Join 2 tables using start date time SQL Developer - sql

I have 2 tables and, I want to create a join in SQL developer through the date times. Example, first table has a START_DATETIME 3/28/1999 15:38:00 and second table has START_DATETIME 3/28/1999 15:47:00, I want to join by date and hour only. Leaving out the min. How can I trunc the min to create a join between these tables. Please help.

Use the trunc() function. The Oracle TRUNC function returns a date truncated to a specific unit of measure. In your case, you'll want to use HH, HH12 or HH24 for the hour format.
The syntax will be trunc(a.start_datetime, 'HH24').
The Oracle documentation contain a much lengthier explanation about each of the
formats you can specify.

One option is to use to_char function with appropriate format model, e.g.
from tab_1 a join tab_2 b on to_char(a.start_datetime, 'dd.mm.yyyy hh24') =
to_char(b.start_datetime, 'dd.mm.yyyy hh24')

Related

How can I return data with a timestamp and how to filter it?

I'm completely new to SQL and I'm struggling. I need to run a query from the dates mentioned below and split the timestamped data into shift hours 6-13:59, 14-21:59 and 22 - 05:59. I need to see how many shipments have been sent in between those hours. I came up with something like this, but it doesn't seem to work.
When I put the date without the timestamp the data gets returned, but I want to have only those rows returned that have been sent in between 6 - 14. The SDG table includes a timestamp, so I don't understand why it doesn't work.
select s1.date, k.su, count(distinct s1.nr) AMO_SHIP2021
from sdg s1 , client k
where s1.clientnr in ('1')
and s1.date between '01.12.2021 06:00:00' and '14.12.2021 13:59:59'
and s1.function in ('20')
and k.nr = s1.clientnr
group by s1.date, k.su, s1.function
You should post the table structure there. Generally, if your column is of Date type you need to operate dates using BETWEEN with dates and not strings
s1.date BETWEEN to_date('01.12.2021 06:00:00', 'DD.MM.YYYY HH24:MI:SS') AND
to_date('14.12.2021 13:59:59', 'DD.MM.YYYY HH24:MI:SS')
Refer in your search to FORMAT MODEL.
to_date('string date', 'format model')

What should be the outcome of TRUNC('02-MAY-14','HH24')?

I found a bizarre snippet which is confusing me so I thought I'll ask the experts.
Let assume a tableA got following columns with data:
"START_TIME":1399075198
"END_TIME":1399075200
"START_DATE":"02-MAY-14"
"END_DATE":"03-MAY-14"
Now query 1:
SELECT MIN(start_date) INTO sdate FROM tableA;
query 2:
SELECT TRUNC(sdate, 'HH24') + INTERVAL '30' MINUTE from dual;
So if start-date = '02-MAY-14', how would that truncate to 'HH24'?
The expression:
TRUNC(sdate, 'HH24')
cuts off everything from a date that is smaller than an hour, i.e. the minutes and seconds. For the specific date:
TRUNC('02-MAY-14','HH24')
it returns the date unchanged. It only makes sense if the Oracle date contains a time component.
Possibly, your SQL tool (SQL Developer, TOAD etc.) is configured to not display the time part of Oracle dates. So the original date might in fact be 02-MAY-14 09:03:25. Then it would return:
02-MAY-14 09:00:00
You mention the columns START_TIME and END_TIME but don't use them in the SQL queries. What are they for?
As start_date does not have a time part in your example, TRUNC is superfluous here. If however it had a timepart, if for example start_time had been added to start_date before, then TRUNC would remove minutes, seconds and microseconds, only keeping the date and hour because of 'HH24' which means "truncate datetime down to full hour".
In Oracle the date datatype inherently store the time as well.
Try executing the below query. It should clear things up a bit:
SELECT TO_CHAR(SYSDATE,'DD-MON-YYYY HH:MI:SS'), TO_CHAR(TRUNC(SYSDATE,'HH24'),'DD-MON-YYYY HH:MI:SS') FROM DUAL;

store dates in oracle

I have a table as
create table Dummy (date_created date)
in oracle.I want to store date in 'dd-mon-yyyy' (12-dec-2010) format.
How should i do this.
Please help.
In Oracle a column created with the DATE datatype just stores the date. It doesn't have a particular format, it just stores the day, month, year, hour, minute, and second. You need to convert from whatever format you have using the TO_DATE function. If you have a text string with the date in 'dd-mon-yyyy' format and you want to put this date into your table you'd use something like
INSERT INTO DUMMY (DATE_CREATED)
VALUES (TO_DATE('01-FEB-2011', 'DD-MON-YYYY');
Going the other way (from DATE column value to character string) you'd use the TO_CHAR function. If you were retrieving a value from your table and wanted to convert it to 'DD-MON-YYYY' format you'd use something like
SELECT TO_CHAR(DATE_CREATED, 'DD-MON-YYYY')
FROM DUMMY;
Share and enjoy.
Use to_date() function. In your case, the syntax would be
insert into Dummy values (to_date('08-09-2010', 'dd-mm-yyyy'));
Here is a link to the detailed help.
The DATE datatype will store date and time information (century, year, month, day, hours, minutes, and seconds) in an internal format in the database. When you get it out of the database, you can choose to display it in whatever format you like.
This information is either created using implicit conversion from a string or explicitly using either the TO_DATE function or the ANSI date literal. If you look in the v$nls_parameters view, this will tell you what the NLS_DATE_FORMAT is which is generally used for the implicit conversion. This may often be defined as DD-MON-RR, which might be why the date will come out as 23-DEC-10 when the query select sysdate from dual is run. (Not entirely sure I'm right about the nls stuff. Correct me if I'm wrong.)
However, all the date information is available if you know how to get it. The query select to_char(sysdate, 'dd-mon-yyyy hh24:mi:ss') from dual will return all the date fields.
Likewise, the insert statement shown below will create a row with a date value in it.
insert into dummy (date_created)
values (to_date('12-dec-2010 12:34:56', 'dd-mon-yyyy hh24:mi:ss'))`
This data can then be retrieved.
select date_created from dummy
This will implicitly convert the date to a character string using the NLS_DATE_FORMAT, providing the output below.
DATE_CREA
---------
23-DEC-10
The full date information is available by explicitly converting the date to a character string.
select to_char(date_created, 'DD-MON-YYYY') as date_created from dummy;
select to_char(date_created, 'DD-MON-YYYY HH24:MI:SS') as date_created
from dummy;
This will provide output in the format you require:
DATE_CREATE
-----------
23-DEC-2010
If you always use the TO_DATE and TO_CHAR functions to convert to/from a date datatype, then you will have fewer problems. Implicit conversion is useful but can cause some confusion or problems.
You can keep and eye here
http://www.techonthenet.com/oracle/functions/to_date.php
use to_date function to save a data with the format you need. I suggest to use SYSDATE updating table and when you need to read data from table use something like that:
dbms_output.put_line(TO_CHAR(SYSDATE, 'DD-MON-YYYY HH24:MI:SS'));
to solve your problem use:
to_date('08/JAN/2010', 'DD/MON/YYYY')
Just use TRUNC(YourDate) if date have time part, it will be truncate time part. Oracle have not just 'DATE' type, 'DATE' always have time part.
However if you do not specify time - it will 00:00:00.
SELECT TRUNC(SYSDATE) from dual
Result:
23-12-2010
Oracle does not support DATE without time part.
You can make it always be an integer date by adding a CHECK constraint:
CREATE TABLE dummy (date_created date CHECK (date_created = TRUNC(date_created)))
, insert it in any format you want:
INSERT
INTO dummy (date_created)
VALUES (TO_DATE('23-DEC-2010', 'dd-mon-yyyy'))
and select it in any format you want:
SELECT TO_CHAR(date_created, 'dd-mon-yyyy')
FROM dummy

Select from table by knowing only date without time (ORACLE)

I'm trying to retrieve records from table by knowing the date in column contains date and time.
Suppose I have table called t1 which contains only two column name and date respectively.
The data stored in column date like this 8/3/2010 12:34:20 PM.
I want to retrieve this record by this query for example (note I don't put the time):
Select * From t1 Where date="8/3/2010"
This query give me nothing !
How can I retrieve date by knowing only date without the time?
DATE is a reserved keyword in Oracle, so I'm using column-name your_date instead.
If you have an index on your_date, I would use
WHERE your_date >= TO_DATE('2010-08-03', 'YYYY-MM-DD')
AND your_date < TO_DATE('2010-08-04', 'YYYY-MM-DD')
or BETWEEN:
WHERE your_date BETWEEN TO_DATE('2010-08-03', 'YYYY-MM-DD')
AND TO_DATE('2010-08-03 23:59:59', 'YYYY-MM-DD HH24:MI:SS')
If there is no index or if there are not too many records
WHERE TRUNC(your_date) = TO_DATE('2010-08-03', 'YYYY-MM-DD')
should be sufficient. TRUNC without parameter removes hours, minutes and seconds from a DATE.
If performance really matters, consider putting a Function Based Index on that column:
CREATE INDEX trunc_date_idx ON t1(TRUNC(your_date));
Personally, I usually go with:
select *
from t1
where date between trunc( :somedate ) -- 00:00:00
and trunc( :somedate ) + .99999 -- 23:59:59
Convert your date column to the correct format and compare:
SELECT * From my_table WHERE to_char(my_table.my_date_col,'MM/dd/yyyy') = '8/3/2010'
This part
to_char(my_table.my_date_col,'MM/dd/yyyy')
Will result in string '8/3/2010'
You could use the between function to get all records between 2010-08-03 00:00:00:000 AND 2010-08-03 23:59:59:000
trunc(my_date,'DD') will give you just the date and not the time in Oracle.
Simply use this one:
select * from t1 where to_date(date_column)='8/3/2010'
Try the following way.
Select * from t1 where date(col_name)="8/3/2010"

how to use = assignment operator with timestamp date column in oracle

I'm using timestamp in dat column in table r3. when I fire command
select dat from r3 where dat='16-nov-09';
it shows "no rows selected" but when i fire command
select dat from r3 where dat>'15-nov-09';
it shows the whole data of 16-nov-09. Tell me what is wrong in my first command or what i have to do.
Quering on oracle date columns is always confusing. The date columntype is always a datetime. Storing the current date from sysdate stores always the time component too.
There good and evil ways quering the date columns. I show and vote some.
where to_char(DAT, 'DD-MON-YYYY') = '16-NOV-2009'
where trunc(DAT) = to_date('16-NOV-2009', 'DD-MON-YYYY')
Both bad, because they do not use any index. To avoid this, you can define a function based index on the expression.
The trick of both is to cut off the time component. If time is not needed, than it is a good advise to cut off the time in INSERT and UPDATE trigger. The function based index can convert to a normal index.
where DAT between to_date('16-NOV-2009', 'DD-MON-YYYY')
and to_date('16-NOV-2009 23:59:59', 'DD-MON-YYYY HH24:MI:SS')
where DAT >= to_date('16-NOV-2009', 'DD-MON-YYYY') and DAT < to_date('16-NOV-2009', 'DD-MON-YYYY')+1
This two are always my favorites.
Its a good advice to use to_date and to_char to convert the values between string and datetime.
As DAT is timestamp you can use as below
select DAT from R3
where DAT between to_date('16-NOV-09' , 'dd-MON-yy') and to_date('16-NOV-09 23:59:59', 'DD-MON-YY hh24:mi:ss')
Timestamp has time and date components, so query
select dat from r3 where dat='16-nov-09';
will work only for records where time component is midnight: '00:00:00'
Beside formatting (to_date function), you can truncate timestamp to get only date:
select dat from r3 where trunc(dat)='16-nov-09';
Beware that this will not use index on field dat (if there is any).
TIMESTAMP and DATE are different data types in oracle and both store time components. If you really do need to store subsecond times then you use TIMESTAMP, otherwise DATE is your best choice.
The ANSI timestamp and date literal syntaxes are quite handy:
create table ts_test (ts1 timestamp);
select *
from ts_test
where ts1 > timestamp '2009-10-11 00:00:00'
/
select *
from ts_test
where ts1 > timestamp '2009-10-11 00:00:00.1'
/
select *
from ts_test
where ts1 > timestamp '2009-10-11 00:00:00.001'
/
select *
from ts_test
where ts1 = date '2009-10-11'
/
use the below format for a date field in where condition.
where to_char(DAT,'mmddyyyy') = '11152009';
In Oracle the date fields also contain a time component, so 16-nov-09 is actually midnight of Nov 16th.
Two different ways to handle this:
where to_char(DAT,'mmddyyyy') = '11152009'
as john suggested, but I like the following version more:
where trunc(dat) = to_date ('11152009', 'mmddyyyy')
TRUNCfor a date "removes" the time component (or to be more specific, truncates it to midnight), and to_date is the proper way to construct a date value in Oracle SQL. (I prefer to do the comparisons in the right domain - DATEs as in the second example- over another - STRINGs as in the first example. With strings you may run into some weird month issues, sorting is easier in dates etc.)
Just to add to it , An easy way out when you are not bothered about the time-stamp but just want to compare the date is to use the 'like' operator.
for example
select dat from r3 where dat LIKE '16-nov-09%'
will give you desired output.