
02:30 AM
202-03-29
02:45 AM
202-03-29
03:00 AM
202-03-29
03:15 AM
.........
........
.........
........
Thanks
Use following as time generator with 15min interval and then use other date time functions as needed to extract date part or time part in separate columns.
with CTE as
(select timestampadd(min,seq4()*15 ,date_trunc(hour, current_timestamp())) as time_count
from table(generator(rowcount=>4*24)))
select time_count from cte;
+-------------------------------+
| TIME_COUNT |
|-------------------------------|
| 2022-03-29 14:00:00.000 -0700 |
| 2022-03-29 14:15:00.000 -0700 |
| 2022-03-29 14:30:00.000 -0700 |
| 2022-03-29 14:45:00.000 -0700 |
| 2022-03-29 15:00:00.000 -0700 |
| 2022-03-29 15:15:00.000 -0700 |
.
.
.
....truncated output
| 2022-03-30 13:15:00.000 -0700 |
| 2022-03-30 13:30:00.000 -0700 |
| 2022-03-30 13:45:00.000 -0700 |
+-------------------------------+
There are many answers to this question h e r e already (those 4 are all this month).
But major point to note is you MUST NOT use SEQx() as the number generator (you can use it in the ORDER BY, but that is not needed). As noted in the doc's
Important
This function uses sequences to produce a unique set of increasing integers, but does not necessarily produce a gap-free sequence. When operating on a large quantity of data, gaps can appear in a sequence. If a fully ordered, gap-free sequence is required, consider using the ROW_NUMBER window function.
CREATE TABLE table_of_2_years_date_times AS
SELECT
date_time::date as date,
date_time::time as time
FROM (
SELECT
row_number() over (order by null)-1 as rn
,dateadd('minute', 15 * rn, '2022-03-01'::date) as date_time
from table(generator(rowcount=>4*24*365*2))
)
ORDER BY rn;
then selecting the top/bottom:
(SELECT * FROM table_of_2_years_date_times ORDER BY date,time LIMIT 5)
UNION ALL
(SELECT * FROM table_of_2_years_date_times ORDER BY date desc,time desc LIMIT 5)
ORDER BY 1,2;
DATE
TIME
2022-03-01
00:00:00
2022-03-01
00:15:00
2022-03-01
00:30:00
2022-03-01
00:45:00
2022-03-01
01:00:00
2024-02-28
22:45:00
2024-02-28
23:00:00
2024-02-28
23:15:00
2024-02-28
23:30:00
2024-02-28
23:45:00
I have table T1
ID SCHEDULESTART SCHEDULEFINISH
1 2018-05-12 14:00:00 2018-05-14 11:00:00
2 2018-05-30 14:00:00 2018-06-01 11:00:00
3 2018-02-28 14:00:00 2018-03-02 11:00:00
4 2018-02-28 14:00:00 2018-03-01 11:00:00
5 2018-05-30 14:00:00 2018-05-31 11:00:00
I want to select all rows where difference in days (it's not important difference in hours) is greater than 1 day.
If SCHEDULESTART or SCHEDULEFINISH are on the same day or SCHEDULEFINISH is on next day then these rows should NOT be selected.
So the result should return rows with IDs: 1 2 3
because first row have difference in two days, second row (1st June is 2 days after 30th May ) and 3rd row (2nd March is 2 days after 28 February).
Is this possible somehow?
I know the function DAY but this will return only day number in that one month!!!
I must beging my query with
SELECT ID FROM T1 WHERE ...
Thanks in advance
In DB2, this should work:
select t1.*
from t1
where date(schedulestart) < date(schedulefinish) - 1 day;
I have a table
ID Value Date
1 10 2017-10-02 02:50:04.480
2 20 2017-10-01 07:28:53.593
3 30 2017-09-30 23:59:59.000
4 40 2017-09-30 23:59:59.000
5 50 2017-09-30 02:36:07.520
I compare Value with previous date. But, I don't need compare result between first day in current month and last day in previous month. For this table, I don't need to compare result between 2017-10-01 07:28:53.593 and 2017-09-30 23:59:59.000 How it can be done?
Result table for this example:
ID Value Date Diff
1 10 2017-10-02 02:50:04.480 10
2 20 2017-10-01 07:28:53.593 NULL
3 30 2017-09-30 23:59:59.000 10
4 40 2017-09-29 23:59:59.000 10
5 50 2017-09-28 02:36:07.520 NULL
You can use this.
SELECT * ,
LEAD(Value) OVER( PARTITION BY DATEPART(YEAR,[Date]), DATEPART(MONTH,[Date]) ORDER BY ID ) - Value AS Diff
FROM MyTable
ORDER BY ID
you can use a query like below
select *,
diff=LEAD(Value) OVER( PARTITION BY Month(Date),Year(Date) ORDER BY Date desc)-Value
from t
order by id asc
see working demo
I have a table that hold the start date and the end date of a financial period.
CHARGE_PERIOD_ID START_DATE END_DATE
13 2013-03-31 00:00:00.000 2013-04-27 00:00:00.000
14 2013-04-28 00:00:00.000 2013-05-25 00:00:00.000
15 2013-05-26 00:00:00.000 2013-06-29 00:00:00.000
16 2013-06-30 00:00:00.000 2013-07-27 00:00:00.000
17 2013-07-28 00:00:00.000 2013-08-24 00:00:00.000
18 2013-08-25 00:00:00.000 2013-09-28 00:00:00.000
19 2013-09-29 00:00:00.000 2013-10-26 00:00:00.000
20 2013-10-27 00:00:00.000 2013-11-23 00:00:00.000
21 2013-11-24 00:00:00.000 2013-12-28 00:00:00.000
22 2013-12-29 00:00:00.000 2014-01-25 00:00:00.000
23 2014-01-26 00:00:00.000 2014-02-22 00:00:00.000
24 2014-02-23 00:00:00.000 2014-03-29 00:00:00.000
The user of a report wants the current financial year split into 12 periods and want to give to feed in 2 parameters into the report , a year and a period number which will go into my sql . So something like #year=2014 #period=1 will be recieved . I have to write some sql to go to this table and set a period start date of 31/03/2014 and a period end date of 27/04/2014.
So in pseudo code:
Look up period 1 for 2014 and return period start date of 31/03/2014 and period end date of 27/04/2014.
#PERIOD_START_DATE = select the the first period that starts in March for the given year . all financial period starts in March.
#PERIOD_END_DATE = select the corresponding END_DATE from the table .
The question is how to begin to code this or my design approach? Should I create a function that calcualtes this or should I do a CTE and add a column which will hold the period number in the way they want etc .
Thinking about it more I think I need a mapping table . So the real question is can I do this without a mapping table ?
DECLARE #Year INT
DECLARE #Period INT
SET #Year= 2013
SET #Period = 1
;WITH CTE AS
(
SELECT *, ROW_NUMBER() OVER (PARTITION BY
CASE WHEN MONTH([START_DATE])<3 THEN YEAR([START_DATE]) -1 ELSE YEAR([START_DATE]) END
ORDER BY
CASE WHEN MONTH([START_DATE])<3 THEN YEAR([START_DATE]) - 1 ELSE YEAR([START_DATE]) END
,CASE WHEN MONTH([START_DATE])<3 THEN MONTH([START_DATE]) + 12 ELSE MONTH([START_DATE]) END
) AS RN
FROM Periods
)
SELECT * FROM CTE
WHERE RN = #Period
AND CASE WHEN MONTH([START_DATE])<3 THEN YEAR([START_DATE]) -1 ELSE YEAR([START_DATE]) END = #Year
SQLFiddle DEMO