I am trying to sum all case where the field name [Unique] is > 1. I am using Sum case statement and the column [Unique] is not picking up, I also tried to paste the code of unique in and that did not work.
SELECT DSID, SRC_START_DTTM, SRC_END_DTTM
, DWID + CONVERT(float, FORMAT(SRC_END_DTTM, N'yyyyMMddHH'))/10000000000 AS [~Project]
,
ROW_NUMBER()
OVER (
PARTITION BY DWID + CONVERT(float, FORMAT(SRC_END_DTTM, N'yyyyMMddHH'))/10000000000
ORDER BY SRC_END_DTTM DESC, SRC_START_DTTM DESC
) AS [UNIQUE],
SUM(
CASE
WHEN [UNIQUE] > 1 THEN 1
ELSE 0
END) as Test
FROM F.DIM
GROUP BY DSID, SRC_START_DTTM, SRC_END_DTTM, DWID
ORDER BY [UNIQUE] DESC
ERROR: Invalid Column Name 'Unique'
You are trying to use aliased name of a column in same query which is not possible
Try below
SELECT
T.DSID, T.SRC_START_DTTM, T.SRC_END_DTTM, T.DWID
,SUM(
CASE
WHEN T.[UNIQUE] > 1 THEN 1
ELSE 0
END) as Test
FROM
(SELECT DSID, SRC_START_DTTM, SRC_END_DTTM
, DWID + CONVERT(float, FORMAT(SRC_END_DTTM, N'yyyyMMddHH'))/10000000000 AS [~Project]
, ROW_NUMBER()
OVER (
PARTITION BY DWID + CONVERT(float, FORMAT(SRC_END_DTTM, N'yyyyMMddHH'))/10000000000
ORDER BY SRC_END_DTTM DESC, SRC_START_DTTM DESC
) AS [UNIQUE]
FROM F.DIM) AS T
GROUP BY T.DSID, T.SRC_START_DTTM, T.SRC_END_DTTM, T.DWID
ORDER BY T.[UNIQUE] DESC
Related
There are a lot questions on CASE WHEN topic, but the closest my question is related to this How to use CASE WHEN condition with MAX() function query which has not been resolved.
Here is some of my sample data:
date
debet
2022-07-15
57190.33
2022-07-14
815616516.00
2022-07-15
40866.67
2022-07-14
1221510.00
So, I want to all records for the last two dates and three additional columns: sum(sales) for the previous day, sum for the current day and the difference between them:
SELECT
[debet],
[date] ,
SUM( CASE WHEN [date] = MAX(date) THEN [debet] ELSE 0 END ) AS sum_act,
SUM( CASE WHEN [date] = MAX(date) - 1 THEN [debet] ELSE 0 END ) AS sum_prev ,
(
SUM( CASE WHEN [date] = MAX(date) THEN [debet] ELSE 0 END )
-
SUM( CASE WHEN [date] = MAX(date) - 1 THEN [debet] ELSE 0 END )
) AS diff
FROM
Table
WHERE
[date] = ( SELECT MAX(date) FROM Table WHERE date < ( SELECT MAX(date) FROM Table) )
OR
[date] = ( SELECT MAX(date) FROM Table WHERE date = ( SELECT MAX(date) FROM Table ) )
GROUP BY
[date],
[debet]
Further, of course, it informs that I can't use the aggregate function inside CASE WHEN. Now I use this combination: sum(CASE WHEN [date] = dateadd(dd,-3,cast(getdate() as date)) THEN [debet] ELSE 0 END). But here every time I need to make an adjustment for weekends and holidays. The question is, is there any other way than using 'getdate' in 'case when' Statement to get max date?
Expected result:
date
sum_act
sum_prev
diff
2022-07-15
97190.33
0.00
97190.33
2022-07-14
0.00
508769.96
-508769.96
You can use dense_rank() to filter the last 2 dates in your table. After that you can use either conditional case expression with sum() to calculate the required value
select [date],
sum_act = sum(case when rn = 1 then [debet] else 0 end),
sum_prev = sum(case when rn = 2 then [debet] else 0 end),
diff = sum(case when rn = 1 then [debet] else 0 end)
- sum(case when rn = 2 then [debet] else 0 end)
from
(
select *, rn = dense_rank() over (order by [date] desc)
from tbl
) t
where rn <= 2
group by [date]
db<>fiddle demo
Two steps:
Get the sums for the last three dates
Show the results for the last two dates.
Well, we could also get all daily sums in step 1, but we just need the last three in order to calculate the sums for the last two days, so why aggregate more data than necessary?
Here is the query. You may have to put the date column name in brackets in SQL Server, as date is a keyword in SQL.
select top(2)
date,
sum_debit_current,
sum_debit_previous,
sum_debit_current - sum_debit_previous as diff
(
select
date,
sum(debet) as sum_debit_current,
lag(sum(debet)) over (order by date) as sum_debit_previous
from table
where date in (select distinct top(3) date from table order by date desc)
group by date
)
order by date desc;
(SQL Server uses TOP(n) instead of standard SQL FETCH FIRST 3 ROWS and while SELECT DISTINCT TOP(3) date looks like "get the top 3 rows, then apply distinct on their date", it is really "apply distinct on the dates, then get the top 3" like in standard SQL.)
I have the following SQL code
SELECT (COUNT(*) filter (WHERE has_a)) AS count_a,
COUNT(*) AS total_count,
process_date
FROM(SELECT process_date::date AS process_date,
(CASE WHEN (columnA > 0) THEN true ELSE false END) AS has_a
FROM my_table)
temptable
GROUP BY process_date
LIMIT 5;
which gives the following table
I want to create a column called percent_a with value (count_a/total_count)*100 grouped by process_date. E.g for row 1 the new column would have value 49.4 i.e. (1030/2085)*100.
I have tried
SELECT process_date,
((COUNT(*) filter (WHERE has_a))/COUNT(*) * 100) AS percent_a,
FROM(SELECT process_date::date AS process_date,
(CASE WHEN (columnA > 0) THEN true ELSE false END) AS has_a,
FROM my_table)
temptable
GROUP BY process_date
ORDER BY process_date DESC
LIMIT 1;
But this just gave 0s.
How can I create the column to display the % I want? I think something is happening with the GROUP BY but I don't know how to fix it.
It's because count returns an integer, you just need to cast it:
SELECT process_date,
(((COUNT(*) filter (WHERE has_balance))::DOUBLE PRECISION)/COUNT(*) * 100) AS percent_a,
FROM(SELECT process_date::date AS process_date,
(CASE WHEN (columnA > 0) THEN true ELSE false END) AS has_a,
FROM my_table)
temptable
GROUP BY process_date
ORDER BY process_date DESC
LIMIT 1;
I have table that contain Id,Date and Status i.e open/close
i just want a result in sql that contain month wise open,close and total count of Id's
e.g In Jan open count 15,close count 5 and total count 20
Use RollUp() and Group By as below:
;WITH T AS
(
SELECT
Id,
DATENAME(MONTH,[Date]) AS [MonthName],
Status
FROM #tblTest
)
SELECT
[MonthName],
[Status],
StatusCount
FROM
(
SELECT
MonthName,
CASE ISNULL(Status,'') WHEN '' THEN 'Total' ELSE Status END AS Status,
Count(Status) AS StatusCount
FROM T
GROUP BY ROLLUP([MonthName],[Status])
)X
WHERE X.MonthName IS NOT NULL
ORDER BY X.[MonthName],X.[Status]
Output:
Note: If required data in single row by month then apply PIVOT
select year(date), month(date),
sum(case when status = 'open' then 1 else 0 end) as open_count,
sum(case when status = 'closed' then 1 else 0 end) as closed_count,
count(*) as total_count
from your_table
group by year(date), month(date)
I try to get in my diagram the top 3 of the worst value in SSRS:
my Code:
SELECT *
FROM (
Select top 3
intervaldate as Datum
,Name
,teamname as Team
,SUM(case when CounterName = 'Blown away' then calculationUnits else 0 end) as Blown
,Sum(case when CounterName = 'Thrown away' then calculationUnits else 0 end) as Thrown
,Sum(case when CounterName = 'total' then calculationUnits else 0 end) as Total
from Counting
where IntervalDate >= dateadd(day,datediff(day,1,GETDATE()),0)
AND IntervalDate < dateadd(day,datediff(day,0,GETDATE()),0)
and Name in (Select SystemID from tSystemView where SystemViewID = 2)
group by intervaldate, teamName, Name
) c
Expression of the diagram:
=Sum(Fields!Blown.Value + Fields!Thrown.Value) / Sum(Fields!Total.Value) * 100
And I sorted it from highest to lowest
But it does not show me the right order.
If I choose every "Name" then it shows me other value then the top 3:
all Names with value:
top 3:
It's because your top 3 statement is in the SQL while your sort is in the report. Without an order by SQL picks the top 3 random records. Also, unless there is more SQL you are not showing, the outer select is unnecessary. Add an order by <column> desc below your group by.
with Calcs as
(
select intervaldate as Datum,
Name,
TeamName,
SUM(case when CounterName = 'Blown away' then calculationUnits else 0 end) as Blown,
Sum(case when CounterName = 'Thrown away' then calculationUnits else 0 end) as Thrown,
Sum(case when CounterName = 'total' then calculationUnits else 0 end) as Total
from Counting
where IntervalDate >= dateadd(day,datediff(day,1,GETDATE()),0)
AND IntervalDate < dateadd(day,datediff(day,0,GETDATE()),0)
and Name in (Select SystemID from tSystemView where SystemViewID = 2)
group by intervaldate, teamName, Name
)
select b.*
from
(
select a.*, row_number() over (order by (Blown + Thrown)/Total desc) as R_Ord -- Change between ASC/DESC depending on needs
from Calcs a
) b
where R_Ord <=3
The below query is working fine in Oracle but it is not working in hive.
SELECT Q.tm_mo_id,
'1380' AS mrc_cd,
NVL (R.itm_profit_ctr_cd, '99') AS profit_center_cd,
MAX(CASE R.itm_profit_ctr_cd
WHEN NULL THEN 'UNASSIGN PROFIT CNTR'
ELSE R.itm_profit_ctr_ds
END) profit_center_desc,
SUM(Q.bp_grs_quota_am) AS mth_bp_plan_gts_am_usd,
SUM(Q.grs_quota_am) AS mth_ju_plan_gts_am_usd
FROM v_l_0002_gb_gds_us_quota_v_1 Q
LEFT JOIN
(SELECT * FROM
(SELECT ph_dtl_id,
itm_profit_ctr_cd,
MIN (itm_profit_ctr_ds) AS itm_profit_ctr_ds,
ROW_NUMBER () OVER (
PARTITION BY ph_dtl_id
ORDER BY COUNT(CASE profit_ctr_cd
WHEN 'JNJDUMMY' THEN NULL
WHEN '99' THEN NULL
ELSE profit_ctr_cd
END) DESC,
itm_profit_ctr_cd ASC) rn
FROM v_l_0002_gb_gds_us_sku_to_profit_center_lookup_v_1
GROUP BY ph_dtl_id,
itm_profit_ctr_cd) E
WHERE rn = 1 ) R
ON (Q.ph_dtl_id = R.ph_dtl_id)
WHERE SUBSTR (Q.tm_mo_id, 1, 4) = '2016'
GROUP BY Q.tm_mo_id,
NVL(R.itm_profit_ctr_cd, '99')