sql table
here in the table above named carpooling contains a column name start_on which has date time as timestamp i have to write a query to select all the rows having date as 25-11-20 using to_char and to_date.
You write a timestamp literal like this:
timestamp '2020-11-25 00:00:00'
so the full filtering condition will be
where start_on >= timestamp '2020-11-25 00:00:00'
and start_on < timestamp '2020-11-26 00:00:00'
Note that dates and timestamps are different in Oracle, and dates include times down to the second (this is for historical reasons - originally there was only the date type, and timestamp was added much later).
Use the TRUNC function, along with date and interval literals:
SELECT *
FROM CARPOOLING
WHERE START_ON BETWEEN DATE '2020-11-25'
AND (DATE '2020-11-26' - INTERVAL '0.000001' SECOND)
You can simply use to_date, but it's recommended to remove the time when comparing the dates. Otherwise, rows having the same date, but a different time will not be selected. Removing the time can be done using TRUNC.
So you can do something like this:
SELECT * FROM carpooling
WHERE TRUNC(start_on) = TO_DATE('2020-11-25','yyyy.mm.dd');
If you don't want to check the 25th of November 2020, but another data, change the date to match your goal.
Related
I have a table with date column in which date is updated in this format - 11/21/2022.
How can I get the results for the last 15 days using this date column in Teradata? Looks like need to change the date format in where clause.
I was using below query which does not work with this format
select *
from table_A
WHERE date BETWEEN (CURRENT_DATE - INTERVAL '30' DAY)
AND CURRENT_DATE
This does not give any results.
Assuming your date column be text, then you must first convert it to a bona fide date using the TO_DATE() function:
SELECT *
FROM table_A
WHERE TO_DATE("date", 'MM/DD/YYYY') BETWEEN (CURRENT_DATE - INTERVAL '30' DAY) AND CURRENT_DATE;
Note that ideally you should be storing your dates in actual date columns, not as text. This would avoid the need to call the clunky TO_DATE() function.
I'm having issues in my WHERE clause selecting data from a specific day to today's date. The day/time format in my date column is '7/2/2020 3:12:08 PM'.
I've tested a couple options but keep getting this error - 'literal does not match format string'.
Any idea's of how I can select all data from March 1, 2020 to current date?
Thanks!
In Oracle date columns are not strings, they are exactly in date datatype, so you don't need to convert/cast it. Just use simple date literals:
https://docs.oracle.com/en/database/oracle/oracle-database/19/sqlrf/Literals.html#GUID-8F4B3F82-8821-4071-84D6-FBBA21C05AC1
select * from table where your_date_columg >= date'2015-12-31'
or with to_date function for your string:
select * from table
where
your_date_columg >= to_date('2019-11-25 13:57:52',
'yyyy-mm-dd hh24:mi:ss')
I have a column called Create_Date which has data in the format like 19-JUN-18 10.27.00.000000000 PM and data type is TIMESTAMP(6).
I am trying to look at date range like yesterday's date or between two dates in Create_Date without using TO_DATE(TO_CHAR(P.CREATE_DATE_TIME,'dd/mon/yy')) and entering the value as '19-JUN-18'.
I want to use Create_Date=SYSDATE-1 OR Create_Date=CURRENT_DATE-1 instead to filter on yesterdays date. Or Use Create_Date>=SYSDATE or Create_Date>=CURRENT_DATE to look at dates greater than or equal to today.
Can someone help?
You could use TRUNC:
SELECT *
FROM tab
WHERE Create_Date >= TRUNC(SYSDATE,'DD') -- -1
-- or between to dates (using date literals)
WHERE Create_Date >= DATE 'yyyy-mm-dd'
AND Create_Date < DATE 'yyyy-mm-dd'
As it's a timestamp I'd cast the truncated (to midnight) current date to a timestamp for clarity; Oracle will use an index on that column even if you leave it as a date, but it doesn't hurt to make it explicit:
where create_date >= cast(trunc(sysdate) as timestamp)
The trunc() function defaults to truncating to midnight; you can explicitly include 'DD' as a second argument if you prefer (for even more clarity, though some would see it as noise).
If you want a range, say yesterday:
where create_date >= cast(trunc(sysdate) - 1 as timestamp)
and create_date < cast(trunc(sysdate) as timestamp)
If you want to specify other dates then you can use timestamp literals, e.g. to see everything for May:
where create_date >= timestamp '2018-05-01 00:00:00'
and create_date < timestamp '2018-06-01 00:00:00'
I'm in PostgreSQL.
I need to print all mailing with creation date strictly more that 2015-04-04. I tried the following queries:
SELECT *
FROM mailing.mailing
WHERE creation_date > '2015-04-04';
and
SELECT *
FROM mailing.mailing
WHERE creation_date >= '2015-04-04';
But they produced the same result set(including '2015-04-04'). Is it possible to write such a query without explicitly saying WHERE creation_date >= '2015-04-05';
UPD: The column's type is timestamp without time zone.
If your creation_date field is of type datetimetry comparing it to '2015-04-04 23:59:59' instead, as '2015-04-04 08:30:00' seems to be greater than '2015-04-04'.
Assuming your default date format for your database is 'YYYY-MM-DD' and creation_date field is a date type, your query will actually be converted automatically to something like:
SELECT *
FROM mailing.mailing
WHERE creation_date > to_date('2015-04-04', 'YYYY-MM-DD');
The date value you have provided represents the first second of that day, that's why you see no difference between your queries. (Your first query would exclude the first second of the day though.)
What you could do to avoid this is:
where creation_date >= to_date('2015-04-05 00:00:00', 'YYYY-MM-DD HH24:MI:SS')
or
where date_trunc(creation_date-1) = '2015-04-04'
I have a table with two temporal columns. First (name is DATE) is storing the date (not including the time part) and therefor the datatype is DATE. Second column (name is TIME) is for storing the time in seconds and therefor the datatype is NUMBER.
I need to compare this two dates with a timestamp from another table. How can I calculate the date of the two columns (DATE and TIME) and compare to the timestamp of the other table?
I have tried to calculate the hours out of the time column and add it to the date column, but the output seems not correct:
SELECT to_date(date + (time/3600), 'dd-mm-yy hh24:mi:ss') FROM mytable;
The output is just the date, but not the time component.
You can use the INTERVAL DAY TO SECOND type:
SELECT your_date + NUMTODSINTERVAL(your_time_in_seconds, 'SECOND') FROM dual;
Example:
SELECT TRUNC(SYSDATE) + NUMTODSINTERVAL(39687, 'SECOND') FROM dual;
The calculated date with time is: 10-11-2013 11:01:27
This is a better idea than dividing your value by 3600 in my opinion, as you have an interval in seconds, so it feels natural to use an interval to represent your time, which can then be easily added to a column of DATE datatype.
Oracle Interval in Documentation
NUMTODSINTERVAL Function in documentation
date + (time/3600) is already a DATE, so you don't need to do to_date(). It does have the time part you added though, you just aren't displaying it. If you want to output that as a string in the format you've shown, use to_char() instead:
SELECT to_char(date + (time/3600), 'dd-mm-yy hh24:mi:ss') FROM mytable;
... except that if time is actually in seconds, you need to divide by 86400 (24x60x60), not 3600. At the moment you're relying on your client's default date format, probably NLS_DATE_FORMAT, which doesn't include the time portion from what you've said. That doesn't mean the time isn't there, it just isn't displayed.
But that is just for display. Leave it as a date, by just adding the two values, when comparing against you timestamp, e.g.
WHERE date + (time/86400) < systimestamp
Try like this,
SELECT TO_DATE('11/11/2013','dd/mm/yyyy') + 3600/60/60/24 FROM DUAL;
Your query,
SELECT date + time/60/60/24 FROM mytable;
try using to_timestamp instead of to_date