I am interested to loop through column to convert into processed series.
Below is an example of two row, four columns data frame:
import pandas as pd
from rapidfuzz import process as process_rapid
from rapidfuzz import utils as rapid_utils
data = [['r/o ac. nephritis. /. nephrotic syndrome', ' ac. nephritis. /. nephrotic syndrome',1,'ac nephritis nephrotic syndrome'], [ 'sternocleidomastoid contracture','sternocleidomastoid contracture',0,"NA"]]
# Create the pandas DataFrame
df_diagnosis = pd.DataFrame(data, columns = ['diagnosis_name', 'diagnosis_name_edited','is_spell_corrected','spell_corrected_value'])
I want to use spell_corrected_value column if is_spell_corrected column is more than 1. Else, use diagnosis_name_edited
At the moment, I have following code to directly use diagnosis_name_edited column. How do I make into if-else/lambda check for is_spell_corrected column?
unmapped_diag_series = (rapid_utils.default_process(d) for d in df_diagnosis['diagnosis_name_edited'].astype(str)) # characters (generator)
unmapped_processed_diagnosis = pd.Series(unmapped_diag_series) #
Thank you.
If I get you right, try out this fast solution using numpy.where:
df_diagnosis['new_column'] = np.where(df_diagnosis['is_spell_corrected'] > 1, df_diagnosis['spell_corrected_value'], df_diagnosis['diagnosis_name_edited'])
Related
I have a Pandas dataframe with several columns wherein the entries of each column are a combination of numbers, upper and lower case letters and some special characters:, i.e, "=A-Za-z0-9_|". Each entry of the column is of the form:
'x=ABCDefgh_5|123|'
I want to retain only the numbers 0-9 appearing only between | | and strip out all other characters. Here is my code for one column of the dataframe:
list(map(lambda x: x.lstrip(r'\[=A-Za-z_|,]+'), df[1]))
However, the code returns the full entry 'x=ABCDefgh_5|123|' without stripping out anything. Is there an error in my code?
Instead of working with these unreadable regex expressions, you might want to consider a simple split. For example:
import pandas as pd
d = {'col': ["x=ABCDefgh_5|123|", "x=ABCDefgh_5|123|"]}
df = pd.DataFrame(data=d)
output = df["col"].str.split("|").str[1]
I am extracting tables from pdf using Camelot. Two of the columns are getting merged together with a newline separator. Is there a way to separate them into two columns?
Suppose the column looks like this.
A\nB
1\n2
2\n3
3\n4
Desired output:
|A|B|
|-|-|
|1|2|
|2|3|
|3|4|
I have tried df['A\nB'].str.split('\n', 2, expand=True) and that splits it into two columns however I want the new column names to be A and B and not 0 and 1. Also I need to pass a generalized column label instead of actual column name since I need to implement this for several docs which may have different column names. I can determine such column name in my dataframe using
colNew = df.columns[df.columns.str.contains(pat = '\n')]
However when I pass colNew in split function, it throws an attribute error
df[colNew].str.split('\n', 2, expand=True)
AttributeError: DataFrame object has no attribute 'str'
You can take advantage of the Pandas split function.
import pandas as pd
# recreate your pandas series above.
df = pd.DataFrame({'A\nB':['1\n2','2\n3','3\n4']})
# first: Turn the col into str.
# second. split the col based on seperator \n
# third: make sure expand as True since you want the after split col become two new col
test = df['A\nB'].astype('str').str.split('\n',expand=True)
# some rename
test.columns = ['A','B']
I hope this is helpful.
I reproduced the error from my side... I guess the issue is that "df[colNew]" is still a dataframe as it contains the indexes.
But .str.split() only works on Series. So taking as example your code, I would convert the dataframe to series using iloc[:,0].
Then another line to split the column headers:
df2=df[colNew].iloc[:,0].str.split('\n', 2, expand=True)
df2.columns = 'A\nB'.split('\n')
The question is, how to gain access to the strings inside of the first column so that string manipulations can be performed with each value. For example remove spaces in front of each string.
import pandas as pd
data = pd.read_csv("adult.csv", sep='\t', index_col=0)
series = data['workclass'].value_counts()
print(series)
Here is the file:
Zipped csv file
It is index, so use str.strip with series.index:
series.index = series.index.str.strip()
But if need convert series here to 2 columns DataFrame use:
df = series.rename_axis('a').reset_index(name='b')
new here and I am new to programming.
So.. as the title says I am trying to swap two full columns from two different files (columns has the same name but different data). I started this:
import numpy as np
import pandas as pd
from pandas import DataFrame
df = pd.read_csv('table1.csv', col_name= 'COL1')
df1 = pd.read_csv('table2.csv', col_name = 'COL1')
df1.COL1 = df.COL1
But now I am stack.. how do I select whole column and how can I print the new combined table to a new file (i.e table 3)?
You could perform the swapping by copying one column in a temporary one and deleting afterwards like follows
df1['temp'] = df1['COL1']
df1['COL1'] = df['COL1']
df['COL1'] = df1['temp']
del df1['temp']
and then writing the result via to_csv to a third CSV
df1.to_csv('table3.csv')
I am trying to add rows to pandas dataframe incrementally inside the for loop.
My for loop is like below:
def print_values(cc):
data = []
for x in values[cc]:
data.append(labels[x])
# cc is a constant and data is a list. I need these values to be appended to a row in pandas dataframe.
# Pandas dataframe structure is like follows: df=pd.DataFrame(columns = ['Index','Names'])
print cc
print data
# This does not work - Not sure about the problem !!
#df_clustercontents.loc['Cluster_Index'] = cc
#df_clustercontents.loc['DatabaseNames'] = data
for x in range(0,10):
print_values(x)
I need the values "cc" and "data" to be appended to the dataframe incrementally.
Any help would be really appreciated !!
You can use ,
...
print(cc)
print(data)
df_clustercontents.loc[len(df_clustercontents)]=[cc,data]
...