SQL select rows - sql

Question

I have Oracle SQL Database with values like:
Date Number
20.04.22 1
20.04.22 2
20.04.22 3
20.04.22 4
20.04.22 5
20.04.22 6
21.04.22 1
21.04.22 2
21.04.22 3
21.04.22 4
21.04.22 5
21.04.22 6
Now, I want to select 3 rows, starting on number==value. The value is coming from somewhere else. For example, that value is 2, then I want to have 20.04.22 number 2-5.
How do I write a query if I want to have the numbers between two days? Like when the value is 6, then I need to have 20.04.22 number 6 and 21.04.22 number 1-2...
If its just one day, I can use where number >= [number i choose]
Thanks!

Answer 1

From Oracle 12, you can use:
SELECT "DATE", "NUMBER"
FROM (
SELECT t.*,
COUNT(CASE "NUMBER" WHEN 6 THEN 1 END) OVER (ORDER BY "DATE", "NUMBER")
AS cnt
FROM table_name t
ORDER BY "DATE", "NUMBER"
)
WHERE cnt > 0
FETCH FIRST 3 ROWS ONLY;
Before Oracle 12, you can use:
SELECT "DATE", "NUMBER"
FROM (
SELECT t.*,
COUNT(CASE "NUMBER" WHEN 6 THEN 1 END) OVER (ORDER BY "DATE", "NUMBER")
AS cnt
FROM table_name t
ORDER BY "DATE", "NUMBER"
)
WHERE cnt > 0
AND ROWNUM <= 3;
(Note: DATE and NUMBER are reserved words and it is considered bad practice to use them as identifiers and, if you do, then must be quoted identifiers.)
Which, for your sample data:
CREATE TABLE table_name ("DATE", "NUMBER") AS
SELECT DATE '2022-04-20', 1 FROM DUAL UNION ALL
SELECT DATE '2022-04-20', 2 FROM DUAL UNION ALL
SELECT DATE '2022-04-20', 3 FROM DUAL UNION ALL
SELECT DATE '2022-04-20', 4 FROM DUAL UNION ALL
SELECT DATE '2022-04-20', 5 FROM DUAL UNION ALL
SELECT DATE '2022-04-20', 6 FROM DUAL UNION ALL
SELECT DATE '2022-04-21', 1 FROM DUAL UNION ALL
SELECT DATE '2022-04-21', 2 FROM DUAL UNION ALL
SELECT DATE '2022-04-21', 3 FROM DUAL UNION ALL
SELECT DATE '2022-04-21', 4 FROM DUAL UNION ALL
SELECT DATE '2022-04-21', 5 FROM DUAL UNION ALL
SELECT DATE '2022-04-21', 6 FROM DUAL;
Outputs:
DATE
NUMBER
20-APR-22
6
21-APR-22
1
21-APR-22
2
db<>fiddle here