I am new to PyCharm and I have 'Process finished with exit code 0' instead of getting (683, 11) as a result (please see attachment), could you guys help me out please? Much appreciate it!
That is good news! It means that there is no error with your code. You have run it right through and there is nothing wrong with it. Pycharm returns 0 when it has found no errors (plus any output you give it) and returns 1 as well as an error message when it encounters errors.
Editors and scripts do not behave like the interactive terminal, when you run a function it does not automatically show the the result. You need to actually tell it to do it yourself.
Generally you just print the results.
If you use print(data.shape) it should return what you expect with the success message Process finished with exit code 0.
exit code 0 means you code run with no error.
Let's give a error code for example(clearly in the below image): in below code, the variable lst is an empty list,
but we get the 5 member in it(which not exists), so the program throws IndexError, and exit 1 which means there is error with the code.
You can also define exit code for analysis, for example:
ERROR_USERNAME, ERROR_PASSWORD, RIGHT_CODE = 683, 11, 0
right_name, right_password = 'xy', 'xy'
name, password = 'xy', 'wrong_password'
if name != right_name:
exit(ERROR_USERNAME)
if password != right_password:
exit(ERROR_PASSWORD)
exit(RIGHT_CODE)
I would recommend you to read up onexit codes.
exit 0 means no error.
exit 1 means there is some error in your code.
This is not pyCharm or python specific. This is a very common practice in most of the programming languages. Where exit 0 means the successful execution of the program and a non zero exit code indicates an error.
Almost all the program(C++/python/java..) return 0 if it runs successful.That isn't specific to pycharm or python.
In program there is no need to invoke exit function explicitly when it runs success it invoke exit(0) by default, invoke exit(not_zero_num) when runs failed.
You can also invoke exit function with different code(num) for analysis.
You can also see https://en.wikipedia.org/wiki/Exit_(system_call) for more details.
What worked for me when this happened was to go to
Run --> Edit Configurations --> Execution --> check the box Run with
Python Console (which was unchecked).
This means that the compilation was successful (no errors). PyCharm and command prompt (Windows OS), terminal (Ubuntu) don't work the same way. PyCharm is an editor and if you want to print something, you explicitly have to write the print statement:
print(whatever_you_want_to_print)
In your case,
print(data.shape)
I think there's no problem in your code and you could find your print results (and other outputs) in the tab 5: Debug rather than 4: Run.
I just ran into this, but couldn't even run a simple print('hello world') function.
Turns out Comodo's Firewall was stopping the script from printing. This is a pretty easy fix by deleting Python out of the Settings > Advanced > Script Analysis portion of Comodo.
Good Luck
I had same problem with yours. And I finally solve it
I see you are trying to run code "Kaggle - BreastCancer.py"
but your pycharm try to run "Breast.py" instead of your code.
(I think Breast.py only contains functions so pycharm can run without showing any result)
Check on tab [Run] which code you are trying to run.
Your starting the program's run from a different file than you have open there. In Run (alt+shift+F10), set the python file you would like to run or debug.
I'm studying the online course from nand2tetris.com through Coursera. When I try to run the nand2tetris CPUEmulator I get the error message 'Illegal character'. Even the simplest program with one command '#0' I get the error message. I tried indenting 0-10 spaces, and I tried the binary version of the command '0000000000000000' and I still get the error message. To run the emulator I'm using a MacBook and I type the command 'CPUEmulator.sh' into the terminal. I'm using TextEdit with Plain Text format. I named the file 'test.hack'. What am I doing wrong?
I am brand new to ms access, and I am having a syntax error that is preventing me from compiling my db into an executable accde. I'm sure it's something simple I'm looking over.
On your first red line, put a space then underscore at the end.
If IsNull(Me.OrderDeliveryDate) Or _
IsNull(Me.OrderDeliveryDate) Then
Or, just use
If IsNull(Me.OrderDeliveryDate) Then
because the second condition is redundant.
Syntax error files:
I want to know where I can see the exact error info.There's no hint in vivado.
Thanks!
You can usually check the message tab at the bottom of the screen. Anyhow Vivado is not particularly good at telling you what's wrong with your code (I'm not sure if this has to do with Vivado or parsing HDL in general), so be aware that your error may be "cascading" from an error above in your code than where the message indicates there's something wrong).
For instance, when making the following mistake in line 13:
13 reg [15:0] test_reg_0
14 reg [15:0] test_reg_1;
it will tell you test_reg_1 is not declared and mark it as an error everywhere it's referenced.
I am trying to execute "db2look" command from within Excel using VB. But I'm getting Run-time Error
An unexpected token "db2look" was found following "BEGIN-OF-STATEMENT". Expected tokens include: "DECLARE". SQLSTATE=42601
I know connection and everything is fine, as I am able to run simple select queries and based on error it's not connection issue but rather like "db2look" not recognized or valid. I've ran same exact command in cmd window at it works fine.
Just wondering if anyone has been able to run the "db2look" command outside of db2 command window/editor and using VB/Excel? Or if there is something that I am missing.
Thanks
db2look is a tool and standalone executable which cannot be run like a regular SQL statement. It needs to be run from the command line (shell).